Amy hikes down a slope to a lake that is 10.2 meters below the trail. Then Amy jumps into the lake, and swims 1.5 meters down. She wonders what her new position is relative to the trail. Which of the following equations matches the situation above?

a. −10.2+1.5=?
b. 10.2−1.5=?
c. None of the above

To whoever answers this, thank you so much!!

Answer:

116.75 oceanic miles

Step-by-step explanation:

A graph of the data shows the distance to be between 110 and 120 miles (closer to 120). There is only one answer choice in that range.

In 2 hours, the ship travels 42.5 miles, so in 1 hour will travel 21.25 miles. Adding that distance to the distance at 4 hours gives the distance at 5 hours, ...

  95.5 +21.25 = 116.75 . . . . "oceanic" miles

_____

In order for the distance from the lighthouse to be uniformly increasing, the ship must be traveling directly away from the lighthouse. Traveling at any other angle, the distances will not fall on a straight line. (That is one reason I wanted to graph the data.)

[tex]\bf \textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{csc(\theta )-sin(\theta )}{cos(\theta )}\implies \cfrac{~~\frac{1}{sin(\theta )}-sin(\theta )~~}{cos(\theta )}\implies \cfrac{~~\frac{1-sin^2(\theta )}{sin(\theta )}~~}{cos(\theta )}[/tex]

[tex]\bf \cfrac{1-sin^2(\theta )}{sin(\theta )}\cdot \cfrac{1}{cos(\theta )}\implies \cfrac{\stackrel{cos(\theta )}{\begin{matrix} cos^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}} }{sin(\theta )}\cdot \cfrac{1}{\begin{matrix} cos(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }\implies \cfrac{cos(\theta )}{sin(\theta )}\implies cot(\theta )[/tex]

Answer:

cot Ф

Step-by-step explanation:

Recall that sin²Ф + cos²Ф = 1, (which also says that cos²Ф - 1 = sin²Ф).

Also recall the definitions of the csc, sin and cos functions.

Your expression is equivalent to:

   1               sin Ф

----------  -  -------------

sin Ф              1

===================

           cos Ф

There are three terms in your expression:  csc, sin and cos.  Multiply all of them by sin Ф.  The result should be:

 1 - sin²Ф

---------------

sin Ф · cos Ф

Using the Pythagorean identity (see above), this simplifies to

  cos²Ф

------------------

sin Ф·cos Ф

and this whole fraction reduces to

   cos Ф

--------------   and this ratio is the definition of the cot function.

   sin Ф

Thus, the original expression is equivalent to cot Ф

By Pythagoras' Theorem:

Sum of the squares of the two side  = Square of longest side

a² + b² = c²

a)

So let's check 7, 24, 25

Is 7² + 24² = 25²  ?

7*7 + 24*24

49 + 576  

=625.

Let us perform the other side 25²

25² = 25 * 25 = 625

Therefore the left hand side = Right hand side.

Therefore 7, 24, 25 is a Pythagorean Triple

b)

Let's check 9, 40, 41

Is 9² + 40² = 41²  ?

9² + 40²

9*9+ 40*40  

81 + 1600

=1681

Let us perform the other side 41²

41² = 41 * 41 = 1681

Therefore the left hand side = Right hand side.

Therefore 9, 40, 41 is a Pythagorean Triple.

The ODE

[tex]M(x,y)\,\mathrm dx+N(x,y)\,\mathrm dy=0[/tex]

is exact if

[tex]\dfrac{\partial M}{\partial y}=\dfrac{\partial N}{\partial x}[/tex]

We have

[tex]M=-xy\sin x+2y\cos x\implies M_y=-x\sin x+2\cos x[/tex]

[tex]N=2x\cos x\implies N_x=2\cos x-2x\sin x[/tex]

so the ODE is indeed not exact.

Multiplying both sides of the ODE by [tex]\mu(x,y)=xy[/tex] gives

[tex]\mu M=-x^2y^2\sin x+2xy^2\cos x\implies(\mu M)_y=-2x^2y\sin x+4xy\cos x[/tex]

[tex]\mu N=2x^2y\cos x\implies(\mu N)_x=4xy\cos x-2x^2y\sin x[/tex]

so that [tex](\mu M)_y=(\mu N)_x[/tex], and the modified ODE is exact.

