Chlorophenols impart unpleasant taste and odor to drinking water at concentrations as low as 5 mg/m3. They are formed when the chlorine dis- infection process is applied to phenol-containing waters. What is the threshold for unpleasant taste and odor in units of (a) mg/L, (b) mg/L, (c) ppmm, and (d) ppbm
Answers
Answer:
See explaination
Explanation:
Chlorine’s disinfection properties have helped improve the lives of billions of people around the world. Chlorine also is an essential chemical building block, used to make many products that contribute to public health and safety, advanced technology, nutrition, security and transportation.
Please kindly check attachment for the step by step solution of the given problem.
The threshold for unpleasant taste and order in the respective units are;
A) 0.005 mg/L
A) 0.005 mg/LB) 5 μg/L
A) 0.005 mg/LB) 5 μg/LC) 0.005 ppm
A) 0.005 mg/LB) 5 μg/LC) 0.005 ppmD) 5 ppb
We are given the concentration of chlorophenols as; M = 5 mg/m³
A) Converting mg/m³ to mg/L means that;
1 mg/m³ = 0.001 mg/L. Thus;
5 mg/m³ = (5 × 0.001)/1
>> 0.005 mg/L
B) Converting mg/m³ to μg/L means that;
1 mg/m³ = 1 μg/L
Thus; 5 mg/m³ = 5 × 1/1 μg/L
>> 5 μg/L
C) Converting mg/m³ to ppm gives;
1 mg/m³ = 0.001 ppm
Thus;
5 mg/m³ = (5 × 0.001)/1 ppm
>> 0.005 ppm
D) Converting mg/m³ to ppb gives;
1 mg/m³ = 1 ppm
Thus;
5 mg/m³ = 5 × 1/1 ppb
>> 5 ppb
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Related Questions
A 3-column table with 4 rows. The first column labeled Scenario has entries A, B, C, D. The second column labeled Object 1 has entries lotion at 26 degrees Celsius, lasagna at 170 degrees Celsius, ocean water at 25 degrees Celsius, eggs at 2 degrees Celsius. The third column labeled Object 2 has entries skin at 37 degrees Celsius, plate at 20 degrees Celsius, lava 950 degrees Celsius, sidewalk at 80 degrees Celsius.
Indicate the direction of heat flow in each scenario.
Scenario A:
Scenario B:
Scenario C:
Scenario D:
Answers
The direction of heat flow in each scenario will be:
Scenario A = toward object 1Scenario B = toward object 2Scenario C = toward object 1Scenario D = toward object 1What is heat transfer?It should be noted that heat transfer means the transfer of heat from a location to another.
It is the process in which the molecules are moved from a region of higher temperature to that of a lower temperature.
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Answer:
It Is Scenario D.
Explanation:
The elementary gas-phase reaction takes place isobarically and isothermally in a PFR where 63.2% conversion is achieved. The feed is pure A. It is proposed to put a CSTR of equal volume upstream of the PFR. Based on the entering molar flow rate to A to the first reactor, what will be the intermediate from the CSTR, X 1 , and exit conversion from the PFR, X 2 , based on the feed to first reactor?
Answers
Answer:
Explanation:
check below for explanation in the attached files.
Which of these statements indicates an experiment is systematic?
A. The experiment is repeated many times.
B. The experiment is about a testable question.
C. The experiment is very complicated and uses lots of chemicals.
D. The experiment includes a good plan for what measurements to take.
Answers
Answer:
D. The experiment includes a good plan for what measurements to take.
Explanation:
A cell is set up with copper and lead electrodes in contact with CuSO4(aq) and Pb(NO3)2(aq), respectively, at 25°C. The standard reduction potentials are Pb2+ + 2e–? Pb E° = –0.13 V Cu2+ + 2e–? Cu E° = +0.34 V
If sulfuric acid is added to the Pb(NO3)2 solution, forming a precipitate of PbSO4, the cell potential
a. It is impossible to tell what will happen.
b. decreases.
c. is unchanged.
d. increases.
Answers
Answer:
increases
Explanation:
Now look at the matter closely. Given the values of electrode potential stated in the question, one can see that lead will function as the anode and copper as the cathode since lead has a more negative electrode potential.
