a person trying to throw a ball as far as possible will run forward during the throw. explain why this increases the distance of the throw

Answers

Answer 1
It increases the throw because you are putting more force and speed into the throw
Answer 2

The time of flight of an object is only limited by its vertical velocity, since gravity only works to pull an object down towards the earth.

What is velocity?

The terms speed and velocity  give us an idea of ​​how fast or slow an object is moving. We often come across situations where we need to identify which of  two or more objects is moving faster. The faster of them can be easily distinguished if they move in the same direction on the same road. However, if their direction of movement is opposite, it is difficult to determine the fastest. In such cases, the concept of speed is useful.

The horizontal velocity remains unchanged. So by running prior to throwing the ball, the person can impart and even faster initial horizontal velocity to the ball. So, although the ball still travels for the same amount of time through the air, it travels at a faster horizontal velocity and, therefore, travels a farther horizontal distance.

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Related Questions

Which body exerts the force that propels the sprinter, the blocks or the sprinter?

Answers

Answer: The blocks

Explanation:
When the sprinter takes off, he/she presses hard on the block.
The blocks apply an equal and opposite force to the sprinter according to Newton's 3rd law of motion.
The reaction force from the blocks gives the sprinter the initial acceleration to begin the race.

A 20 kg object is dropped from a very tall building. What is the weight of this objects? After 5 seconds, how has the object fallen and what is its speed at this instant?

Answers

1. What is the weight of this objects?

Weight is simply the product of mass and gravitational acceleration. Therefore the weight is:

w = 20 kg * 9.81 m/s^2

w = 196.2 kg m/s^2 = 196.2 N

 

2. After 5 seconds, how has the object fallen and what is its speed at this instant?

We can use the formula:

y = v0 t  + 0.5 g t^2

v = v0 + g t

where v0 = 0 since the object starts from rest, y is the distance it fell, t is time

y = 0 + 0.5 * 9.81 * 5^2 = 122.625 m

v = 0 + 9.81 * 5 = 49.05 m/s

When you lift a box off the ground, gravity opposes your lifting force.
A.True
B.False

Answers

That's true because every action has an equal and opposite reaction and weight is literally the force gravity has on an object.
true. When you lift the box, you are doing work, but gravity is using force to push it back down towards the center of earth. 
Hope I helped!

Michael jordan's vertical leap is reported to be 47.2 inches. what is his takeoff speed? give your answer in meters per second

Answers

Michael Jordan's takeoff speed for his 47.2-inch vertical leap would be approximately 4.85 m/s, calculated using the kinematic equation for vertical motion.

To find Michael Jordan's takeoff speed, we can use the kinematic equation for vertical motion without air resistance: vf^2 = vi^2 + 2 * a * d, where vf is the final velocity (0 m/s at the peak of the jump), vi is the initial velocity (takeoff speed we want to find), a is the acceleration due to gravity (-9.81 m/s^2), and d is the vertical leap distance.

First, we convert the vertical leap from inches to meters: 47.2 inches = 1.2 meters (approximately).

Now, we can set vf to 0 m/s and solve for vi:

0 = vi^2 + 2 * (-9.81) * 1.2

vi^2 = 2 * 9.81 * 1.2

vi = sqrt(2 * 9.81 * 1.2)

vi ≈ 4.85 m/s (rounded to two decimal places)

Therefore, Michael Jordan's takeoff speed would be approximately 4.85 m/s.

What is the uncertainty of the position of the bacterium? express your answer with the appropriate units?

Answers

For two un-related quantities, the Heisenberg uncertainty equations holds: the prduct of the two uncertainty quantities is greater than [tex]\hbar/2[/tex]
Example of unrelated quantities are position and momentum, energy and time. 
Thus
[tex]\Delta x*\Delta p \ \textgreater \ \hbar/2[/tex]
Knowing the speed of the bacteria the uncertainty in its position is
[tex]\Delta x \ \textgreater \ \hbar/(2 \Delta p) =\hbar/(2mv)[/tex]

Give an order-of-magnitude estimate for the time in seconds of a year

Answers

We all know that there are 365 days in a year, 24 hours in a day, 60 minutes in an hour and lastly 60 seconds in a minute. Round that off to 100, 10, 100 and 100.That will be 10^2 x 10^2 x 10^1 x 10^2 = 10^7 seconds.

