Answer:
ClCO2
Explanation:
What change shows a tenfold increase in concentration of h+ ions?
Friction is not related to the efficiency of a machine.
True
False
How many moles of hydrogen gas (h2) would be produced from the reaction of 0.30 moles of water (h2o) and excess sodium? (na)?
When 0.30 moles of water react with excess sodium, 0.15 moles of hydrogen gas are produced, judged by the 2:1 molar ratio between water and hydrogen in the reaction.
Explanation:The reaction between water (H2O) and sodium (Na) produces sodium hydroxide (NaOH) and hydrogen gas (H2). The balanced chemical equation for this reaction is: 2Na + 2H2O -> 2NaOH + H2.
In this reaction, it's clear that the molar ratio between water and hydrogen gas is 2:1. That means, for every two moles of water consumed in the reaction, one mole of hydrogen gas is produced. If only 0.30 moles of water is reacted, then 0.30 / 2 = 0.15 moles of hydrogen gas would be produced.
So, in the reaction of 0.30 moles of water and excess sodium, 0.15 moles of hydrogen gas would be produced.
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One of the several oxides of tin found in the earthâs crust is 78.77% by mass tin. what is its empirical formula and name?
Final answer:
The empirical formula of the tin oxide with 78.77% tin by mass is SnO2, also known as tin (IV) oxide.
Explanation:
One of the several oxides of tin found in the earth's crust is 78.77% by mass tin. To determine its empirical formula and name, we first assume a 100 g sample for simple calculations. This approach implies we have 78.77 g of tin (Sn) and the remainder, 21.23 g, being oxygen (O).
To find the mole ratio, we divide the mass of each element by its respective atomic mass (Sn = 118.71 g/mol, O = 16.00 g/mol), resulting in:
By dividing each element's mole count by the smallest number of moles obtained, we find the empirical formula ratio. In this case, the ratio for Sn to O approximates to 1:2. Hence, the empirical formula of the tin oxide in question is SnO2, which is commonly named tin (IV) oxide.
Use Cell Membrane in a sentence
The function of cell membrane is to protect the cell from its surroundings by controlling the movement of substances in and out of the cells.
What is cell membrane?
The cell membrane, provides protection for a cell. It also provides a fixed environment inside the cell, and that membrane has several different functions. One is to transport nutrients into the cell and also to transport toxic substances out of the cell. Another is that the membrane of the cell, which would be the plasma membrane, will have proteins on it which interact with other cells.
Those proteins can be glycoproteins, meaning there's a sugar and a protein moiety, or they could be lipid proteins, meaning that there's a fat and a protein. And those proteins which stick outside of the plasma membrane will allow for one cell to interact with another cell. The cell membrane also provides some structural support for a cell.
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Which statements about viscosity are true? (i) viscosity increases as temperature decreases. (ii) viscosity increases as molecular weight increases. (iii) viscosity increases as intermolecular forces increase?
Answer : All the statements are true.
Explanation :
Viscosity : It measures the resistance of a liquid to flow is known as the viscosity.
There are many factors affects the viscosity which are temperature, pressure, molecular weight and inter-molecular forces.
Viscosity and Temperature :There is an inverse relationship between the viscosity and the temperature. As the temperature decreases, viscosity increases and the temperature increases, viscosity decrease.
Viscosity and Pressure :There is a direct relationship between the viscosity and the pressure. As the pressure decreases, viscosity decreases and the pressure increases, viscosity increases.
Viscosity and Molecular weight :There is a direct relationship between the viscosity and the molecular weight. As the molecular weight decreases, viscosity decreases and the molecular weight increases, viscosity increases.
Viscosity and Inter-molecular force :There is a direct relationship between the viscosity and the inter-molecular force. As the inter-molecular force decreases, viscosity decreases and the inter-molecular force increases, viscosity increases.
Hence, all the statements are true.
Statements about viscosity are true:
(i) viscosity increases as temperature decreases.
(ii) viscosity increases as molecular weight increases.
(iii) viscosity increases as intermolecular forces increase
Viscosity is a measure of a fluid's resistance to flow. A viscous fluid flows slowly, while a non-viscous fluid flows quickly.
