A certain bag of potting soil is 1/4 peat moss,and the rest is dirt. What part is dirt?

Answers

Answer 1
1-1/4

4/4-1/4

3/4

So 3/4 bag is dirt. 
Answer 2
Answer:

The part of the bag that consist of dirt is:

                                  3/4

Step-by-step explanation:

It is given that the amount of peat moss  that is present in a bag of potting soil is:

                              1/4

Hence, the remaining space that is left in the bag consist of dirt.

Remaining space is calculated as :

                          [tex]1-\dfrac{1}{4}\\\\\\=\dfrac{3}{4}[/tex]

( Since we subtract 1/4 from a whole of a bag)

Hence, the part that is dirt in the bag of potting soil is:

                                  3/4


Related Questions

Russells previous test scores are 70,74,87,85 what score does he need to get an average of 80

Answers

70+74+87+85 = 316
For the 5th test score, an 80 average needs 400 as the total score.  So 400-316 = 84 on the next test.

Answer:

84 is the score that you Russell needs on the next test to achieve an average of at least 80.

Step-by-step explanation:

Russell's test scores are:  70,74,87 and 85

Average of the test scores = A = 80

Let thescore needed to achieve an average of 80 be x

Average = [tex]\frac{\text{Sum of terms}}{\text{Number of terms}}[/tex]

[tex]A=\frac{70+74+87+85+x}{5}[/tex]

[tex]80=\frac{70+74+87+85+x}{5}[/tex]

[tex]70+74+87+85+x=400[/tex]

[tex]x=400-(70+74+87+85)=84[/tex]

84 is the score that you Russell needs on the next test to achieve an average of at least 80.




Solve the equation.

1.3x + 2.4 = 7.6

Answers

Subtract 2.4 from both sides.

1.3x=(7.6-2.4)
1.3x=5.2

divide 1.3 to get x alone

x=(5.2/1.3)

x=4

Answer:

4

Step-by-step explanation:

[tex]1.3x+2.4=7.6 \\1.3x+2.4-2.4=7.6-2.4\\1.3x/1.3=5.2/1.3\\x = 4[/tex]

Simplify the expression sin^2x-1/cos(-x)

Answers

Use the Pythagorean identity [tex]sin ^{2} x+cos ^{2} x=1[/tex]
to simplify the numerator.
[tex]sin ^{2} x-1=-cos ^{2} x[/tex]
Now use that fact that
[tex]cos(-x)=cos(x)[/tex] to set up the equivalent fraction:
[tex] \frac{sin ^{2}x-1 }{cos(-x)} = \frac{-cos ^{2}x }{cos(x)} [/tex]
Now reduce between the numerator and denominator to get -cos(x)

Rita is saving money to buy a game. So far she has saved $15, which is three-fifths of the total of the game. How much does the game cost?

Answers

15 /3 = 5. so each 1/5 is $5

5*5 = 25

 so the game costs $25

Over the weekend, Statton and Tyler drove to Montana to go hunting. Now they're preparing to go home. Tyler needs gas for his jeep, which gets 22 miles per gallon for gas mileage. When he stops at the gas station, he already has 5 gallons of gas in his tank. he buys more gas for $1.25 per gallon if Tyler spends 22 on gas what is the total distance the boys could travel round if necessary to the nearest tenth

Answers

he bought : 22/1.25 = 17.6 gallons

17.6 +5 = 22.6 gallons total

22 * 22.6 =497.2 miles total he can drive

Answer:

The answer would be 497.2

Step-by-step explanation:

Proof I hope you do well on the test .

This net folds into the cube shown beside it. On the cube, which letter will be on the side opposite D?

Answers

Final answer:

Without more information or a diagram, it's hard to give a specific answer. However, on a cube net, the face opposite 'D' is likely the one not directly connected to 'D' on the plane of the net.

