An action-reaction pair shows the direct relationship two objects have directly on each other. Therefore, the correct answer is C. The Moons gravity pulls on you, and your gravity pulls on the Moon because it is moon gravity-person person gravity-moon.
Choice A would be made correct if it was you pull on a drawer and the drawer pushes on you OR the table pushes on the ground and the ground pushes on the table.
Choice B would be made correct if it was a computer sits on a table and the table pushes up on the computer.
Choice D would be made correct if it was an eraser sits on a shelf and the shelf pushes up on the eraser OR the wall pushes on the shelf and the shelf pushes against the wall.
Hope this helps!!
A person drives an automobile with a mass of 450 kilograms at a velocity of 26 meters per second. The driver accelerates to a velocity of 30 meters per second. The difference in the automobile’s kinetic energy between the two velocities is joules. You may use the calculator.
To answer the question, we shall determine the kinetic energy of the automobile in each case. This can be obtained as illustrated below:
Case 1:Mass (m) = 450 Kg
Velocity (v₁) = 26 m/s
Kinetic energy (KE₁) =?KE₁ = ½mv₁²
KE₁ = ½ × 450 × 26²
KE₁ = 225 × 676
KE₁ = 152100 JCase 2:Mass (m) = 450 Kg
Velocity (v₂) = 30 m/s
Kinetic energy (KE₂) =?KE₂ = ½mv₂²
KE₂ = ½ × 450 × 30²
KE₂ = 225 × 900
KE₂ = 202500 JFinally, we shall determine the difference in the kinetic energy of the automobile. This can be obtained as illustrated below:
Kinetic energy of case 1 (KE₁) = 152100 J
Kinetic energy of case 2 (KE₂) = 202500 J
Difference =?Difference = KE₂ – KE₁
Difference = 202500 – 152100
Difference = 50400 JTherefore, the difference in the kinetic energy of the automobile is 50400 J
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The difference in the automobile's kinetic energy between the two velocities is -12.15 kJ.
Explanation:The kinetic energy of an object is given by the formula KE = 1/2mv², where m is the mass of the object and v is its velocity. To find the difference in kinetic energy between two velocities, we can subtract the initial kinetic energy from the final kinetic energy. Given that the initial mass of the automobile is 450 kg and its initial velocity is 26 m/s, and the final velocity is 30 m/s, we can calculate the initial and final kinetic energies using the formula.
Initial kinetic energy = 1/2(450 kg)(26 m/s)² = 1/2(450 kg)(676 m²/s²) = 72900 J or 72.9 kJ.
Final kinetic energy = 1/2(450 kg)(30 m/s)² = 1/2(450 kg)(900 m²/s²) = 60750 J or 60.75 kJ.
Difference in kinetic energy = Final kinetic energy - Initial kinetic energy = 60750 J - 72900 J = -12150 J or -12.15 kJ.
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what are winter flowers
Flowers that bloom during the winter.
Hope this helps and please mark as brainliest!
- JJ
The Flowers Blooming in Winter are: Acashia, Alstromeria, Amaryllis, Carnation, Chrysanthemums, Cyclamen, Evergreens, Gerbera Daisy, Ginger, Helleborus, Holly berry, Lily, Asiatic Lily, Casa Blanca Lily, Narcissus, Orchid, Pansy, Pepperberry, Phlox, Protea, Queen Ann's Lace, Roses, Star of Bethlehem, Statice.
Two boys want to balance a seesaw perfectly. One boy weighs 120 pounds and is sitting four feet from the fulcrum. The other boy weighs 80 pounds. Where should the lighter boy sit to balance the seesaw?
Basically a distance multiplied by a weight that is equal to the distance that is going to be multiplied by the weight. (for the equation we will use X for the distance).
equation: 4 x1 20 = ? x 80
Now step one: 4(120) = X(80)
Or another way is 480 = 80X
480/80 = X
48/8= X
X = 6
I hope this could help! Sorry if it didn't make much sense otherwise!
a force of 10. N toward the right is exerted on a wooden crate initially moving to the right on a horizontal wooden floor. the crate weight 25 N.
