A 50 Kg box sits at rest on a 30 degree ramp where the coef of static friction is 0.5773. How hard would you have to push horizontally to get the box to start to move up the ramp?

Answer:

Efficiency is defined as "it is the ratio  of output to the input

input work  = 25 J ,

output work = (4 × 5) = 20 J  ,

                                           Work  =Force × distance moved

                                                       = 4 × 5

                                                        = 20 J  

                 efficiency (η ) = 20 ÷ 25

                                          = 80%

Efficiency is 80%              

R = √ (5²m² + 13²m²)

R = √ (25m² + 169m²)

R = √194m²

R = 13.928... m

R = 13.9 m

The magnitude of the resultant vector would be 13.93 meters because as per the triangle law of the vector addition the resultant is the closing side of the triangle.

The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.

Examples of the vector quantities are displacement, velocity acceleration, force, etc.

While the scalar quantities do not contain the information of the direction they only have a magnitude of the quantity measured.

The resultant vector can be calculated with the help of the triangle law of the vector addition

By using the Pythagoras theorem for the right-angled triangle

Resultant² = base² + height²

Resultant² = 13² + 5²

Resultant²  = 194

Resultant = √194

                =13.93 m

Since the resultant is the closing side of the triangle according to the triangle law of vector addition, the resultant vector's magnitude would be 13.93 meters.

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Answer:

The points 2 and 4 should be connected.

Explanation:

To complete the circuit, we need to connect the two points which when connected, encompass the battery and the bulb in the circuit. The points 2 and 4 do the job, since they connect the terminal of the battery and the terminal of the bulb, and thus complete the circuit.

Therefore,  the choice C is correct.

Answer:

C) Points 2 and 4

Explanation:

In a complete electric circuit, wires carry the current from the battery to the bulb and from the bulb to the battery. The wires should be attached to points 2 and 4 to make the bulb glow.

This is because the nasal mucus is blocking the nasal passage, meaning that if there is anything that he/she is trying to smell will be blocked by the mucus and will not be able to go down into the nasal passage where the smells are detected.

The correct answer to your question would be the 1st answer choice, A series circuit.

Hope this helped you!! (:

Final answer:

A circuit with a single current path is a series circuit, characterized by its components connected end-to-end in a single loop.

Explanation:

A circuit that has only a single path for current to flow through is best classified as a series circuit. In a series circuit, all components are connected end-to-end to form a single loop, giving current only one path to follow. This is in contrast to a parallel circuit where components are connected across common points and current divides into multiple paths. In a series circuit, the current is the same throughout and the sum of the voltages across each component must equal the supplied voltage. An open circuit refers to a broken path where no current flows, a parallel circuit has multiple paths for current, and a short circuit indicates an unintended path allowing current to bypass a component within the circuit.

Use the defining equation for kinetic energy.

E = mv² / 2

E = (1500kg)(2 m/s)² / 2

E = 6000 J / 2

E = 3000 J

Therefore, the cars kinetic energy is 3000 J.

K.E= 1/2 mv2

=1/2 (1500)(2)2

=3000J

meters per second or m/s

The standard unit of measure for speed in physics is meters per second (m/s). It is derived from the SI unit system where speed is calculated as distance over time. Consistent units and including measurement units with values are crucial in physics.

In physics, the standard unit of measure for speed is meters per second (m/s). This unit comes from the International System of Units (SI), which is a consistent framework for physical measurements. Speed is the distance traveled over time, requiring a measurement of length divided by time. Therefore, the dimension of speed is L/T, with L representing length and T representing time, and its SI unit is m/s.

The preservation of consistent units across physics equations is essential; the dimensions on both sides of an equation must match. For instance, you cannot equate quantities that have different dimensions. Since motion can be measured in various units, such as kilometers per hour, it is important to use the correct conversion when comparing or converting speeds. Additionally, speed has a defined value in m/s given that the speed of light is defined in these units since 1983.

Furthermore, when considering units named after people, they are capitalized, as in 'Newtons'. It is critical in physics to always include units in your answer, for they provide context and scale to the value. Therefore, when providing the speed of an object, it should always be expressed with the appropriate unit, like '5 m/s'—not just '5'.

Speed is defined as the distance an object moves per unit of time.

The distance an object moves per unit of time is known as speed. Speed is defined as the rate of change of distance with respect to time and is expressed as distance covered in unit time. This concept is a fundamental aspect of motion, helping us understand how fast or slow an object moves relative to time. The formula to calculate speed is speed (v) = distance covered (D) / time taken (Δt). It's important to note that speed is a scalar quantity, meaning it has magnitude but not direction, unlike velocity which includes direction. An everyday example illustrating speed is driving a car: if you travel 60 miles in 1 hour, your speed is 60 miles per hour (mph).