(i) Temperature affects viscosity because it affects the kinetic energy of the molecules in a fluid. As temperature decreases, the kinetic energy of the molecules decreases. This means that the molecules move more slowly, and the fluid becomes more viscous.
(ii) Molecular weight affects viscosity because it affects the strength of the intermolecular forces between the molecules in a fluid. As molecular weight increases, the intermolecular forces become stronger. This means that it is more difficult for the molecules to move past each other, and the fluid becomes more viscous.
(iii) Intermolecular forces affect viscosity because they are the forces that hold the molecules in a fluid together. As intermolecular forces increase, the molecules are held more tightly together. This means that it is more difficult for the molecules to move past each other, and the fluid becomes more viscous.
Therefore, all three statements about viscosity are true.
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Sodium hydroxide reacts with carbon dioxide as follows: which is the limiting reactant when 1.85 mol naoh and 1.00 mol co2 are allowed to react? how many moles of na2co3 can be produced? how many moles of the excess reactant remain after the completion of the reaction?
The limiting reactant in the reaction is NaOH, 0.925 moles of Na2CO3 can be produced, and there would be 0.075 moles of CO2 remaining after the reaction is complete.
Explanation:The given balanced reaction is: 2NaOH(aq) + CO2(aq) → Na2CO3(aq) + H2O(1). Firstly, let's identify the limiting reactant. For every mole of CO2, two moles of NaOH are required. Therefore, 1.85 moles of NaOH would react completely with 0.925 moles of CO2. But since we have 1.00 mol of CO2, our limiting reactant is NaOH.
Since the reaction produces 1 mole of Na2CO3 for every 2 moles of NaOH, we can expect to produce 0.925 moles of Na2CO3 based on the amount of our limiting reactant.
Finally, to determine the remaining amount of the excess reactant after the completion of the reaction, we subtract the amount of CO2 that reacted (0.925 moles) from the initial amount (1.00 mol), which gives us 0.075 moles of CO2 remaining.
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In metallic bonding, the electrons
Answer:
In metallic bonds the electrons of the valence shell can move freely within the metal, thus explaining its electric conductivity.
What is being oxidized?
What is the formula for manganese (ii) fluoride decahydrate? (you may use a * to represent the dot in the formula.)?
Answer:
MnF₂*10H₂O.
Explanation:
What isotope has 13 protons and 14 neutrons? enter the name of the element followed by a hyphen and the mass number (e.g., uranium-234)?
Potassium-40 has a half-life of 1.25 billion years (by) and decays to argon-40. how old is a fossil that has a 40k/40ar ratio of ~ 26%?
Which class of molecules contains the carbonyl group, co?
There are many compounds in organic chemistry containing carbonyl group as the part of their structure.
First kind of compounds with carbonyl group are carbonyl compounds (aldehyde with R-CHO and ketone, RCOR' as their structural formula)
Next, Carboxylic acid and their derivatives
Carboxylic acid: RCOOH
Ester: RCOOR'
Acid chloride: RCOCl
Anhydride: (RCO)2O
Amide: RCONH2
And carbohydrates, amino acids also have Carbonyl group in their structures.
Structure of carbonyl group: -C=O
A 18.21 g sample of a compound contains 5.81 g potassium (k), 5.27 g chlorine (cl), and oxygen (o). calculate the empirical formula.
To
determine the empirical formula of the compound given, we need to
determine the ratio of the elements present in the compound. To do that we use the given amount of sample
of the compound and the masses of each of the element included. Then, we calculate for the number
of moles of each element. We do as follows:
mass moles
Potassium 5.81 0.1486
Chlorine 5.27 0.1487
Oxygen 18.21 - 5.81 - 5.27 = 7.13 0.4456
Dividing the number of moles of each element with
the smallest value of number of moles, we will have the ratio of the elements:
K = 1 Cl = 1 O = 3
Therefore, the empirical formula would be KClO3.
The empirical formula of the compound is KClO3.
Explanation:To calculate the empirical formula, we need to determine the ratio of the different elements present in the compound. In this case, we have 5.81 g of potassium (K), 5.27 g of chlorine (Cl), and an unknown amount of oxygen (O).