You wash the dishes. when you let the water down the drain, where is the water flowing the fastest?

Answers

The water flows the fastest at the center.

This is due to the friction between the water and the sink/drain. The outer parts of the water that are in contact with the kitchen sink/drain experience a greater frictional force and slow down. Their slowing down also affects the layers of water molecules adjacent to them, thereby reducing their speed as well. The layer of water molecules least affected by the friction with the sink/drain is at the center, and so they are the ones that move the fastest.

I drop a penny from the top of the tower in Midland Borough and it takes 1.85 seconds to hit the ground. Calculate the velocity at impact in m/s.

Answers

u = 0, initial velocity
t = 1.85 s, the time of flght

Assume g = 9.8 m/s² and no air resistance
If the velocity of impact is v, then
v = u + gt
v = (9.8 m/s²)*(1.85 s) = 18.13 m/s

Answer: 18.13 m/s

If you could live on the moon through one lunar cycle, how you would experience the phases of the moon?

Answers

Wherever you're sitting on the moon, the sun would be up and shining on you for about two Earth weeks, then the sun would be down and you would be in pitch dark for the next two weeks. You would have no idea of the "phases", because they're only visible to someone on Earth. BUT . . . If you really knew what's what, you could always know what moon phase people on Earth are seeing right now ... but you would need to be somewhere on the side of the moon that always faces Earth. Then, the Earth would always be in your sky, and IT would go through phases for you ! And you would know that the Earth phase you're seeing is exactly the same as the moon phase that people down there are seeing, only BACKWARDS ... the section of the Earth that's DARK for you is the same shape as the section of the moon that's LIGHT for the people down there. Is that cool or what !

Astronomers have discovered several volcanoes on io, a moon of jupiter. one of them, named loki, ejects lava to a maximum height of 2.00 â 105 m. suppose another volcano on a different moon ejected lava at a height of 1.89 â 105 m where the acceleration of gravity is 1.72 m/s2.

Answers

The question seems to be incomplete. However, I can think of a possible logical question this problem could have. The equation for the maximum height attained by any object thrown upwards is:

H = v²/2g

I think the question would be determining the gravity in Io assuming that the initial velocity of the lava is the same. Then, the solution is as follows:

Let's use the other volcano to find v.
1.89×10⁵ m = v²/2(1.72 m/s²)
Solving for v,
v = 806.325 m/s

So, we use this to find g in Io.
2×10⁵ m = (806.325)²/2(g)
Solving for g,
g = 1.6254 m/s²

Final answer:

The question deals with the heights of volcanic lava ejections on moons within our solar system under varying gravitational conditions, highlighting Io, a moon of Jupiter. It emphasizes physics concepts like kinematics and gravitational force, and underlines the contribution of space exploration to our understanding of celestial phenomena.

Explanation:

The question explores the phenomenon of volcanic eruptions on moons in our solar system, focusing on Io, one of Jupiter's moons, and another hypothetical moon. Specifically, it mentions volcanoes ejecting lava to great heights under different gravitational conditions. The question implicitly asks for an analysis or comparison based on the given data, such as the maximum height of lava ejection and the acceleration due to gravity on another moon.

The subject matter delves into the principles of kinematics and gravitational force, which are fundamental concepts in physics. It exemplifies how extraterrestrial volcanism can offer insights into the geological and physical dynamics of celestial bodies other than Earth. Furthermore, the mention of Galileo and Voyager spacecrafts underlines the importance of space exploration in understanding these phenomena.

If a flea can jump straight up to a height of 21.1 cm , what is its initial speed as it leaves the ground, neglecting air resistance?

Answers

The flea jumps at high velocity, reaches zero velocity at the maximum height 21.1 cm before starting to fall. Solve for initial velocity given final velocity is zero.
since time is not given, use the equation:
v^2 = u^2 + 2as
convert gravity or displacement to have same units. 9.8 m/s = 980 cm/s
0 = u^2 + 2(-980)(21.1)
41356 = u^2
sqrt(41356) = u
203.4 cm/s = u

Answer:

Initial speed, u = 2.03 m/s

Explanation:

Flea jumps to a height of, h = 21.1 cm = 0.211 m

As it leaves the ground, its final speed, v = 0

Acceleration, a = -g

Let u is the initial speed of the flea. It can be calculated as :

[tex]v^2-u^2=2as[/tex]

[tex]-u^2=2\times (-9.8)\times 0.211[/tex]

u = 2.03 m/s

So, the initial speed of the flea as it leaves the ground is 2.03 m/s. Hence, this is the required solution.