1)calculate the magnitude of the force of friction between the crate and the floor.
2)What is the magnitude of the net force acting on the crate?
3)is the crate accelerating? explain.
1) 5 N
The crate is initially moving, so we must calculate the force of kinetic friction, which is given by:
[tex]F_f = \mu_k mg[/tex]
where
[tex]\mu_k=0.2[/tex] is the coefficient of friction between the crate (made of wood) and the floor (made of wood). The coefficient of kinetic friction between wood and wood is about 0.2.
[tex]mg=25 N[/tex] is the weight of the crate
Substituting the numbers into the formula, we find
[tex]F_f=(0.2)(25 N)=5 N[/tex]
2) 5 N
There are two forces acting on the crate along the horizontal direction:
- The force that pushes the crate toward the right, of magnitude [tex]F=10 N[/tex]
- The force of friction, which acts in the opposite direction (so, towards the left), of magnitude [tex]F_f = 5 N[/tex]
Since the two forces are in opposite directions, the net force is given by their difference:
[tex]F_{net}=F-F_f = 10 N-5 N=5 N[/tex]
3) Yes
The crate is accelerating. In fact, according to Second Newton's Law:
[tex]F_{net}=ma[/tex] (1)
where Fnet is the net force on the crate, m is its mass, a is its acceleration. We can immediately see that since Fnet is not zero, the acceleration is also non-zero, so the crate is accelerating.
We can even calculate the magnitude of the acceleration. In fact, the mass of the crate is given by:
[tex]m=\frac{Weight}{g}=\frac{25 N}{9.8 m/s^2}=2.55 kg[/tex]
And by using (1) we find
[tex]a=\frac{F_{net}}{m}=\frac{5 N}{2.55 kg}=1.96 m/s^2[/tex]
Exact calculations for solving this physics problem are hindered by a lack of information on the coefficient of friction, but it can be asserted that the net force acting on the crate is 10N, and the crate should be accelerating due to this net force.
Explanation:In this scenario we're dealing with the concepts of force, friction, and acceleration from the field of physics. Let's go step by step.
1) The frictional force equals the weight of the crate times the coefficient of friction. But since we are not given the coefficient of friction, we cannot calculate it. However, to calculate it, you would use the following formula: Force of Friction = µ * Weight
2) The net force is simply the sum of all forces. Here, there's only one force acting on the crate in horizontal direction - the force of 10N to the right. Therefore, the Net Force = 10 N.
3) If there's a net force acting on an object, it means the object is accelerating, as per Newton's Second Law of Motion(F=ma). This suggests that the crate is indeed accelerating.
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A 100-watt light bulb illuminates a solar cell. The electricity from the solar cell operates a water pump that delivers 1 watt of power. What is the efficiency of the system?
Answer:
1 %
Explanation:
The efficiency of a system is defined as the ratio between the energy produced and the energy in input:
[tex]\eta = \frac{E_{out}}{E_{in}}\cdot 100[/tex]
The same formula can also be rewritten in terms of the power produced and the power in input:
[tex]\eta = \frac{P_{out}}{P_{in}}\cdot 100[/tex]
Since in this problem we have:
[tex]P_{in}=100 W\\P_{out}=1 W[/tex]
The efficiency is
[tex]\eta = \frac{1 W}{100 W}\cdot 100[/tex]=1 \%
Final answer:
The efficiency of the system where a 100-watt light bulb illuminates a solar cell, which powers a water pump with a 1 watt output, is 1%.
Explanation:
The efficiency of the system is calculated by comparing the output power to the input power. In this case, if a 100-watt light bulb illuminates a solar cell and the electricity from the solar cell operates a water pump that delivers 1 watt of power, the efficiency (η) of the system can be found using the formula: η = (output power / input power) × 100%. Therefore, the efficiency of this system is (η = (1 W / 100 W) × 100%) which equals 1% efficiency. This is a simple calculation that demonstrates a common issue with energy conversion systems, where a lot of energy is often lost in the process of converting one form of energy to another, resulting in low conversion efficiency.