We're looking for a solution of the form

[tex]\Psi(x,y)=C[/tex]

so that by differentiation, we should have

[tex]\Psi_x\,\mathrm dx+\Psi_y\,\mathrm dy=0[/tex]

[tex]\implies\begin{cases}\Psi_x=\mu M\\\Psi_y=\mu N\end{cases}[/tex]

Integrating both sides of the second equation with respect to [tex]y[/tex] gives

[tex]\Psi_y=2x^2y\cos x\implies\Psi=x^2y^2\cos x+f(x)[/tex]

Differentiating both sides with respect to [tex]x[/tex] gives

[tex]\Psi_x=-x^2y^2\sin x+2xy^2\cos x=2xy^2\cos x-x^2y^2\sin x+\dfrac{\mathrm df}{\mathrm dx}[/tex]

[tex]\implies\dfrac{\mathrm df}{\mathrm dx}=0\implies f(x)=c[/tex]

for some constant [tex]c[/tex].

So the general solution to this ODE is

[tex]x^2y^2\cos x+c=C[/tex]

or simply

[tex]x^2y^2\cos x=C[/tex]

We are to verify and confirm if the given differential equations are exact or not. Then solve for the exact equation.

The first differential equation says:

[tex]\mathbf{(-xy \ sin x + 2y \ cos x) dx + 2(x \ cos x) dy = 0 }[/tex]

Recall that:

A differential equation that takes the form [tex]\mathbf{M(x,y)dt + N(x, y)dy = 0 }[/tex] will be exact if and only if:

From equation (1), we can represent M and N as follows:

Thus, taking the differential of M and N, we have:

[tex]\mathbf{ \dfrac{\partial M}{\partial y }= M_y = -x sin x + 2cos x}[/tex]

[tex]\mathbf{ \dfrac{\partial N}{\partial x }= N_x = 2 cos x + 2x sin x}[/tex]

From above, it is clear that:

[tex]\mathbf{\dfrac{\partial M }{\partial y} \neq \dfrac{\partial N }{\partial x}}[/tex]

∴

We can conclude that the equation is not exact.

Now, after multiplying the given differential equation in (1) by the integrating factor μ(x, y) = xy, we have:

Representing the equation into form M and N, then:

[tex]\mathbf{M = -x^22y^2 sin x +2xy^2 cos x}[/tex]

[tex]\mathbf{N = 2x^2y cos x}[/tex]

Taking the differential, we have:

[tex]\mathbf{\dfrac{\partial M}{\partial y }= M_y = -2x^2y sin x + 4xy cos x }[/tex]

[tex]\mathbf{\dfrac{\partial N}{\partial x} =N_x= 4xycos \ x -2x^2 y sin x}[/tex]

Here;

[tex]\mathbf{\dfrac{\partial M}{\partial y} = \dfrac{\partial N}{\partial x} }[/tex]

Therefore, we can conclude that the second equation is exact.

Now, the solution of the second equation is as follows:

[tex]\int_{y } M dx + \int (not \ containing \ 'x') dy = C[/tex]

[tex]\rightarrow \int_{y } (-x^2y^2 sin(x) +2xy^2 cos (x) ) dx + \int(0)dy = C[/tex]

[tex]\rightarrow-y^2 \int x^2 sin(x) dx +2y ^2 \int x cos (x) dx = C[/tex]    ---- (3)

Taking integrations by parts:

[tex]\int u v dx = u \int v dx - \int (\dfrac{du}{dx} \int v dx) dx[/tex]

∴

[tex]\int x^2 sin (x) dx = x^2 \int sin(x) dx - \int (\dfrac{d}{dx}(x^2) \int (sin \ (x)) dx) dx[/tex]

[tex]\to x^2 (-cos (x)) \ - \int 2x (-cos \ (x)) \ dx[/tex]

[tex]\to -x^2 (cos (x)) \ + \int 2x \ cos \ (x) \ dx[/tex]   ----- replace this equation into (3)

∴

[tex]\rightarrow-y^2( -x^2 cos (x) \ + \int 2x \ cos \ (x) \ dx) +2y ^2 \int x cos (x) dx = C[/tex]

[tex]\mathbf{\rightarrow -x^2 y^2 cos (x) \ -2y ^2 \int x \ cos \ (x) \ dx +2y ^2 \int x cos (x) dx = C}[/tex]

[tex]\mathbf{x^2y^2 cos (x) = C\ \text{ where C is constant}}[/tex]

Therefore, from the explanation, we've can conclude that the first equation is not exact and the second equation is exact.

