Final answer:
The substance with a molar mass of 44.01 g/mol is carbon dioxide (CO2), which can be deduced by calculating the combined molar masses of one carbon atom and two oxygen atoms.
Explanation:
The question concerns the identification of a compound with a molar mass of 44.01 g/mol. One well-known substance with this molar mass is carbon dioxide (CO2). To arrive at this conclusion, one can examine the atomic masses of carbon and oxygen. Carbon has a molar mass of about 12.01 g/mol, while oxygen has a molar mass of about 16.00 g/mol. Given that carbon dioxide is composed of one carbon atom and two oxygen atoms, the total molar mass can be calculated as follows: 12.01 amu (for carbon) + 2 × 16.00 amu (for each oxygen) = 44.01 amu, which corresponds to g/mol when talking about molar mass. Hence, the molecular mass of carbon dioxide is 44.01 g/mol.
G.com what is the mass of a gold bar that is 7.379 × 10–4 m3 in volume
Consider the anion whose charge is 2- and whose electron configuration is identical to argon. what is the symbol for this anion
If the ion is negatively charged, anion, it means that it gains two electrons from its surroundings. The number of electrons of an argon (neutral atom) is 18. Two of the electrons in our anion is from the surrounding, so originally it only has 16 electrons.
In the periodic table, the 16th element is sulphur. The chemical symbol of sulphur is S. Thus, the anion is the negatively charged sulphur with chemical symbol of S2-.
Cracking the periodic table code why aren't the elements listed in alphabetical order answer key
The elements in the periodice table are not listed in alphabetical order, because the arragement in rows (periods) and columns (groups or familes), in increasing order of atomic number (number of protons of the atoms) permits to explain similarities among the elements, trend in some properties, and even predict properties of unknown elements.
For example, the elements of the first group (family), called alkaline metals, all have 1 valence electron, have similar physical properties (ductibility, malleability, luster, thermal and electricity conductivity), react in similar way with water, show a trend in the atomic radii and in the ionization energy.
You can tell similar stories for other groups like, alkalyne earth metals, halogens and noble gases.
You can also tell trends in electroneativities, and atomic radii, for a row of elements, as per the order they are in the row.
So, the current array resulted very helpul for chemists to explain and predict the behavior and properties of the elements.
The periodic table of elements is organized based on chemical properties and atomic structure, not in alphabetical order. Elements are arranged in ascending order of their atomic numbers, and elements in the same group have similar chemical properties.
Explanation:The elements on the periodic table are not listed in alphabetical order, but instead they are organized based on their chemical properties and atomic structure. This organization makes it easier to understand and predict how different elements will react with each other. The elements are arranged in ascending order based on their atomic number, which is the number of protons in an atom's nucleus. Elements in the same group (vertical column) have similar chemical properties because they have the same number of electrons in their outer shell.
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Chromatography Portfolio
5. What evidence is there that marker ink is a mixture?
6. Each compound in the marker ink is represented by a color. Did one compound travel farther than others? Explain why you think that this is the case.
7. Did the compounds travel farther in water or isopropyl alcohol (rubbing alcohol)? Explain why you think that this is the case.
8. How could you improve upon the accuracy of your R[f] measurements?
Answer:
i honestly dont know but ill try
Explanation:
hope this helps its yes
What is the charge on a hypothetical ion with 85 protons and 82 electrons?
A substance with a density of 2.70 g/ml occupies a volume of 21.3 ml. what is the mass of the sample
The blank variable response to changes in the manipulated variable
All substances are composed of which type of matter
Answer: All substances are composed of elements.
Explanation: Matter is anything which has mass and occupies space.
The substances can be made up element alone like Helium (He).
They can be made up of molecules of elements also like hydrogen [tex](H_2)[/tex]
They can also be made up of molecules of compounds like carbon dioxide [tex](CO_2)[/tex]
They can be made up of mixtures like salt solution in water.
Since all the mixtures, compounds and molecules consists of elements. Therefore, all the substances are composed of elements.
Use appropriate metric prefixes to write the following measurement without use of exponents 15.7 x 10^3g
Classify each structure as alkane, alcohol, carboxylic acid, or other. click on a structure to access the rotational controls.
To classify each molecule as an aliphatic or an aromatic hydrocarbon, we need to determine if they are alkanes, alkenes, or alkynes.
Explanation:To classify each molecule as an aliphatic or an aromatic hydrocarbon, we need to determine if they are alkanes, alkenes, or alkynes.