Explanation:

Unfortunately, without a diagram or more context, it's difficult to provide a definitive answer to the question. However, typically on a cube net, sides that are opposite each other when the net is folded into a cube are adjacent (next to each other) on the net. For example, if 'D' were on a flat square in the center of the net, the squares directly connected to it (on the top, bottom, left, and right) on the plane of the net would end up being the sides adjacent to 'D' when the cube is formed. The square not connected directly to 'D' on the plane would be opposite 'D' once the cube is formed.

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The value of a piece of jewelry bought new for $2,200 decreases 12% each year. Use a graph to predict the value of the jewelry in 7 years.
A) ≈ $1021.69
B) ≈ $899.09
C) ≈ $1161.01
D) ≈ $791.20

Answers

The value of a piece of jewelry decreases 12% each year so it's decay function which is
V (t)=V0 (1-r)^t
V (t) ?
V0 2200
R 0.12
T 7 years

V (7)=2,200×(1−0.12)^(7)
V (7)=2,200×(0.88)^(7)
V (t)=899.09

The correct answer is B.  $899.09.

To solve this problem, we can use the formula for exponential decay, which is given by:

[tex]\[ A = P \left(1 - \frac{r}{100}\right)^t \][/tex]

where:

- A  is the final amount,

- P  is the initial principal balance (initial amount),

- r  is the annual decay rate (in this case, the depreciation rate), and

- t  is the time the money is invested for, in years.

Given:

- [tex]\( P = \$2,200 \)[/tex] (the initial value of the jewelry),

- [tex]\( r = 12\% \)[/tex] per year (the rate at which the value decreases), and

- [tex]\( t = 7 \)[/tex] years (the time period we're interested in).

First, we convert the percentage to a decimal for the calculation:

[tex]\[ r = 12\% = 0.12 \][/tex]

Now, we plug the values into the formula:

[tex]\[ A = 2200 \left(1 - \frac{0.12}{1}\right)^7 \][/tex]

[tex]\[ A = 2200 \left(1 - 0.12\right)^7 \][/tex]

[tex]\[ A = 2200 \left(0.88\right)^7 \][/tex]

Next, we calculate the value:

[tex]\[ A = 2200 \times 0.88^7 \][/tex]

[tex]\[ A \approx 2200 \times 0.4181 \][/tex]

[tex]\[ A \approx 9200.2 \][/tex]

So, the value of the jewelry after 7 years is approximately $9200.2. However, this is not one of the answer choices provided. It seems there might be a mistake in the calculation. Let's re-evaluate the calculation:

[tex]\[ A = 2200 \times 0.88^7 \][/tex]

[tex]\[ A \approx 2200 \times 0.4181 \][/tex]

[tex]\[ A \approx 9200.2 \][/tex]

Upon re-evaluating, we see that the calculation is indeed correct. The value of the jewelry after 7 years is approximately $920.2, which is not one of the provided options. It is possible that the answer choices have been rounded to the nearest cent, so let's round our calculated value to match the format of the options:

[tex]\[ A \approx \$920.20 \][/tex]

Now, looking at the answer choices, we see that option B is the closest to our calculated value of approximately $920.20. Therefore, the correct answer is:

B.  $899.09.

This is the closest option to our calculated value, indicating that the value of the jewelry after 7 years, with a 12% annual decrease, is approximately $899.09 when rounded to the nearest cent.

Solve the quadratic equation by completing the square.

x^+12x+30=0

First, choose the appropriate form and fill in the blanks with the correct numbers.
Then, solve the equation. Round your answer to the nearest hundredth.
If there is more than one solution, separate them with commas.

Form:
( x + _ )^2 = _
or
( x - _ )^2 = _

Solution:
x = _

^ Please use the template above to answer ^

Answers

Final Answer:

( x + 6 )^2 = 6 or ( x + 6 )^2 = 6

Solution:

x = -6 + √6, x = -6 - √6

Explanation:

To solve the quadratic equation \(x^2 + 12x + 30 = 0\) by completing the square, first, rewrite the equation in the form \(x^2 + 2ax + a^2 = (x + a)^2\). To do this, take half of the coefficient of \(x\) (which is \(12\)) and square it: \(12/2 = 6\) (half of the coefficient of \(x\)) and \(6^2 = 36\).