Learn more about differential equations here:

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Answer:

The recursive rule is a1 = 3 , an = (1/6) a(n-1)

Step-by-step explanation:

* Lets revise the recursive formula for a geometric sequence:

1. Determine if the sequence is geometric (Do you multiply, or divide,

  the same amount from one term to the next?)

2. Find the common ratio. (The number you multiply or divide.)

3. Create a recursive formula by stating the first term, and then

   stating the formula to be the common ratio times the

   previous term.

# a1 = first term;

# an= r • a(n-1)

- Where:

- a1 = the first term in the sequence

- an = the nth term in the sequence

- an-1 = the term before the nth term  

- n = the term number

- r = the common ratio

* Lets solve the problem

∵ an = 3(1/6)^(n-1) ⇒ geometric sequence

∵ The explicit rule is an = a1(r)^n-1

∴ a1 = 3 and r = 1/6

- Lets write the recursive rule

∵ a1 = first term;

∵ an= r • a(n-1)

∴ a1 = 3

∴ an = (1/6) a(n-1)

* The recursive rule is a1 = 3 , an = (1/6) a(n-1)

Answer:

a1 = 3
an = 1/6a n-1

Step-by-step explanation:

i took the test

Answer:

see below

Step-by-step explanation:

The number of columns of A is equal to the number of rows of B, so multiplication is possible. It works well to have a calculator do this for you. It involves 27 multiplications and 18 additions, tedious at best.

Each product term is the sum of products ...

p[row=i, column=j] = a[i, 1]b[1, j] +a[i, 2]b[2, j] +a[i, 3]b[3, j]

For example, the product term in the 3rd row, 2nd column is ...

p[3, 2] = a[3, 1]b[1, 2] +a[3, 2]b[2, 2] +a[3, 3]b[3, 2]

= (-4)(-5) +(-1)(3) +(-9)(4) = 20 -3 -36

p[3, 2] = -19

The events “cheering for Team A” and “being a female” are not mutually exclusive. The probability that a randomly selected attendee is female or cheers for Team A is approximately 0.741.

(a) No, the events “cheering for Team A” and “being a female” are not mutually exclusive. This is because there are females who are cheering for Team A. Mutually exclusive events cannot happen at the same time.

(b) To find the probability that a randomly selected attendee is female or cheers for Team A, we need to add the probabilities of each event happening and subtract the probability of both events happening at the same time. We can use the formula:

P(A or B) = P(A) + P(B) - P(A and B)

In this case, P(A) is the probability of cheering for Team A, P(B) is the probability of being female, and P(A and B) is the probability of being a female who cheers for Team A.

Given the numbers provided, the probability of cheering for Team A is 2118/4997 and the probability of being female is 2568/4997. The probability of being a female who cheers for Team A is 982/4997. Plugging these values into the formula, we get:

P(Female or Team A) = P(Team A) + P(Female) - P(Female and Team A) = 2118/4997 + 2568/4997 - 982/4997 = 3704/4997 ≈ 0.741

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Answer:

  1557/1892

Step-by-step explanation:

Your calculator can do this:

[tex]\dfrac{18M}{K}=\dfrac{18\cdot 3\cdot 11\cdot 173}{2\cdot 33\cdot 11\cdot 172}=\dfrac{18\cdot 173}{2\cdot 11\cdot 172}\\\\=\dfrac{1557}{1892}[/tex]

will you receive the grade immediately?

Answer:

21

Step-by-step explanation:

√(35x)

The prime factorization of 35 is 5×7.  To simplify the radical, the expression underneath must be a multiple of a perfect square.  So we need to choose a value of x that has either 5 or 7 as a factor.

21 has a factor of 7.  Let's see:

√(35×21)

√(5×7×3×7)

√(15×7²)

7√15

Answer:

Associative property of multiplication

Step-by-step explanation:

To show that 9(3x) = 27(x), we need to show that 9(3x) = (9 * 3)x.

The APM does just that. By this property, in multiplication, the order of which numbers are multiplied do not matter.

So, 9(3x) = (9 * 3)x.

And by multiplication, (9 * 3)x = 27x.

So 9(3x) = 27x

Answer:

Volume of the Right Triangular Prism is 1771 m³.

Step-by-step explanation:

Given:

A Right Triangular base Prism.