Alkane: The molecule has only single bonds between carbon atoms.Alkene: The molecule has at least one carbon-carbon double bond.Alkyne: The molecule has at least one carbon-carbon triple bond.By examining the structure of each molecule, we can identify their classification as aliphatic or aromatic hydrocarbons.
What is the maximum height at which the solvent should condense (in the condenser) during reflux? What might happen if the solvent condenses higher than this?
During buildup in reflux condenser, the greatest tallness is most of the way up to the condenser. In the event that dissolvable gathers higher than this most extreme tallness, the majority of the dissolvable may keep running over into the response cup or might be the response will begin prior, And if the dissolvable don't go up than the greatest stature, the response does not occur to begin prior.
Further Explanation:
Reflux:
Heartburn is otherwise called acid reflux, corrosive acid reflux, or pyrosis. It happens when a portion of the acidic stomach substance return up into the throat. Heartburn makes a consuming agony in the lower chest zone, frequently in the wake of eating.
reason for a reflux device:
Reflux is a procedure including the buildup of vapors and the arrival of this condensate to the framework from which it began. It is utilized in mechanical and research center refining processes. It is likewise utilized in science to supply vitality to responses over an extensive stretch of time.
Reflux is utilized:
To keep the dissolvable from dissipating, a reflux condenser is utilized. This is a glass segment with a subsequent segment encompassing it through which cool water streams. As vapor from the bubbling dissolvable ascents into inside section of the reflux condenser, it is cooled by the coat of water outwardly and consolidates.
Subject: chemistry
Level: college
Keywords: Reflux, reason for a reflux device, Reflux is utilized.
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which of the following statements about line graphs is true?
A The dependent variable is on the horizontal axis.
B Line graphs are always straight lines.
C Every data point should be shown on a line graph.
D There is a maximum number of data points that can be used in a line graph.
How many moles of n are in 0.163 g of n2o?
First convert 0.163 grams of N2O to mol by dividing it with the molecular weight. The molecular weight of N2O is 44 grams/mol. The answer would be 3,79x10^-3. Then multiply it with 2 since there are 2 Nitrogen in one mole of N2O. Therefore, there are 7.41x10^-3 moles of Nitrogen.
Answer:
[tex]n_N=7.41x10^{-3}molN[/tex]
Explanation:
Hello,
In this case, one develops the following mass-mole relationship, taking into account that [tex]N_2O[/tex] has two nitrogens inside, thus:
[tex]n_N=0.163gN_2O*\frac{1molN_2O}{44gN_2O}*\frac{2molN}{1molN_2O}\\n_N=7.41x10^{-3}molN[/tex]
Best regards.
What is the ratio of [a–]/[ha] at ph 3.75? the pka of formic acid (methanoic acid, h–cooh) is 3.75?
At pH 3.75, the ratio of [tex]\frac{[A^-]}{[HA]}\right)[/tex] for formic acid ([tex]pK_a[/tex] = 3.75) is 1.
To find the ratio of the concentrations of the conjugate base [A⁻] to the acid [HA] for formic acid (HCOOH) at pH 3.75, we can use the Henderson-Hasselbalch equation:
[tex]\text{pH} = \text{p}K_a + \log\left(\frac{[A^-]}{[HA]}\right)[/tex]Given that the pH is 3.75 and the [tex]pK_a[/tex] of formic acid is also 3.75, we can set up the equation as follows:
[tex]3.75 = 3.75 + \log\left(\frac{[A^-]}{[HA]}\right)[/tex]Subtract 3.75 from both sides:
[tex]0 = \log\left(\frac{[A^-]}{[HA]}\right)[/tex]To solve for the ratio [tex]\frac{[A^-]}{[HA]}\right)[/tex], we need to exponentiate both sides with base 10:
[tex]10^0 = \frac{[A^-]}{[HA]}[/tex]Therefore:
[tex]\frac{[A^-]}{[HA]}\right) = 1[/tex]This result makes sense because when the pH of the solution is equal to the [tex]pK_a[/tex] of the acid, the concentrations of the acid and its conjugate base are equal. Consequently, the ratio is exactly 1.
a scientist has developed a new type of material that is suppose to float on water. this material has a mass of 2.0g for every 3.0cm3 of volume. will this material float on water (density= 1.0g/cm3) explain
Final answer:
The material, with a density of 0.67g/cm³, will float on water since its density is less than water's density of 1.0g/cm³. This is determined by dividing its mass by its volume and comparing it to water's density.