This implies that at the anode, the half reaction going on is this;
Pb(s) -------> Pb^2+(aq) + 2e.
There will be a build up of Pb^2+ in the anode compartment. The addition of H2SO4 and formation of PbSO4 favours the removal of the Pb^2+ ions;
Pb^2+(aq) + SO4^2-(aq) -------> PbSO4(s)
As this continues, Pb^2+ concentration begins to decrease, in order to maintain equilibrium, more Pb^2+ is formed thereby increasing the current and voltage flowing in the cell as more electrons are transferred from anode to cathode(more current flows).
In the case when the sulfuric acid is added to the Pb(NO3)2 solution increases so the cell potential is increased.
Impact on cell potential:Here the anode and copper treated as the cathode because it contains more negative electrode potential. Due to this, it should be half reaction
Pb(s) -------> Pb^2+(aq) + 2e.
Also, there should be the addition of H2SO4 and creation of the PbSO4 that eliminates the Pb^2+ ions.
So,
Pb^2+(aq) + SO4^2-(aq) -------> PbSO4(s)
Here the concentration of Pb^2+ should reduced for maintaining the equilibrium.
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The small bags of silica gel you often see in a new shoe box are placed there to control humidity. Despite its name, silica gel is a solid. It is a chemically inert, highly porous, amorphous form of SiO2. Water vapor readily adsorbs onto the surface of silica gel, so it acts as a desiccant. Despite not knowing mechanistic details of the adsorption of water onto silica gel, from the information provided, you should be able to make an educated guess about the thermodynamic characteristics of the process. Predict the signs of ΔG, ΔH, and ΔS. Predict the sign of ΔG. ΔG = 0 ΔG < 0 ΔG > 0 Predict the sign of ΔH. ΔH < 0 ΔH > 0 ΔH = 0 Predict the sign of ΔS. ΔS > 0 ΔS < 0 ΔS = 0
Answers
Answer:
The sign of \Delta GΔG is negative.
The sign of \Delta HΔH is negative.
The sign of \Delta SΔS is negative.
Explanation:
The water vapor is adsorbed on silica gel due to strong hydrophilicity of silica get towards the water.
The thermodynamic properties of adsorbate and adsorbent changes after adsorption. Silica gel is very porous and hydrophilic, thus, it absorbs the water from the shoe box.
The adsorption process occurs spontaneously, therefore Delta G < 0.
When adsorption occurs, bonds are formed between water molecules and SiO2, and the bond formation process is exothermic (heat is released).
Thus, Delta H < 0.
The water molecules become immobilized on the surface when adsorption occurs, thus, entropy/disorder decreases.
So, Delta S < 0.
1. A cylinder of gas has a pressure of 4.40 atm at 25°C. At what temperature in °C
will it reach a pressure of 6.50 atm? Answer 167°C.
Answers
Answer: The final temperature in °C is 167
Explanation:
To calculate the final temperature of the system, we use the equation given by Gay lussac's Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant volume.
Mathematically,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1\text{ and }T_1[/tex] are the initial pressure and temperature of the gas.
[tex]P_2\text{ and }T_2[/tex] are the final pressure and temperature of the gas.
We are given:
[tex]P_1=4.40atm\\T_1=25^oC=(25+273)K=298K\\P_2=6.50atm\\T_2=?[/tex]
Putting values in above equation, we get:
[tex]\frac{4.40}{298}=\frac{6.50}{T_2}\\\\T_2=440K=(440-273)^0C=167^0C[/tex]
Thus the final temperature in °C is 167
To determine at what temperature a gas cylinder will reach 6.50 atm pressure from 4.40 atm at 25°C, we use Gay-Lussac's Law and find that the temperature is 167°C.
We can solve this problem using Gay-Lussac's Law, which states that for a given mass and constant volume of an ideal gas, the pressure is directly proportional to its temperature.
