Bicarbonate concentrate mixers may have a which are replaced on a routine basic.
A) True
B) False

Answer:

[tex]Frequency=2.88\times 10^{14}\ s^{-1}[/tex]

Explanation:

The relation between frequency and wavelength is shown below as:

[tex]c=frequency\times Wavelength [/tex]

c is the speed of light having value [tex]3\times 10^8\ m/s[/tex]

Given, Wavelength = 1040 nm

Also, 1 m = [tex]10^{-9}[/tex] nm

So,  

Wavelength = [tex]1040\times 10^{-9}[/tex] m

Thus, Frequency is:

[tex]Frequency=\frac{c}{Wavelength}[/tex]

[tex]Frequency=\frac{3\times 10^8}{1040\times 10^{-9}}\ s^{-1}[/tex]

[tex]Frequency=2.88\times 10^{14}\ s^{-1}[/tex]

Answer:

0.0400 g for the example given below.

Explanation:

pH value is not provided, so we'll solve this problem in a general case and then we will use an example to justify it.

Now, let's say that pH is given as 12.00 and we use a 100-ml volumetric flask. Then we would obtain:

[tex]m_{NaOH} = 10^{12.00 - 14.00}\cdot 39.997 g/mol\cdot 0.100 L = 0.0400 g[/tex]

The mass of sodium hydroxide that the chemist must weigh out depends on the volume of the solution.

To calculate the mass of sodium hydroxide that the chemist must weigh out in the second step, we can use the equation:

Mass NaOH = Molarity x Volume x Molar mass

From the given information, the chemist wants to prepare a sodium hydroxide solution with a pH of 14, which corresponds to a concentration of 1.0 M. The volume of the solution is not provided, so we cannot calculate the exact mass of sodium hydroxide. We need this volume information to proceed with the calculation.

To determine the number of grams of H2 formed when 4.52 moles of Na reacts with an excess of water, use the balanced chemical equation and the molar mass of H2.

To determine the number of grams of H2 formed when 4.52 moles of Na reacts with an excess of water, we first need to balance the chemical equation. The balanced equation for the reaction between Na and water is:
2Na + 2H2O → 2NaOH + H2

From the balanced equation, we can see that for every 2 moles of Na that react, 1 mole of H2 is formed. Therefore, if 4.52 moles of Na react, we expect to produce half that amount of moles of H2.

Number of moles of H2 = (4.52 moles of Na) / 2 = 2.26 moles of H2

To convert the moles of H2 to grams, we need to use the molar mass of H2, which is 2 g/mol.

Mass of H2 = (2.26 moles of H2) * (2 g/mol) = 4.52 grams of H2

Moisture, rising unstable air, and a lifting mechanism etc.  are the main features of severe thunderstorm. Hence, option a is correct.

Thunderstorm is resulting from the collision of clouds accompanied with an electric current producing the lightning. Severe thunderstorms produce convective instability .

It brings about a significant negative buoyancy in conjunction with thunderstorm downdrafts. Intense evaporation, negative buoyancy, and a powerful downdraft are produced as the dry air entrains with the cloud's wet air.

Hail that is falling undergoes less melting because to evaporative cooling. Severe thunderstorms also causes tilting of storms, displaces updraft from downdraft; Creates a vacuum affect at the top of storms; helps sustains the intensity and verticality of the updraft.

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Final answer:

Severe thunderstorms require moisture, rising unstable air (updrafts), and a lifting mechanism. These storms form in conditions of atmospheric instability, often involving lifting caused by convection, orographic uplift, or encounters between different air masses such as cold fronts and warm fronts.

Explanation:

Severe thunderstorms are complex weather systems that require specific atmospheric conditions to form. Based on the information provided, the elements that severe thunderstorms have with them include moisture, rising unstable air, and a lifting mechanism. Rising unstable air, also known as updrafts, is a crucial component for the development of thunderstorms. This unstable air rises and cools, leading to water vapor condensing into clouds. The process of condensation releases latent heat, which further fuels the updrafts, causing the thunderstorms to intensify.

Different lifting mechanisms can lead to the formation of thunderstorms, including convection, orographic uplift, and weather fronts such as cold fronts and warm fronts, where air masses of different temperatures collide, forcing the warmer air to rise. This process leads to atmospheric instability, which is a critical condition for thunderstorm formation.

Answer:

[tex]M=147.014 g/mol[/tex]

Explanation:

The atomic weights of the elements:

Ca=40.078 g/mol

Cl=35.453 g/mol

H=1.008 g/mol

O=15.999 g/mol

The calcium chloride dihydrate:

[tex]M=(40.078+35.453*2+2*2*1.008+2*15.999)g/mol[/tex]

[tex]M=147.014 g/mol[/tex]

Answer:

Approximately 75%.

