Find function domain
f(x) = sqrt( 2sin x - 1 )

Answer: C

Step-by-step explanation: An open line of credit is a line of credit against which additional debt may be drawn. An open credit line allows you to borrow money against the credit line at different times. You can borrow against it up to the credit limit.

Answer: 3x^2-10x+8

Step-by-step explanation:

x*3x+x(-4)+(-2)*3x+(-2)(-4) Foil Method

3x^2-4x-6x+8    Add and subtract like factors

Answer:

Step-by-step explanation:

Use FOIL: (a + b)(c + d) = ac + ad + bc + bd

[tex](x-2)(3x-4)=(x)(3x)+(x)(-4)+(-2)(3x)+(-2)(-4)[/tex]

[tex]=3x^2-4x-6x+8[/tex]       combine like terms

[tex]=3x^2+(-4x-6x)+8=3x^2-10x+8[/tex]

Answer:

The correct answer would be A

Step-by-step explanation:

The slope of the given linear line is 3/5 thus the equation is y = 3/5 x so option (A) is correct.

A straight line on the coordinate plane is represented by a linear function.

A linear function always has the same and constant slope.

The formula for a linear function is f(x) = ax + b, where a and b are real values.

As per the given,

The slope of the line is 3/5

Since, the equation is y = mx + c where m is the slope and c is the y-intercept.

In the given line c = 0 and m = 3/5

y = 3/5 x

Hence "The slope of the given linear line is 3/5 thus the equation is y = 3/5 x".

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Answer:

[tex]\large\boxed{A)\ u^2-11u+24=0}[/tex]

Step-by-step explanation:

[tex](x^2-1)^2 -11(x^2-1)+24=0\\\\\text{Substitute}\ (x^2-1)=u\\\\\underbrace{(x^2-1)}_{u}\ ^2 -11\underbrace{(x^2-1)}_{u}+24=0\to u^2-11u+24=0[/tex]

Answer:  The correct option is

(A) [tex]u^2-11u+24=0,~~\textup{where }u=(x^2-1).[/tex]

Step-by-step explanation:  We are given to select the correct quadratic equation that is equivalent to the following equation :

[tex](x^2-1)^2-11(x^2-1)+24=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

Let us consider that

[tex]u=x^2-1.[/tex]

Substituting the value of u in equation (i), we get

[tex](x^2-1)^2-11(x^2-1)+24=0\\\\\Rightarrow u^2-11u+24=0.[/tex]

Thus, the required equivalent quadratic equation is

[tex]u^2-11u+24=0,~~\textup{where }u=(x^2-1).[/tex]

Option (A) is CORRECT.

70% × 413 =

(70 ÷ 100) × 413 =

(70 × 413) ÷ 100 =

28,910 ÷ 100 =

289.1

Proof

289.1 ÷ 413 =

0.7 =

0.7 × 100/100 =

0.7 × 100% =

(0.7 × 100)% =

70%

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4*6m=24m

-7*4=-28

24m -28

Answer:

24m-28

Step-by-step explanation:

This is valid.

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Answer:

π/64

Step-by-step explanation:

assuming that c= circumference, and the circumference being 2πr(radius), then r=1/8 because 2π/8=π/4. to find the area, we use the formula πr^2, or π*1/8^2, or π/64

Answer:

About $31,200

Step-by-step explanation:

Answer:

V = 60

Step-by-step explanation:

Yes, it is

Best regards

Answer:

yes that is that is that is the right answer hope u get all your homework right

Step-by-step explanation:

Answer:

e=23

Step-by-step explanation:

The equation representing this scenario is e-5=18.

Add 5 to both sides and you get e=23 (eggs)

Answer:

e=23

Step-by-step explanation:

Answer:  x = {-1, 1, -i√2, i√2, -3, 4}

Step-by-step explanation:

(x² - 1)(x² + 2)(x + 3)(x - 4)(x+1)=0

Set each factor equal to zero and solve.

x² - 1 = 0  →  x² = 1  →  x = ±1

x² + 2 = 0  →  x² = -2  →  x = ± i√2

x + 3 = 0  →  x = -3

x - 4 = 0  →  x = 4

x + 1 = 0  →  x = -1   (note that -1 is a duplicate - solved from the first factor)

Answer:

Answer:  x = {-1, 1, -i√2, i√2, -3, 4}

Step-by-step explanation:

Answer:

y = 6

Step-by-step explanation:

Given

y = [tex]\frac{3}{4}[/tex] x + 3 and (4, ? )

Substitute the x- coordinate x = 4 into the equation for corresponding value of the y- coordinate.

x = 4 : y = [tex]\frac{3}{4}[/tex] × 4 + 3 = 3 + 3 = 6

Hence the coordinate point is (4, 6)

When there was no snow fall, the line would be flat ( horizontal).

There was no snow Between 3:30 pm and 2:00 pm.

Answer:

12:30 pm to 1:00 pm.

Step-by-step explanation:

Hope this helps you.

Answer:

sin2b sin b

2 sin b cos b sin b

2 cos b sin^2 b

1−cos2b cos b

1- (2cos^2 b−1) cosb

2 cos beta

Answer:2sin =bahsyg=a=78sinb-7823sin=   1-tan2b

Answer:   b) (x - 2)(x + 1)(x + 3) = 0

Step-by-step explanation:

Look at the graph to find the x-intercepts (where the graph crosses the x-axis).

x = 2,       x = -1,      and   x = -3

Rewrite them as factors:

x - 2 = 0,  x + 1 = 0, and  x + 3 = 0

Combine the factors through multiplication:

(x - 2) (x + 1) (x + 3) = 0

The inequality is determined by examining the graph, identifying the lines, their slopes and determining if they are increasing or decreasing. Positive slopes are for increasing lines and negative slopes are for decreasing lines. Inequalities should represent the identified lines and their slopes.

From your question, it seems that there's a graph involved depicting certain lines and you're supposed to choose an inequality that represents the graph. As per the given information that line A is decreasing and line B is increasing, it sounds like these lines may represent an inequality on the coordinate plane. Consider the slope of line A and line B. If one is steeper than the other, the steeper slope has a larger absolute value. An increasing line indicates a positive slope, while a decreasing line indicates a negative slope. For example, if line A is y < -2x + 3 (negative slope, line decreasing) and line B is [tex]y > 5x + 1[/tex](positive slope, line increasing), the inequality would be [tex]y > 5x + 1 - y < -2x + 3.[/tex]For a precise and correct answer, you need to analyze the graph, identify lines, intercepts, slopes, and shading to form the correct inequality.

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when all goes wrong...choose c my friend.

[tex]\huge\text{$x=\boxed{\frac{1}{5}}$}[/tex]

Hey there! To solve this problem, we need to isolate [tex]x[/tex] on one side of the equation.

[tex]\begin{aligned}5(3x+4)&=23\\5\cdot3x+5\cdot4&=23&&\smash{\Big|}&&\text{Distribute the $5$.}\\15x+20&=23&&\smash{\Big|}&&\text{Multiply.}\\15x&=3&&\smash{\Big|}&&\text{Subtract $20$ from both sides.}\\x&=\frac{3}{15}&&\smash{\Big|}&&\text{Divide both sides by $15$.}\\x&=\boxed{\frac{1}{5}}&&\smash{\Big|}&&\text{Divide the numerator and denominator by $3$.}\end{aligned}[/tex]

Answer:

[tex] x = \frac { 1 } { 5 } [/tex]

Step-by-step explanation:

We are given the following equation and we are to find the value of x by making it the subject of the equation:

[tex] 5 ( 3 x + 4 ) = 23 [/tex]

We will start by opening the brackets and expanding the term by multiplying 5 with the terms inside the brackets to get:

[tex] 15 x + 20 = 23 [/tex]

[tex] 15 x = 23 - 20 [/tex]

[tex] 15 x = 3 [/tex]

[tex] x = \frac { 3 }  { 15 } [/tex]

[tex] x = \frac { 1 } { 5 } [/tex]

Answer:

[tex]4(3\frac{2}{5})[/tex] is greater

Step-by-step explanation:

step 1

we have

[tex]4(3\frac{2}{5})[/tex]

convert to an improper fraction

[tex]3\frac{2}{5}=\frac{3*5+2}{5}=\frac{17}{5}[/tex]

so

[tex]4(3\frac{2}{5})=4(\frac{17}{5})=\frac{68}{5}[/tex]

step 2

we have

[tex]3(4\frac{2}{5})[/tex]

convert to an improper fraction

[tex]4\frac{2}{5}=\frac{4*5+2}{5}=\frac{22}{5}[/tex]

so

[tex]3(4\frac{2}{5})=3(\frac{22}{5})=\frac{66}{5}[/tex]

therefore

[tex]4(3\frac{2}{5})[/tex] is greater

Final answer:

After converting mixed numbers to improper fractions and multiplying, it is clear that 4 x [tex]3\frac{2}{5}[/tex] is greater than 3 x [tex]4\frac{2}{5}[/tex].

Explanation:

The question asks which is greater: 4 x [tex]3\frac{2}{5}[/tex] or 3 x [tex]4\frac{2}{5}[/tex]. Let's compare these two expressions

First, convert the mixed numbers to improper fractions:

[tex]3\frac{2}{5}[/tex] = (3x5 + 2)/5 = 17/5

[tex]4\frac{2}{5}[/tex] = (4x5 + 2)/5 = 22/5

Next, multiply each by the whole number:

4 x 17/5 = 68/5 = 13.6

3 x 22/5 = 66/5 = 13.2

Therefore, 4 x [tex]3\frac{2}{5}[/tex] is greater than 3 x [tex]4\frac{2}{5}[/tex].

Points "in common with the x-axis" are also known as the roots of the quadratic equation [tex]x^2-12x+12=0[/tex]. You can apply the quadratic root formula to determine the roots, and also to determine how many such roots there are. With a quadratic (whose graph is a parabola), there can be maximum of 2 roots. But under certain circumstances, there may be only one or no such root.

The root formula for a generic quadratic [tex]ax^2+bx+c[/tex] is as follows:

[tex]x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

The expression [tex]b^2-4ac[/tex] under the square root is called the determinant. It is called so because it determines the number of real roots. If the determinant value is > 0, there will be 2 roots (and so the parabola will cross the x-axis in 2 points), if its value is =0, there will be only a single root (the the parabola will touch the x-axis in exactly one point), and, finally, if its value is < 0, the quadratic has no real root (andthe parabola will not have any x-intercepts).

So, let's take a look:

[tex]b^2-4ac= (-12)^2-4\cdot 1\cdot12=96[/tex]

This means the parabola will intercept the x-axis at 2 points, two real roots.

Since the coefficient of the quadratic term is positive (a=1), the parabola is oriented "open-up." But since we already know the parabola intercepts in two points, the fact that it is open-up implies now that the vertex must lie below the x-axis (otherwise it could not intercept it).

The number of common points between a parabola and the x-axis is determined by the discriminant of its equation, while the position of its vertex relative to the x-axis is determined by the value of y at the vertex. A positive discriminant yields two points of intersection, zero yields one, and negative yields none. The vertex's position can be above, on, or below the x-axis depending on whether k in its vertex form is positive, zero, or negative.

To determine how many points a parabola has in common with the x-axis, we look for the solutions to the parabolic equation when y is set to zero. The number of intersections corresponds to the number of real solutions to this equation. If the parabola's equation is given in the standard form y = ax2 + bx + c, we can use the discriminant (b2 - 4ac) to find out how many times the parabola touches the x-axis. If the discriminant is positive, the parabola intersects the x-axis at two distinct points; if it is zero, the parabola touches the x-axis at exactly one point (the vertex); and if it is negative, the parabola does not intersect the x-axis at all.

The vertex of the parabola lies above, on, or below the x-axis depending on the value of y at the vertex. In the vertex form of a parabola, y = a(x - h)2 + k, where (h, k) is the vertex, if k is positive, the vertex lies above the x-axis; if k is zero, the vertex is on the x-axis; and if k is negative, the vertex lies below the x-axis. Typically, the coefficient a determines the direction of the parabola opening—upwards if a is positive, and downwards if a is negative, but this does not affect the vertical placement of the vertex relative to the x-axis.

Answer:

1.58

Step-by-step explanation:

Okay. We're solving for t because we need to know how many seconds. From the problem, we know the height (10), but we don't know when that height happens.

[tex]10 = -16tx^{2} -7t+61[/tex]

We can factor by multiplying -16 by 61 first to get -976 and see what multiplies to get -976 AND adds to get -7 at the same time. But we can also use the quadratic formula because, let's be honest, factoring can be a lot of extra work.

[tex]10 = -16t^{2} -7t+61\\\\0 = -16t^{2} -7t+51\\\\t=\frac{-b\pm \sqrt{b^{2}-4ac } }{2a} \\=\frac{-(-7)\pm \sqrt{(-7)^{2}-4(-16)(51) } }{2(-16)} \\=\frac{7\pm \sqrt{49+64(51) } }{-32} \\=\frac{7\pm \sqrt{3313} }{-32}[/tex]

Plug both the plus and the minus versions into your calculator and...

[tex]t\approx -2.02, 1.58[/tex]

There's no such thing as negative time, so -2.02 is automatically disqualified, leaving 1.58 as the answer.

Hope this helps, let me know if I missed anything!

The time takes for the egg to reach the height 10 feet from the ground on the basis of the given quadratic equation will be 1.58 seconds.

An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax2 + bx + c = 0, where x is the variable, and a must not be zero.

For example, 3x² + 6x + 8 = 0 here x has the highest term as 2 and the coefficient of x² is not zero.

As per the given quadratic equation,

d = - 16t² - 7t + 61

The time t in seconds at d = 10

-16t² - 7t + 61 = 10

16t² + 7t - 51 = 0

The roots of the above quadratic equation will be,

t = [-7 ± √(7² - 4 × 16 × -51 )] /(2 × 16)

t = (-7 ± 57.586)32

t = 1.58 or -2.02

Since, time is always positive thus, t = 1.58 seconds.

Hence "The time takes for the egg to reach the height 10 feet from the ground on the basis of the given quadratic equation will be 1.58 seconds".

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Answer:

3.3 apex

Step-by-step explanation:

Answer:

3.3

Step-by-step explanation:

Answer:

(24 / 43) * 100 = 55.81395349 %

which equals roughly 55.81 %

Step-by-step explanation:

Answer:

8c > 21

The solution is c > 21/8.

Step-by-step explanation:

Not all math problems have only one solution. Some math problems have multiple solutions such as set or group of solutions. These problems are called inequalities. Inequalities have solutions within a range using symbols such as >, <, ≤, and ≥. These are known as greater than, less than, less than or equal and greater than or equal. You can write any inequality expression from words into symbols using these signs.

The expression "the product of c and 8 is greater than 21​" is translated into

8c > 21

since product is multiplication.

It can be solved by dividing both sides by 8.

The solution is c > 21/8.

he will be reimbursed 137.26 dollars for two days

Answer:

these are independent

Step-by-step explanation:

the answer is 28

have a good day!

Answer:

You can do it four ways for horizontal straight line using a ruler.

Step-by-step explanation:

i did was make a 2x2 grid, and then arrange the four pictures inside.

Final answer:

There are 24 different ways to arrange four pictures on a wall in a horizontal straight line, calculated using the factorial of the number of pictures (4!).

Explanation:

The question of how many different ways you can arrange four pictures on a wall if you want them in a horizontal straight line is a problem of permutations, which is a concept in mathematics. To determine the number of different arrangements, we calculate the factorial of the number of pictures. The factorial, represented by an exclamation mark (!), means that you multiply the number by every number below it down to 1. For four pictures, the calculation is 4! (which is 4 x 3 x 2 x 1).

The result is:

Therefore, there are 24 different ways to arrange four pictures on a wall in a horizontal straight line.