The formula for Gay-Lussac's Law is:
P1/T1 = P2/T2
Where:
P1 is the initial pressureT1 is the initial temperature in KelvinP2 is the final pressureT2 is the final temperature in KelvinFirst, we need to convert the initial temperature into Kelvin:
T1 (in Kelvin) = 25°C + 273 = 298 K
Now, we rearrange the equation to solve for T2:
T2 = (P2 × T1) / P1
Substitute the known values into the formula:
T2 = (6.50 atm × 298 K) / 4.40 atm
T2 ≈ 440 K
Finally, convert the temperature back to Celsius:
T2 (in °C) = 440 K - 273 = 167°C
Therefore, the temperature at which the gas will reach a pressure of 6.50 atm is 167°C.
A 0.0200 gram piece of unknown alkaline earth metal, M, is reacted with excess 0.500 M H 2 SO 4 , and the hydrogen gas produced is collected over water. The total gas pressure inside the collecting tube is 1.01 atm., the temperature 24.0 o C. The volume of gas collected is 19.6 mL. The gas in the tube contains water vapor, at a pressure of 0.029 atm. M(s) + H 2 SO 4 (aq) → MSO 4 (aq) + H 2 (g). What is the partial pressure of the dry hydrogen gas collected in the tube?
Answers
Answer:
0.981atm
Explanation:
According ot Dalton's law total pressure of a mixture of non-reactive gas is equal to sum of partial pressures of individual gases.
total pressure= 1.01at
Number of gases=2
Gases: water vapor and hydrogen
partial pressure of water vapor= 0.029atm
1.01= partial pressure of water vapor+ partial pressure of hydrogen
1.01= 0.029 + partial pressure of hydrogen
partial pressure of hydrogen = 0.981atm
What will the concentration of LiOH be if 27ml of a 4.5 M LiOH solution is diluted to 435ml? *
Answers
Answer: 0.28 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
According to the neutralization law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of stock [tex]LiOH[/tex] solution = 4.5 ml
[tex]V_1[/tex] = volume of stock [tex]LiOH[/tex] solution = 27 ml
[tex]M_2[/tex] = molarity of dilute c solution = ?
[tex]V_2[/tex] = volume of dilute [tex]LiOH[/tex] solution = 435 ml
[tex]4.5\times 27=M_2\times 435[/tex]
[tex]M_2=0.28M[/tex]
Thus the concentration of LiOH be if 27 ml of a 4.5 M LiOH solution is diluted to 435 ml is 0.28 M
if you hang a bird feeder, fill it with food but no birds come to it what would the hypothesis be?
Answers
Answer:
You could have many hypothesis...
Explanation:
A hypothesis is a guess as to what is going to happen in a situation. Without knowing the exact question you are developing a hypothesis for I can't give you an exact answer and the hypothesis takes place before the experiment. So you wouldn't know why the birds didn't come.
But if I had to give a bs answer I would say that the conditions weren't ideal for the birds (ie not right location or type of food)
The hypothesis could be that the type of food, the feeder's visibility, or its location is not attracting the birds. You could test this hypothesis by trying to change these variables.
Explanation:If you filled a bird feeder with food and hung it but noticed no birds coming to it, the hypothesis might be that either the birds are not attracted to the type of food in the feeder, they are not aware of the feeder's presence, or the location of the feeder is not suitable or safe for them.
To test this hypothesis, one could try changing the food type, moving the feeder to a different location, or drawing attention to the feeder somehow, then observing if there are changes in bird visitation.
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A balloon at 30.0°C has a volume of 222 mL. If the temperature is
increased to 53.1°C and the pressure remains constant, what will the new volume be, in ml?
Answers
Answer : The new volume will be, 238.9 mL
Explanation :
Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.
Mathematically,
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1\text{ and }T_1[/tex] are the initial volume and temperature of the gas.
[tex]V_2\text{ and }T_2[/tex] are the final volume and temperature of the gas.
We are given:
[tex]V_1=222mL\\T_1=30.0^oC=(30.0+273)K=303K\\V_2=?\\T_2=53.1^oC=(53.1+273)K=326.1K[/tex]
Putting values in above equation, we get:
[tex]\frac{222mL}{303K}=\frac{V_2}{326.1K}\\\\V_2=238.9mL[/tex]
Therefore, the new volume will be, 238.9 mL
The magnesium and calcium ions present in seawater ([Mg2+] = 0.059 M and [Ca2+] = 0.011 M) can be separated by selective precipitation with KOH.
