Find the ordered pair solution of y = (2/5)x + 2 corresponding to -5

Answer:

see the explanation

Step-by-step explanation:

we know that

The equation of the line in slope intercept form is equal to

[tex]y=mx+b[/tex]

where

m is the slope or unit rate of the linear equation

b is the y-intercept or initial value of the linear equation

In this problem we have

[tex]y=25x+50[/tex]

This is the equation of a line in slope intercept form

so

Is a linear equation (the graph is a line)

The slope is positive and is equal to [tex]m=25[/tex]

The y-intercept is the point (0,50) (y-intercept is the value of y when the value of x is equal to zero)

The value of b is [tex]b=50[/tex] (y-coordinate of the y-intercept)

The x-intercept is the point (-2,0) (x-intercept is the value of x when the value of y is equal to zero)

The linear function is a increasing function (the slope is positive)

Answer:

The answer is k = [tex]-\frac{3}{5}[/tex]

Explanation:

We know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form  [tex]k=\frac{y}{x}[/tex] or [tex]y=kx[/tex]

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

we have the point (-30,18)

so

x=-30, y=18

Find the value of k

[tex]k=\frac{y}{x}[/tex]

substitute

[tex]k=\frac{18}{-30}[/tex]

Simplify

Divide by 6 both numerator and denominator

[tex]k=- \frac{3}{5}[/tex]

Answer:

Only 1 time

Step-by-step explanation:

When it is compound interest it can be added in the following ways:

Annually = 1 Time in a year

Semiannually = 2 Times in a year

Quarterly = 4 Times in a year

Monthly = 12 Times in a year

Answer:

2

Step-by-step explanation:

a.p.e.x

Answer:

b. 2005

Step-by-step explanation:

(apex)

300=150(1.07)^x

1.07^x=2

x=ln 2/ln 1.07

=10.24

1995 plus ten years = 2005

hope this helps

Answer:

B. 2005

Step-by-step explanation:

We have been given that population of deer in a certain national park can be approximated by the function [tex]P(x)=150(1.07)^x[/tex], where x is the number of years since 1995. We are asked to find the year in which population will reach 300.

To solve our given problem, we will equate [tex]P(x)=300[/tex] and solve for x as:

[tex]300=150(1.07)^x[/tex]

[tex]\frac{300}{150}=\frac{150(1.07)^x}{150}[/tex]

[tex]2=(1.07)^x[/tex]

Now, we will take natural log on both sides as:

[tex]\text{ln}(2)=\text{ln}((1.07)^x)[/tex]

[tex]\text{ln}(2)=x\text{ln}(1.07)[/tex]

[tex]x=\frac{\text{ln}(2)}{\text{ln}(1.07)}[/tex]

[tex]x=10.2447[/tex]

[tex]x\approx 10[/tex]

Now, we will find 10 years after 1995 that is [tex]1995+10=2005[/tex].

Therefore, the population will be 300 in year 2005 and option B is the correct choice.

Answer:

Point T

Step-by-step explanation:

The only point that is right across from (-3,-5) is point T. If you reflect across the Y-axis, you get (3,-5)

Answer:

altitude = 10 cm

Step-by-step explanation:

Finding the altitude of triangle when area and base is given:

         [tex]\sf \boxed{\text{\bf Area of triangle = $\dfrac{1}{2}*base*altitude$}}[/tex]

                               base = 20 cm

          Area of a triangle = 100 sq.cm

               [tex]\sf \dfrac{1}{2}*20*altitude = 100\\\\\\[/tex]

                   10 * altitude = 100      

                          altitude = 100 ÷ 10

                         altitude = 10 cm

Answer:

Area of the path is 475 m².

Step-by-step explanation:

Let us first draw the diagram for the given question.

Here rectangle ABCD represents a park whose length is 55 m and breadth is 35 m. The shaded portion shows the path all around the park whose width is 2.5 m.

Now, length of rectangle ABCD, l = 55 m

breadth of rectangle ABCD, B = 35 m

Now, width of the path = 2.5 m

So, length of rectangle PQRS, L = 55 + 2.5 + 2.5 = 60 m

breadth of rectangle PQRS, B = 35 + 2.5 + 2.5 = 40 m

Now, to calculate the area of shaded portion or the area of the path, we will subtract the area of the park or area of rectangle ABCD from the area of rectangle PQRS.

Now, area of rectangle PQRS, A₁ = L × B = 60 × 40 = 2400 m²

Area of rectangle ABCD, A₂ = l × b = 55 × 35 = 1925 m²

So, area of the path = A₁ - A₂ = 2400 - 1925 = 475 m²

Hence the area of the path is 475 m².

Answer:

1.13 repeated

Step-by-step explanation:

Answer:

1 and 100 over 750

Step-by-step explanation:

The area common to both triangles is [tex]18\sqrt3[/tex] square centimeters.

In a 30-60-90 triangle, the ratio of the side lengths is [tex]1:\sqrt{3} :2[/tex]. Since the hypotenuse is 12 cm, we can determine the lengths of the other sides using this ratio.

The shorter leg (opposite the 30-degree angle) is (1/2) times the hypotenuse, which is (1/2) * 12 cm = 6 cm.

The longer leg (opposite the 60-degree angle) is [tex]\sqrt3[/tex] times the shorter leg, which is 6 * [tex]\sqrt{3[/tex] cm = [tex]6\sqrt3[/tex] cm.

Now, since the two triangles are congruent, the overlapping region forms an isosceles triangle with two sides measuring 6 cm (the shorter leg) and a base measuring [tex]6\sqrt3[/tex] cm (the longer leg).

The base of the isosceles triangle is [tex]6\sqrt3[/tex] cm, and since it's an isosceles triangle, the height is the same as the shorter leg, which is 6 cm.

Common Area = ([tex]6\sqrt3[/tex] cm * 6 cm) / 2 = [tex]36\sqrt3[/tex] cm² / 2 = [tex]18\sqrt3[/tex] cm².

Therefore, the area common to both triangles is [tex]18\sqrt3[/tex] square centimeters.

Read more about congruent triangles,

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The area common to both triangles is 144 square centimeters.

To find the area common to both triangles, we need to determine the overlapping region, which is a rhombus formed by the intersection of the two 30-60-90 triangles.

First, let's consider one of the 30-60-90 triangles. The sides of a 30-60-90 triangle are in the ratio 1:√3:2. In this case, the hypotenuse is 12 cm, so the sides of the triangle are:

Shorter leg (opposite the 30-degree angle) = 12 cm / 2 = 6 cm

Longer leg (opposite the 60-degree angle) = 6 cm * √3

Now, let's look at the overlapping region, which forms a rhombus. The diagonals of a rhombus are perpendicular bisectors of each other, so each diagonal will be twice the length of the shorter leg of the 30-60-90 triangle.

Diagonal of the rhombus = 2 * 6 cm = 12 cm

The area of a rhombus can be calculated using the formula: Area = (diagonal1 * diagonal2) / 2

In this case, both diagonals are equal (12 cm each), so the area of the rhombus (and hence the common area of the triangles) is:

Area = (12 cm * 12 cm) / 2

Area = 144 cm²

So, the area common to both triangles is 144 square centimeters.

To know more about triangles:

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#SPJ2

Solve for x in this equation.

x+(-9)=-36

x-9=-36

x=-27

answer: -27

Answer:

y=-2x

Step-by-step explanation:

Parallel means same slope.

y-y1=m(x-x1)

y-(-8)=-2(x-4)

y+8=-2x+8

y=-2x+8-8

y=-2x

Answer:

three hundred and ninety three billion, two hundred and thirty four million, and thirty four.

Step-by-step explanation:

billion is any digit that has seven to nine digits behind it

Answer:

Three hundred and ninety three billion, two hundred and thirty four million and thirty four.

Step-by-step explanation:

Answer:

[tex]\frac{3}{8} or\ 0.375\ km[/tex]

Step-by-step explanation:

Given: Chandler walk 1/16 km every 10 minutes.

First, lets find how many 10 minutes in one hours or convert minutes in hours.

∴ Time= [tex]\frac{60}{10} \ h[/tex]

Now, finding kilometres travelled in 1 hour.

Distance travelled= [tex]\frac{1}{16} \times \frac{60}{10} = \frac{1}{16} \times 6[/tex]

Distance travelled = [tex]\frac{3}{8}[/tex]

Converting [tex]\frac{3}{8} \ km[/tex] into decimal will have 0.375 km.

∴ [tex]\frac{3}{8} or\ 0.375\ km[/tex] will chandler walk in 1 hour.

Answer:

.45($259) = $116.55

The sale price of the surfboard is $116.55.

Answer:

6*(3/4) is 75% of 6.

Step-by-step explanation:

3/4 =0.75

Consider this:

6*1 =6, so 1=100%.

6*1/2 =6*0.5=3, so 1/2=50%.

You can then see that 6*0.75=4.5 is 75% of 6.

Answer:

x-=13

Step-by-step explanation:

9x+2=119

subrtact 2 from both sides

9x=117

divide 9 from both sides

x=13

Answer: x=13

Step-by-step explanation:

Since alternate interior angles are congruent so

9x+2=119

9x=119-2

9x=117

x=117/9

x=13

Answer:

this photo should be it

Answer:

B. FOR SURE !!!

Step-by-step explanation:

Answer: B

Step-by-step explanation:

Answer:

10. ○[tex]\displaystyle 4,85; 4\frac{17}{20}[/tex]

9. ○680%

8. ○40%

7. ○[tex]\displaystyle 60[/tex]

6. ○0,4, 40,5%, 11⁄25, 4⁄9

5. ○[tex]\displaystyle 0,928[/tex]

4. ○1%

3. ○76%

2. [tex]\displaystyle See\:above\:grid[/tex]

1. [tex]\displaystyle See\:above\:grid[/tex]

Step-by-step explanation:

10. To convert from a percentage to a decimal, move the decimal mark twice to the left; each 20 is worth 5, and since 5 by 17 is 85, you have your fractional part of 17⁄20, then attach the whole number of 4.

9. To convert from a mixed number\improper fraction to a percentage, first evaluate the fractional part for a decimal answer, then move the decimal mark twice to the right.

8. To convert from a fraction to a percentage, evaluate the fraction for a decimal answer, then move the decimal mark twice to the right.

7. [tex]\displaystyle \frac{132}{220} = \frac{3}{5} =[/tex]60%

Greatest Common Divisor [GCD]: 44

6. [tex]\displaystyle \frac{11}{25} =[/tex]44%

_

[tex]\displaystyle \frac{4}{9} =[/tex]44,4%

[tex]\displaystyle 0,4 =[/tex]40%

Now that these are all percentages, it is alot easier to order them from least to greatest.

5. To convert from a percentage to a decimal, move the decimal mark twice to the left.

4. To convert from a decimal to a percentage, move the decimal mark twice to the right.

3. Each 25 is worth 4, and since 4 by 19 is 76, you get 76%.

2. Each 25 is worth 4, and since 4 by 6 is 24, you get 24%, and this graph.

1. Each 36 is worth 2 7⁄9, and since 12 by 2 7⁄9 is 33⅓, you get 33⅓%, so you would choose this answer.

I am joyous to assist you anytime.

Solve: 4(6x - 10) = 8x + 40

A 0

B.5/2

c. 23

D. 5​

Option D

The solution to given equation is x = 5

Given that we have to solve the given equation

4(6x - 10) = 8x + 40

Let us solve the above expression and find value of "x"

Multiplying 4 with terms inside bracket in L.H.S we get,

24x - 40 = 8x + 40

Move the variables to one side and constant terms to other side

24x - 8x = 40 + 40

Combine the like terms,

16x = 80

[tex]x = \frac{80}{16} = 5[/tex]

Thus solution to given equation is x = 5

Answer:

324

Step-by-step explanation:

Given:

[tex]g(x)=4x^2+2x\\ \\f(x)=\int\limits^x_0 {g(t)} \, dt[/tex]

Find:

[tex]f(6)[/tex]

First, find f(x):

[tex]f(x)\\ \\=\int\limits^x_0 {g(t)} \, dt\\ \\=\int\limits^x_0 {(4t^2+2t)} \, dt\\ \\=\left(4\cdot \dfrac{t^3}{3}+2\cdot \dfrac{t^2}{2}\right)\big|\limits^x_0\\ \\=\left(\dfrac{4t^3}{3}+t^2\right)\big|\limits^x_0\\ \\= \left(\dfrac{4x^3}{3}+x^2\right)-\left(\dfrac{4\cdot 0^3}{3}+0^2\right)\\ \\=\dfrac{4x^3}{3}+x^2[/tex]

Now,

[tex]f(6)\\ \\=\dfrac{4\cdot 6^3}{3}+6^2\\ \\=288+36\\ \\=324[/tex]

To find the temperature in Boxerville at 4:00 p.m. after a drop of 18 degrees by 7:00 p.m. (with a 7:00 p.m. temperature of 64 degrees), we add the dropped degrees back to find the original temperature was 82 degrees.

The question asks to find the temperature at 4:00 p.m. in Boxerville given that it dropped 18 degrees by 7:00 p.m., and the temperature at 7:00 p.m. is 64 degrees. To solve this, we simply need to add the 18-degree drop back to the 7:00 p.m. temperature to find the original temperature at 4:00 p.m.

To find the temperature at 4:00 p.m., we calculate:

Temperature at 7:00 p.m.: 64 degrees

Temperature drop: 18 degrees

Original temperature at 4:00 p.m.: 64 degrees + 18 degrees = 82 degrees

Therefore, the temperature at 4:00 p.m. was 82 degrees.

Answer:

Circle the 15 in the diagram, that's the correct answer

Answer:

184π units²

Step-by-step explanation:

see attached for reference

given sloped height = 15 units

base radius = 8 units

the height of the cone can be found by using the Pythagorean equation

(sloped height)² = height ² + (base radius)²

15² = h² + 8²

h² = 15²-8² = 161

h = √161

Base surface area = πr² = π 8² = 64π units²

Lateral Surface Area,

= πr √(r² + h²)

= π(8) √[  (8)²  + (√161)²  ]

= 8π√(64 + 161)

= 8π√225

= 8π (15)

= 120π

Surface area = base area + lateral surface area

= 64π + 120π

= 184π units²

Answer:

Explanation:

1. First, calculate the number of hits had during the month, by difference:

2. Round the result to obtain an approximation = 43,000 hits

3. Multiply by the time that each lasted:

Hence, the answer is the option A.

Answer:

17

Step-by-step explanation:

Answer: 56

Step-by-step explanation:

difference goes up by 2 each time.

Final answer:

To find the value of d in the equation 749/d ∙ d/749 = 1, we can simplify the equation and solve for d. Canceling out the like terms and cross multiplying leads us to the solution: d = 1.

Explanation:

To find the value of d in the equation 749/d ∙ d/749 = 1, we need to simplify the equation and solve for d.

We can start by canceling out the like terms: 749 and d. Multiplying the numerators and denominators gives us:
(749/d) ∙ (d/749) = (749 ∙ d) / (d ∙ 749)

Since the two fractions are equal to 1, we can set up the equation:
(749 ∙ d) / (d ∙ 749) = 1

Next, we can cross multiply:
749 ∙ d = d ∙ 749

Now, we can divide both sides of the equation by 749:
d = d ∙ 749 / 749

Simplifying further:
d = 749 / 749

Finally, we arrive at the solution:
d = 1

Two different non-vertical lines in the same plane with the same slope are parallel to each other. The slope determines the angle of the line with respect to the x-axis, and lines with the same slope do not intersect if they have different y-intercepts.

When making a conjecture about two different non-vertical lines in the same plane that have the same slope, one can conclude that these two lines are parallel to each other. This is because the slope of a line represents the steepness and direction of the line, and lines with the same slope will never intersect and are hence parallel. The slope is determined by the ratio of the rise (change in y) over the run (change in x), and as illustrated in Figure A1, the slope is consistent along the entire length of a straight line. If two lines have the same slope but different y-intercepts, they will maintain the same angle with respect to the x-axis but will be positioned at different locations in the plane.

An example is given in Figure A1, where a line has a y-intercept of 9 and a slope of 3. The slope and y-intercept are represented by the 'm' and 'b' terms in the linear equation y = mx + b. Therefore, even if two lines have the same 'm' value, if their 'b' values are different, the lines will be parallel but not coincident (overlapping).

Answer:

Volume of the cone in ascending order.

[tex]V_{2}=270\pi\ units^{3}<V_{3}=300\pi\ units^{3}<V_{4}=363\pi\ units^{3}<V_{1}=400\pi\ units^{3}[/tex]

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let [tex]V_{2}. V_{3}. and\  V_{4}.[/tex] be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

[tex]d_{1} = 20\ and\ h_{1}=12[/tex]

[tex]d_{2} = 18\ and\ h_{2}=10[/tex]

[tex]r_{3} = 10\ and\ h_{3}=9[/tex]

[tex]r_{4} = 11\ and\ h_{14}=9[/tex]

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

[tex]V=\pi r^{2} \frac{h}{3}[/tex]----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for [tex]d_{1} = 20\ and\ h_{1}=12[/tex]

[tex]r_{1} = \frac{d_{1}}{2}[/tex]

[tex]r_{1} = \frac{20}{2}=10\ units[/tex]

[tex]V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}[/tex]

[tex]V_{1}=\pi (10)^{2} \frac{12}{3}[/tex]

[tex]V_{1}=\pi\times 100\times 4[/tex]

[tex]V_{1}=400\pi\ units^{3}[/tex]

Similarly, for volume of the cone for [tex]d_{2} = 18\ and\ h_{2}=10[/tex]

[tex]r_{2} = \frac{d_{2}}{2}[/tex]

[tex]r_{2} = \frac{18}{2}=9\ units[/tex]

[tex]V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}[/tex]

[tex]V_{2}=\pi (9)^{2} \frac{10}{3}[/tex]

[tex]V_{2}=\pi\times 81\times \frac{10}{3}[/tex]

[tex]V_{2}=\pi\times 27\times 10[/tex]

[tex]V_{2}=270\pi\ units^{3}[/tex]

Similarly, for volume of the cone for [tex]r_{3} = 10\ and\ h_{3}=9[/tex]

[tex]V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}[/tex]

[tex]V_{3}=\pi (10)^{2} \frac{9}{3}[/tex]

[tex]V_{3}=\pi\times 100\times 3[/tex]

[tex]V_{3}=\pi\times 300[/tex]

[tex]V_{3}=300\pi\ units^{3}[/tex]

Similarly, for volume of the cone for [tex]r_{4} = 11\ and\ h_{4}=9[/tex]

[tex]V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}[/tex]

[tex]V_{4}=\pi (11)^{2} \frac{9}{3}[/tex]

[tex]V_{4}=\pi\times 121\times 3[/tex]

[tex]V_{4}=\pi\times 363[/tex]

[tex]V_{4}=363\pi\ units^{3}[/tex]

So, the volume of the cone in ascending order.

[tex]V_{2}=270\pi\ units^{3}<V_{3}=300\pi\ units^{3}<V_{4}=363\pi\ units^{3}<V_{1}=400\pi\ units^{3}[/tex]