After brushing, Fluffy's fur has a charge of 8.0 x 10^-9 coulombs and her plastic brush has charge of -1.4× 10^-8 coulombs. If the distance between the fur and brush is roughly 5.0 × 10^-1 meters, what is the approximate magnitude of the force between them?
Given data:
charge 1 (q₁) = 8.0 × 10⁻⁹ coulombs
charge 2 (q₂) = -1.4 × 10⁻⁸ coulombs
distance between fur and brush (r) = 5.0 × 10⁻¹ m
We know that,
The couloumb's law describes the charge between two particles
Mathematically,
F = k.(q₁ . q₂)/r² ----------------------- (i)
Where F = Force between particles
k = constant, 8.99 × 10⁹ Nm²/C² -------------- (ii)
keep the charge, distance values and value of k in equation (i), to determine the magnitude of force
F = 8.99 × 10⁹ ×{ (8.0 × 10⁻⁹) × ( -1.4 × 10⁻⁸)} / (5.0 × 10⁻¹)²
= -4.02 × 10⁻⁶
The force is negative means "the force is attractive"
The launching velocity of a missile is 20.0 m/s, and it is shot at 53? above the horizontal. What is the vertical component of the velocity at launch?
Answer:
The vertical component of the velocity is about 16 m/s.
Explanation:
The vertical component is the magnitude of the velocity reduced by the sinus of the angle 53 degrees. So
[tex]v_y = |v|\cdot \sin 53^\circ = 20.0 \frac{m}{s}\cdot 0.7986 \approx 16.0 \frac{m}{s}[/tex]
what type of friction occurs when you are trying to move an object, but the object isnt moving?
rolling friction
momentum friction
static friction
sliding friction
the answer is static friction
Answer:
Static friction.
Explanation:
I had this question, it was worded a bit differently. Hope this helped!
the unit of work is what
Work is defined as a force acting on a body in the direction of a displacement. The unit for displacement is the meter, and the unit for a force is the Newton. Therefore, the unit for work is the Newton-meter or joule.
pitbulllover101
Rutherford's famous gold foil experiments shot heavy particles at a thin sheet of gold foil. What did he observe, and why did these observations eventually result in the addition of a nucleus to the atomic model?
Some of the heavy particles bounced off the foil, because there are positive particles spread throughout the atom.
Some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom.
The heavy particles all passed straight through the foil, because the atoms are mostly empty space.
The heavy particles all bounced off the foil, because the subatomic particles have mass and volume.
Some of the heavy particles bounced off the foil, because there are positive particles spread throughout the atom
Answer:
Some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom.
Explanation:
In Rutherford experiment following is the observations made by the Rutherford
1). Major part of the alpha particles will go out undeviated which shows that major portion of the atoms vacant or empty space
2). Few part of the alpha particle moves out with deviation in path which shows that electrons moves in different shells and when alpha particles pass through a given electron then it will show the deviation in path
3). very few alpha particles will get deviated by 180 degree and returns to original path which shows the presence of nucleus. So nucleus is made up of positive charge which is concentrated at very small space
so here correct answer would be
Some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom.
WILL MARK BRAINLIEST!!!!!!!!!!!!!
What was the acceleration during the segment labeled "A"?
4 m/s/s
5 m/s/s
10 m/s/s
20 m/s/s
The acceleration during the segment labeled "A" will be 4 [tex]ms^{2}[/tex].
What is acceleration?The rate at which velocity changes is called acceleration. Acceleration typically indicates a change in speed, but still not necessarily.
What is the formula of acceleration?The formula of acceleration is Δv / Δt.
Where. v is velocity and t is time.
Acceleration can be determined by the the formula :
a = Δv / Δt. = 8 / 2 = 4 [tex]ms^{2}[/tex].
Therefore, the acceleration during the segment labeled "A" will be 4 [tex]ms^{2}[/tex].
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If Angle "a" is 25°, Angle "b" is:
A) equal to Angle c
B) less than Angle c
C) greater than Angle c
Since angles a and c are alternate interior angles formed by a transversal intersecting two parallel lines, they are congruent. Therefore, angle b must also be equal to angle c. So, the correct answer is: A) equal to Angle c
If angles "a," "b," and "c" are part of a triangle, then the sum of the interior angles of a triangle is always 180°. Given that angle "a" is 25°, the sum of angles "b" and "c" must be 180° - 25° = 155°.
With this constraint, we can't determine whether angle "b" is greater than, equal to, or less than angle "c" without additional information about their specific values. If one angle is specified, the other angle can be found using the fact that the sum of angles in a triangle is 180°. For example, if angle "c" is known to be, say, 70°, then angle "b" would be 155° - 70° = 85°.
In summary, the relationship between angle "b" and angle "c" depends on their specific values or additional constraints provided. Without this information, we cannot make a definitive comparison between them. Therefore, the correct answer to the given question would be that we cannot determine the relationship between angle "b" and angle "c" based solely on the measure of angle "a."
please help on this one ?
Describe a real-world example in which the amount of potential and kinetic energy change, but the total amount of mechanical energy stays the same.
n physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.
Final answer:
A pendulum swinging back and forth is an example where the amounts of potential and kinetic energy change, but the total mechanical energy remains constant.
Explanation:
An example of a real-world scenario where the amount of potential and kinetic energy change, but the total amount of mechanical energy stays the same is when a pendulum swings back and forth. As the pendulum swings to its highest point, it has maximum potential energy and minimum kinetic energy. As it swings down, the potential energy decreases and the kinetic energy increases until it reaches its lowest point, where it has maximum kinetic energy and minimum potential energy. However, the total mechanical energy of the pendulum remains constant throughout its motion because there is no significant energy loss due to friction.
Which statement about how light travels is true? A Light waves need a medium to travel, and they travel at the same speed even if the light source is moving. B Light waves can travel in a vacuum and travel at a constant speed even if the light source is moving. C Light waves can travel in a vacuum and will travel faster if the light source is moving forward. D Light waves need a medium to travel, and they travel faster if the light source is moving forward.
Answer:
Light wave can travel in a vacuum and travel at a contest speed even if the light source is moving
Explanation:
Light waves are electromagnetic waves and they need no medium to travel. The speed of light is constant and does not change with the movement of source.
What is electromagnetic waves?Electromagnetic waves are transfer of energy through vacuum. These electromagnetic waves are associated with specific wavelength, frequency and energy.
Visible light is in between IR and UV waves in electromagnetic spectrum. Light is the fastest moving thing in the world and it does need a medium to travel. The waves which need a medium to propagate is called mechanical waves.
Therefore, the true statement about light is light waves can travel in a vacuum and travel at a constant speed even if the light source is moving. Thus, option B is correct.
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Please help me with this! (:
Convert 4.9 m/s to km/h.
A. 18 km/h
B. 49,000 km/h
C. 1.4 km/h
D. 18,000,000 km/h
Answer:
(A) 18 km/h
Explanation:
[tex]4.9\frac{m}{s}=4.9\cdot \frac{\frac{1}{1000}km}{\frac{1}{3600}h}=4.9\cdot3.6\frac{km}{h}=17.64\frac{km}{h}\approx18\frac{km}{h}[/tex]
Select the correct answer.
How does the law of conservation of energy apply to machines?
A.
Machines create energy from scratch.
B.
Machines consume energy until no energy remains.
C.
Energy transferred to a machine equals energy transferred from it.
D.
Engineers break the law of conservation of energy by using machines.
Energy transferred into a machine equals energy transferred out of it (including waste heat generated by friction). (C)
Which direction is the force of friction?
A. The same direction of the movement
B. The opposite direction of the movement
C. 90 degrees from the direction of movement
Friction always acts opposite to the motion. (B)
A railroad train is traveling at 32 m/s in still air. The frequency of the train whistle is 350 Hz. What is the wavelength of the sound and the frequency of the sound heard by the listener in front of the locomotive?
