f a hypothesis can stand the test of repeated examination, it can become a _____.

Answer:

0.24  moles.

Explanation:

number of moles  = mass of sample /mass of 1 mole

9.8g /40.08g  = 0.2445  moles <3

Answer:

volume, pressure, moles of air molecules

Explanation:

The volume, Pressure and Moles of air molecules expect to change when you compare the starting and ending state of the tire.

So, option A , C and D is correct option.

Learn about pressure , volume and moles

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Answer:

Cl₂ is the limiting reactant.

Explanation:

2Na + Cl₂ → 2NaCl,

It is clear that 2 mol of Na react with 1 mol of Cl₂ to produce 2 mol of NaCl.

For Na:

n = mass/molar mass = (8.0 g)/(22.989 g/mol) = 0.348 mol.

For Cl₂:

n = mass/molar mass = (8.0 g)/(70.9 g/mol) = 0.113 mol.

The limiting reagent in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by this reagent, since the reaction cannot continue without it.

So, 0.113 mol of Cl₂ react completely with 0.226 mol of Na which be in excess (0.384 - 0.226 = 0.158 mol).

So, the limiting reactant is Cl₂ which is the reactant has the lowest molar ratio.

Diatomic chlorine (Cl₂) is the limiting reactant for the reaction between 8 g of sodium and 8 g of diatomic chlorine.

The limiting reactant in a chemical reaction is simply defined as the reactant which is completely used up in the chemical reaction.

With the above information in mind, we can determine the limiting reactant for the reaction between 8 g of sodium and 8 g of diatomic chlorine (Cl₂). This can be obtained as follow:

2Na + Cl₂ —> 2NaCl

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of Cl₂ = 35.5 × 2 = 71 g/mol

Mass of Cl₂ from the balanced equation = 1 × 71 = 71 g

From the balanced equation above,

46 g of Na reacted with 71 g of Cl₂

Therefore,

8 g of Na will react with = [tex]\frac{8 * 71}{46}\\\\[/tex] = 12.3 g of Cl₂

From the calculation made above, we can see clearly that a higher mass of Cl₂ (i.e 12.3 g) than what was given (i.e 8 g) is needed to react completely with 8 g of Na.

Therefore, Cl₂ is the limiting reactant and Na is the excess reactant.

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The bond formed here would be a covalent bond.

This is because not only are the two molecules (Chlorine) listed nonmetals, but they also have identical electronegativity values. (Both have 7 electrons.)

Hope I could help! :)

Answer:

2.56 L NiCl2

Explanation:

This is a stoichiometry problem. You need to find a way to go from g of Ni3(PO4)2 to L of NiCl2. To do this you travel

mass Ni3(PO4)2 > moles Ni3(PO4)2 > moles NiCl2 > L NiCl2

so you need to know the key that lets you travel from one to the next.

Mass > moles, use molar mass

moles > moles, use the mole ratio

moles > L, use the molarity (moles / liter) in this case. (With gases, you use the STP gas volume of 22.4L / mole).

The attached picture shows what this problem looks like.

The problem requires application of stoichiometry using a balanced chemical equation. About 2.51 L of 0.219 M NiCl2 solution is needed to produce 68.4 g of Ni3(PO4)2 precipitate.

The subject of the problem concerns stoichiometry in chemistry. Specifically, the use of a balanced chemical equation to calculate volumes of a solution needed, in this case - 0.219M of NiCl2 solution required to produce 68.4g of Ni3(PO4)2 precipitate.

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Answer: HBr & HF are correct on edmentum/ plato

Explanation:

All acids that start with the prefix "hydro" are also called binary acids. HCl containing anionic chloride is called hydrochloric acid. HCN containing hydrogen cyanide is called hydrocyanic acid

H2SO3 is not sulfite. Description: Acids containing non-metal elements other than hydrogen and oxygen are called hydrogen acids. Examples: HCl, HBr, HI.

A diprotic acid is an acid composed of hydrogen and one other element. The most common diprotic acids contain halogens. Acid names start with the prefix hydro-.

Acid has its own nomenclature. If the acid is composed of only hydrogen and one other element, its name is water- + stem of another element + -acid. For example, the compound HCl (aq) is hydrochloric acid, while H2S (aq) is hydrogen sulfide.

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answer:

temperature

pressure

volume

concentration of amount of reactants and product

Answer:

Q14: 17,140 g = 17.14 kg.

Q16: 504 J.

Explanation:

Q14:

Q = m.c.ΔT,

where, Q is the amount of heat absorbed by ice (Q = 3600 x 10³ J).

m is the mass of the ice (m = ??? g).

c is the specific heat of the ice (c of ice = 2.1 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 100.0°C - 0.0°C = 100.0°C).

∵ Q = m.c.ΔT

∴ (3600 x 10³ J) = m.(2.1 J/g.°C).(100.0°C)

∴ m = (3600 x 10³ J)/(2.1 J/g.°C).(100.0°C) = 17,140 g = 17.14 kg.

Q16:

Q = m.c.ΔT,

where, Q is the amount of heat absorbed by ice (Q = ??? J).

m is the mass of the ice (m = 12.0 g).

c is the specific heat of the ice (c of ice = 2.1 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 0.0°C - (-20.0°C) = 20.0°C).

∴ Q = m.c.ΔT = (12.0 g)(2.1 J/g.°C)(20.0°C) = 504 J.

Answer:

1st answer:  A. nitrogen

2nd answer:  A. Sodium carbonate

Explanation:

The gas usually filled in the electric bulb is

OPTION A

Washing soda is the common name for

OPTION A

Answer:

Brick.

Explanation:

The formula for the amount of heat absorbed by an object is

q = mCΔT

You want to know how much ΔT changes for each object.

[tex]\Delta T=\dfrac{q}{mC}[/tex]

If each object has the same mass and absorbs the same amount of heat, then

[tex]\Delta T \propto \dfrac{1}{C}[/tex]

The object with the smallest specific heat capacity should have the greatest temperature increase.

Brick will have the greatest temperature increase (we can't say how fast the objects will heat up, because that depends on thermal conductivity: how quickly the heat is carried to the interior of the object).  

Answer: Brick

Explanation:

Because any number is the lowest in this question it would be brick

Final answer:

To determine the concentration of NaOH in a solution, you can use titrants such as Hydrochloric acid (HCl), Sulfuric acid (H2SO4), or Potassium hydrogen phthalate (KHP) through the titration process.

Explanation:

In order to determine the concentration of NaOH in a solution, you can use a process called titration with a titrant. Three possible titrant solutions that can be used to titrate an NaOH solution include:

Each of these substances can act as an acid to neutralize the basic NaOH solution, and through the process of titration, you can determine the exact concentration of NaOH presented in the solution.

Answer:

148.1 mL.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

(V₁T₂) = (V₂T₁)

V₁ = 125 mL, T₁ = 25°C + 273 = 298 K,

V₂ = ??? mL, T₂ = 55°C + 273 = 353 K,

(V₁T₂) = (V₂T₁)

∴ V₂ = (V₁T₂)/(T₁) = (125 mL)(353 K)/(298 K) = 148.1 mL.