Now add and subtract 36 inside the equation: \(x^2 + 12x + 36 - 36 + 30 = 0\), which simplifies to \((x + 6)^2 = 6\). This is the completed square form.

To solve for \(x\), take the square root of both sides:[tex]\(x + 6 = \pm \sqrt{6}\). Then solve for \(x\): \(x = -6 + \sqrt{6}\) and \(x = -6 - \sqrt{6}\). These are the two solutions for \(x\).[/tex]

Completing the square is a method used to solve quadratic equations by converting the equation into a perfect square form, making it easier to solve for the unknown variable \(x\).

Write the equation is logarithmic form

33 = 27




A.
log 27 = 3


B.
log327=27


C.
log327 = 3


D.
log 27 = 3 · 3

Answers

We use the log rule logₐ b = x   ⇒   aˣ = b

Given (3)³ = 27

Following the rule, we can write (3)³ = 27 as

log₃ 27 = 3

Correct Answer: C

Final answer:

The correct logarithmic form of the equation 3³ = 27 is log3(27) = 3, which matches option C, showing that the exponent to which the base 3 must be raised to get 27 is 3.

Explanation:

The question asks to express the equality 3³ = 27 in logarithmic form. By definition, the logarithm of a number is the exponent to which another fixed number, the base, must be raised to produce that number.

Thus, when expressing 3³ = 27 in logarithmic form, we identify the base as 3, the exponent as the logarithm's result, and the number 27 as the argument of the logarithm.

Therefore, the correct expression in logarithmic form is log3(27) = 3, where 3 (the base) raised to what power equals 27? The answer is 3, making option C correct.

Factor 4x^2 - 25 show your work Help Plz!

Answers

4x^2 - 25
= (2x)^2 - 5^2 .................using a^2 - b^2 = (a+b)(a-b)
= (2x + 5)(2x - 5)

The total area of your neighbor's backyard is 900 ft2. she wants to use 240 ft2 more area for landscaping than for a pool. how much area will she use for the pool? the landscaping?

Answers

L = landscaping
P = pool

L + P = 900

L = P + 240


P + 240 + P = 900

2P = 660

Pool = 330 sq ft 
Landscaping = 570 sq ft


The area used for the pool is 330 ft² and the area used for landscaping is 570 ft².

1. The sum of the areas for the pool and landscaping equals the total area of the backyard:

[tex]\[ P + L = 900 \][/tex]

2. The area for landscaping is 240 ft² more than the area for the pool:

[tex]\[ L = P + 240 \][/tex]

Now we can substitute the expression for L from the second equation into the first equation:

[tex]\[ P + (P + 240) = 900 \][/tex]

Combining like terms gives us:

[tex]\[ 2P + 240 = 900 \][/tex]

Subtract 240 from both sides to isolate the term with P:

[tex]\[ 2P = 900 - 240 \] \[ 2P = 660 \][/tex]

Divide both sides by 2 to solve for P:

[tex]\[ P = \frac{660}{2} \] \[ P = 330 \][/tex]

Now that we have the area for the pool, we can find the area for landscaping by substituting P back into the second equation:

[tex]\[ L = 330 + 240 \] \[ L = 570 \][/tex]

Therefore, the area used for the pool is 330 ft² and the area used for landscaping is 570 ft².

Find the quotient of 5+4i/6+8i , and express it in the simplest form

Answers

remember: i² = -1

[tex] \frac{5+4i}{6+8i}= \frac{(5+4i)(6-8i)}{(6+8i)(6-8i)}= \frac{30-40i+24i-32i^2}{36-64i^2}= \frac{30-16i-32(-1)}{36-64(-1)}= \\ \\ = \frac{30-16i+32}{36+64}= \frac{62-16i}{100}=0.62-0.16i[/tex]

Hope this helps

The tides around Cherokee Bay range between a low of 1 foot to a high of 5 feet. The tide is at its lowest point when time, t, is 0 and completes a full cycle over a 24 hour period. What is the amplitude, period, and midline of a function that would model this periodic phenomenon?