Explanation:
The question asks whether a new material with a mass of 2.0g and volume of 3.0cm3 will float on water, which has a density of 1.0g/cm3. To determine whether this material will float, we calculate its density using the formula density = mass / volume. Plugging in the given values, we find the density of the material to be 2.0g / 3.0cm3 = 0.67g/cm3.
Since the density of the material (0.67g/cm3) is less than the density of water (1.0g/cm3), the material will float on water. This is explained by the principle of buoyancy, which states that an object will float in a fluid if its density is less than the density of the fluid.
G brønsted-lowry proton transfer reaction, hydroxide functions as a/an ______.
In a bronsted lowry proton transfer reaction, the hydroxide functions as a/an proton acceptor.
Bases are the opposite of acids. Bases are basic since they take or accept protons. For example, a Hydroxide ion can accept a proton to form water.
Answer:
Base
Explanation:
A Brønsted-Lowry acid is simply a compound that supplies a hydrogen ion in a reaction. A Brønsted-Lowry base on the other hand, is a compound that accepts a hydrogen ion in a reaction.
Thus, the Brønsted-Lowry definitions of an acid and a base focus on the movement of hydrogen ions in a reaction, rather than on the production of hydrogen ions and hydroxide ions in an aqueous solution.
The hydroxide ion in these compounds accepts a proton (Hydrogen ion) from acids to form water: This means shydroxides functions as a base.
Which action is not an example of work
What two things are responsible for most weathering and erosion?
The phosphate functional group in the non cyclic amp molecule answer
AMP is a nucleotide which stands for Adenosine monophosphate and it is also known as 5'-adenylic acid. It can exist as a cyclic adenosine monophosphate molecule and non cyclic adenosine monophosphate.
please help me dont just comment for points please i actually need help
Order the relative rate of diffusion of the following gases from slowest to fastest.
1. 1 Ar
2. 2 Ne
3. 3 N
4. 4 Kr
Answer:
Kr < Ar < Ne < N (N is fastest and Kr is slowest)
Explanation:
According to graham law of diffusion, rate of diffusion of a gas is inversely proportional to the square root of molar mass of the gas.
[tex]R\propto \frac{1}{\sqrt{M}}[/tex]
Where R is rate of diffusion and M is molar mass
Molar masses of given gases are - Ar(40 g/mol), Ne(20 g/mol), N(14 g/mol) and Kr(84 g/mol)
So molar mass order : Kr > Ar > Ne > N
Hence rate of diffusion order: Kr < Ar < Ne < N (N is fastest and Kr is slowest)
Cu has an anomalous electron configuration. write the observed electron configuration of cu.
Explanation:
Atomic number of copper is 29 and it is a d-block element.The electronic configuration of copper is as follows.
Electronic configuration of copper is [tex][Ar]4s^1 3d^{10}[/tex]
According to the Aufbau principle, in the ground state of an atom or ion the electrons fill atomic orbitals of the lowest energy levels first, before filling the higher energy levels.
But completely filled d-shell is more stable in nature. Hence, one electron from the 4s shell goes into the d-orbital so the copper atom can attain stability.
So, when a copper atom loses an electron then it goes out from the 4s shell first.
Final answer:
The observed electron configuration of copper (Cu) is [Ar] 3d10 4s1.
Explanation:
The observed electron configuration of Cu is [Ar] 3d10 4s1.
Copper has an anomalous electron configuration because it is a transition metal. The half-filled 3d manifold with one 4s electron is more stable than a partially filled d-manifold and a filled 4s manifold. This leads to the anomalous electron configuration of Cu.
This deviation from the normal electron design happens on the grounds that copper has a higher dependability when its 3d sublevel is totally loaded up with 10 electrons, as opposed to having 9 electrons in the 3d sublevel and 2 during the 4s sublevel. This peculiarity is known as the "half-filled or completely filled sublevel soundness."
Convert 35 m3 to liters
In a certain grocery store, strawberries cost $4.16 per pound ( 4.16 dollars/lb ). What is the cost per ounce?
What happens to the volume of a liquid when it is poured from a small container into a large container
Lithium carbonate, li2co3, contains 18.8 % lithium and is used in the treatment of mental illnesses such as bipolar disorder. what mass of lithium is present in a 1.70−g dose of lithium carbonate?