Explanation:

Look up the relative atomic mass of Ca on a modern periodic table:

There are one mole of Ca atoms in each mole of CaCO₃ formula unit.

Calculate the mass ratio of Ca in a pure sample of CaCO₃:

[tex]\displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} = \frac{40.078}{100} \approx \frac{2}{5}[/tex].

Let the mass of the sample be 100 g. This sample of CaCO₃ contains 30% Ca by mass. In that 100 grams of this sample, there would be [tex]\rm 30 \% \times 100\; g = 30\; g[/tex] of Ca atoms. Assuming that the impurity does not contain any Ca. In other words, all these Ca atoms belong to CaCO₃. Apply the ratio [tex]\displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} \approx \frac{2}{5}[/tex]:

[tex]\begin{aligned} m\left(\mathrm{CaCO_3}\right) &= m(\mathrm{Ca})\left/\frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)}\right. \cr &\approx 30\; \rm g \left/ \frac{2}{5}\right. \cr &= 75\; \rm g \end{aligned}[/tex].

In other words, by these assumptions, 100 grams of this sample would contain 75 grams of CaCO₃. The percentage mass of CaCO₃ in this sample would thus be equal to:

[tex]\displaystyle 100\%\times \frac{m\left(\mathrm{CaCO_3}\right)}{m(\text{sample})} = \frac{75}{100} = 75\%[/tex].

The percent composition of CaCO3 in a sample that contains 30% calcium by weight is 75%. This is calculated by dividing the actual weight % of calcium in the sample by the weight % of calcium in pure CaCO3, and multiplying by 100.

The subject of this question is the calculation of the percent composition of a compound, which comes under the realm of Chemistry, specifically, Stoichiometry. In this question, we are examining a sample of calcium carbonate (CaCO3) reported to contain 30% calcium (Ca). We are to determine the percent of CaCO3 present in the sample.

Given that the molar mass of CaCO3 is 100 grams, 30% of this is calcium, that equates to 30 grams of calcium. Calcium's contribution to the molar mass of CaCO3 is 40 g/mol, so in a 100 g sample of pure CaCO3, calcium would naturally account for 40%. However, in our sample, the calcium content is lower at 30%. Thus, the sample is not 100% pure CaCO3. To calculate the percent composition of CaCO3 in this sample, we divide calcium's actual proportion of the sample by its proportion in pure CaCO3, and multiply by 100. Hence, (30/40)*100 = 75%.

Therefore, the sample is 75% CaCO3.

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Answer : The correct option is, (3) change states of matter.

Explanation :

Latent heat : It is defined as the heat required to convert the solid into liquid or vapor and a liquid into a vapor without changing the temperature.

There are two types of latent heat.

(1) Latent heat of fusion

(2) Latent heat of vaporization

Latent heat of fusion : It is defined as the amount of heat energy released or absorbed when the solid converted to liquid at atmospheric pressure at its melting point.

Latent heat of vaporization : It is defined as the amount of heat energy released or absorbed when the liquid converted to vapor at atmospheric pressure at its boiling point.

Hence, latent heat is used to change states of matter.

Latent heat refers to the energy absorbed or released during phase changes in substances without affecting temperature. It plays a crucial part in transforming the phase of the matter from solid, liquid to gas, and vice versa by breaking and forming bonds between particles.

Latent heat refers to the energy entered or left in a system during a phase change, without causing a change in the system's temperature. Different substances undergo phase changes at fixed temperatures, commonly known as boiling and freezing points. During these phase changes, heat is either absorbed or released without affecting the temperature of the substance itself.

The three common phases of matter include solid, liquid, and gas. The process of transitioning from one phase to another is principally guided by the latent heat. For example, latent heat is absorbed during the processes of melting (solid to liquid) and vaporization (liquid to gas). On the contrary, it is released during freezing (liquid to solid) and condensation (gas to liquid). It's also noteworthy that the amount of latent heat involved during phase changes is primarily conditioned by the substance's molecular forces.

Correspondingly, latent heat is involved in breaking and forming the bonds between particles during phase changes. When a solid is melted, for example, energy is employed to break the bonds between the solid's particles, with no temperature change until the phase change is completed.

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Answer: the answer is D

Explanation:

Answer:

D. zinc and hydrochloric acid.

Explanation:

Step 1: The balanced equation:

Zn + 2HCL → ZnCl2 + H2

Step 2:

All chemical reactions involve both reactants and products. Reactants are substances that start a chemical reaction, and products are substances that are produced in the reaction.

This means the substances on the left side, Zinc (Zn)  and hydrochloric acid (HCl) are the reactants and will react with eachother, to form the products Zinc chloride (ZnCl2) and hydrogen gas (H2).

Option A: is not correct because zinc chloride and hydrogen are the products

Option B: is not correct because there is no hydrogen carbonate in the reaction

Option C: is not correct because there is no zinc chlorate, neither water in the reaction

The correct answer is D. zinc and hydrochloric acid.