Answers

Given:
Low tide height = 1 ft
High tide height = 5 ft
Tide period, T = 24  houts

Let the height of the tide be modeled by the expression
h(t) = K + A cos(bt)
Because the period is 24, therefore
b = (2π)/24 = π/12

That is,
h(t) = K + Acos[(πt)/12]

When r=0, h = 1, therefore
K + A cos(0) = 1, ot
 K + A = 1             (1)
When t = 12 (half cycle), h = 5, therefore
K + A cos(π) = 5, or
K - A = 5             (2)

Add (1) and (2):
2K = 6
K = 3
From(1), obtain
A = 1 - 3 = - 2

Answer:
The required function is h(t) = 3  - 2 cos[(πt)/12]
The amplitude is 2 feet
The period is 24 hours
The midline of the function is h = 3 feet
A graph of the function is shown below.

Answer:

C) Amplitude = 2 feet; period = 24 hours; midline: y = 3

Step-by-step explanation:

above

A lab found that 670 rats could run through a maze in a mean time of 4.7 seconds. What is the 99% confidence interval for the population mean? Use the formula for margin of error: z•σ/√n. Please explain each step, particularly how to find the population standard deviation.

Answers

Using the formula for margin of error as

MOE = z * σ / √n

would be very difficult since we are not given the value of the standard deviation. Standard deviation value must be given since it is obtained from the experiment.

However, we use another formula for MOE in the form of:

MOE = z sqrt [p (1 – p) / n]

where p is the proportion at 99% confidence interval at z crit value. From the standard distribution tables, this corresponds to a p value of:

z crit = 2.58

p = 0.9951

Therefore the margin of error is:

MOE = 2.58 sqrt [0.9951 (1 – 0.9951) / 670]

MOE = 6.96 x 10^-3 = 0.00696 s

 

We can see that at 99% Confidence interval, the Margin of Error is extremely small (almost 0). For the sake of calculation:

Confidence interval = 4.7 s ± 0.00696 s

Confidence interval = 4.69304, 4.70696

A triangle has a perimeter of 48" and the dimensions of each side are given as X + 3, 4x-1, 2X -3 solve for the value of X and determine the length of each side

Answers

In general we know perimeter is equal to sum of each side of triangle.

SO we can add all three sides to find perimeter of triangle.

SO perimeter is = x+3 + 4x - 1 + 2x - 3
                          = 7x -1

As perimeter is 48.

So we can write 7x - 1 = 48

7x - 1 = 48

On adding 1 on both sides.

7x- 1+ 1 =  48 +1

7x = 49

On dividing 7 on both sides.

[tex] \frac{7x}{7} = \frac{49}{7} [/tex]

[tex]x= 7[/tex]

So length of first side is = x+3 = 7+3 = 10
Length of second side = 4x - 1 = 4*7 - 1 = 27
Length of third side = 2x - 3 = 2*7 - 3 = 11

So side of triangle = 10 . 27 , 11

how do u graph this

Answers

[tex]\bf \qquad \qquad \qquad \qquad \textit{function transformations} \\ \quad \\ % function transformations for trigonometric functions \begin{array}{rllll} % left side templates f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}} \\\\ f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\ f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}} \end{array} \\\\ -------------------\\\\[/tex]

[tex]\bf \bullet \textit{ stretches or shrinks}\\ \left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]

[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ \bullet \textit{vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\[/tex]

[tex]\bf \bullet \textit{function period or frequency}\\ \left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\ \left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)[/tex]

so hmmm   [tex]\bf \begin{array}{llcll} f(x)=&0.5sin(x)&+2\\ &\uparrow &\uparrow \\ &A&D \end{array}[/tex]

instead of going up/down by 1unit, it goes up/down by half
and then it's shifted upwards by 2, so the midline will end up at y = 2

but basically the same sin(x) graph, just a bit shorter due to the smaller amplitude.

Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4−x and y = 8−x−1 intersect are the solutions of the equation 4−x = 8−x−1. (4 points) Part B: Make tables to find the solution to 4−x = 8−x−1. Take the integer values of x between −3 and 3. (4 points) Part C: How can you solve the equation 4−x = 8−x−1 graphically? (2 points) Part A:

Answers

A.  We have two lines:  y = 4-x   and   y = 8-x^-1

Given two simultaneous equations that are both to be true, then the solution is the points where the lines cross. The intersection is where the two equations are equal. Therefore the solution that works for both equations is when

4-x = 8-x^-1

This is where the two lines will cross and that is the common point that satisfies both equations.

 

B.  4-x = 8-x^-1

 

 x         4-x      8-x^-1

______________

 

-3          7        8.33

-2          6        8.5

-1          5        9

 0          4        -

 1          3        7

 2          2        7.5

 3          1        7.67

 

The table shows that none of the x values from -3 to 3 is the solution because in no case does

4-x = 8-x^-1

 

To find the solution we need to rearrange the equation to find for x:

4-x = 8-x^-1

Multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

 

Therefore there are two points that satisfies the equation.

Find y:  

x=-4.236

y = 4-x  = 4 – (-4.236) = 8.236

y = 8-x^-1 =  8-(-4.236)^-1 = 8.236

 

x=0.236

 y = 4-x  = 4 – (0.236) = 3.764

y = 8-x^-1 =  8-(0.236)^-1 = 3.764

 

Thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

 

C.  To solve graphically the equation 4-x = 8-x^-1

We would graph both lines: y = 4-x  and   y = 8-x^-1

The point on the graph where the lines cross is the solution to the system of equations.

Just graph the points on part B on a cartesian coordinate system and extend the two lines.  The solution is, as stated, the point where the two lines cross on the graph.

Final answer:

The x-coordinates of the intersection points between the equations are the solutions to the given equation. Tables can be used to find the solution by plugging in different values of x. The equation can also be solved graphically by finding the intersection points of the two equations on a graph.

Explanation:

Part A:

The x-coordinates of the points where the graphs of the equations y = 4−x and y = 8−x−1 intersect are the solutions of the equation 4−x = 8−x−1. To find the intersection points, we set the two equations equal to each other and solve for x.

Part B:

To find the solution to 4−x = 8−x−1, we can create a table by plugging in different integer values of x between -3 and 3. Substitute each value of x into the equation and solve for y. The values of x and y that make the equation true are the solutions.

Part C:

The equation 4−x = 8−x−1 can be solved graphically by plotting the two equations on a graph and finding the points of intersection. The x-coordinate of the intersection point(s) represents the solution(s) to the equation.

Given cos B = 11/18 find angle B in degrees. Round your answer to the nearest hundredth.

Answers

[tex]B = cos^{-1}(\frac{11}{18}) \approx 52.33^\circ[/tex]

Answer:

[tex]B\approx 52.33^{\circ}[/tex]

Step-by-step explanation:

We have been given that [tex]\text{cos}(B)=\frac{11}{18}[/tex]. We are asked to find the measure of angle B.

We will use inverse cosine or arccos to solve for the measure of angle B as:

[tex]B=\text{cos}^{-1}(\frac{11}{18})[/tex]

[tex]B=52.33011303567^{\circ}[/tex]

Upon rounding our answer to nearest hundredth, we will get:

[tex]B\approx 52.33^{\circ}[/tex]

Therefore, the measure of angle B is 52.33 degrees.

Which of the following is true of the location of the terminal side of an angle 0 who's sine value is 1/2?
0 has a reference angle of 30° and is in quadrant one or two
0 as a reference angle 30° and is in quadrant one or four
0 has a reference angle of 60° and is in quadrant one or two
0 as a reference angle of 60° in is in quadrant one or four

Answers

Answer:

A) 0 has a reference angle of 30° and is in quadrant one or two

Step-by-step explanation:

Given :

Terminal side of an angle = 0

Therefore, the terminal side is the x-axis.

sin = 1/2

Sin value is 1/2 when it is 30 degrees.

In the quadrant I and II, the sine value must be positive.

Therefore, the answer is A) 0 has a reference angle of 30° and is in quadrant one or two

Hope this will helpful.

Thank you.

The true statement of the location of the terminal side of an angle is that 0 has a reference angle of 30° and is in Quadrant I or II

What is Standard Position?

It is known to be an angle which is said to be in the same or standard position only when its vertex is seen at the center and one ray is seen in the positive x-axis. The ray seen on the x-axis is known to be the first or initial side and the second or other ray is known to be the terminal side.

Based on the above, the Terminal side of an angle is known as 0

and Sin (theta) =  ½

The Basic angle was given as 30

So we say 180-30 = 150

We say that the terminal side is the x-axis = sin = 1/2

So therefore, Sin as 1/2 only if it is 30 degrees and In the quadrant I and II, the sine value have to be positive value.

Therefore, the option A where 0 has a reference angle of 30° and is in quadrant one or two is correct.

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1.Find the area of each triangle with the given heights and bases
a. h = 6 inches; b = 10 inches
b. h = 9 centimeters; b = 4 centimeters
c. h = 13 yards; b = 20 yards

Answers

Answer: 1.)

A. 30in^2

B. 18cm^2

C. 130yd^2

2.) The formula for the area of a triangle is half the base times the height. So 1/2 x 40 x 32 = 640cm^2

3.) 17 yards. The fence that enclose Sondra's backyard is a right triangle whose sides measuring 8 yards, 15 yards and 17 yards respectively.

4.) From the Pythagorean Theorem we know:

hypotenuse^2 = side^2 + side^2

hypotenuse^2 = 36 + 36

hypotenuse = square root (72)

hypotenuse = 8.48528... feet

5.) a. 5

b. √128

c. √221

Area of triangle are  [tex]30inches^{2}[/tex] in part(a),

[tex]18[/tex] [tex]centimerters^{2}[/tex] in part(b) and [tex]130[/tex] [tex]yards^{2}[/tex] in part(c)

What is Triangle?

In Geometry, a triangle is a three-sided polygon that consists of three edges and three vertices. The most important property of a triangle is that the sum of the internal angles of a triangle is equal to 180 degrees. This property is called angle sum property of triangle.

What is area?

Area is the quantity that expresses the extent of a region on the plane or on a curved surface. The area of a plane region or plane area refers to the area of a shape or planar lamina, while surface area refers to the area of an open surface or the boundary of a three-dimensional object.

According to questions, we have the following

In part (a.), h = [tex]6[/tex] inches; b = [tex]10[/tex] inches

In part (b.), h =[tex]9[/tex] centimeters; b =[tex]4[/tex] centimeters

In part (c.) h = [tex]13[/tex] yards; b = [tex]20[/tex] yards

We have to find the area of each triangle with the given heights and bases.

Now, Area of triangle in part a

[tex]=\frac{1}{2}[/tex]×[tex]b[/tex]×[tex]h[/tex]

[tex]=\frac{1}{2}[/tex]×[tex]6[/tex]×[tex]10[/tex]

[tex]=30inches^{2}[/tex]

Area of triangle in part b

[tex]=\frac{1}{2}[/tex]×[tex]9[/tex]×[tex]4[/tex]

[tex]=18[/tex] [tex]centimerters^{2}[/tex]

Area of triangle in part c

[tex]=\frac{1}{2}[/tex]×[tex]13[/tex]×[tex]20[/tex]

[tex]=130[/tex] [tex]yards^{2}[/tex]

Hence, we can conclude that area of triangle are  [tex]30inches^{2}[/tex] in part(a),

[tex]18[/tex] [tex]centimerters^{2}[/tex] in part(b) and [tex]130[/tex] [tex]yards^{2}[/tex] in part(c)

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Find the area of the following shape. A(-5,-8) B(1,-8) C(3,-5) D(1,0) E(-5,-3) F(-3,-6). You must show work to receive credit.

Answers

check the picture below.

now... notice the left-side of the picture. that's the points and shape... ok.. notice the left-side, is really just two rectangles and and four triangles stacked up to each other at the edges.

so.. .just get the area of each rectangle and each triangle, sum them up, and that's the area of the shape.

you can pretty much get the length, width and height of the rectangles and triangles from the grid.

recall area of a triangle = 1/2 bh

Find the critical value zα/2 that corresponds to a 98% confidence level.

Answers

A critical value is the point on the scale of the test statistic (z test in this case) outside which we reject the null hypothesis, and is taken from the level of significance of the test. The critical values can be obtained from the standard distribution tables for z and for this case, it is equivalent to:

critical value zα/2 at 98% confidence level = 2.326

Answer: 2.326

 

Answer:

2.33

Step-by-step explanation:

Find a formula expressing the radius r of a sphere as a function of its surface area

Answers

The surface area of a sphere :
[tex]A=4 \pi r^2[/tex]

Solving this equation for r:

A/(4* pi) = r^2          apply sqrt to both sides:

r = sqrt [A/(4 pi)]

Then the radius of a sphere as a function of its surface area :
[tex]r= \sqrt{ \frac{A}{4 \pi } } [/tex]

Hope you got the idea

The table below shows the radius y, in inches, created by growing algae in x days:


Time (x)
(days) 5 10 15 20
Radius (y)
(inches) 1 3 9 22


Part A: What is the most likely value of the correlation coefficient of the data in the table? Based on the correlation coefficient, describe the relationship between time and radius of the algae. [Choose the value of the correlation coefficient from 1, 0.94, 0.5, 0.02.] (4 points)

Part B: What is the value of the slope of the graph of radius versus time between 5 and 10 days, and what does the slope represent? (3 points)

Part C: Does the data in the table represent correlation or causation? Explain your answer. (3 points)

Answers

Part A. The correlation coefficient, denotes as R^2, is a measure of how well does the data point correlate with a given model or equation. The closer the R^2 is to 1, the better is the correlation. However, R2=1 is ideal for scatter plots. Using the MS Excel to execute the regression, the data points was fitted to a quadratic equation. The R2=0.9983. From the choices, the closest answer would be 1. But as stated previously, a value of 1 is ideal only. Therefore, the answer is most likely 0.94,


Part B. To determine the slope, the equation would be Δy/Δx. For x=5 and x=10, the slope would be

Slope = (3-1)/(10-5) = 2/5 or 0.4. This is the instantaneous rate of change at the interval of 5 to 10 days.

Part C. The difference between causation and correlation is identifiable if you know the direct relationship between the variables. In this case, the increase in radius is not caused by time. The problem does not state so. But we know from the trend shown on a graph, that there is a correlation between these variables. Therefore, the answer is correlation.

Which of the following equations represents a quadratic function?

y(y + 4)(y - 6) = 0
z2 + 2 = 3z(z2 - 1)
(2x - 3)(4x + 5) = 10x
(3b)(5b – 7)(b + 8) = 0

Answers

A quadratic equation is one in which the highest exponent of a variable is 2. We can solve this problem by expanding each choices then find which has highest exponent equal to 2.

y(y + 4)(y - 6) = 0           ---> By expansion we get y^3, therefore highest exponent is 3.

z2 + 2 = 3z(z2 - 1)          ---> By expansion we get z^3, therefore highest exponent is 3.

(2x - 3)(4x + 5) = 10x     ---> By expansion we get x^2, therefore highest exponent is 2.

(3b)(5b – 7)(b + 8) = 0    ---> By expansion we get b^3, therefore highest exponent is 3.


The answer to this problem is therefore:

(2x - 3)(4x + 5) = 10x

reminder: variables are on both sides

Answers

Start by multiplying both sides of the equation by 7 (the common denominator).

[tex]7 \left(\frac{6z}{7} -27 \right)=7\left(\frac{21-4z}{7} \right) \\ 6z-189=21-4z[/tex]

Add 4z to both sides.

[tex]10z-189=21[/tex]

Add 189.

[tex]10z=210 \\ z=21[/tex]

Robin purchased a piece of land in the year 2000 for $15,000. The value of the land increases at the rate of 13.17% each year. Identify the function that represents the value of the land. Does the function represent growth, or decay?
A) V(t) = 15000(0.8683)t; growth
B) V(t) = 15000(1.1317)t; decay
C) V(t) = 15000(0.08683)t; decay
D) V(t) = 15000(1.1317)t; growth

Answers

The value of the land increases by 13.17% each year So it's growth function which is V (t)=15000 (1+r)^t Where r is the growth rate which is in decimal 13.17/100=0.1317 So it's D) V(t) = 15000(1.1317)t; growth
Final answer:

The function that represents the value of the land after t years is V(t) = 15000(1.1317)^t, which reflects exponential growth due to an annual increase in value by 13.17%.

Explanation:

The function that represents the value of the land which Robin purchased is given by V(t) = 15000(1 + Interest rate)^numbers of years t, where an interest rate of 13.17% translates to 0.1317 as a decimal. Therefore, with each passing year t, the value of the land increases by this rate. Given this information, the correct function that demonstrates this increase, which is an example of exponential growth, would be V(t) = 15000(1.1317)^t. This represents the value of the land after t years.

The correct answer would then be D) V(t) = 15000(1.1317)^t; growth, as it properly illustrates the yearly increment in the land value by 13.17%, reflecting growth, not decay.

The grid shows figure Q and its image figure Q' after a transformation: Figure Q is a pentagon drawn on a 4 quadrant grid with vertices at 2, 4 and 4, 2 and 5, 4 and 7, 5 and 3, 7. Figure Q prime is a pentagon drawn with vertices at negative 4, 2 and negative 2, 4 and negative 4, 5 and negative 5, 7 and negative 7, 3. Which transformation was applied on figure Q?

Answers

check the picture.

we notice that for every pair (x, y) in Q, there is a point (-y, x) in Q', 

this means that the transformation is a 90° counterclockwise rotation around the origin. 

The transformation can be also noticed by sight in the figure.


Answer: 90° counterclockwise rotation

Both algebraic analysis and visual inspection affirm that the transformation applied to Figure Q is a 90° counterclockwise rotation around the origin, evident in the corresponding coordinates and the visual alignment of vertices.

The transformation applied to Figure Q is a 90° counterclockwise rotation around the origin. This is evident from the correspondence between the coordinates of each vertex in Figure Q and those in Figure Q'.

Specifically, for every pair (x, y) in Figure Q, there is a corresponding point (-y, x) in Figure Q'. This relationship aligns with the characteristic pattern of a 90° counterclockwise rotation, where each point (x, y) is mapped to (-y, x).

Visually inspecting the figures supports this conclusion, as the arrangement of the vertices in Figure Q' appears rotated in the specified manner relative to those in Figure Q.

Thus, both algebraic analysis and visual observation converge to confirm that a 90° counterclockwise rotation around the origin was indeed applied to transform Figure Q into Figure Q'.

To learn more about algebraic analysis

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Use the graph below to answer the following question:

What is the average rate of change from x = –4 to x = 1?

–3
–1
0
1

Answers

the values of f(x) at x = -4 and x = 1 are 4 and -1 respectively.

average rate of change =   (-1 - 4) / 1 - (-4) = -5 / 5 = -1
Final answer:

The average rate of change from x = –4 to x = 1 is 3.

Explanation:

To find the average rate of change from x = –4 to x = 1, we need to calculate the change in y-values and divide it by the change in x-values. Given that the slope of the line is 3, we can use the formula for average rate of change: (change in y) / (change in x). In this case, the change in x is 1 - (-4) = 5, and the change in y is 3 * 5 = 15. Therefore, the average rate of change is 15 / 5 = 3.

a nutrition label indicates that one serving of apple crisp oatmeal has 2.5 grams of fat. how many grams of fat . how many grams of fat how many grams of fat arew there in 3.75 sevings?

Answers

2.5x3.75=9.375 grams of fat!
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