40. 383 Hz, 0.9 m
6. 20.78 m/s
Explanation:40. You know the pitch will be increased when the train is moving toward you. The only answer choice that is greater than 350 Hz is the one shown above.
Using the formula shown in the attachment, we compute the observed frequency to be ...
... f' = (343 m/s)/(343 m/s -32 m/s)×(350 Hz) ≈ 1.102893×350 Hz ≈ 386 Hz
The wavelength is given by ...
... λ = v/f = (343 m/s)/(386 Hz) ≈ 0.8886 m ≈ 0.9 m
_____
Comment on the answer choice
If you erroneously use the frequency modification formula f'=(v+vo)/v·f, then you get 382.7 Hz ≈ 383 Hz. We suspect an error in the answer key. Have your teacher show you how to work this problem.
__________
6. The velocity can be computed from the acceleration and distance covered by ...
... v = √(2ad)
... v = √(2·9.8 m/s²·22 m) = (√431.2) m/s ≈ 20.77 m/s
The closest answer among those offered is 20.78 m/s. Again, you should have your teacher show you how to work this problem to arrive at the offered answer.
One
I putting this up because I have answers. This is another doppler effect problem.
Givens
f = 350 Frequency in Hz of the train whistlev = 343 m/s Speed of soundvs = 32 m/s Train's speed moving towards the observer vo = 0 The observer is standing stillf' = ?? What the observer thinks the frequency isFormula
f' = (v + vo) * f / (v - vs)Solution
f' = (342 + 0)*350/(342 - 32)f' = (342)*350 / 310f' = 386 Hzv= f * wavelength
v = 343 m/s
f = 386 Hz
343 = 386 * wavelength
343 / 386 = wavelength
wavelength = 0.881 m
Answer: 386, 0.9 C
Problem Two
Givens
d = 22 ma = 9.81vi = 0vf = ?Formula
vf^2 = vi^2 + 2*a * dSolution
vf^2 = 2 * 9.81 * 22vf^2 = sqrt(431.64)vf = 20.78Answer: A
Note to get 20.78 they used 9.8 but then there should only be 2 places and the answer (rounded) is 21. Otherwise the answer is 20.77
Which is not one of the three tiny bones in the middle ear?
cochlea
hammer
anvil
stirrup
The average ear (Auris media) is the middle part of the ear and consists of the tympanic membrane, the Eustachio tube and the oval and round windows. In the tympanic cavity are contained the oscillations of the middle ear. Timpan has the role of transforming the sounds collected by the external ear into vibrations, which are sent to the three oscillators (hammer, anvil and stair). In turn, they send the vibrations to the inner ear.
So the cochlea is not part of the average ear
The cochlea is not a bone in the middle ear; the three tiny bones are the malleus (hammer), incus (anvil), and stapes (stirrup), which transmit and amplify vibrations for hearing.
Among the options provided, the cochlea is not one of the three tiny bones in the middle ear. The three bones in the middle ear are known as the malleus (hammer), the incus (anvil), and the stapes (stirrup).
These bones are crucial for hearing as they work to transmit the vibrations from the tympanic membrane to the oval window of the cochlea. The hammer, anvil, and stirrup are the smallest bones in the body and help in amplifying and transferring sound waves into the inner ear.
A 0.28-kg stone you throw rises 34.3 m in the air. The magnitude of the impulse the stone received from your hand while being thrown is
Answer:
7.3 kg m/s
Explanation:
First of all, let's calculate the gravitational potential energy of the stone as it reaches its highest point:
[tex]U=mgh=(0.28 kg)(9.8 m/s^2)(34.3 m)=94.1 J[/tex]
For the law of conservation of energy, this is equal to the initial kinetic energy of the stone at ground level (where the potential energy is zero), just after the stone leaves your hand:
[tex]K=\frac{1}{2}mv^2=94.1 J[/tex]
From this equation we can find the velocity of the stone as it leaves your hand:
[tex]v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(94.1 J)}{0.28 kg}}=25.9 m/s[/tex]
The initial velocity of the stone (before leaving your hand) is zero:
[tex]u=0[/tex]
The impulse received by the stone is equal to its change in momentum, so:
[tex]I=\Delta p=m\Delta v=m(v-u)=(0.28 kg)(25.9 m/s-0)=7.3 kg m/s[/tex]
The magnitude of the impulse the stone received from your hand while being thrown is approximately 17.22 kg*m/s, calculated by considering the conversion of its gravitational potential energy into kinetic energy, and consequently finding the change in momentum.