If the concentration of Mg2+ in the solution were 0.039 M, what minimum [OH−] triggers precipitation of the Mg2+ ion? (Ksp=2.06×10−13.)
Answers
Answer:
the minimum [OH−] triggers precipitation = 2.3x10^-6 M
Explanation:
Mg2+ + 2OH- --> Mg(OH)2(s)
Ksp = [Mg2+][OH-]^2
(2.06x10^-13) = (0.039*x^2)
x = [OH-] = 2.3*10^-6 M
the minimum [OH−] triggers precipitation = 2.3x10^-6 M
Final answer:
The minimum [OH-] that triggers the precipitation of Mg2+ ion can be calculated using the Ksp value.
Explanation:
The minimum [OH-] that triggers the precipitation of Mg2+ ion can be calculated using the Ksp value. Given that the concentration of Mg2+ in the solution is 0.039 M, and the Ksp value is 2.06×10⁻¹³, the minimum [OH-] can be determined to initiate precipitation.
Complete the reaction, which is part of the electron transport chain. The abbreviation FMN represents flavin mononucleotide. Use the appropriate abbreviation for the product.
NADH + H^+ + FMN ⟶
The reactant that is reduced is_________ .
In complex III, electrons are transferred from coenzyme Q to cytochrome c, which contains iron.
QH2 + 2cyt c ( Fe3+) ⟶ Q + 2cyt c(Fex) + 2H^+
Determine the oxidation number for iron on the right side of the reaction arrow.
Answers
Answer:
1. NADH + H⁺ + FMN + Q ⟶ NAD⁺ + FMN + QH₂
2. The reactant that is reduced is Q
3. The charge on iron on the right side is +2, Fe²⁺
Explanation:
NADH + H⁺ + FMN + Q ⟶ NAD⁺ + FMN + QH₂
The reaction above is catalysed by NADH:ubiquinone oxidoreductase (complex 1), which transfers a hydride ion from NADH to FMN, from which two electrons pass through a series of of Fe-S centers to the iron-sulfur protein N-2. Electron transfer from N-2 to Ubiquinone forms QH₂
The species in a reaction which gains hydrogen irons is reduced, Therefore, the reactant that is reduced is Q, ubiquinone to form QH₂, ubiquinol.
To determine the oxidation number of iron on the right side of the reaction below,
QH2 + 2cyt c ( Fe3+) ⟶ Q + 2cyt c(Fex) + 2H^+
Sum of charges on the left side = Sum of charges on the right side
Sum of charges on the left side = 2 *+3 = +6
Therefore 2 * x + 2= 6
2x = 6 -2 = 4
x = 4/
x = 2
Therefore the charge on iron on the right side is +2, Fe²⁺
Solve the following problem:
Answers
Answer:
Option 3.
Explanation:
Isomerism is a phenomenon where by two or more compounds have the same molecular formula but different structural patterns.
Geometric Isomerism is a type of Isomerism that occurs within a double bond i.e Geometric isomers have different arrangement within the double bond.
Considering the options given above,
The 1st option is exactly the same as the compound only, it is inverted.
The 2nd option is still the same as the compound, only it is laterally inverted.
The 3rd option satisfy geometric Isomerism as the arrangement differ from the compound in the double bond.
The 4th option is entirely a saturated compound in which geometric Isomerism is not possible.
1. A solution is a mixture. The part of
the solution in the greater amount is
called the
Answers
Answer:
Solvent
Explanation:
Many people use the solute to describe the solid being dissolved and the solvent to describe the thing doing the dissolving, but really solvent means the part of the solution with a greater amount/concentration.
For example, if you have 1 gram of salt in 10 liters of water, the water is the solvent.
Final answer:
A solution is a homogeneous mixture where the component with the largest quantity is known as the solvent, and the substance in the smaller quantity is the solute.
Explanation:
A solution is a homogeneous mixture of two or more pure substances. When we talk about a solution, we refer to its components as the solvent and the solute. The solvent is the part of the solution that is present in the greater amount and acts as the medium in which the other substance, or substances, are dispersed.