When a 75 kg man sits on the stool, by what percent does the length of the legs decrease? assume, for simplicity, that the stool's legs are vertical and that each bears the same load?

Answers

Each leg of the stool decreases in length by approximately 1.40 × 10⁻⁴% when the 70 kg man sits on it.

Calculate the force exerted on each leg:

Given: mass (m) = 70 kg, acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mass × acceleration = 70 kg × 9.8 m/s² = 686 N

Determine the original length of the legs:

Let's assume the height of the stool is 1 meter (100 cm).

Calculate the cross-sectional area of each leg:

Given the diameter of each leg is 2.5 cm, the radius (r) is 1.25 cm or 0.0125 m.

Area (A) = π × r²

Area ≈ 3.14 × (0.0125 m)² ≈ 4.91 × 10⁻⁴ m²

Determine the modulus of elasticity of Douglas fir:

Let's assume E = 10 × 10⁹ N/m².

Calculate the change in length for each leg:

Using the formula for axial deformation:

Change in length (ΔL) = (Force × Length) / (Area × Modulus of Elasticity)

ΔL = (686 N × 1 m) / (4.91 × 10⁻⁴ m² × 10 × 10⁹ N/m²)

ΔL ≈ 1.40 × 10⁻⁶ m

Calculate the percentage decrease in length:

Percentage decrease = (Change in length / Original length) × 100%

Percentage decrease = (1.40 × 10⁻⁶ m / 1 m) × 100%

Percentage decrease ≈ 1.40 × 10⁻⁴ %

So, each leg of the stool decreases in length by approximately 1.40 × 10⁻⁴% when the 70 kg man sits on it.

The question probable may be:

A three-legged wooden bar stool made out of solid Douglas firhas legs that are 2.5 cm in diameter.

When a 70 kg man sits on thestool, by what percent does the length of the legs decrease?Assume, for simplicity, that the stool's legs are vertical and thateach bears the same load.

Sunspots _____. A) are found in the chromosphere B) are dark spots in the corona C) are areas where the photosphere is cooler D) happen when certain areas are hotter than others

Answers

C) are areas where the photosphere is cooler is the correct answer.
The answer is C, are areas where the photosphere is cooler. Hope this helps:)

Alice and tom dive from an overhang into the lake below. tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s. neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below. alice and tom dive from an overhang into the lake below. tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s. neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below. tom reaches the surface of the lake first. alice reaches the surface of the lake first. alice and tom will reach the surface of the lake at the same time.

Answers

Alice and Tom reach the lake simultaneously due to gravity's independence from their initial horizontal velocities. The correct answer is (E).

Let us consider the concept of horizontal motion and vertical motion of a projectile (in this case, Alice and Tom) are independent of each other when there is no air resistance.

This means that the horizontal velocity does not affect the vertical motion.

Both Alice and Tom are subject to the same gravitational acceleration, and since they are both falling vertically, they will reach the surface of the lake at the same time.

So, the correct answer is (E). Alice and Tom will reach the surface of the lake at the same time.

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Alice and tom dive from an overhang into the lake below. tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s. neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below.

(A) alice and tom dive from an overhang into the lake below.

(B) tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s.

(c) neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below. tom reaches the surface of the lake first.

(D) alice reaches the surface of the lake first.
(E) alice and tom will reach the surface of the lake at the same time.

Both Alice and Tom will reach the surface of the lake at the same time because their times to hit the water depend only on the vertical distance and gravitational acceleration.

Alice and Tom both dive from the same overhang into a lake below.

Although Alice takes a running start and has an initial horizontal velocity of 25 m/s, the time it takes both of them to reach the lake is the same. This is because the vertical motion for both divers is under uniform acceleration due to gravity, which is not affected by their horizontal velocities.The time it takes to reach the surface is dictated by the height of the overhang and gravity alone.

Both Alice and Tom experience the same vertical acceleration and fall the same vertical distance, hence, they will both reach the surface of the lake at the same time.