(2m west) + (3m south) + (4m east) + (1m north) =

[ (2m west)+(4m east) ] + [ (3m south)+(1m north) ] =

[ (-2m east)+(4m east) ] + [ (3m south)-(1m south) ] =

(2m east) + (2m south)

Now, so far, we have the orthogonal (perpendicular) components of the displacement ... the North/South component and the East/West component.

To combine these, it's time for Pythagoras:

Displacement = √[ (2m)² + (2m)² ]

Displacement = √ (4m² + 4m²)

Diplacement = √8m²  

Displacement =  2.83 meters Southeast

M = mass of the first sphere = 10 kg

m = mass of the second sphere = 8 kg

V = initial velocity of the first sphere before collision = 10 m/s

v = initial velocity of the second sphere before collision = 0 m/s

V' = final velocity of the first sphere after collision = ?

v' = final velocity of the second sphere after collision = 4 m/s

using conservation of momentum

M V + m v = M V' + m v'

(10) (10) + (8) (0) = (10) V' + (8) (4)

100 = (10) V' + 32

(10) V' = 68

V' = 6.8 m/s

Answer

3

Left resistance

These three resistances are in Parallel. Their fractions are added.

Right Resistance

Answer

R_left + R_right = 2 + 1 = 3

Hope it helps.

If you have any query, feel free to ask.

Answer:

answer is D

Explanation:

I just took this asesment

Answer if you have a picture on your screen if to man pulling a cart it’s c

Explanation:

Ans) D) -7.6N

See magnitude of force along x direction will not depend on forces along y - direction

So we would only consider forces along x direction

Now , net force acting along positive direction = -24 + 20cos35°

As only cos component is acting along x-direction.

Putting value of cos35° we would get,

Net force = -24 +16.4N

= -7.6 N

Hope it helps!!!

Answer:

-7.6 N

Explanation:

Use Net Force Equation.

Fnet = F1 + F2 + F3 + F4

In which the following main forces in play are:

F1 = Gravitational Force

F2 = Normal Force

F3 = Thrust Force

F4 = Air resistance

Since this is assumed to happen on a flat surface, the gravitational and normal forces cancel out. So we are left with:

Fnet = F(thrust) + F(air resistance)

Now we can use this equation to solve for the net force.

Fnet = 10N [right] + 7N [left]

Fnet = 10N [right] - 7N [right]

Fnet = 3N [right].

Therefore, the total net force acting on this car would be 3N [right]

The net force acting on the race car is 7 N to the right.

The net force acting on the race car can be determined by considering the forces acting on it. In the picture, we can see that there are two forces: a 10 N force to the right and a 3 N force to the left. Since the forces are in opposite directions, we can subtract the magnitude of the smaller force from the magnitude of the larger force to find the net force. Therefore, the net force acting on the race car is 7 N to the right.

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Answer:

The ball will have a kinetic energy of 0.615 Joules.

Explanation:

Use the kinetic energy formula

[tex]E_k = \frac{1}{2}mv^2 = \frac{1}{2}0.032kg\cdot 6.2^2 \frac{m^2}{s^2}= 0.615J[/tex]

The kinetic energy at the moment of leaving the hand will be 0.615 Joules. (From there on, as it ball is traveling upwards, this energy will be gradually traded off with potential energy until the ball's velocity becomes zero at the apex of the flight)

Amplitude is the height of a wave.

Given data:

Mechanical advantage (M.A) = 6

Load is moved(Output force) = Fo = 36 N,

Input force = Fi = ?

We know that Mechanical advantage = Fo÷Fi

                                                  M.A. = Fo÷Fi

                                                       6 = 36÷Fi

                                                       Fi= 6N

Input force is 6N

To move a 36 N load up a ramp with a mechanical advantage of 6, an input force of 6 N is required. The work done when moving objects up a ramp involves overcoming gravity by applying a force over a certain distance.

Mechanical Advantage: The mechanical advantage of a ramp is calculated by dividing the length of the ramp by the vertical height it spans. In this case, with a mechanical advantage of 6, the input force needed can be calculated using the formula: Input Force = Load Force ÷ Mechanical Advantage.

Calculation: Given Load Force = 36 N and Mechanical Advantage = 6, Input Force = 36 N ÷ 6 = 6 N. Therefore, an input force of 6 Newtons is needed to push the 36 Newton load up the ramp.

Work and Energy: When moving objects up a ramp, work is done against gravity. The work done is equal to the force applied multiplied by the distance moved in the direction of the force.

The time frame is the same for both triangles and the area is the same for both triangles. hence, option (2) and (3) are correct.

According to Kepler's Second Law, a line extending from the sun to the planet sweeps out equal regions of the ellipse in equal amounts of time. Accordingly, the planet moves more slowly away from the sun than it does toward it.

So, the two highlighted triangles in the image refer that:

Hence option (2) and (3) are correct.

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Relative to reference frame of the airplane he's sitting in:

-- Gravitational potential energy = (mass) (gravity) (height)

His height above the airplane is zero, so his GPE is zero.

-- Kinetic energy = (1/2) (mass) (speed)²

His speed relative to the airplane is zero, so his KE is zero.