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

[tex]-w=\frac{dm}{dt}[/tex]

w is the mass flow

m is the mass of salt

[tex]-v*C=\frac{dm}{dt}[/tex]

v is the volume flow

C is the concentration

[tex]C=\frac{m}{V+(6-3)*L/min*t}[/tex]

[tex]-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}[/tex]

[tex]-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}[/tex]

[tex]-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}[/tex]

[tex]-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}[/tex]

[tex]-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)[/tex]

[tex]-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)[/tex]

[tex]m=90kg*[2000L/(2000L+3*L/min*t)][/tex]

a) Initially: t=0

[tex]m=90kg*[2000L/(2000L+3*L/min*0)]=90kg[/tex]

b) t=210 min (3.5 hr)

[tex]m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg[/tex]

c) If time trends to infinity the  division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

To find the amount of salt initially in the tank, divide the amount of salt by the initial volume of water and multiply by the initial volume of water. After 3.5 hours, find the new amount of salt by subtracting the salt loss and adding the salt gain. As time approaches infinity, the concentration of salt in the tank will approach 0 kg/L.

(a) To find the amount of salt initially in the tank, we use the formula: amount of salt = initial concentration of salt * initial volume of water. The initial concentration of salt can be found by dividing the amount of salt (90 kg) by the initial volume of water (2000 L). So, the initial concentration of salt is 90 kg / 2000 L = 0.045 kg/L. Now, we can find the amount of salt initially in the tank by multiplying the initial concentration of salt by the initial volume of water: 0.045 kg/L * 2000 L = 90 kg.

(b) After 3.5 hours, the amount of salt in the tank can be found using the formula: new amount of salt = initial amount of salt - salt loss + salt gain. The salt loss can be found by multiplying the drain rate (3 L/min) by the time (3.5 hours) and the initial concentration of salt (0.045 kg/L). The salt gain can be found by multiplying the incoming water rate (6 L/min) by the time (3.5 hours) and the concentration of salt in the incoming water, which is 0 kg/L. So, the new amount of salt = 90 kg - (3 L/min * 3.5 hours * 0.045 kg/L) + (6 L/min * 3.5 hours * 0 kg/L). Solve the equation to find the new amount of salt after 3.5 hours.

(c) As time approaches infinity, the concentration of salt in the solution in the tank will approach the concentration of the incoming water (0 kg/L), since the incoming water has no salt. Therefore, the concentration of salt in the tank as time approaches infinity is 0 kg/L.

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Answer: The value of [tex]x_1,x_2,x3\text{ and }x_4[/tex] are 2, 3, 12 and 6 respectively.

Explanation:

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.  

A balanced chemical equation always follow this law.

For the given chemical reaction, the balanced equation follows:

[tex]2C_6H_6+3O_2\rightarrow 12C+6H_2O[/tex]

By Stoichiometry of the reaction:

2 moles of benzene reacts with 3 mole of oxygen gas to produce 12 moles of carbon and 6 moles of water

From the above reaction:

[tex]x_1=2\\x_2=3\\x_3=12\\x_4=6[/tex]

Hence, the value of [tex]x_1,x_2,x3\text{ and }x_4[/tex] are 2, 3, 12 and 6 respectively.

The balanced equation for the complete combustion of benzene is 2C6H6 + 15O2 → 12CO2 + 6H2O, which means x1=2, x2=15, x3=12, and x4=6.

The complete combustion of benzene (C6H6) forms carbon dioxide (CO2) and water (H2O). To balance the chemical equation for this reaction, each atom on the reactant side must be equal to the total number of the same atom on the product side. The chemical equation for the combustion of benzene is:

2C6H6 + 15O2 → 12CO2 + 6H2O

Here, x1 is 2, x2 is 15, x3 is 12, and x4 is 6. Hence, the balanced chemical equation is 2 moles of benzene reacting with 15 moles of oxygen to produce 12 moles of carbon and 6 moles of water.

Answer:

The particles are spread evenly throughout the dispersion medium, which can be a solid, liquid, or gas. Because the dispersed particles of a colloid are not as large as those of a suspension, they do not settle out upon standing

Explanation:

My teacher asked us this question We had to answer it.

pls thank me

Final answer:

Colloidal particles remain suspended in a dispersion medium due to their small size that allows Brownian motion to keep them from settling, and the Tyndall effect distinguishes them by scattered light. Particles in a suspension settle out due to their larger size.

Explanation:

The reason why particles in a colloid stay suspended in a liquid, as opposed to particles in a suspension which settle out, is due to the size of the dispersed particles. Particles in a suspension are larger and will settle upon standing, but colloidal particles are small enough that Brownian motion counteracts the effects of gravity, maintaining the particles in suspension. Additionally, colloidal particles may be either hydrophilic, with an affinity for water, which prevents them from aggregating, or hydrophobic, in which case they are often stabilized by surfactants to remain dispersed.