The solute, on the other hand, is any component of a solution that is not the solvent. In other words, it is the material present in the smaller amounts within the solution. When a solute is dissolved in a solvent, the resulting mixture is uniform on a microscopic level, ensuring that the composition is consistent throughout.
Solutions can come in various forms and are not limited to liquids; for instance, air is a solution that is in a gaseous state. It is important to note that the largest component by mole fraction is always considered the solvent, and this remains the same whether the components are in solid, liquid, or gaseous form.
At pH0 the more thermodynamically stable species is ______ and the most strongly oxidizing species is _______ . At pH14 the more thermodynamically stable species is _______ and the most strongly oxidizing species is ______ . At pH0 ______ will tend to disproportionate and pH14 ________will tend to disproportionate. Under acidic conditions mixing Mn3+(aq) and MnO42- (aq) will result in the formation of______.
Answers
Answer:
At pH0 the more thermodynamically stable species is lower and the most strongly oxidizing species is higher. At pH14 the more thermodynamically stable species is higher and the most strongly oxidizing species is lower . At pH0 convex curve will tend to disproportionate and pH14 concave curce will tend to disproportionate. Under acidic conditions mixing Mn3+(aq) and MnO42- (aq) will result in the formation of redox oxidation-reduction reaction.
True False The colors emitted depends on the number of free electrons passing through the lamp. True False When a free electron hits an atom, the atom is always excited to the highest energy level possible. True False The kinetic energy of the free electron at the point of collision increases as the voltage of the battery increases. True False The kinetic energy of the free electron at the point of collision is higher if the atom is closer to the source of electrons. True False The only way to emit IR photons is if there are empty electronic energy levels really close to the ground state (lowest energy level). True False When atomic electrons are excited to a higher level, they always return to their lowest energy level by jumping down one level at a time.
Answers
Answer:
False
False
True
False
False
False
Explanation:
The colour emitted by an excited atom depends on the emission Spectra of the atom rather than on the number of free electrons passing through the lamp.
When a free electrons hits an atom, the atom can be excited to various intermediate states other than the highest energy level depending on the amount of energy it absorbed.
Increase in voltage of the battery also increases the kinetic energy of the electron
The kinetic energy of the electron depends on the voltage difference not on the distance from the atom.
The Paschen, Brackett, and Pfund series of lines are due to transitions from higher-energy orbits to orbits with n = 3, 4, and 5, respectively; these transitions release substantially less energy, corresponding to infrared radiation.
Excited atoms can jump from a higher level to the ground state in a series of steps or directly to the ground state
Which of the following is a property of a base?
A
taste sour
(B
slippery feel
(c produces hydrogen gas when reacting with a metal
D
produces carbon dioxide when reacting with carbonates
Answers
Answer:
produces carbon dioxide when reacting with carbonates
Which of these substances is the least acidic? solution A, pOH = 1.5 solution B, pOH = 7.0 solution C, pOH = 13.5
Answers
A 100g sample of Carbon-14 has a half-life of 5 years. How much Carbon-14 is left after 10 years?