Length of the legs of the right triangle of the base is 14 m , 23 m

Hypotenuse of the triangle is 26.9 m

Height of the Prism is 11 m

To find: volume of the Prism.

We know that Volume of the Prism = Base Area × Height

Volume of the Right Triangular Prism = Area of Base Triangle × Height

                                                              = 1/2 × 14 × 23 × 11

                                                              = 7 × 23 × 11

                                                              = 1771 m³

Therefore, Volume of the Right Triangular Prism is 1771 m³.

Answer:

1,771

Step-by-step explanation:

ANSWER

[tex]x = \frac{ 5 - \sqrt{ 5} }{4} \: or \: \: x = \frac{ 5 + \sqrt{ 5} }{4} [/tex]

EXPLANATION

The given quadratic equation is

[tex]4 {x}^{2} - 10x + 5 = 0[/tex]

We compare this to

[tex]a {x}^{2} + bx + c = 0[/tex]

to get a=4, b=-10, and c=5.

The quadratic formula is given by

[tex]x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]

We substitute these values into the formula to get:

[tex]x = \frac{ - - 10 \pm \sqrt{ {( - 10)}^{2} - 4(4)(5)} }{2(4)} [/tex]

This implies that

[tex]x = \frac{ 10 \pm \sqrt{ 100 - 80} }{8} [/tex]

[tex]x = \frac{ 10 \pm \sqrt{ 20} }{8} [/tex]

[tex]x = \frac{ 10 \pm2 \sqrt{ 5} }{8} [/tex]

[tex]x = \frac{ 5 \pm \sqrt{ 5} }{4} [/tex]

The solutions are:

[tex]x = \frac{ 5 - \sqrt{ 5} }{4} \: or \: \: x = \frac{ 5 + \sqrt{ 5} }{4} [/tex]

Answer:

[tex]\large\boxed{x=\dfrac{5-\sqrt5}{4},\ x=\dfrac{5+\sqrt5}{4}}[/tex]

Step-by-step explanation:

[tex]\text{The quadratic formula for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac<0,\ \text{then the equation has no real solution}\\\\\text{if}\ b^2-4ac=0,\ \text{then the equation has one solution:}\ x=\dfrac{-b}{2a}\\\\\text{if}\ b^2-4ac,\ ,\ \text{then the equation has two solutions:}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\==========================================[/tex]

[tex]\text{We have the equation:}\ 4x^2-10x+5=0\\\\a=4,\ b=-10,\ c=5\\\\b^2-4ac=(-10)^2-4(4)(5)=100-80=20>0\\\\x=\dfrac{-(-10)\pm\sqrt{20}}{2(4)}=\dfrac{10\pm\sqrt{4\cdot5}}{8}=\dfrac{10\pm\sqrt4\cdot\sqrt5}{8}=\dfrac{10\pm2\sqrt5}{8}\\\\=\dfrac{2(5\pm\sqrt5)}{8}=\dfrac{5\pm\sqrt5}{4}[/tex]

ANSWER

[tex]|^{ \to} _{YZ}| = \sqrt{13} [/tex]

EXPLANATION

Given the points, y(-2,5),z(1,3)

[tex] ^{ \to} _{YZ} = \binom{1}{3} - \binom{ - 2}{5} = \binom{3}{ - 2} [/tex]

Therefore the ordered pair is <3,-2>

The magnitude is

[tex] |^{ \to} _{YZ}| = \sqrt{ {3}^{2} + ( - 2)^{2} } [/tex]

[tex] |^{ \to} _{YZ}| = \sqrt{ 9 +4} [/tex]

[tex]|^{ \to} _{YZ}| = \sqrt{13} [/tex]

Answer: AAAAAAAAAAAAAAAAAAAAAAAAAAa

Answer: A

Step-by-step explanation:

Answer:

a.

“Let’s go outside. It’s really noisy in here and I can’t really hear what you are saying.”

Step-by-step explanation:

Which of the following statements reflects the principles of avoiding distractions and being other-oriented?

a. “Let’s go outside. It’s really noisy in here and I can’t really hear what you are saying.”

This is clear from option A - the person is saying that its noisy here and he cannot listen to the other person.

Answer:

Step-by-step explanation:

The absolute value function prevents the expression from being a polynomial. The degree of 3 in y^3 is an odd number so that polynomial function will not be even.

Answer:

The equation [tex]y=x^3[/tex] is not an equation of a simple , even polynomial function.