In a 1.70-g dose of lithium carbonate, which contains 18.8% lithium, there is approximately 0.3196 g of lithium.
Explanation:The question is asking for the amount of lithium in a 1.70-g dose of lithium carbonate (Li2CO3) which is known to contain 18.8% lithium. The calculation is fairly straightforward once we understand that the percentage given is by mass. Hence, to find out the lithium content, we simply multiply the total mass of the dose by the percentage of lithium.
Step 1. Convert the lithium percentage to a decimal by dividing 18.8 by 100, giving us 0.188.
Step 2. Multiply the mass of the lithium carbonate dose (1.70 g) by the decimal from Step 1. The calculation is: 1.70 g × 0.188 = 0.3196 g.
The result indicates that in a 1.70-g dose of lithium carbonate, there is approximately 0.3196 g of lithium.
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To find the mass of lithium in a 1.70-g dose of lithium carbonate, multiply the mass by the percentage of lithium content (18.8%). This calculation results in 0.3196 grams of lithium.
Step-by-Step Solution
First, identify the percentage of lithium in lithium carbonate: 18.8%.Next, calculate the mass of lithium in the given dose using the percentage formula:Mass of lithium = (percentage of lithium / 100) * mass of lithium carbonate
Substitute the given values:Mass of lithium = (18.8 / 100) * 1.70 g
Mass of lithium = 0.3196 g
Therefore, there are 0.3196 grams of lithium present in a 1.70-g dose of lithium carbonate.
Which statement best compares the properties of compounds and elements that the compounds contain?
Using the mass of the proton 1.0073 amu and assuming its diameter is 1.0×10−15m, calculate the density of a proton in g/cm3.
Answer : [tex] 3.2 X 10^{15} g/cm^{3} [/tex]
Explanation : To convert amu i.e. atomic mass unit in grams we have the conversion factor as 1 amu = [tex] 1.66054 X 10^{-24} g [/tex]
we know the mass of the proton is 1.0073 amu
So converting it into grams we have to multiply;
1.0073 amu X [tex] 1.66054 X 10^{-24} g/amu [/tex] = [tex] 1.673 X 10^{-24} g [/tex]
Now, Volume = 1/6πd³ as diameter is given as [tex] 1.0 X 10^{-15} m [/tex] converting it to cm will require to multiply with 100
∴ Volume = 1/6π [tex](1.0 X 10^{-15}mX 100 cm / 1 m)^{3} [/tex]
Hence, volume = [tex] 5.236 X 10^{-40} cm^{3} [/tex]
Therefore, Density = mass / volume
∴ Density = [tex] 1.673 X 10^{-24} g / 5.236 X 10^{-40} cm^{3} [/tex]
Therefore, Density will be [tex] 3.2 X 10^{15} g/cm^{3} [/tex].
The density of a proton in g / cm₃ = 3.19.10⁻¹⁵
Further explanationAtoms are composed of 3 types of basic particles namely protons, electrons, and neutrons
the mass of the basic particle is expressed in units of atomic mass
This atomic unit uses the standard atomic mass, that is, the C-12 isotope
1 atom C-12 = 12 atomic mass units
1 atomic mass unit = 1/12 x mass 1 C-12 atom
1 unit of atomic mass = 1.66.10 ⁻²⁴ g
the basic particle mass in atomic mass units is:
electron mass = 9.11.10⁻²⁸ g
proton mass = 1.6726.10⁻²⁴ g
neutron mass = 1,675.10⁻²⁴ g
The proton mass is considered to be equal to 1 atomic mass unit and is also considered to be equal to 1 atomic mass unit
1 unit of atomic mass = 1.6726.10⁻²⁴ g = 1.6726.10⁻²⁷kg
Density is a quantity derived from the mass and volume
density is the ratio of mass per unit volume
The unit of density can be expressed in g / cm³ or kg / m3³
Density formula:
[tex]\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}[/tex]
ρ = density
m = mass
v = volume
Assume protons as spheres
with a diameter of 1.0 × 10⁻¹⁵m = 1.0.10⁻¹³ cm
then the volume = 4/3 π r³ or 1/6πd³
proton volume = 1 / 6π(1.0 × 10⁻¹³)³
proton volume = 5.23.10⁻⁴⁰
density becomes:
density = mass: volume
density = 1.6726.10⁻²⁴: 5.23.10⁻⁴⁰
density = 3.19.10⁻¹⁵ g/cm³
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What is the ratio of [a–]/[ha] at ph 3.75? the pka of formic acid (methanoic acid, h–cooh) is 3.75?
The formula for pH given the pKa and the concentrations are:
pH = pKa + log [a–]/[ha]
Therefore calculating:
3.75 = 3.75 + log [a–]/[ha]
log [a–]/[ha] = 0
[a–]/[ha] = 10^0
[a–]/[ha] = 1
Answer:
[tex]\frac{[A^-]}{[HA]}=1[/tex]
Explanation:
Hello,
In this case, one state the following relationship among the pH, pKa and the [a–]/[ha] ratio for the formic acid:
[tex]\frac{[A^-]}{[HA]}=\frac{Ka}{[H^+]}[/tex]
In such a way, we compute both the concentration of hydrogen ions and the acid's dissociation constant as:
[tex][H^+]=10^{-pH}=10^{-3.75}=1.78x10^{-4}M[/tex]
[tex]Ka=10^{-Ka}=10^{-3.75}=1.78x10^{-4}[/tex]
Thus, the [a–]/[ha] ratio becomes:
[tex]\frac{[A^-]}{[HA]}=\frac{1.78x10^{-4}}{1.78x10^{-4}}\\\frac{[A^-]}{[HA]}=1[/tex]
Best regards.
Suppose there are two known compounds containing the generic elements X and Y. You have a 1.00-g sample of each compound. One sample contains 0.25 g of X and the other contains 0.33 g of X. Identify plausible sets of formulas for these two compounds. Check all that apply.
I think the correct answers are X2Y and X3Y, X2Y5 and X3Y5, and X4Y2 and X3Y,
for the following reason:
If you look at the combining masses of X and Y in
each of the two compounds,
The first compound contains 0.25g of X combined with
0.75g of Y
so the ratio (by mass) of X to Y = 1 : 3
The second compound contains 0.33 g of X combined with
0.67 g of Y
so the ratio (by mass) of X to Y = 1 : 2
Now, you suppose to prepare each of these two
compounds, starting with the same fixed mass of element Y ( I will choose 12g
of Y for an easy calculation!)
The first compound will then contain 4g of X and 12g
of Y
The second compound will then contain 6g of X and
12g of Y
The ratio which combined
the masses of X and the fixed mass (12g) of Y
= 4 : 6
or 2 : 3
So, the ratio of MOLES of X which combined with the
fixed amount of Y in the two compounds is also = 2 : 3
The two compounds given with the plausible formula must therefore contain the same ratio.
To identify plausible sets of formulas for two compounds containing elements X and Y, use the given masses to calculate the ratios and apply the law of multiple proportions to determine simple whole-number ratios for potential empirical formulas.
Explanation:The question is regarding the identification of plausible sets of formulas for two compounds containing generic elements X and Y based on the amounts of element X in both compounds. By using the mass data provided (0.25 g and 0.33 g of X), along with the total sample mass (1.00 g for each compound), we can find the respective amounts of element Y in each compound (0.75 g and 0.67 g of Y, respectively).
Then, by taking the ratios of the masses of X to Y for each compound, we can determine simple whole-number ratios, which can suggest possible empirical formulas for the compounds. These formulas are based on the law of multiple proportions, which states that if two elements form more than one compound between them, then the ratios of the masses of the second element that combine with a fixed mass of the first element will be ratios of small whole numbers.
What mass of HCl is contained in 45.0 mL of an aqueous HCl solution that has a density of 1.19 g cm–3 and contains 37.21% HCl by mass?
Final answer:
To find the mass of HCl in a 45.0 mL aqueous solution with a specific density and concentration, the volume is converted to mass using the given density, and then the mass of HCl is calculated based on its percentage concentration, resulting in 19.93 g of HCl.
Explanation:
The question asks to find the mass of HCl contained in 45.0 mL of an aqueous HCl solution with a density of 1.19 g cm–3 and a concentration of 37.21% HCl by mass. First, we convert the volume of the solution to mass using the given density. Calculating the mass of the solution: 45.0 mL × 1.19 g/mL = 53.55 g. Next, to find the mass of HCl, we use the percentage concentration of HCl in the solution. Calculating the mass of HCl: 53.55 g × 0.3721 = 19.93 g. Therefore, the mass of HCl in the 45.0 mL solution is 19.93 g.