Another key feature of colloids is the Tyndall effect, where light is scattered by the particles in the colloid. This effect can make colloidal mixtures appear cloudy or opaque, which differentiates them from true solutions, where such scattering does not occur because the dissolved species are at the molecular or ionic level and too small to scatter light.

Answer: Epinephrine (adrenaline) and Norepineprine (noradrenaline) are hormones released during the fight-or-flight response of the sympathetic division of the autonomic nervous system.

The major physiologic triggers of epinephrine and norepinephrine release are stresses, such as physical threat, excitement, noise, bright lights, and high or low ambient temperature.

Explanation:

The nervous system can be divided into two functional parts: the somatic nervous system and the autonomic nervous system. The somatic nervous system causes contraction of skeletal muscles (voluntary actions). The autonomic nervous system controls cardiac and smooth muscle, as well as glandular tissue (involuntary actions). The autonomic nervous system regulates many of the internal organs through a balance of two aspects, or divisions. The two divisions of the autonomic nervous system are the sympathetic division and the parasympathetic division.

Adrenaline/epinephrine is released in response to the activation of the sympathetic nervous system. It increases heart rate and heart contractility, constricts blood vessels, is a bronchodilator that dilates the bronchi of the lungs to increase air volume in the lungs, and stimulates gluconeogenesis.

The general function of norepinephrine is to mobilize the brain and body for action. Norepinephrine release is lowest during sleep, rises during wakefulness, and reaches much higher levels during situations of stress or danger (fight-or-flight response).

Answer:

Option 3 is the true one

Explanation:

1 mole of carbon atoms contains a mass of 12 g. So If you have 6 moles, you have six times the number of particles that are in 12 grams of carbon-12.

1 mol of anything occupies 6.02x10²³ particles (NA)

Answer : The correct option is, You have six times the number of particles that are in 12 grams of carbon-12.

Explanation :

As we are given that the number of moles of substance is, 6 moles.

First we have to calculate the moles of carbon-12.

[tex]\text{Moles of carbon}=\frac{\text{Mass of carbon}}{\text{Molar mass of carbon}}[/tex]

Mass of carbon = 12 g

Molar mass of carbon = 12 g/mol

[tex]\text{Moles of carbon}=\frac{12g}{12g/mol}=1mol[/tex]

Now we have to calculate the number of particles in 12 g of carbon-12.

1 mole of carbon-12 contains [tex]6.022\times 10^{23}[/tex] number of particles.

Now we have to calculate the number of particles in 6 mole of substance.

As, 1 mole of substance contains [tex]6.022\times 10^{23}[/tex] number of particles.

So, 6 mole of substance contains [tex]6\times 6.022\times 10^{23}[/tex] number of particles.

From this we conclude that, we have six times the number of particles that are in 12 grams of carbon-12.

Hence, the correct option is, You have six times the number of particles that are in 12 grams of carbon-12.

Answer : The resulting concentration of [tex]Na^+[/tex] ion is, 4.5 M

Explanation : Given,

Concentration of [tex]Na_2CO_3[/tex] = [tex]M_1[/tex] = 3.0 M = 3.0 mol/L

Volume of [tex]Na_2CO_3[/tex] = [tex]V_1[/tex] = 70 mL = 0.07 L

Concentration of [tex]NaHCO_3[/tex] = [tex]M_2[/tex] = 1.0 M = 1.0 mol/L

Volume of [tex]NaHCO_3[/tex] = [tex]V_2[/tex] = 30 mL = 0.03 L

First we have to calculate the moles of [tex]Na_2CO_3[/tex] and [tex]NaHCO_3[/tex]

[tex]\text{Moles of }Na_2CO_3=\text{Concentration of }Na_2CO_3\times \text{Volume of }Na_2CO_3=3.0mol/L\times 0.07L=0.21mol[/tex]

and,

[tex]\text{Moles of }NaHCO_3=\text{Concentration of }NaHCO_3\times \text{Volume of }NaHCO_3=1.0mol/L\times 0.03L=0.03mol[/tex]

Now we have to calculate the moles of [tex]Na^+[/tex] ions.

As, 1 mole of [tex]Na_2CO_3[/tex] will give 2 moles of [tex]Na^+[/tex] ions

So, 0.21 moles of [tex]Na_2CO_3[/tex] will give [tex]2\times 0.21=0.42[/tex] moles of [tex]Na^+[/tex] ions

and,

As, 1 mole of [tex]NaHCO_3[/tex] will give 1 mole of [tex]Na^+[/tex] ions

So, 0.03 moles of [tex]NaHCO_3[/tex] will give 0.03 moles of [tex]Na^+[/tex] ions

So,

Total number of moles of [tex]Na^+[/tex] ions = 0.42 + 0.03 =0.45 mole

Total volume of both solution = 70 mL + 30 mL = 100 mL = 0.1 L

Now we have to calculate the concentration of [tex]Na^+[/tex] ions.

[tex]\text{Concentration of }Na^+=\frac{\text{Moles of }Na^+}{\text{Volume of solution}}=\frac{0.45mol}{0.1L}=4.5mol/L=4.5M[/tex]

Therefore, the resulting concentration of [tex]Na^+[/tex] ion is, 4.5 M

To find the resulting concentration of Na+, calculate the moles of Na+ ions in each compound and then add them together. Finally, divide the total moles of Na+ ions by the total volume of the solution to find the concentration of Na+.

To find the resulting concentration of Na+, we need to calculate the total amount of Na+ ions present in the solution after the reaction occurs. We can do this by calculating the moles of Na+ ions in each compound and then adding them together.

First, calculate the moles of Na2CO3:

3.0 M Na2CO3 * 0.070 L = 0.210 mol Na2CO3

Next, calculate the moles of NaHCO3:

1.0 M NaHCO3 * 0.030 L = 0.030 mol NaHCO3

Now, add the moles of Na+ ions:

0.210 mol Na2CO3 + 0.030 mol NaHCO3 = 0.240 mol Na+

Finally, calculate the resulting concentration of Na+:

0.240 mol Na+ / (0.070 L + 0.030 L) = 2.0 M concentration of Na+

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The new volume of the gas is 0.109 L.

To find the new volume of the gas, we can use the combined gas law formula:

P1V1/T1 = P2V2/T2

Where P1 is the initial pressure, V1 is the initial volume, T1 is the initial temperature, P2 is the final pressure, V2 is the final volume, and T2 is the final temperature.

In this case, we are given:

P1 = 1.0 atm, V1 = 100.0 mL = 0.100 L, T1 = 25.0 ℃ = 298 K

P2 = 1.0 atm (since the pressure remains the same), T2 = 50.0 ℃ = 323 K

Substituting the values into the formula, we can solve for V2:

(1.0 atm)(0.100 L) / (298 K) = (1.0 atm)(V2) / (323 K)

Cross-multiplying and solving for V2, we find:

V2 = (1.0 atm)(0.100 L)(323 K) / (298 K) = 0.109 L

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Answer:

Partial pressure O₂  = 1.78 atm

Explanation:

We can apply the mole fraction to solve the question:

Moles of gas / Total moles = Partial pressure of gas / Total pressure

Total moles = 1 H₂ + 2.5 He + 2O₂ = 4.5 moles

2 mol O₂ / 4.5 mol = Partial pressure O₂ / 4 atm

(2 mol O₂ / 4.5 mol ) . 4 atm = Partial pressure O₂  → 1.78 atm

Answer:

The partial pressure of oxygen is 1.45 atm

Explanation:

Step 1: Data given

Number of moles of hydrogen = 1 mol

Number of moles of helium = 2.5 mol

Number of moles of oxygen = 2 mol

Total pressure = 4 atm

Step 2: Calcualte total number of moles

Total number of moles = number of moles of hydrogen + number of moles of helium + number of moles of oxygen = 1 + 2.5 + 2 = 5.5 mol

Step 3: Calculate mol fraction of oxygen

Mol fraction oxygen = 2 mol / 5.5 mol = 0.3636

Step 4: Calculate partial pressure of oxygen

Partial pressure of oxygen = mol fraction of oxygen * total pressure

Partial pressure of oxygen = 0.3636 * 4 atm = 1.45 atm

The partial pressure of oxygen is 1.45 atm

Answer:

False. The balance equation for the redox reaction is:

2Fe  + 3CuSO₄ → 3Cu + Fe₂(SO₄)₃

Explanation:

Let's think the half reactions:

Fe → Fe³⁺  +  3e⁻

The Fe increase the oxidation state. This is the oxidation, where Fe changes from 0 to +3

Cu²⁺  + 2e⁻ → Cu

This is the reduction. Cu changes from 2+ to 0

We multiply the half reaction x2 and x3 to balance the electrons

2Fe → 2Fe³⁺  +  6e⁻

3Cu²⁺  + 3e⁻ → 3Cu

And we sum both

2Fe  + 3Cu²⁺  + 6e⁻ → 3Cu + 2Fe³⁺  +  6e⁻

The electrons are cancelled, so the balance reaction is:

2Fe  + 3CuSO₄ → 3Cu + Fe₂(SO₄)₃

The given equation is not balanced for a redox reaction. The statement is false.

Balanced the reaction:

Fe + CuSO₄ → Cu + Fe₂(SO₄)₃

A redox reaction, also known as an oxidation-reduction reaction, is a type of chemical reaction that involves the transfer of electrons between species.

In a redox reaction, one species undergoes oxidation (loses electrons) while another species undergoes reduction (gains electrons).

The oxidation states of the elements involved are:

Fe: 0 → +3

Cu: +2 → 0

S: +6 → +6

O: -2 → -2

Balance the equation by assigning coefficients to the compounds:

Fe + 3CuSO₄ → 3Cu + Fe₂(SO₄)₃

The balanced equation shows the conservation of mass and charge on both sides of the reaction.

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Answer: 75g of Carbon and 25g of Hydrogen

Explanation: the ratio of carbon to hydrogen is 12:4

Total ratio = 16

Mass of carbon in the natural gas

= (12/16) x 100 = 75g

Mass of Hydrogen in the natural gas = (4/16) x 100 = 25g

Answer:

η = 0.5686

Explanation:

Isentropic compressor efficiency (η):

* η = Isentropic compressor work / real compressor work = Ws / Wreal

∴ Wreal = 76 KW = 76 KJ/s

first law:

∴ Q = 0 ....adiabatic compressor

∴ ΔU = CvΔT

∴ W = - PδV

⇒ ΔU = W ,,,,,isentropic process adiabatic

⇒ CvΔT = - PδV

ideal gas:

⇒ (R + Cv / R) Ln(T2/T1) = Ln (P2/P1)

∴ Cv = 3/2 R....monoatomic ideal gas

∴ R = 8.314 E-3 KJ/K.mol

∴ P1 = 90 KPa

∴ P2 = 800 KPa

∴ T1 = 25 °C ≅ 298 K

∴ r He = 2 Kg/min

⇒ (5/2) Ln(T2/T1) = Ln(800/90) = 2.185

⇒ Ln (T2/T1) = 0.874

⇒ T2/T1 = e∧0.874 = 2.3963

⇒ T2 = (2.3963)(298 K) = 714.094 K

⇒ Ws = CvΔT = (3/2 R)(714.094 - 298 ) = 5.1891 KJ/mol

∴ Mw He = 4.0026 g/mol

⇒ Ws = ( 5.1891 KJ/mol)(mol / 4.0026 g)(1000 g/Kg)(2Kg/min)(min/60s)

⇒ Ws = 43.2144 KJ/s

⇒ η = 43.2144 KJ/s / 76 KJ/s = 0.5686

Answer:

Number of moles of LiF produced by F₂ are less so it will limiting reactant.

Explanation:

Given data:

Mass of lithium = 1.1 g

Mass of F₂ = 1.8 g

Limiting reactant = ?

Solution:

Chemical equation:

2Li + F₂ → 2LiF

Number of moles of Li:

Number of moles = mass/ molar mass

Number of moles = 1.1 g / 6.94 g/mol

Number of moles = 0.2 mol

Number of moles of F₂:

Number of moles = mass/ molar mass

Number of moles = 1.8 g / 38 g/mol

Number of moles = 0.05 mol

Now we will compare the moles of Li and F₂ with LiF.

                      Li                :               LiF

                       2                :                 2

                     0.2               :               0.2

                      F₂                :              LiF

                       1                  :               2

                      0.05             :           2×0.05 = 0.1 mol

Number of moles of LiF produced by F₂ are less so it will limiting reactant.

Answer : The reagent present in excess and remains unreacted is, [tex]O_2[/tex]

Solution : Given,

Moles of [tex]FeCl_3[/tex] = 3.00 mole

Moles of [tex]O_2[/tex] = 2.00 mole

Excess reagent : It is defined as the reactants not completely used up in the reaction.

Limiting reagent : It is defined as the reactants completely used up in the reaction.

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

[tex]2FeCl_3(s)+O_2(g)\rightarrow 2FeO(s)+3Cl_2(g)[/tex]

From the balanced reaction we conclude that

As, 2 moles of [tex]FeCl_3[/tex] react with 1 mole of [tex]O_2[/tex]

So, 3.00 moles of [tex]FeCl_3[/tex] react with [tex]\frac{3.00}{2}=1.5[/tex] moles of [tex]O_2[/tex]

From this we conclude that, [tex]O_2[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]FeCl_3[/tex] is a limiting reagent and it limits the formation of product.

Hence, the reagent present in excess and remains unreacted is, [tex]O_2[/tex]

The price of the bond if the interest rate falls to 8 percent is mathematically given as Dp=12.29%

Question Parameter(s):

The duration of a ten-year, 10 percent coupon bond when the interest rate is 10 percent is 6.76 years.

Generally, the equation for the  Price change is mathematically given as

Dp=Duration*change in interest/initial interest rate

Thereofore

Dp=-6.76*(-0.18)/1.1

Dp=12.29

In conclusion,the price of the bond

Dp=12.29%

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The price of a bond is inversely proportional to the interest rate. If the interest rate decreases, the price of the bond increases. In this case, a drop in interest rates from 10 percent to 8 percent will cause the price of the bond to rise above its face value.

The price of a bond is inversely proportional to the interest rate. This means that if the interest rate falls, the price of the bond increases. The reason is that the fixed payments from the bond become more attractive compared to other investments with the now lower interest rate. Assuming that our bond does not have any features that would otherwise impact its valuation, and that it makes annual payments, a drop in interest rates from 10 percent to 8 percent would cause the price of the bond to rise above its face value. The exact amount would depend on the specific financial calculations involved in bond pricing.

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Answer:

Scopolamine.

Explanation:

Scopolamine is also known as hyoscine. It is an anticholinergic, oral topical drug which is used to manage, and prevent motion sickness, and acute treatment. It is must be taken to be effective before the onset of motion sickness.

The scopolamine is helps to prevent communication between the vomiting center which is present in the brain, and the nerve of the vestibule by blocking the action of acetylcholine (it is a chemical which nervous used to transmit massage to each other).

Explanation:

In liquids, the molecules are held by less strong intermolecular forces of attraction as compared to solids. Due to which they are able to slide past each other. Hence, they have medium kinetic energy.

In gases, the molecules are held by weak Vander waal forces. Hence, they have high kinetic energy due to which they move rapidly from one place to another leading to more number of collisions.

So, when at 298 K and 1 atm [tex]Br_{2}[/tex] exists in liquid state and [tex]Cl_{2}[/tex] exists as a gas then it means there occurs strong force of attraction between the molecules of [tex]Br_{2}[/tex] due to which it exists in liquid form.

Thus, we can conclude that at 298 K and 1 atm, bromine is a liquid with a high vapor pressure, whereas chlorine is a gas. This provides evidence that, under these conditions, the forces among [tex]Br_2[/tex] molecules are greater than those among [tex]Cl_2[/tex] molecules.

The statement that at 298K and 1 atm, bromine is a liquid with a high vapor pressure, whereas chlorine is a gas provides evidence that forces among Br2 molecules are greater than those among Cl2 molecules.

FORCE OF ATTRACTION:

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The correct answer is (B) average molecular speed.

The correct answer is (B) average molecular speed.

According to the kinetic molecular theory, the average kinetic energy of gas molecules is directly proportional to their temperature. Since the temperature is the same for both the H2 and O2 gases, they will have the same average kinetic energy. However, the average molecular speed is inversely proportional to the square root of the molar mass. Since H2 has a lower molar mass than O2, it will have a higher average molecular speed.

The correct answer is a. average molecular kinetic energy.

At standard temperature and pressure (STP), all ideal gases have the same average molecular kinetic energy regardless of their molar mass or any other properties. This is a consequence of the kinetic molecular theory of gases, which states that the average kinetic energy of gas particles is directly proportional to the temperature of the gas in Kelvin. Since both samples are at the same temperature, they have the same average molecular kinetic energy.

 To understand why the other options are incorrect, let's consider each one:

 b. average molecular speed: According to the kinetic molecular theory, the average molecular speed of a gas is inversely proportional to the square root of its molar mass. Since hydrogen (H2) has a molar mass of approximately 2 g/mol and oxygen (O2) has a molar mass of approximately 32 g/mol, the average molecular speed of H2 will be greater than that of O2 at the same temperature.

 c. volume: According to Avogadro's law, equal volumes of gases at the same temperature and pressure contain the same number of moles. Therefore, a 0.50 mol sample of H2 gas will occupy twice the volume of a 1.0 mol sample of O2 gas at STP.

 d. effusion rate: The rate of effusion of a gas is inversely proportional to the square root of its molar mass (Graham's law). Since H2 has a lower molar mass than O2, H2 will effuse more quickly than O2.

 e. density: The density of a gas is directly proportional to its molar mass. Since O2 has a higher molar mass than H2, a 1.0 mol sample of O2 gas will have a higher density than a 0.50 mol sample of H2 gas at STP.

Therefore, the only property that is the same for both gas samples at STP is their average molecular kinetic energy.

Answer:

High concentration of glutathione should be included in the elution buffer for the given experiment to remove protein from the column.

Explanation:

Affinity chromatography is one of important biochemical technique of chromatography which depends on the affinity of ligand for the receptor.Here the ligand is a protein mixture which act as mobile phase and the receptor is present in the wall of chromatography column act as stationary phase.When the protein mixture is applied on the top of the column the substances present within the protein that have high affinity for the receptor present in the walls of chromatography column binds to the later but rest of the protein pass away through the column.High concentration of ligand is used within an buffer solution to remove the desired protein from the column.

    From this point of view it can be stated that in the given question high concentration of glutathione should be used to remove the desired protein from the column.

Answer: Ethanol

Explanation: When we consume alcohol (ethanol), the ethanol has a wide range of effects on the body and it also metabolize in the liver producing acetaldehyde which is believed to be a main cause of hangover

Congeners, which are toxic chemical by-products formed during the production of alcohol, contribute to hangover symptoms. High levels of congeners can exacerbate the depressant effects of alcohol and lead to severe hangover symptoms.

The compounds in alcohol that contribute to hangover symptoms are called congeners. These are toxic chemical by-products that are formed in small amounts when alcohol, specifically ethanol, is produced. Drinks with high quantities of congeners, such as red wine, whiskey, and tequila, are associated with more severe hangover symptoms. Congeners are thought to exacerbate the effects of the more commonly known depressant effects of alcohol, leading to symptoms such as fatigue, headache, nausea, and dizziness.

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Answer:C. Penicious anaemia

Explanation: Penicious anaemia is a disease caused by the bodies inability to make enough vitamin B-12 required to produce healthy red blood cells,it is a very rear disease with a 0.1% prevalence in the population,it has a higher of approximately 2% prevalence among the older members of the population especially those above 60years old according to a 2012 medicine study.

The symptoms of this disease include weight loss, memory loss,loss of appetite,heart burn etc

It can be treated with vitamin B-12 drugs or injections,it can be prevented by taking enough foods like Meats, shellfish,eggs, poultry products and vitamin B-12 supplements.

Answer:

The percent yield for this reaction was 45.98 %

Explanation:

Let's take a look to the reaction:

CH₄(g)  + 2H₂S (g) → CS₂ (g)  +  4H₂ (g)

We can not apply the limiting reactant's concept, as we don't have any information of H₂S. So let's work only with methane.

To know the moles we must do mass / molar mass

32 g / 16 g/m = 2 moles

Ratio is 1:1, so 2 moles of methane produce 2 moles of disulfide.

Molar mass of CS₂ = 76.12 g/m

Moles . molar mass = 2 m . 76.12 g/m = 152.24 g

This are the moles of gas, with the 100 % yield reaction, we only made 70 g so let's find out the yield percent, by a rule of three.

152.24 g ____ 100 %

70 g _____ (70 . 100) / 45.98 %

The percent yield for the reaction was 46.07%.

The question involves a chemical reaction where methane reacts with hydrogen sulfide to produce carbon disulfide and hydrogen gas. To calculate the percent yield, we first need to determine the theoretical yield of carbon disulfide from the given mass of methane. Using molar mass and stoichiometry from the balanced chemical equation, we find the mass of carbon disulfide that should be produced theoretically. The percent yield is then calculated by dividing the actual yield (in this case, 70.0 g of carbon disulfide) by the theoretical yield and multiplying by 100.

First, calculate moles of methane using its molar mass (16.04 g/mol), which equals 32.0 g / 16.04 g/mol = 1.995 moles. According to the chemical equation, one mole of methane produces one mole of carbon disulfide. Therefore, the theoretical yield of carbon disulfide would also be 1.995 moles. The molar mass of carbon disulfide (CS₂) is 76.14 g/mol. Thus, the theoretical yield in grams is 1.995 moles × 76.14 g/mol = 151.91 g.

To find the percent yield, divide the actual yield (70.0 g) by the theoretical yield (151.91 g) and multiply by 100. This gives a percent yield of (70.0 g / 151.91 g) × 100 = 46.07%.

Answer:

c) 35 fl oz

Explanation:

Hello,

In this case, to compute the recommended amount of calcium that the teenager must drink, one performs the following relationship:

[tex]8.0-fl \ oz -->298mg\\x-->1,300mg[/tex]

Solving for [tex]x[/tex], one gets:

[tex]x=\frac{8.0-fl \ oz *1,300mg}{298mg} \\x=35-fl \ oz[/tex]

Best regards.

Final answer:

To meet the calcium RDA of 1,300 mg, a teenager would need to drink approximately 34.9 fl oz of reduced-fat milk, which is closest to 35 fl oz (answer option c). This calculation involves dividing the RDA by the amount of calcium per 8 fl oz of milk and multiplying the result by 8.

Explanation:

The question involves calculating the quantity of milk required for a teenager to meet their recommended dietary allowance (RDA) of calcium. An 8.0 fl oz glass of reduced-fat milk contains 298 mg of calcium. To determine how many fluid ounces of milk are needed to get the entire recommended amount of calcium, one would divide the RDA of calcium for teenagers, which is 1,300 mg, by the amount of calcium in one glass of milk.

Here is the calculation: 1,300 mg (RDA for calcium) ÷ 298 mg (calcium per glass of milk) = 4.3624161.

Since we cannot have a fraction of a fluid ounce if we are considering actual glasses to be consumed, we round up to the nearest whole number, which would suggest a teenager needs to drink at least 5 glasses of milk. However, in terms of exact fluid ounces needed, it would be 4.3624161 × 8 fl oz = 34.9 fl oz, which is closest to answer option c)