Step-by-step explanation:

Even  function : A function  is even when its graph is symmetric with respect to y-axis.

Algebrically , the function f is even if and only if

f(-x)=f(x) for all x in the domain of f.

When the function does not satisfied the above condition then the function is called non even function.

f(x)[tex]\neq[/tex] f(-x)

Now , we check given function is even or not

A. y= [tex]\mid x\mid[/tex]

If x is replaced by -x

Then we get the function

f(-x)=[tex]\mid -x \mid[/tex]

f(-x)=[tex]\mid x \mid[/tex]

Hence, f(-x)=f(x)

Therefore , it is even  polynomial function.

B. [tex]y=x^2[/tex]

If x is replace by -x

Then we get

f(-x)=[tex](-x)^2[/tex]

f(-x)=[tex]x^2[/tex]

Hence, f(-x)=f(x)

Therefore, it is even polynomial function.

C. [tex]y=x^3[/tex]

If x is replace by -x

Then we get

f(-x)=[tex](-x)^3[/tex]

f(-x)=[tex]-x^3[/tex]

Hence, f(-x)[tex]\neq[/tex] f(x)

Therefore, it is not even polynomial function.

D.[tex]y= -x^2[/tex]

If x is replace by -x

Then we get

f(-x)= - [tex](-x)^2[/tex]

f(-x)=-[tex]x^2[/tex]

Hence, f(-x)=f(x)

Therefore, it is even polynomial function.

Answer: C. [tex]y=x^3[/tex] is not simple , even polynomial function.

Answer:

6433.98 ft

Step-by-step explanation:

In order to find what 25% of the tank's capacity is, we know to know the full capacity of the tank then take 25% of that.  The volume formula for a right circular cone is

[tex]V=\frac{1}{3}\pi r^2h[/tex]

We have all the values we need for that:

[tex]V=\frac{1}{3}\pi (16)^2(96)[/tex]

This gives us a volume of 25735.93 cubic feet total.

25% of that:

.25 × 25735.93 = 6433.98 ft

Answer:

The height of the water is [tex]60.5\ ft[/tex]

Step-by-step explanation:

step 1

Find the volume of the tank

The volume of the inverted right circular cone is equal to

[tex]V=\frac{1}{3}\pi r^{2} h[/tex]

we have

[tex]r=16\ ft[/tex]

[tex]h=96\ ft[/tex]

substitute

[tex]V=\frac{1}{3}\pi (16)^{2} (96)[/tex]

[tex]V=8,192\pi\ ft^{3}[/tex]

step 2

Find the 25% of the tank’s capacity

[tex]V=(0.25)*8,192\pi=2,048\pi\ ft^{3}[/tex]

step 3

Find the height, of the water in the tank  

Let

h ----> the height of the water  

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

[tex]\frac{R}{H}=\frac{r}{h}[/tex]

substitute

[tex]\frac{16}{96}=\frac{r}{h}\\ \\r= \frac{h}{6}[/tex]

where

r is the radius of the smaller cone of the figure

h is the height of the smaller cone of the figure

R is the radius of the circular base of tank

H is the height of the tank

we  have

[tex]V=2,048\pi\ ft^{3}[/tex] -----> volume of the smaller cone

substitute

[tex]2,048\pi=\frac{1}{3}\pi (\frac{h}{6})^{2}h[/tex]

Simplify

[tex]221,184=h^{3}[/tex]

[tex]h=60.5\ ft[/tex]

Answer:

Eric’s share in the profit is $30,000 ⇒ answer B

Step-by-step explanation:

* We will use the ratio to solve this problem

- At first lets find the ratio between their invested

∵ Eric has invested $400,000

∵ George has invested $300,000

∵ Denzel has invested $300.000

- To find the ratio divide each number by 100,000

∴ Eric : George : Denzel = 4 : 3 : 3

- They will divide the profits among themselves in the ratio of their

  respective investments

- The total profit will divided by the total of their ratios

∵ The total of the ratios = 4 + 3 + 3 = 10

∴  Eric : George : Denzel : Sum = 4 : 3 : 3 : 10

- That means the profit will divided into 10 equal parts

- Eric will take 4 parts, George will take 3 parts and Denzel will take

 3 parts

∵ The profit = $75,000

- Divide the profit by the sum of the ratio

∴ Each part of the profit = 75,000 ÷ 10 = $7,500

- Now lets find the share of each one

∴ The share of Eric = 4 × 7,500 = $30,000

∴ The share of George = 3 × 7,500 = $22,500

∴ The share of Denzel = 3 × 7,500 = $22,500

* Eric’s share in the profit is $30,000

# If you want to check your answer add the shares of them, the answer

  will be the total profit (30,000 + 22,500 + 22,500 = $75,000), and if

  you find the ratio between their shares it will be equal the ratio

  between their investments (divide each share by 7,500 to simplify

  them the answer will be 4 : 3 : 3)