To find the amount of oxygen, we subtract the combined mass of potassium and chlorine from the total mass of the compound: 18.21 g - (5.81 g + 5.27 g) = 7.13 g.
Now we can find the moles of each element by dividing their masses by their molar masses (K = 39.10 g/mol, Cl = 35.45 g/mol, O = 16.00 g/mol). The moles of each element are approximately K: 0.148, Cl: 0.149, O: 0.445.
Dividing these mole values by the smallest one (0.148), we find that the ratio of elements is approximately K: 1, Cl: 1, O: 3. Therefore, the empirical formula of the compound is KClO3.
What are the vertical columns on a periodic table called
Which best describes the definition for the atomic mass of an element?
Answer: it is a weighted average of the masses of an element’s isotopes
Explanation:
In the reaction of 1.23 g of salicylic acid, molar mass 138.12 g/mol, with 2.85 g of acetic anhydride, molar mass 102.10 g/mol, a student obtained 1.39 g of acetylsalicylic acid, molar mass 180.17 g/mol. What is the percent yield?
I found that salicylic acid was the limiting reactant so do I just find the mass from there?
Yes, salicylic acid is the limiting reactant. The theoretical yield is calculated using the moles of the limiting reactant and converting it to grams of the product. The percent yield is then determined by comparing the actual yield to the theoretical yield.
Explanation:Yes, you are correct that salicylic acid is the limiting reactant in this reaction. The first step in this scenario is to calculate the theoretical yield, which is the quantity of product that would be produced assuming that the reaction proceeds perfectly and all of the limiting reactant is consumed. This is done by calculating the moles of the limiting reactant (salicylic acid), then using stoichiometry to convert this to moles of the product (acetylsalicylic acid), and finally converting this to grams. The next step is to calculate the actual yield, which is the amount of product that was actually produced in the reaction, and then use these values to calculate the percent yield using the formula:
Percent Yield = (Actual Yield / Theoretical Yield) x 100%
In this case, the actual yield is given as 1.39 g of acetylsalicylic acid. So, you would calculate the percent yield by dividing this value by the theoretical yield (which you calculated in the previous step) and then multiply by 100%.
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Solid barium sulfate dissolves into its respective ions at 25°C. Suppose that in a particular solution, [Ba2+ ] = 1.76 x 10-3 M. Find the value of Ksp.
Answer:
The value of solubility product of barium sulfate is [tex] 3.09\times 10^{-6}[/tex].
Explanation:
[tex]BaSO_4\rightarrow Ba^{2+}+SO_4^{2-}[/tex]
S S
1 mole of barium sulfate dissociates into 1 mole of barium ion and one mole sulfate ion.
So, [tex][Ba^{2+}]=[SO_4^{2-}]=S[/tex]
[tex][Ba^{2+}]=S=1.76\times 10^{-3} M[/tex]
The solubility product the barium sulfate will be given by:
[tex]K_{sp}=S\times S=S^2[/tex]
[tex]K_{sp}= (1.76\times 10^{-3})^2=3.09\times 10^{-6}[/tex]
The value of solubility product of barium sulfate is [tex] 3.09\times 10^{-6}[/tex].
Metals present in municipal wastewater may still be present in treated sewage sludge; ______
During a lab, you heat 1.62 g of a CoCl2 hydrate over a Bunsen burner. After heating, the final mass of the dehydrated compound is 0.88 g. Determine the formula of the hydrate and also give the full name of the hydrate. Please show all your work for the calculations for full credit.
After heating a CoCl₂ hydrate to remove water, the formula is determined using the mass of water lost and the molar masses of CoCl₂ and H₂O. The calculations show that every mole of CoCl₂ is associated with 6 moles of H₂O, giving the hydrate a formula of CoCl₂•6H₂O, known as cobalt(II) chloride hexahydrate.
To determine the formula of the hydrate of cobalt(II) chloride (CoCl₂ hydrate), you first need to calculate the mass of water lost during heating. The initial mass of the hydrate was 1.62 g and the mass after heating was 0.88 g. The mass of the water is therefore the difference between these two masses.