Answers
Answer: The carbon-14 left after 10 years is 25 g
Explanation:
Expression for rate law for first order kinetics is given by:
[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) for rate constant
[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]
[tex]k=\frac{0.693}{5years}=0.139years^{-1}[/tex]
b) for amount left after 10 years
[tex]t=\frac{2.303}{k}\log\frac{a}{(a-x)}[/tex]
[tex]10=\frac{2.303}{0.139}\log\frac{100}{(a-x)}[/tex]
[tex](a-x)=25g[/tex]
Thus carbon-14 left after 10 years is 25 g
A 75.0-mLmL volume of 0.200 MM NH3NH3 (Kb=1.8×10−5Kb=1.8×10−5) is titrated with 0.500 MM HNO3HNO3. Calculate the pHpH after the addition of 13.0 mLmL of HNO3
Answers
Answer:
The pH is [tex]pH = 9.4[/tex]
Explanation:
From the question we are told that
The volume of [tex]NH_3[/tex] is [tex]V_N = 75mL = 75 *10^{-3} L[/tex]
The concentration of [tex]NH_3[/tex] is [tex]C_N = 0.200M[/tex]
The concentration of [tex]HNO_3[/tex] is [tex]C_H = 0.500 M[/tex]
The volume of [tex]HNO_3[/tex] added is [tex]V_H = 13mL = 13 *10^{-3 } L[/tex]
The base dissociation constant is [tex]K_b = 1.8*10^{-5}[/tex]
The number of moles of [tex]HNO_3[/tex] that was titrated can be mathematically represented as
[tex]n__{H}} = C_H * V_H[/tex]
substituting values
[tex]n__{H}} = 0.500* 13*10^{-3}[/tex]
[tex]n__{H}} = 0.0065 \ moles[/tex]
The number of moles of [tex]NH_3[/tex] that was titrated can be mathematically represented as
[tex]n__{N}} = C_N * V_N[/tex]
substituting values
[tex]n__{N}} = 0.200 * 75*10^{-3}[/tex]
[tex]n__{N}} = 0.015 \ mole[/tex]
So from the calculation above the limited reactant is [tex]HNO_3[/tex]
The chemical equation for this reaction is
[tex]NH_3 + HNO_3 ------> NH^{4+} + NO^{3+}[/tex]
From the chemical reaction
1 mole of [tex]HNO_3[/tex] is titrated with 1 mole of[tex]NH_3[/tex] to produce 1 mole of NH^{4+}
So
0.0065 moles of [tex]HNO_3[/tex] is titrated with 0.0065 mole of [tex]NH_3[/tex] to produce 0.0065 mole of [tex]NH^{4+}[/tex]
So
The remaining moles of [tex]NH_3[/tex] after the titration is
[tex]n = n__{N}} - n__{H}}[/tex]
=> [tex]n = 0.015 - 0.0065[/tex]
[tex]n = 0.0085 \ moles[/tex]
Now according to Henderson-Hasselbalch equation the pH of the reaction is mathematically represented as
[tex]pH = pK_a + log [\frac{NH_3}{NH^{4+}} ][/tex]
Where [tex]pK_b[/tex] is mathematically represented as
[tex]pK_a = -log K_a[/tex]
Now [tex]K_a = \frac{K_w}{K_b}[/tex]
Where [tex]K_w[/tex] is the ionization constant of [tex]NH_3[/tex] with value [tex]K_w = 1.0*10^{-14}[/tex]
Hence [tex]K_a = \frac{1.0*10^{-14}}{1.8 *10^{-5}}[/tex]
[tex]K_a = 5.556 * 10^{-10}[/tex]
Substituting this into the equation
[tex]pH = -log K_a + log [\frac{NH_3}{NH^{4+}} ][/tex]
[tex]pH = log [\frac{\frac{NH_3}{NH^{4+}} }{K_a} ][/tex]
substituting values
[tex]pH = log [\frac{\frac{0.0085}{0.0065} }{5.556*10^{-10}} ][/tex]
[tex]pH = 9.4[/tex]
Calculate the percent oxygen in sodium oxide.
Answers
Answer:
% is 51.6% of Oxygen
Explanation:
According to the working in the photo
51.6% is the percent of oxygen in sodium oxide. It represents the amount of solute in a given amount of solution.
What is mass percentage?A concentration is expressed as a mass percent. Furthermore, it defines the component of a particular blend. The solution component can be expressed in terms of mass percentage. It represents the amount of solute in a given amount of solution.
The amount of solute is measured in mass or moles. We shall study the mass percent equation using numerous solved numerical examples in this post. Mass is often represented in grams, although any unit of measurement is acceptable as long as an equivalent unit is used both for the component or solute mass and thus the total or solution mass.
mass percentage= (mass of oxygen / mass of sodium oxide)×100
=(32/62)×100
= 51.6%
Therefore, 51.6% is the percent of oxygen in sodium oxide.
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On January 2, 2020, Nash Company purchases a call option for $290 on Merchant common stock. The call option gives Nash the option to buy 1,050 shares of Merchant at a strike price of $51 per share. The market price of a Merchant share is $51 on January 2, 2020 (the intrinsic value is therefore $0). On March 31, 2020, the market price for Merchant stock is $54 per share, and the time value of the option is $210.