Explanation:Given the mass of the stone (m = 0.28 kg) and the height to which the stone rises (h = 34.3 m), the impulse can be calculated using the relationship between impulse, momentum, and energy.
Firstly, as we're considering a height and a resultant vertical motion, we can approach this in terms of gravitational potential energy for simplicity. The stone's kinetic energy is converted to gravitational potential energy at the highest point of its trajectory. So, the potential energy at peak is mgh, which is equal to 0.28 kg * 9.8 m/s^2 * 34.3 m = 93.0284 Joules.
Considering that the kinetic energy the stone started with (K=0.5mv^2) is equivalent to this potential energy (as no energy is lost, only converted), we can derive the initial velocity using v= sqrt(2*K/m).
Now, plug the knowns in to solve for velocity: v= sqrt((2*93.0284Joules)/0.28kg), which gets us v≈61.5 m/s. The magnitude of the impulse is given by the change in momentum, which in this case is the stone's momentum as it leaves the hand (because it starts at rest). So finally, the impulse is equal to the product of the mass of the object and the change in its velocity (Impulse = mv): Impulse = 0.28 kg * 61.5 m/s = approximately 17.22 kg*m/s (rounded).
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The light bulb converts electrical energy into light and _________. A) chemical Eliminate B) electromagnetic C) heat D) nuclear
Answer: C) heat
Explanation: As law of conservation of energy applies to all the systems, which says the energy cannot be created nor destroyed, it can only be converted from one form to another.
The light bulb converts electrical energy into light and heat energy.
A) chemical energy is stored in the bonds.
B) Light is a form of electromagnetic radiation.
D) nuclear energy is stored in the nucleus of the atom.
Which of the following types of particles can be categorized into different kind of elements?
A. Protons
B. Atoms
C. Electrons
D. Neutrons
The answer would be atoms
Answer: The correct answer is Atom.
Explanation:
Atom consists of proton, electron, neutron and nucleus. The subatomic particles of the atom are electron, proton and neutron.
The electrons revolve around the nucleus while neutrons and protons are located in nucleus. The whole mass of the atom is supposed to be concentrated at nucleus.
The electron is negatively charged particle. The proton is positively charged particle. The neutron has no charge. It is neutral.
Therefore, the correct option is B.
How far can a mother push a 20.0 kg baby carriage, using a force of 62.0 N at an angle of 30.0º to the horizontal, if she can do 2920 J of work?
Answer:
54.4 m
Explanation:
The work done by the mother in pushing the carriage is equal to:
[tex]W=Fdcos \theta[/tex]
where
F is the force applied
d is the displacement of the carriage
[tex]\theta[/tex] is the angle between the direction of the force and the displacement
In this problem, we have the following data:
[tex]F=62.0 N[/tex] is the force
[tex]W = 2920 J[/tex] is the work done
[tex]\theta=30.0^{\circ}[/tex] is the angle between the direction of the force and the displacement
Re-arranging the equation above and substituting data, we find the displacement:
[tex]d=\frac{W}{F cos \theta}=\frac{2920 J}{(62.0 N)(cos 30^{\circ})}=54.4 m[/tex]
When a force is applied at an angle, we should consider the horizontal component of the force for any horizontal movement. In this case, the mother can push the baby carriage about 54.5 meters by expending 2920 Joules of work.