Mechanical energy = (potential energy) + (kinetic energy)

Mechanical energy = ( 0 ) + ( 0 )

The poor fellow's total mechanical energy is zero .

The mechanical energy of a system is the sum of its kinetic energy and potential energy. The given system will have a mechanical energy equal to 26379 × 10³  J.

Kinetic energy of an object is generated by virtue of its motion whereas, potential energy is stored by virtue of its position. The sum of potential and kinetic energy is called mechanical energy.

Potential energy p = m g h.

mass  = 60 Kg

height h = 8000 m

g = 9.8 m/s² .

p = 60 kg × 9.8 m/s² × 8000 m

  = 4704 × 10³ J

Kinetic energy Ke = 1/2 m v²

             Velocity v = 850 km/hr

Ke = 1/2 (60 Kg × (850 km/hr)²  )

     = 21675 × 10³ J

Thus, mechanical energy = 4704 × 10³ J  + 21675 × 10³ J  

                                           =  26379 × 10³  J

Therefore, the mechanical energy of the man is 26379 × 10³  J.

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Answer:

Force = 20N

acceleration (a) = 1.5 m/s²

Mass of object (m) = ?

From Newtons II law

                       F = m. a N

                        m =  F/a

                        m = 20/1.5

                       m = 13.34 Kg

Mass of an object is 13.34 Kg

We will use the percentage difference formula and so:

[tex]\frac{|Population_{final}-Population_{initial}|}{Population_{initial}}[/tex]

By plugging in our values we obtain:

[tex]\frac{321-281}{281}=0.142349[/tex]

And 0.142349 converted to percentage is :

[tex]0.142349 \times 100 = 14.2349%[/tex]

Therefore, there was a population increase of 14.2349% from 2000 to 2015 in the US.

Given:

Year 2000 = 281 million people

Year 2015 = 321 million people

321 M - 281 M = 40 M

An increase of 40 million people.

40M/281M = 0.14 or 14%.

From 2000 to 2015

the population increased by 14%

Given that:

mass (m) = 0.5 Kg,

spring pulled (x) =0.50 m,

spring constant (k)= 50 N/m,

                   accelearation = ?

        we know that from Hook's law

                         F = k.x

                            = 50 × 0.5

                            =25 N

Also we know that Force = m. a

                                    25  = 0.5 × a

                                      a = 50 m/s²

÷

To find the acceleration of the mass when released from the spring, we use Hooke's Law and Newton's second law to calculate it as 50 m/s².

The student is asking about the acceleration of a 0.50 kg mass when it is released from 0.50 m below the equilibrium point of a spring with a spring constant of 50 N/m. To find the acceleration, we use Hooke's law, which states that the restoring force of the spring is F = -kx, where k is the spring constant and x is the displacement from the equilibrium position. Since the restoring force is the only force acting in the vertical direction (ignoring air resistance and assuming gravity is being balanced by the tension in the spring), this force will also be the net force acting on the mass to produce acceleration, according to Newton's second law, F = ma, where m is the mass and a is the acceleration.

First, we calculate the force:

F = kx = 50 N/m × 0.50 m = 25 N

Then, we use Newton's second law to find the acceleration:

a = F/m = 25 N / 0.50 kg = 50 m/s²

Answer: 9.43 s

Explanation:

Since there is no external force acting in space, the total momentum of the entire system would be conserved.

When the astronaut throws a canister, an equal and opposite amount of force would act on the astronaut which means momentum of the canister would be equal to momentum of the astronaut,

⇒ m v = m' v'

⇒ 12 kg × 12 m/s = 68 kg × v'

The velocity of the astronaut would be:

v' = 2.12 m/s

The distance need to be covered by astronaut to reach the spaceship = 20 m

Time taken : Distance/ velocity = 20 m / 2.12 m/s = 9.43 s.

Hence, astronaut would take 9.43 s to reach the spaceship.

Answer:

The greatest horizontal force that can be exerted without moving the table is 168.56N.

Explanation:

The maximum friction force is determined from the coefficient of static friction as follows:

[tex]F_{fr}=\mu\cdot F_{norm} = 0.43\cdot F_{norm}[/tex]

where the the normal force is exerted by the ground as a reaction to the weight of the table, and has same magnitude as but opposite direction to the gravitational force on the table:

[tex]F_{fr} = 0.43\cdot 40kg\cdot 9.8 \frac{m}{s^2} = 168.56 N[/tex]

This is the maximum static force, so the friction force will be matching and opposing any horizontal force up to 168.56N.

The greatest horizontal force that could be exerted on the table while it remains stationary is 168.56 N.

We'll begin by calculating the normal reaction. This can be obtained as follow:

N = mg

N = 40 × 9.8

N = 392 N

Finally, we shall determine the frictional force.

F = μN

F = 0.43 × 392

F = 168.56 N

Therefore, the greatest horizontal force that could be exerted on the table is 168.56 N

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