Mass of water lost = Initial mass \'96 Final mass = 1.62 g \'96 0.88 g = 0.74 g
Next, calculate the number of moles of CoCl₂ and H₂O. The molar mass of anhydrous CoCl₂ is 129.84 g/mol.
Moles of CoCl₂ = Mass of anhydrous CoCl₂ / Molar mass of CoCl₂ = 0.88 g / 129.84 g/mol = 0.006776 moles of CoCl₂
The molar mass of H₂O is approximately 18.015 g/mol.
Moles of H2O = Mass of water / Molar mass of H₂O = 0.74 g / 18.015 g/mol = 0.04107 moles of H₂O
To find the ratio of CoCl₂ to H₂O in the hydrate, divide the moles of water by the moles of CoCl₂.
Ratio = Moles of H₂O / Moles of CoCl₂ = 0.04107 / 0.006776 = 6.06, which rounds to 6.
The formula of the hydrate is CoCl₂•6H₂O. The full name of the hydrate is cobalt(II) chloride hexahydrate.
Compare rutherford's expected outcome of the gold-foil experiment with the actual outcome.
Final answer:
Rutherford's expected outcome of the gold-foil experiment was for the alpha particles to pass through the foil un-deflected, but the actual outcome showed scattering of the particles at large angles. This discovery challenged the plum pudding model of the atom and led to the development of the nuclear model.
Explanation:
Rutherford's expected outcome of the gold-foil experiment was that the alpha particles would pass through the gold foil un-deflected, similar to bullets passing through a Styrofoam sheet. However, the actual outcome of the experiment showed that while most of the alpha particles did pass through the foil without deflection, some were scattered at large angles and a few even came back in the direction they came from.
This result, known as Rutherford scattering, indicated that the gold nuclei were actually very small compared to the size of the gold atom. It suggested the presence of a small, dense, positively-charged nucleus at the center of the atom. This discovery challenged the plum pudding model of the atom and led to the development of the nuclear model of the atom.
The net ionic equation for the reaction between aqueous sulfuric acid and aqueous sodium hydroxide is ________.
The net ionic equation for the reaction will be [tex]\rm \bold{2\;H^+\;+\;2\;OH^-\;\rightarrow\;2\;H_2O}[/tex].
A chemical equation has been the chemical representation of the reactants involved with the formed products. The ionic equation has been consisted of the ionic form of the reactants and products.
The reaction for Sulfuric acid and Sodium hydroxide will be:
[tex]\rm H_2SO_4\;+\;2\;NaOH\;\rightarrow\;Na_2SO_4\;+\;2\;H_2O[/tex]
The ionic equation for reactants will be:
[tex]\rm H_2SO_4\;+\;2\;NaOH[/tex] = [tex]\rm 2\;H^+\;+\;SO_4^2^-\;+\;2\;Na^+\;2\;OH^-[/tex]
The ionic equation for the products has been:
[tex]\rm Na_2SO_4\;+\;2\;H_2O[/tex] = [tex]\rm 2\;Na^+\;+\;SO_4^2^-\;+\;4\;H^+\;+\;2\;O^-[/tex]
The total equation will be:
[tex]\rm 2\;H^+\;+\;SO_4^2^-\;+\;2\;Na^+\;2\;OH^-[/tex] [tex]\rightarrow[/tex] [tex]\rm 2\;Na^+\;+\;SO_4^2^-\;+\;4\;H^+\;+\;2\;O^-[/tex]
In the net ionic equation, the ions same on both sides of the products and reactants are eliminated.
The net ionic equation for the reaction will be:
[tex]\rm 2\;H^+\;+\;2\;OH^-\;\rightarrow\;4\;H^+\;+\;2O^-[/tex]
[tex]\rm \bold{2\;H^+\;+\;2\;OH^-\;\rightarrow\;2\;H_2O}[/tex]
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How can you distinguish a substance from a mixture
What is the mass percent of nitrogen in lead (ii) nitrate (pb(no3)2)?
The mass percent of nitrogen in lead (II) nitrate (Pb(NO3)2) is calculated by dividing the total mass of nitrogen by the molecular mass of lead (II) nitrate and multiplying by 100%, which is approximately 8.46%.
Explanation:To determine the mass percent of nitrogen in lead (II) nitrate (Pb(NO3)2), you need to find the total mass of nitrogen in the compound and divide it by the molecular mass of lead (II) nitrate. The molar mass of lead (II) nitrate is the sum of the mass of one lead atom, two nitrogen atoms, and six oxygen atoms. Thus, the molar mass of Pb(NO3)2 is 207.2 (mass of Pb) + 2(14.007) (mass of N) + 6(15.999) (mass of O) = 331.209 g/mol. The total mass of nitrogen is 2 × 14.007 g/mol = 28.014 g/mol.
To find the mass percent, we use the formula:
Mass percent of N = (Total mass of N / Molar mass of Pb(NO3)2) × 100%
Mass percent of N = (28.014 g/mol / 331.209 g/mol) × 100% ≈ 8.46%
Describe, on a molecular level, how you would expect these lipids to behave in water.
According to the concept of solubility and lipids being hydrophobic they are insoluble in water and hence would float on water.
What is solubility?Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.
The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.Concept of solubility is not valid for chemical reactions which are irreversible. The dependency of solubility on various factors is due to interactions between the particles, molecule or ions.
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What type of graph or chart would be best for showing the relationship between bird wing length and average flight distance
A key step in the extraction of iron from its ore is feo(s) + co(g) fe(s) + co2(g) kp = 0.403 at 1000°c. this step occurs in the 700°c to 1200°c zone within a blast furnace. what are the equilibrium partial pressures of co(g) and co2(g) when 1.58 atm co(g) and excess feo(s) react in a sealed container at 1000°c?
The extraction of iron from its ore involves reduction with carbon monoxide at high temperatures, yielding iron metal and carbon dioxide. The equilibrium partial pressures of CO(g) and CO2(g) can be determined by employing the kp equation with initial and equilibrium pressures.
Explanation:The question is asking for the partial pressures of CO(g) and CO2(g) during the extraction of iron from its ore. Our reaction of interest is FeO(s) + CO(g) → Fe(s) + CO2(g), where kp = 0.403 at 1000°C. The reaction involves reducing FeO(s), iron(II) oxide, to Fe(s), i.e., iron metal, with carbon monoxide, or CO(g), in a high-temperature furnace. In the process, CO(g) is converted to CO2(g), or carbon dioxide gas. Given an initial pressure of CO(g) as 1.58 atm and that FeO(s) is in excess, at equilibrium, the partial pressure of CO(g) will be decreased as it is used up, while that of CO2(g) will be increased as it is produced.
From the kp equation [P of products / P of reactants], we have kp = PCO2 / PCO. We need to find the decrease in partial pressure of CO (x) such that the increase in partial pressure of CO2 equals x. This gives us PCO = (Initial P of CO) - x and PCO2 = x. Substituting these expressions into the kp equation, we get 0.403 = (x) / (1.58 - x). Solving this equation will yield the equilibrium pressures of CO(g) and CO2(g).
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The equilibrium partial pressures are approximately 0.454 atm for CO₂(g) and 1.126 atm for CO(g).
Firstly, we need to set up the equilibrium expression using the given Kp:
Kp = P(CO₂) / P(CO)
0.403 = P(CO₂) / (1.58 - x)
Assuming x is the change in pressure for both CO₂ and CO:
Kp = P(CO₂)/(1.58 − P(CO2)) = 0.403
Let P(CO₂) = y. Hence, 0.403 = y / (1.58 − y)
Solve for y (P(CO₂)):
0.403 (1.58 − y) = y
0.63734 = 1.403y
y = 0.63734 / 1.403 ≈ 0.454 atm
Thus, the equilibrium partial pressure of CO₂(g) is 0.454 atm, and for CO(g) it is 1.58 - 0.454 = 1.126 atm.
A(n) _____ is a region where fresh water and salt water mix.
Calculate the mass in grams of iodine (i 2 ) that will react completely with 20.4 g of aluminum (al) to form aluminum iodide (ali
Except in the case of hydrocarbons, when naming virtually all compounds made up of two elements, the second element mentioned