Explanation:The subject of the problem involves the concept of work and force in physics. When the mother pushes the baby carriage at an angle, not all of the force she applies is used to move the carriage horizontal. We need to consider the horizontal component of the force which is 62.0N*cos(30.0º) = 53.61047 N. Work is defined as force times the distance over which the force is applied, or in this case, the force times the distance the carriage is pushed. The calculation looks like this:
Work = Force x Distance = 2920 J
Distance = Work / Force = 2920 J / 53.61047 N = 54.48013 m
So the mother can push the baby carriage approximately 54.48013 meters with an expenditure of 2920 joules of work.
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what is the net force of this object?
F air=400N
F grav=600N
A) 0 nuetons
B) 200 nuetons
C) 400 nuetons
D) 600 nuetons
B The object is fallint with pressure pushing up, so 600N-200N=400N
The moon has a mass of 7.35 E 22 kg and is located 3.84 E 8 meters from the Earth. If Ellen, an earthling, has a mass of 47 kg, what is the gravitational force between Ellen and the moon? I found the correct answer but I am confused on how I did so, please explain.
Under the law of universal attraction:F=km₁m₂/r²=6.67*10⁻¹¹*7.347*10²²*47/3.844*10⁸=23.0321*10¹³/3.844*10⁸=5.99*10⁵≈6*10⁵ N
It's probably going to be a phase out of the approximations
When using a calorimeter, the initial temperature of a metal is 70.4C. The initial temperature of the water is 23.6C. At the end of the experiment, the final equilibrium temperature of the water is 29.8C.
What is the final temperature of the metal?
C
What is the temperature change of the water?
C
What is the temperature change of the metal?
C
1) 29.8 C
At the beginning, the metal is at higher temperature (70.4 C) while the water is at lower temperature (23.6 C). When they are put in contact, the metal transfers heat to the water, until they reach thermal equilibrium: at thermal equilibrium the two objects (the metal and the water have same temperature). Therefore, since the temperature of the water at thermal equilibrium is 29.8 C, the final temperature of the metal must be the same (29.8 C).
2) 6.2 C
The temperature change of the water is given by the difference between its final temperature and its initial temperature:
[tex]\Delta T = T_f - T_i[/tex]
where
[tex]T_f = 29.8 C\\T_i = 23.6 C[/tex]
Substituting into the formula,
[tex]\Delta T=29.8 C-23.6 C=6.2 C[/tex]
And the positive sign means that the temperature of the water has increased.
3) -40.6 C
The temperature change of the metal is given by the difference between its final temperature and its initial temperature:
[tex]\Delta T = T_f - T_i[/tex]
where
[tex]T_f = 29.8 C\\T_i = 70.4 C[/tex]
Substituting into the formula,
[tex]\Delta T=29.8 C-70.4 C=-40.6 C[/tex]
And the negative sign means the temperature of the metal has decreased.
Answer:
29.8, 6.2, -40.6
Explanation:
A rowboat passenger uses an oar to push the boat off the dock by exerting a force of 40N for 3.0s. What impulse acts on the boat.
Answer:
120 Ns
Explanation:
The impulse exerted on an object is given by:
[tex]I=Ft[/tex]
where
F is the force applied
t is the time taken
In this problem, we have:
F = 40 N
t = 3.0 s
So, the impulse acting on the boat is
[tex]I=Ft=(40 N)(3.0 s)=120 Ns[/tex]
Answer:
120kg*m/s
Explanation:
the total amount of force they exert on the box is 500 Newton's . Despite their efforts, the box will not move. What is the amount of force exerted by the box on each person?
Whatever amount of force each person exerts on the box, THAT's the amount of force the box exerts on him. There's no reason the forces of each person have to be equal.
Let's say . . .
-- Mr. Smith pushes on the box with 499.99 newton's of force.
-- Mr. Jones is actually a fly; he pushes on the box with 0.01 newton of force.
The total of their forces is 500 Newtons on the box.
The box exerts 499.99 newtons of force back on Mr. Smith, and 0.01 newton of force back on Mr. Jones, the fly.
The gas used to fill party ballons contain only helium atoms .This make helium a(n).
a gas
hope this is right
the anser on apex is element