Answers
Final answer:
A call option is a financial contract that gives the buyer the right to purchase shares of a stock at a predetermined price. The net profit from this call option transaction can be calculated by determining the difference between the market price and the strike price, multiplied by the number of shares.
Explanation:
A call option is a type of financial contract that gives the buyer the right, but not the obligation, to purchase a specified number of shares of a stock at a predetermined price within a certain time frame. In this case, Nash Company purchased a call option to buy 1,050 shares of Merchant stock at a strike price of $51 per share. On March 31, 2020, the market price for Merchant stock is $54 per share, and the time value of the option is $210.
The net profit from this stock transaction can be calculated by determining the difference between the market price of the stock and the strike price, multiplied by the number of shares:
Net Profit = (Market Price - Strike Price) x Number of Shares
Using the given information, the net profit from this call option transaction would be:
Net Profit = ($54 - $51) x 1,050 = $3 x 1,050 = $3,150
a gas occupies 34.5 liters at a pressure of 345 torr what will be the volume of this gas if the pressure becomes 760 torr
Answers
Answer:
THE NEW PRESSURE IS 15.5 L.
Explanation:
Using Boyle's law which states that the pressure of a given mass of gas is inversely proportional to the volume of the gas at constant temperature.
Mathematically,
P1V1 =P2V2
P1 = 345 torr = 345/760 atm = 0.45 atm
P2 = 760 torr = 760/760 atm = 1 atm
V1 = 34.5 L
V2 = ?
Rearranging the variables, making V2 the subject of the formula, we obtain:
V2 = P2 V1 / P1
V2 = 1 * 34.5 / 0.45
V2 = 15.525 Litres
The volume of the gas when the pressure becomes 760 torr or 1 atm is 15.5 Litres
Write a balanced chemical equation for the standard formation reaction of solid sodium carbonate
Answers
Answer:
2Na(s) + C(s) + 3/2 O2(g) -----> Na2CO3(s).
Explanation:
Balancing and writring chemical reactions in Chemistry is a very important aspect of chemistry and,
writting and balancing of chemical reaction is often regarded as the heart of chemistry. A balanced Chemical reaction shows the number of each species in a reaction.
Hence, the balanced chemical equation for the standard formation reaction of solid sodium carbonate is given below;
(1). The reaction(unbalanced Reaction):
Na(s) + C(s) + O2(g) -----> Na2CO3(s).
Where solid sodium carbonate = Na2CO3(s).
(2). Balanced Reaction;
2Na(s) + C(s) + 3/2 O2(g) -----> Na2CO3(s)
The balanced chemical equation for the standard formation reaction of
solid sodium carbonate is shown below:
2Na(s) + C(s) + 3/2 O2(g) -----> Na2CO3(s).
The reaction involves elements which include Sodium(Na) , Carbon(C) and
Oxygen(O2). They react under certain conditions to form solid sodium
carbonate.
The reaction involves specific number of atoms involved in the reaction
which is why the equation must be balanced. The number of atoms of an
element on the left hand side should always be equal to those on the right
hand side.
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Radiation detectors use which of the following properties to detect radioactivity?
○ charge
○ ionizing
○ mass
○ energy
Answers
Answer:
ionizing
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Measurements show that the enthalpy of a mixture of gaseous reactants decreases by 162. kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that -194. kJ of work is done on the mixture during the reaction. a.Calculate the change in energy of the gas mixture during the reaction. Round your answer to 3 significant digits b. Is the reaction exothermic or endothermic?
Answers
Answer:
= -356KJ
therefore, the reaction where heat is released is exothermic reaction since theΔH is negative
Explanation:
given that enthalpy of gaseous reactants decreases by 162KJ and workdone is -194KJ
then,
change in enthalpy (ΔH) = -162( released energy)
work(w) = -194KJ
change in enthalpy is said to be negative if the heat is evolved during the reaction while heat change(ΔH) is said to be positive if the heat required for the reaction occurs.