Determine the vertical motion of each diver, which is independent of horizontal motion.Use the kinematic equation for vertical motion: h = 1/2 * g * t².Since both Alice and Tom start from the same height and are only influenced by gravity (9.8 m/s²), their times to hit the water are the same.

If a microwave oven produces electromagnetic waves with a frequency of 2.70 ghz, what is their wavelength?

Answers

Ok this one is pretty straight forward :) This is what we know:

1. 2.7GHz is how many vibrations in 1 second. (2.7 x10^9 Hz)
2. Light always has a constant speed 2.9 x10^8 meters per second.

Therefore to find out the length of one of those vibrations you just divide        2.9 x10^8 by 2.7 x10^9
which looks like this in your calculator:
290000000 / 2700000000
= 0.107m
= 10cm

A package of chips weighs 45 grams. How much is that in kilograms?

Answers

There is 1000 grams in 1 kilogram, and so:

Your answer to this question is 0.045 kilograms

hope this helps
45 grams is 0.045 kilograms, i am 100% positive this is right. Good Luck

A vw beetle goes from 0 to 60 mi/h with an acceleration of 2.35 m/s^2.
a.how much time does ti take for the beetle to reach 60 mi/h?
b.a top - fuel dragster can go from 0 to 60 mi/h in 0.600 seconds. find the acceleration (m/s^2) of the dragster.

Answers

Part a.
u = 0, the initial velocity
v = 60 mi/h, the final velocity
a = 2.35 m/s², the acceleration.

Note that
1 m = 1609.34 m.
Therefore
v = (60 mi/h)*(1609.34 m/mi)*(1/3600 h/s) = 26.822 m/s
Use the formula
v = u + at
(26.822 m/s) = (2.35 m/s²)*(t s)
t = 26.822/2.35 = 11.4 s

Answer: 11.4 s

Part b.
We already determined that v = 60 mi/h = 26.822 m/s.
t = 0.6 s
Therefore
(26.822 m/s) = (a m/s²)*(0.6 s)
a = 26.822/0.6 = 44.7 m/s²

Answer:  44.7 m/s²

A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no appreciable air drag. (a) how tall, in meters, is the building? (b) how fast is the brick moving just before it reaches the ground? (c) sketch graphs of this falling brickâs acceleration, velocity, and vertical position as functions of time.

Answers

initial velocity = 0
time = 2.50 s
acceleration = gravity, 9.8 m/s^2

use the equations for linear motion.
s = ut + (1/2)at^2
v = u + at

A. displacement given u, a and t.
s = (0)(2.50) + (1/2)(9.8)(2.50)^2
s = 0 + 4.9(6.25)
s = 30.625 m
three significant figures..
s = 30.6 m

B. final velocity given u, a and t
v = 0 + 9.8(2.50)
v = 24.5 m/s

C. graphs
s vs. t
object starts at zero and displacement increases linearly to (2.5, 30.6) and stops. slope of line is average velocity, s/t
v vs. t
object starts at zero velocity and increases linearly to (2.5, 24.5) and stops. slope of line is acceleration, v/t.
a vs. t
acceleration is gravity, it's constant horizontal line at; y = 9.8. stops at (2.5,9.8)

Answer:

Part a)

y = 30.625 m

Part b)

v = 24.5 m/s

Explanation:

Part a)

As we know that brick will hit the floor after t = 2.50 s

so here we will have

[tex]y = v_i t + \frac{1}{2}at^2[/tex]

[tex]y = 0 + \frac{1}{2}(9.8)(2.50^2)[/tex]

[tex]y = 30.625 m[/tex]

Part b)

velocity of the brick just before it will strike the ground is given as

[tex]v_f = v_i + at[/tex]

[tex]v_f = 0 + (9.8)(2.5)[/tex]

[tex]v_f = 24.5 m/s[/tex]

Part c)

Vector c has a magnitude 24.6 m and is in the direction of the negative y-axis. vectors a and b are at angles α = 41.4° and β = 27.7° up from the x-axis respectively. if the vector sum a b c = 0, what are the magnitudes of a and b?

Answers

Final answer:

To find the magnitudes of vectors a and b, we need to resolve them into their x and y-components and equate them to zero to form two equations. Solving these equations will give us the magnitudes of a and b.

Explanation:

To find the magnitudes of vectors a and b, we need to analyze the given vector sum equation a + b + c = 0. Since vector c is in the negative y-axis direction, it can be written as c = 0î - 24.6ĵ m. According to the vector sum equation, the x-components and y-components of the vectors should cancel out each other. Using trigonometric identities, we can resolve vectors a and b into their x and y-components:

a = (ax)î + (ay)ĵ

b = (bx)î + (by)ĵ

After resolving the vectors, we equate their x-components and y-components to zero to form two separate equations. Solving these equations will give us the magnitudes of vectors a and b.

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The tropical year, the time from vernal equinox to the next vernal equinox, is the basis for our calendar. it contains 365.242199 days. find the number of seconds in two and a half tropical years.

Answers

Final answer:

The length of a tropical year is approximately 365.242199 days, or approximately 31556926 seconds. Therefore, the number of seconds in two and a half tropical years is approximately 78892315 seconds.

Explanation:

The tropical year is based on the time it takes the Earth to revolve around the sun, and is the basis of our calendar. This time period lasts approximately 365.242199 days. To find the number of seconds in a tropical year, we need to first convert this period into hours, minutes, and then seconds. There are 24 hours in a day, 60 minutes in an hour, and 60 seconds in a minute. Here's the calculation:

1 tropical year = 365.242199 days = 365.242199 x 24 = 8765.812776 hours8765.812776 hours = 8765.812776 x 60 = 525948.76656 minutes525948.76656 minutes = 525948.76656 x 60 = 31556925.9936 seconds

So, one tropical year is approximately 31556926 seconds.

To find out the number of seconds in two and a half tropical years, we simply multiply this number by 2.5:

2.5 tropical years = 2.5 x 31556926 = 78892315 seconds

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Work is the transfer of _______ that occurs when a force makes an object move.

Answers

I think it is energy

Select the correct statement to describe when a sample of liquid water vaporizes into water vapor. Question 12 options: Temperature increases and molecular motion increases while shape becomes less defined. Temperature increases and molecular motion decreases while shape becomes more defined. Temperature decreases and molecular motion decreases while shape becomes more defined. Temperature decreases and molecular motion increases while shape becomes less defined.

Answers

temperature increases and molecular motion increases while shape becomes less defined.


if you used 16 gallons when driving 367 miles, what was your gas mileage over that distance

Answers

Your gas mileage would be 22.93 miles per gallon.

What is the resultant velocity vector when you add your swimming velocity and the current velocity? give the x and y components in meters per second separated by a comma?

Answers

The resultant vector, is the vector that adds the components x and y separately.

Since the two x components are 0.00 m/s and 1.00 m/s, the resultant x component will be:

0.0   m/s + 1.00 m/s = 1.00 m/s in + x direction

Similarly, the y components will be:

  -1.00 m/s + 0.00 m/s = -1.00 m/s in -y direction

So, the resultant vector will be: 

(1.00 m/s, -1.00 m/s)

The simultaneous vector of velocity in the form of components x and y is

1, -1 m / s

Further explanation

Vectors are quantities that have magnitude and direction

Vector can be symbolized in the form of directed line segments

One of the presentations of vector shapes is in geometric conditions where the vector components are expressed in the form of x and y coordinates which can be described in matrix form

The position vector of a vector starts from the starting point to the endpoint

Addition of two vectors is the addition of component x and component y

A (x1, y1) and B (x2, y2)

A + B = (x1 + x2, y1 + y2)

There is additional information on the problem:

a swimmer moves to the right with a speed of 1 m / s while the current from the river with the same speed down by 1 m / s (picture attached)

so the vector component position based on components x and y becomes:

swimmer (p): (1,0)

river current (s): (0, -1)

So if the two vectors are added it will become:

v = p + s

v = (1 + 0, 0-1)

v = (1, -1) m / s

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Keywords: vectors, a swimmer, river, Addition of two vectors

The average distance between the variable scores and the mean in a set of data is the __________. A. range B. standard deviation C. mean D. median

Answers

The average distance between the variable scores and the mean in a set of data is the standard deviation.

Answer: B. standard deviation

Explanation:

In statistics , Standard deviation is a term which is used to to represent the measure of dispersion of data from the mean-value.

It is used to determine how closely the data values are with the mean of the entire data.

It is the average distance from each data value to the mean.

Hence, the average distance between the variable scores and the mean in a set of data is the standard deviation.

A runner runs 4875 ft in 6.85 minutes. what is the runnerâs average speed in miles per hour?

Answers

about 8.09 miles is the average speed mph

Plyometric helps strengthen your bones true or false

Answers

plyometric does indeed help strengthen your bones

An object is lifted to a certain height and then dropped. During the drop, which of the following is increased?

a) gravitational potential energy
b) kinetic energy
c) total mechanical energy
d) B and C

Answers

Kinetic energy increases as the object falls.

If the total charge on a rod of length 0.4 m is 2.6 nc, what is the magnitude of the electric field at a location 3 cm from the midpoint of the rod?

Answers

Let the rod be on the x-axes with endpoints -L/2 and L/2 and uniform charge density lambda (2.6nC/0.4m = 7.25 nC/m). 

The point then lies on the y-axes at d = 0.03 m. 

from symmetry, the field at that point will be ascending along the y-axes. 


A charge element at position x on the rod has distance sqrt(x^2 + d^2) to the point. 

Also, from the geometry, the component in the y-direction is d/sqrt(x^2+d^2) times the field strength. 


All in all, the infinitesimal field strength from the charge between x and x+dx is: 


dE = k lambda dx * 1/(x^2+d^2) * d/sqrt(x^2+d^2) 


Therefore, upon integration, 


E = k lambda d INTEGRAL{dx / (x^2 + d^2)^(3/2) } where x goes from -L/2 to L/2. 


This gives:


E = k lambda L / (d sqrt((L/2)^2 + d^2) ) 


But lambda L = Q, the total charge on the rod, so 


E = k Q / ( d * sqrt((L/2)^2 + d^2) )

Final answer:

To calculate the electric field magnitude at a distance from a charged rod, determine the charge per unit length and use the electric field formula.

Explanation:

Electric Field and Charged Rod:

To find the magnitude of the electric field at a distance from a charged rod, you can use the formula for the electric field of a long, charged rod. Given the total charge on the rod and its length, you can calculate the charge per unit length. Then, apply the formula to find the electric field at the specified location.

Let the rod be on the x-axes with endpoints -L/2 and L/2 and uniform charge density lambda (2.6nC/0.4m = 7.25 nC/m).

The point then lies on the y-axes at d = 0.03 m.

from symmetry, the field at that point will be ascending along the y-axes.

A charge element at position x on the rod has distance sqrt(x^2 + d^2) to the point.

Also, from the geometry, the component in the y-direction is d/sqrt(x^2+d^2) times the field strength.

All in all, the infinitesimal field strength from the charge between x and x+dx is:

dE = k lambda dx * 1/(x^2+d^2) * d/sqrt(x^2+d^2)

Therefore, upon integration,

E = k lambda d INTEGRAL{dx / (x^2 + d^2)^(3/2) } where x goes from -L/2 to L/2.

This gives:

E = k lambda L / (d sqrt((L/2)^2 + d^2) )

But lambda L = Q, the total charge on the rod, so

E = k Q / ( d * sqrt((L/2)^2 + d^2) )

A fugitive tries to hop on a freight train traveling at a constant speed of 4.5 m/s. Just as an empty box car passes him, the fugitive starts from rest and accelerates at a = 3.6 m/s2 to his maximum speed of 8.0 m/s.

Answers

Let’s see if he catches before he reaches 8m/sVelocity = acceleration * time, V = at, So, 8 m/s = 3.6 m/s * t, so t = 2.22 sec in that time he moved Distance = Initial Velocity * time + 1/2 acceleration * time * time  S = 0*2.22 + 1/2*3.6*2.22*2.22 = 8.9 meters in 2.22 seconds, the boxcar moved S = V*t = 4.5 * 2.22= 9.99 meters, so he still needs to catch up 9.99 m - 8.9 m = 1.09 meters. Since he’s moving at 8 m/s and the train also is moving at 4.5 m/s, his closing speed is (8 - 4.5) = 3.5 m/s 
It will take him 1.09m/ 3.5m /s = .31 seconds more to catch up. 
So, answer for How long does it take him to catch up to the empty box car is 2.22 sec + .31 sec = 2.53 seconds. answer for What is the distance traveled to reach the box car, we use the speed of the train since it was constant, Distance = Velocity * time = 4.5 m/s * 2.53 s = 11.4 meters.
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