Answer:

B

Step-by-step explanation:

Answer:

a. X is the number of adults in America that need to be surveyed until finding the first one that will watch the Super Bowl.

b. X can take any integer that is greater than or equal to 1. [tex]\rm X\in \mathbb{Z}^{+}[/tex].

c. [tex]\rm X \sim NB(1, 0.40)[/tex].

d. [tex]E(\rm X) = 2.5[/tex].

e. [tex]P(\rm X = 7) = 0.0187[/tex].

f. [tex]P(\text{X} = 3) +P(\text{X} = 4) = 0.230[/tex].

Step-by-step explanation:

In this setting, finding an adult in America that will watch the Super Bowl is a success. The question assumes that the chance of success is constant for each trial. The question is interested in the number of trials before the first success. Let X be the number of adults in America that needs to be surveyed until finding the first one who will watch the Super Bowl.

It takes at least one trial to find the first success. However, there's rare opportunity that it might take infinitely many trials. Thus, X may take any integer value that is greater than or equal to one. In other words, X can be any positive integer: [tex]\rm X\in \mathbb{Z}^{+}[/tex].

There are two discrete distributions that may model X:

[tex]\rm NB(1, p)[/tex] (note that [tex]r=1[/tex]) is equivalent to [tex]\sim Geo(p)[/tex]. However, in this question the distribution of [tex]\rm X[/tex] takes two parameters, which implies that [tex]\rm X[/tex] shall follow the negative binomial distribution rather than the geometric distribution. The probability of success on each trial is [tex]40\% = 0.40[/tex].

[tex]\rm X\sim NB(1, 0.40)[/tex].

The expected value of a negative binomial random variable is equal to the number of required successes over the chance of success on each trial. In other words,

[tex]\displaystyle E(\text{X}) = \frac{r}{p} = \frac{1}{0.40} = 2.5[/tex].

[tex]P(\rm X = 7) = 0.0187[/tex].

Some calculators do not come with support for the negative binomial distribution. There's a walkaround for that as long as the calculator supports the binomial distribution. The r-th success occurs on the n-th trial translates to (r-1) successes on the first (n-1) trials, plus another success on the n-th trial. Find the chance of (r-1) successes in the first (n-1) trials and multiply that with the chance of success on the n-th trial.

[tex]P(\text{X} = 3)+P(\text{X} = 4) = 0.230 [/tex].

To convert 88 square yards to square meters, we use the conversion factor 1 square yard = 1.196 square meters. By multiplying 88 by 1.196, we find that 88 square yards is approximately 105.3 square meters.

The question is part of the mathematics subject, specifically in the area of unit conversion. We have a conversion factor to use, which is 1 square yard = 1.196 square meters, based on the provided reference information.

So to convert 88 square yards to square meters, you multiply 88 by 1.196.

88 yards2 * 1.196 m2/yard2 = 105.3 m2.

so 88 square yards is approximately = 105.3 square meters.

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Answer:

The correct answer option is x = 4.

Step-by-step explanation:

We are given the following logarithmic equation and we are to determine whether which of the given options shows its extraneous solution:

[tex] log _ 7 ( 3 x ^ 3 + x ) - log _ 7 ( x ) = 2 [/tex]

We can rewrite it as:

[tex]log7[\frac{3x^3+x}{x} ]=2[/tex]

But we know that [tex]log_7(49)=2[/tex]

So, [tex]log7[\frac{3x^3+x}{x} ]=log_7(49)[/tex]

Cancelling the log to get:

[tex]\frac{3x^3+x}{x} =49[/tex]

Further simplifying it to get:

[tex]3x^2+1=49[/tex]

[tex]3x^2=48[/tex]

[tex]x^2=\frac{48}{3}[/tex]

[tex]x^2=16[/tex]

x = 4

Answer:

The extraneous solution to the logarithmic equation is [tex]x=-4[/tex]

Step-by-step explanation:

We have the equation:

[tex]Log_{7} (3x^3+x)-Log_7(x)=2[/tex]

By properties of logarithms:

[tex]LogA-LogB=Log(\frac{A}{B})[/tex]

So, with the equation we have:

[tex]Log_{7} \frac{(3x^3+x)}{x}=2[/tex]

[tex]Log_{7}( \frac{3x^3+x}{x})=2\\Log_{7}( \frac{3x^3}{x}+\frac{x}{x})=2\\Log_{7}( \frac{3x^3}{x}+1)=2\\Log_{7}(3x^2+1)=2[/tex]

This logarithm base is 7 and this equation is equal to 2,  the number 7 passes as the base on the other side of the equation and the two as an exponent, after that we just to find x:

[tex]7^2=(3x^2+1)\\49=3x^2+1\\49-1=3x^2\\\frac{48}{3} =x^2\\16=x^2[/tex]

Now, we can find x with square root

[tex]16=x^2\\\sqrt{16} =\sqrt{x^2} \\x_1=4\\x_2=-4[/tex]

This equation has two answers because it is a quadratic equation, so with this logic the strange solution is -4

Answer:

B

Step-by-step explanation:

The volume of a sphere is given by

[tex]V=\frac{4}{3}\pi r^3[/tex]

where r is the radius

For $2.75, we can get 1 large  OR  2 small scoops.

Giant scoop has diameter 6, so radius is half of that, which is 3, hence the volume is:

[tex]V=\frac{4}{3}\pi r^3\\V=\frac{4}{3}\pi (3)^3\\V=113.1[/tex]

Regular scoop's diameter is 4, hence radius is 2. So volume of 1 regular scoop is:

[tex]V=\frac{4}{3}\pi r^3\\V=\frac{4}{3}\pi (2)^3\\V=33.51[/tex]

We can get 2 of those, so total volume is 33.51 + 33.51 = 67.02

Hence, the max volume for $2.75 is around 113, answer choice B.

Answer:

Step-by-step explanation:

The total sold is the sum of the individual numbers sold, hence c+h.

We assume "3 times more" means "3 times as many", so the number of hotdogs sold (h) is 3 times the number of cheeseburgers sold (c), hence 3c.

  c + h = 220

  h = 3c

_____

55 cheeseburgers and 165 hotdogs were sold.

0.3 or 30%. The probability that Ace pick a banana from a basket that content others fruits is 0.3.

The key to solve this problem is using the equation of probability [tex]P(A)=\frac{n(A)}{n}[/tex] where n(A) the numbers of favorables outcomes and n the numbers of possible outcomes.

There are in the basket 10 fruits in total (3 bananas + 4 apples + 3 oranges = 10fruits). Then, extract a fruit can occur in 10 ways, this is n. There is only 3 bananas in the basket, so the fruit that ACE will pick be a banana can occur in 3 ways out of 10,  so 3 is n(A).

Solving the equation:

[tex]P(A)=\frac{3}{10}=0.3[/tex]

The probability that Ace will pick a banana from the basket is 3/10, as there are 3 bananas out of a total of 10 pieces of fruit.

The question asks for the probability that Ace will pick a banana from a basket containing 3 bananas, 4 apples, and 3 oranges. To calculate this, you sum up the total number of pieces of fruit, which is 3 bananas + 4 apples + 3 oranges = 10 pieces of fruit. The probability is then the number of desired outcomes (bananas) over the total number of possible outcomes (all pieces of fruit), which is 3 bananas / 10 pieces of fruit = 3/10 or 30%.

Answer:

  80 cm²

Step-by-step explanation:

Trapezoid LPKB has area ...

  A = (1/2)(b1 +b2)h = (1/2)(4 +20)(20) = 240 . . . . cm²

Triangle BPN has area ...

  A = (1/2)bh = (1/2)(20)(20) = 200 . . . . cm²

Triangle BKN has a height that is 4/5 the height of triangle BPN, so will have 4/5 the area:

  ΔBKN = (4/5)(200 cm²) = 160 cm²

The area of quadrilateral LPKB is that of trapezoid LPNB less the area of triangle BKN, so is ...

  240 cm² - 160 cm² = 80 cm²

Answer:

78(0.50)+87(0.25)+80(0.15)+90(0.10)=x

Step-by-step explanation:

Let

x-----> the final average

we know that

To find the final average multiply each performance by its weight in decimal and then sum the results

x=78(0.50)+87(0.25)+80(0.15)+90(0.10)

x=39+21.75+12+9

x=81.75

Answer:

C. there is a common difference of 3 for f(x) when x increases by 1

Step-by-step explanation:

As 3 is the slope of this function, there will be a common difference of 3 when x increases by 1.

f(x) = 3x  - 7

Let's think, whenever we add 1 to x it i'll increase 3 in the result

f(0) = 3.0 - 7 = 0 - 7 = -7

f(1) = 3.1 - 7 = 3 - 7 = -4

f(2) = 3.2 - 7 = 6 - 7 = -1

So we can know that there's a common difference of 3 for f(x) when x increase by 1.

The answer is:

The number of teeth of Gear 2 is 90 teeth.

[tex]N_{2}=90teeth[/tex]

To calculate the number of teeth for the Gear 2, we need to use the following formula that establishes a relation between the number of RPM and the number of teeth of two or more gears.

[tex]N_{1}Z_{1}=N_{2}Z_{2}[/tex]

Where,

N, are the rpm of the gears

Z, are the teeth of the gears.

We are given the following information:

[tex]Z_{1}=30teeth\\N_{1}=150RPM\\N_{2}=50RPM[/tex]

Then, substituting and calculating we have:

[tex]N_{1}Z_{1}=N_{2}Z_{2}[/tex]

[tex]150RPM*30teeth=N_{2}50RPM[/tex]

[tex]N_{2}=\frac{150RPM*30teeth}{50RPM}=90teeth[/tex]

[tex]N_{2}=90teeth[/tex]

Hence, we have that the number of teeth of Gear 2 is 90 teeth.

Have a nice day!

Explanation:

To find the value, put 320 where x is and do the arithmetic.

f(320) = 0.11·320 +43 = 35.20 +43 = 78.20

The meaning is described by the problem statement:

"how much Derek pays for phone service" for "the number of minutes, [320], used for international calls in a month."

Derek pays 78.20 for 320 minutes of international calls in a month.

__

The units (dollars, rupees, euros, pounds, ...) are not specified.

Answer:

Given the function f(x) = 0.11x + 43, this shows the relationship between how much Derek has to pay for phone service for the amount of minutes he uses on international calls a month.  f(320) can be solved by substituting x = 320, and this is shown below: f(x) = 0.11x + 43 f(320) = 0.11(320) + 43 f(320) = 78.2 This means that Derek has to pay $78.20 for the 320 minutes of calls. Among the choices, the correct answer is B.

Answer:

[tex]\large\boxed{x=\dfrac{5-\sqrt5}{4},\ x=\dfrac{5+\sqrt5}{4}}[/tex]

Step-by-step explanation:

[tex]\text{The quadratic formula for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac<0,\ \text{then the equation has no real solution}\\\\\text{if}\ b^2-4ac=0,\ \text{then the equation has one solution:}\ x=\dfrac{-b}{2a}\\\\\text{if}\ b^2-4ac,\ ,\ \text{then the equation has two solutions:}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\==========================================[/tex]

[tex]\text{We have the equation:}\ 4x^2-10x+5=0\\\\a=4,\ b=-10,\ c=5\\\\b^2-4ac=(-10)^2-4(4)(5)=100-80=20>0\\\\x=\dfrac{-(-10)\pm\sqrt{20}}{2(4)}=\dfrac{10\pm\sqrt{4\cdot5}}{8}=\dfrac{10\pm\sqrt4\cdot\sqrt5}{8}=\dfrac{10\pm2\sqrt5}{8}\\\\=\dfrac{2(5\pm\sqrt5)}{8}=\dfrac{5\pm\sqrt5}{4}[/tex]

Answer:

165

Step-by-step explanation:

[tex]5c^{2} -3d+15[/tex]

c = 6 and d = 10

[tex]5c^{2}[/tex] = 5 × 6² = 5 × 36 = 180

[tex]5c^{2}[/tex] - ( 3 d ) = 180 - ( 3 × 10 ) = 180 - 30 = 150

[tex]5c^{2}[/tex] -  3 d  ( + 15 ) = 150 + 15 = 165

Answer:

165

Step-by-step explanation:

Substitutet 6 for c and 10 for d in  5c^2 - 3d + 15​ .

Note that " ^ " is used here to denote exponentiation; c2 is meaningless.

Then we have 5(6)^2 - 3(10) + 15, or   180 - 30 + 15, or 165.