At constant pressure the change in enthalpy is given as
ΔH = ΔU + PΔV
ΔU = change in energy
ΔV = change in volume
P = pressure
w = -pΔV
therefore,
ΔH = ΔU -W
to evaluate energy change we have,
ΔU =ΔH + W
ΔU = -162+ (-194KJ)
= -356KJ
therefore, the reaction where heat is released is exothermic reaction since theΔH is negative
Final answer:
The change in energy of the gas mixture during the reaction is 32 kJ. The reaction is exothermic because it releases heat to the surroundings as indicated by the negative enthalpy change.
Explanation:
To calculate the change in energy of the gas mixture during the reaction, we use the formula for change in internal energy (ΔU) at constant pressure:
ΔU = ΔH - PΔV
where ΔH is the change in enthalpy and PΔV is the work done on or by the system. Given that the enthalpy of the system decreases by 162 kJ and the work done on the system is -194 kJ, we can substitute these values into the equation:
ΔU = -162 kJ - (-194 kJ)
ΔU = -162 kJ + 194 kJ
ΔU = 32 kJ
Therefore, the change in energy of the gas mixture during the reaction is 32 kJ. The reaction can be classified as exothermic since the enthalpy decreases (ΔH is negative), which means heat is released by the system to the surroundings.
what kind of solution would have a Ka value that is much less than 1
Answers
Answer:
A weakly acidic solution.
Explanation:
Final answer:
A solution with a Ka value much less than 1 refers to a weak acid, where only a small portion of the acid is ionized, resulting in relatively low concentrations of hydronium ions and the conjugate base.
Explanation:
The type of solution that would have a Ka value much less than 1 is a weak acid solution. This is because the Ka (acid dissociation constant) value indicates the strength of the acid in solution; the lower the Ka, the weaker the acid. For a Ka value significantly less than 1, this means that only a small fraction of the acid molecules donate protons (H+) to the water, resulting in few hydronium ions (H₋₃O⁺) and the conjugate base (A-).
In contrast, strong acids have a Ka value that approaches infinity since they are almost completely ionized in solution. Acetic acid, with a Ka value of 1.75 x 10⁻⁵, is an example of a weak acid, indicating that in equilibrium, the concentration of the undissociated acetic acid is much greater than the concentrations of the acetate and hydronium ions.
when 1564 J of heat energy is added to a sample of gold at 25.0°C, the temperature of the gold increases to 449°C. what is the means of the gold sample? (specific heat of gold= 0.129 J/g-°C
Answers
Answer:
The mass of the gold sample is 28.59 g
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system. The amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without changing its physical state (solid, liquid or gaseous) is calculated by:
Q = c * m * ΔT
Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case:
Q= 1564 Jc= 0.129 [tex]\frac{J}{g*C}[/tex]m=?ΔT= Tfinal - Tinitial= 449°C - 25°C= 424 °CReplacing:
[tex]1564 J=0.129\frac{J}{g*C}*m*424 C[/tex]
Solving:
[tex]m=\frac{1564 J}{0.129\frac{J}{g*C}*424 C}[/tex]
m=28.59 g
The mass of the gold sample is 28.59 g
17
¿Cuál de las siguientes
propiedades distingue una solución
sobresaturada de una diluida?
Answers
Answer:
Which of the following
properties distinguishes a solution
oversaturated with a dilute?
The supersaturated solution is one in which the solvent has dissolved more solute than it can dissolve in the saturation equilibrium. The solute can be a solid, or a gas. The molecules of the solvent surround those of the solute and seek to open space between themselves to be able to harbor more amount of solute.A dilute solution is a solution that has not reached the maximum concentration of solute dissolved in a solvent. The additional solute will dissolve when added in a dilute solution and will not appear in the aqueous phase. It is considered a state of dynamic equilibrium where the speeds in which the solvent dissolves the solute are greater than the recrystallization rate.How is the Gobi Desert different from the Sahara Desert
Answers
Explanation: The Gobi actually gets snow and frost! ... The Sahara is also seven times larger, taking up half a continent: Almost ten million square kilometres, compared to only 1.3 million for the Gobi. Both are expanding, though; the Gobi is gaining another 3.5 thousand square km a year, and the Sahara a commensurate amount
Answer:
I have the same question same
Explanation: