How do you get the molar ratio and concentration of the acid?

I think it could be "an asteroid" .

➷ It would be a covalent bond most likely. It cannot be an ionic bond as the two elements have the same number of electrons. It also couldn't be a metallic bond as they are obviously not metals.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

The following is true for electronegativity and the bonds formed between atoms:

The difference in electromagnetically is 1.0 (4.0-3.0=1.0). Thus, the bond will be polar covalent, which is a type of covalent bond.

Let me know if you need any clarifications, thanks!

~ Padoru

To calculate the pH after the addition of 10.0 mL of HCl to a 10.0 mL solution of NH3, we need to understand the reaction that occurs between the two. NH3 is a weak base, while HCl is a strong acid. The reaction between NH3 and HCl results in the formation of NH4+ ions and Cl- ions, which will affect the pH of the solution.

To calculate the pH after the addition of 10.0 mL of HCl to a 10.0 mL solution of NH3, we need to understand the reaction that occurs between the two. NH3 is a weak base, while HCl is a strong acid. The reaction between NH3 and HCl is:

NH3 + HCl -> NH4+ + Cl-

This reaction results in the formation of NH4+ ions and Cl- ions. Since HCl is a strong acid, it will completely dissociate in water, while NH3 is a weak base, it will only partially ionize. Therefore, after the addition of HCl, the solution will contain NH4+ ions and Cl- ions, which will affect the pH of the solution.

To calculate the pH, we need to determine the concentration of NH4+ ions in the solution. Since the initial solution of NH3 is 0.300 M, the concentration of NH4+ ions will be equal to the concentration of NH3 that has been converted to NH4+. To find this, we can use the stoichiometry of the reaction:

1 mol NH3 = 1 mol NH4+ ions

Therefore, the concentration of NH4+

...

Final answer:

To calculate the pH after the addition of 10.0 mL of 0.100 M HCl to a 10.0 mL solution of 0.300 M NH3, we need to consider the reaction between NH3 and HCl. NH3 is a weak base and HCl is a strong acid. The balanced chemical equation for the reaction is NH3 + HCl → NH4Cl.

Explanation:

To calculate the pH after the addition of 10.0 mL of 0.100 M HCl to a 10.0 mL solution of 0.300 M NH3, we need to consider the reaction between NH3 and HCl. NH3 is a weak base and HCl is a strong acid.

The balanced chemical equation for the reaction is NH3 + HCl → NH4Cl. Here, NH3 reacts with HCl to form NH4Cl.

Since NH3 is a weak base, it will not completely dissociate in water. However, HCl is a strong acid and will dissociate completely. Therefore, the concentration of HCl will be equal to 0.100 M after the addition.

Using the equation, we can determine the number of moles of HCl added and the resulting concentration of HCl in the final solution. Then, the pH can be calculated using the formula pH = -log[H+], where [H+] is the concentration of H+ ions in the solution.

Answer:

= 0.030 M

Explanation:

We can take x to be the concentration in mol/L of Ag2SO4 that dissolves  

Therefore;  concentration of  Ag+ is 2x mol/L and that of SO4^2- x mol/L.

Ksp = 1.4 x 10^-5

Ksp = [Ag+]^2 [SO42-]

      = (2x)^2(x)

      = 4x^3  

Thus;

4x^3  = 1.4 x 10^-5

         = 0.015 M

molar solubility = 0.015 M

But;

[Ag+]= 2x

Hence; silver ion concentration is

= 2 x 0.015 M

= 0.030 M

Final answer:

The silver ion concentration in a saturated solution of silver(I) sulfate with a Ksp of 1.4 × 10–5 is approximately 1.52 × 10–2 M.

Explanation:

To calculate the silver ion concentration in a saturated solution of silver(I) sulfate, first we must understand that the dissolution of silver sulfate, Ag2SO4, in water can be represented by the equation:

Ag2SO4(s) ⇌ 2Ag+(aq) + SO42-(aq)

Applying the solubility product constant (Ksp), the equilibrium constant expression for this dissolution can be written as:

Ksp = [Ag+]2[SO42-]

Given that the Ksp for silver(I) sulfate is 1.4 × 10–5, and assuming that the concentrations of silver and sulfate ions are equal to their stoichiometric coefficients, we can set up the equation:

1.4 × 10–5 = x2[SO42-]

Where x is the molar concentration of Ag+. Since there are two moles of Ag+ for every mole of Ag2SO4 that dissolves, we can express the sulfate ion concentration as [SO42-] = x, which simplifies the equation to:

1.4 × 10–5 = (2x)2x

Now we can solve for x:

1.4 × 10–5 = 4x3

x3 = 3.5 × 10–6

x ≈ 1.52 × 10–2 M

So the concentration of silver ions, [Ag+], in a saturated solution of silver(I) sulfate is approximately 1.52 × 10–2 M.

When a halogen combines with hydrogen, a covalent molecule is formed.

When a halogen, such as chlorine (Cl), fluorine (F), bromine (Br), or iodine (I), combines with hydrogen (H), they typically form covalent molecules. In covalent bonding, atoms share electrons to achieve a stable electron configuration. Halogens have one electron missing in their outermost electron shell, while hydrogen needs one more electron to complete its shell. To satisfy these electron needs, they share electrons through a covalent bond.

In hydrogen chloride (HCl), hydrogen shares its electron with chlorine, forming a covalent bond. This sharing allows both atoms to achieve a stable electron configuration. Covalent molecules, in contrast to ionic compounds, involve the sharing of electrons rather than the transfer of electrons, resulting in the formation of discrete molecules with relatively low melting and boiling points.

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A hydrogen bomb relies on a nuclear fission bomb to trigger a fusion reaction between deuterium and tritium using lithium deuteride as the fusion fuel. The explosion is enhanced by a U-238 shell which reflects neutrons back into the fuel and fissions to add to the energy output. This process results in a bomb significantly more powerful than atomic bombs.

The construction and subsequent chain of reactions in a hydrogen bomb, or a thermonuclear bomb, typically begin with a nuclear fission bomb. The fission bomb, when exploded, produces extremely high temperatures necessary for fusion to occur. A common method is to use lithium deuteride as the fusion fuel, which is in close proximity to the fission bomb. Upon detonation, the fission bomb's gamma rays heat and compress the fusion fuel. Meanwhile, neutrons from the fission reaction cause the lithium to undergo a reaction to generate tritium: n + 6Li → ³ H + ª He. This newly generated tritium then fuses with deuterium in the reaction 2H+ ³H → He + n + 17.6 MeV, producing helium, another neutron, and a significant amount of energy.

Additional fusion and fission fuels are enclosed within a dense shell of U-238. This uranium shell serves two purposes: it reflects some neutrons back into the fuel to enhance fusion, and the fast-moving neutrons cause the uranium itself to fission, adding to the overall energy output of the bomb.

The first hydrogen bomb was detonated in 1952, but unlike the atomic bomb, a hydrogen bomb has never been used in warfare. Thermonuclear bombs are significantly more powerful than atomic ones - the power of a modern hydrogen bomb is approximately 1000 times that of the bombs dropped on Hiroshima and Nagasaki during World War II.

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Answer:

C. a large amount of solute

Explanation:

To make a solution we need both solute and solvent. Therefore both options A and D are incorrect. In a dilute solution there is a lower concentration of solute dissolved in the solvent. Therefore option B is incorrect.  In a concentrated solution there is a higher concentration of solute dissolved in the solvent. Therefore option C is correct.  

In the concentrated solution there is "large amount of the solute". The correct option is C.

The concentrated solution is the solution in which the solution contains a large amount of the solute as compared to the amount that could be dissolve. When the amount of the solute added to the solvent is in the large amount that could be dissolve then the solution is referred as the concentrated solution.

The concentration of the solution is the measurement of the amount of the solute which is dissolved in the amount of solution or the solvent. The concentrated solution becomes more solute when we added the more solute. Therefore, the option C is correct.

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Answer:

1. Kindly, see the attached image.

2. 18.369 J.

3. Yes, the metal is pure silver.

Explanation:

1. Draw a graph of an exothermic reaction. Label reactants, products and ∆H.

2. Calculate the amount of energy required to raise the temperature of 3.00 g of gold from 45.9 to 93.0°C.

Q = m.c.ΔT.

Where, Q is the amount of energy required to raise the temperature of gold (J).

m is the mass of the gold (m = 3.0 g).

c is the specific heat of gold (c = 0.13 J/g.°C).

ΔT is the temperature difference between the initial and final T (ΔT = 93.0 °C - 45.9 °C = 47.1 °C).

∴ Q = m.c.ΔT = (3.0 g)(0.13 J/g.°C)(47.1 °C) = 18.369 J.

3. 1.70 g of a silvery metal requires 1000.0 J of energy to change its temp from 298 K to 2749 K. Is the metal pure silver?

As mentioned in details in the second point, we can use the relation:

Q = m.c.ΔT

Q = 1000.0 J, m = 1.70 g, ΔT = 2749 - 298 = 2451 °C.

∴ c = Q/(m.ΔT) = (1000.0 J)/(1.70 g)(2451 °C) = 0.239 J/g.°C ≅ 0.24 J/g.°C.

The process is called electrolysis.

Answer:

0.23 V.

Explanation:

∵ ΔG° = -RT lnK.

∴ ΔG° = -RTlnK = -(8.314 J/mol)(298 K) ln(7.3 × 10⁷) = - 44.86 x 10³ J/mol.

∵ ΔG° = - nFE°

∴ E° = - ΔG°/nF = - (- 44.86 x 10³ J/mol)/(2 x 96500 s.A/mol) = 0.2324 V ≅ 0.23 V.

To calculate the value for the standard cell potential (E°) in a redox reaction given the equilibrium constant (K) and the number of electrons transferred, you can use the Nernst equation in a simplified form. The Nernst equation shows the relationship between the cell potential (E), the standard cell potential (E°), the number of electrons transferred (n), and the reaction quotient (Q). Assuming Q=K at equilibrium, solving the equation will provide you the value for E°.

The equilibrium constant, K, for a redox reaction is logarithmically related to the reaction's cell potential. The Nernst equation, an essential concept in electrochemistry, can help calculate the standard cell potential, E°, with the provided K and number of electrons transferred.

The Nernst equation in a simplified form, including values for fundamental constants (R and F) and standard temperature (298 K), along with a factor converting from natural to base-10 logarithms, is:
E = E° - (0.0592/n)logQ Where E° is the standard cell potential, n is the number of electrons transferred, and Q is the reaction quotient, essentially a measure of the value of product and reactants concentrations at any point.

From the equilibrium constant K, we can calculate Q. For a redox reaction at equilibrium, Q is equal to K. Given that the overall redox reaction transfers 2 electrons (n=2), the equilibrium constant, K, is 7.3 x 10^7, and assuming that Q=K, the equation simplifies into: E = E° - (0.0592/2)log(7.3 x 10^7). Solving this equation will give you the value for E°.

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Answer:

4. E) Both A) and C) are true.

5. D) 1.39 J·°C⁻¹g⁻¹

6. C) 5.11 × 10² kJ

Step-by-step explanation:

4. Heat of reaction

H₂(g) + ½O₂(g) ⟶ H₂O(ℓ); ΔH° = -286 kJ

A) The negative sign tells you that energy  has gone out of the system. Therefore, the reaction is exothermic.

B) is wrong. The reaction is exothermic.

C) If energy has left the system (and the products are part of the system), the enthalpy of the products is less than that of the reactants,

D) is wrong. Energy is released from the system.

E) Both A) and C) are correct, so E) is the correct answer.

5. Specific heat capacity

q = mCΔT

C = q/(mΔT)

Data:

q = 166.7 J

m = 15.0 g

T₁ = 25.00 °C

T₂ = 33.00 °C

Calculation:

ΔT = T₂ - T₁ = (33.00 - 25.00) °C = 8.00 °C

C = 166.7/(15.0× 8.00) = 1.39 J·°C⁻¹g⁻¹

The specific heat capacity of mercury is 1.39 J·°C·g⁻¹.

6. Heat of combustion

M_r:     46.1

        C₂H₅OH + 3O₂ ⟶ 2CO₂ + 3H₂O; ΔH = -1.37 × 10³ kJ

m/g:     17.2

n =17.2/46.1 = 0.3731 mol

q = nΔH = 0.3731 × (-1.37 × 10³) = -511 kJ = -5.11 × 10² kJ

The reaction releases 5.11 × 10² kJ of heat.

Fructose O_O

Fructose is the sweetest of the naturally-occurring sugars.

Fructose is the sweetest of all natural sugars, found in fruits, vegetables, honey, and high fructose corn syrup. It is used by plants to attract insects and animals, facilitating pollination and seed dispersal. Sucrose and lactose are other natural sugars with differing sweetness levels and roles.

The question pertains to the identification of the sweetest of all natural sugars. The answer is fructose, which is a monosaccharide that surpasses other sugars in sweetness. Naturally occurring in fruits, vegetables, honey, and high fructose corn syrup, fructose plays a significant role in the diet and the ecosystem.

Sugars like sucrose and lactose are also prevalent in our diets, coming from sources such as sugar cane, sugar beets, and dairy, respectively. Sucrose, commonly known as table sugar, and lactose, known as milk sugar, have their unique roles and sweetness profiles. However, fructose is distinguished by its exceptional sweetness and is employed by plants as a strategy to attract insects for pollination and animals for seed dispersal, creating a beneficial relationship between fauna and flora.

Understanding the types of naturally occurring sugars and their sources can contribute significantly to our knowledge of diet, nutrition, and ecosystem interdependencies.

Answer: option C. in a solution that is 0.20 M in KNO₃.

Explanation:

This question deals with the common ion effect.

Any presence in a solution of a common ion with the solute will decrease its solubility and here you can find why.

AgCl (silver chloride) is highly insoluble in water.

Its solubility equation is given by this equilibrium equation:

  AgCl(s)  ⇄  Ag⁺(aq)  +  Cl⁻(aq)

The constant for this equilibrim is called constant of solubility product and is indicated as Ksp:

Then, any increase of the product ions (on the right side of the equilibrium equation), will result, according to Le Chatelier's principle in a shift of the equilibrium toward the left side, this is in an increase of the AgCl(s), meaning that less AgCl will be soluble.

Let's see in which of the given solutions is AgCl most soluble

A. Solution 0.20 M in CaCl₂

CaCl₂ is a ionic compound which also ionizes in solution, given Ca²⁺ and Cl⁻ ions. So, you can see that it will increase the concentration of Cl⁻, which means that the equlibrium  AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq), will be shifting to the left, decreasing the solubility of silver chloride.

B. Solution 0.20 M in AgNO₃

AgNO₃ is also a ionic salt which dissociates in water giving Ag⁺ and NO₃ ions. So, it will increase Ag⁺ ions, also shifting the equilibrium AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq) to the left, decreasing the solubility of silver chloride.

C. Solution 0.20 M in KNO₃

Since KNO₃ has no common ions with AgCl, it will not affect the equilibrium equation in the same manner and you can expect that AgCl is most soluble in KNO₃.

AgCl is most soluble in the 0.20 M KNO3 solution because it does not provide common ions to AgCl, thus avoiding the reduction of AgCl's solubility due to the common ion effect.

The solubility of AgCl (silver chloride) in various solutions can be affected by the common ion effect. However, due to the formation of a two-coordinate complex with chloride ions, AgCl₂⁻, AgCl's solubility in solutions can differ from what the common ion effect alone would predict. The given information states that AgCl is approximately 10 times more soluble in 1.0 M KCl than in pure water, despite the common ion effect suggesting it should be much less soluble.

Given the choices of:

AgCl would be most soluble in the solution that does not contain a common ion with AgCl. Because CaCl₂ and KNO₃ are both salts with different ions than Ag+ and Cl−, they would not directly provide a common ion that would decrease the solubility of AgCl through the common ion effect. Whereas the AgNO₃ solution contains Ag+ ions which would vastly decrease the solubility of AgCl due to the common ion effect. Therefore, the AgCl is most soluble in the 0.20 M KNO₃ solution (Choice C), because it does not supply any common ions that could reduce its solubility.

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When two magnets are brought near each other, like poles repel; opposite poles attract. When a magnet is brought near a piece of iron, the iron also gets attracted to the magnet, and it acquires the same ability to attract other pieces of iron.

Answer:

The poles closest to each other are opposite poles.

Explanation:

The 60% is the total of the humid y

Answer:

2.5 × 10–5 M H3O+ and 4.0 × 10–10 M OH–

Explanation:

pH = - log[H3O+]

Therefore;

pH = - log[H3O+] = 4.6

Hence;

[H3O+]  = 10^-4.6

             = 2.51 ×10^-5 M

             = 2.5 ×10^-5 M

Additionally;

pH + pOH = 14

Thus; pOH = 14 -pH

                  = 14 -4.6

                  = 9.4

but; pOH = - log [OH-]

Therefore;

[OH-] = 10^-9.4

        = 3.98 × 10^-10 M

        =  4 × 10^-10 M

Answer:

2.5 × 10–5 M H3O+ and 4.0 × 10–10 M OH–

The electromagnetic strength can be increased by increasing the number of coils in the wires but not by decreasing the thickness of the wires - there is no mathematical relationship between wire thickness and field strength.

Hope this helps!

Technology

The answer is c because some plants can die from too much water

Answer: C. amount of rainfall

Explanation:

The amount of rainfall is an abiotic factor (non-living) which is necessary for the growth of plants. The water from the rainfall is necessary for the large scale natural irrigation of an agricultural land, forest, meadow or grassland. The water enters into the soil and through the roots the water is absorbed by the plants.

If a region receives very low annual rainfall then the region may experience desertification. The soil will become compact and dry which cannot support the growth of plants.

If a region receives adequate rainfall then the soil will hold water it will remain fertile to support the diversity of plants.            

A. Dehydration reactions.

Answer:

20.3 L

Explanation:

Assuming that the gas behaves similar to an ideal gas we can use the ideal gas law equation

PV = nRT

Where

P - pressure - 14 atm

V - volume

n - number of moles - 12 mol

R - universal gas constant - 0.0821 L.atm /mol.K

T - absolute temperature - 16 degrees + 273 = 289 K

Substituting the values in the equation

14 atm x V = 12 mol x 0.0821 L.atm/mol.K x 289 K

V = 20.3 L

Answer:

(for those of us with 4 answer choices)

Explanation:

a p e x

A factor that will decrease the rate of chemical reaction is lowering the temperature.

The rate of a chemical reaction is the speed at which a chemical reaction takes place. The rate of chemical reaction is directly proportional to the  concentration of the reactant  and the temperature of the reactant.

That is, as the temperature of the reactant increases, the rate of the reaction increases, while a decrease in temperature will decrease the rate of reaction.

Thus, a factor that will decrease the rate of chemical reaction is lowering the temperature.

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Answer:

              mol(SiO₂)              mol(C)               mol(SiC)                    mol(CO)

Row 1:      0.8 x 10               0.9 x 10              0.3 x 10                     0.6 x 10

Row 2:     0.2 x 10               0.6 x 10              0.2 x 10                     0.4 x 10

Row 3:         8.0                   2.4 x 10                   8.0                        1.6 x 10

Row 4:         2.8                      8.4                        2.8                            5.6

Row 5:        0.816                  2.45                      0.816                         1.63

Explanation:

SiO₂(s) + 3C(s) → SiC(s) + 2CO(g),

It is clear that 1.0 mole of SiO₂ reacts with 3.0 moles of C to produce 1.0 mole of SiC and 2.0 moles of CO.

A. complete the first row. Express your answers using one significant figure separated by commas. Mol C, Mol SiC, Mol CO =

3.0 moles of SiO₂:

We use the triple amount of SiO₂, so we multiply the others by 3.0.

So, it will be 3.0 moles of SiO₂ with 9.0 moles of C that produce 3.0 moles of SiC and 6.0 moles of CO.

B. Complete the second row. Express your answers using one significant figure separated by commas. Mol SiO2, Mol SiC, Mol CO =

6.0 mole of C:

We use the double amount of C, so we multiply the others by 2.0.

So, it will be 2.0 moles of SiO₂ with 6.0 moles of C that produce 2.0 moles of SiC and 4.0 moles of CO.

C. Complete the third row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =

16.0 moles of CO:

We use the amount of CO higher by 8 times than that in the balanced equation, so we multiply the others by 8.0.

So, it will be 8.0 moles of SiO₂ with 24.0 moles of C that produce 8.0 moles of SiC and 16.0 moles of CO.

D. Complete the fourth row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =

2.8 moles of SiO₂:

We use the amount of SiO₂ higher by 2.8 times than that in the balanced equation, so we multiply the others by 2.8.

So, it will be 2.8 moles of SiO₂ with 8.4 moles of C that produce 2.8 moles of SiC and 5.6 moles of CO.

E. Complite the fifth row. Express your answers using three significant figures separated by commas. Mol SiO2, Mol SiC, Mol CO =

2.45 moles of C:

We use the amount of C lower by 0.8167 times than that in the balanced equation, so we multiply the others by 0.8167.

So, it will be 0.8167 moles of SiO₂ with 2.45 moles of C that produce 0.8167 moles of SiC and 1.633 moles of CO.

Answer:

A) [tex]3SiO_2(s)+9C(s)\rightarrow 3SiC(s)+6CO(g)[/tex]

B) [tex]2SiO_2(s)+6C(s)\rightarrow 2SiC(s)+4CO(g)[/tex]

C)[tex]8.0SiO_2(s)+24C(s)\rightarrow 8.0SiC(s)+16CO(g)[/tex]

D)[tex]2.8SiO_2(s)+8.4C(s)\rightarrow 2.8SiC(s)+5.6CO(g)[/tex]

E)[tex]0.816SiO_2(s)+2.45C(s)\rightarrow 0.816SiC(s)+1.63CO(g)[/tex]

Explanation:

[tex]SiO_2(s)+3C(s)\rightarrow SiC(s)+2CO(g)[/tex]

A) When 3 moles of silicon dioxide are present.

According to reaction 1 mole of silicon dioxide react with 3 moles of carbon to give 1 mole of silicon carbide and 2 moles of carbon monoxide.

Then 3 moles of silicon dioxide will react with :

[tex]\frac{3}{1}\times 3mol=9 mol[/tex] of carbon

Then 3 moles of silicon dioxide will give :

[tex]\frac{1}{1}\times 3 mol= 3 mol[/tex] of silicon carbide

Then 3 moles of silicon dioxide will give :

[tex]\frac{2}{1}\times 3 mol= 6 mol[/tex] of carbon monoxide

[tex]3SiO_2(s)+9C(s)\rightarrow 3SiC(s)+6CO(g)[/tex]

B) When 6 moles of carbon are present.

According to reaction 3 moles of carbon reacts with 1 mole of silicon dioxide react with to give 1 mole of silicon carbide and 2 moles of carbon monoxide.

Then 6 moles of carbon will react with :

[tex]\frac{1}{3}\times 6 mol=2 mol[/tex] of silicon dioxde

Then 3 moles of carbon  will give :

[tex]\frac{1}{3}\times 6 mol= 2 mol[/tex] of silicon carbide

Then 6 moles of carbon will give :

[tex]\frac{2}{3}\times 6 mol= 4 mol[/tex] of carbon monoxide

[tex]2SiO_2(s)+6C(s)\rightarrow 2SiC(s)+4CO(g)[/tex]

C)When 6 moles of carbon are present.

According to reaction ,1 mole of silicon carbide and 2 moles of carbon monoxide is produced when, 3 moles of carbon reacts with 1 mole of silicon dioxide reacts.

Then 16 moles of carbon monoxide will be produced from :

[tex]\frac{1}{2}\times 16 mol=8 mol[/tex] of silicon dioxide

Then 16 moles of carbon monoxide will give :

[tex]\frac{3}{2}\times 16 mol= 24 mol[/tex] of carbon

Along with 16 moles of carbon monoxide will give :

[tex]\frac{1}{2}\times 16 mol= 8 mol[/tex] of silicon carbide

[tex]8SiO_2(s)+24C(s)\rightarrow 8SiC(s)+16CO(g)[/tex]

D) When 2.8 moles of silicon dioxide are present.

According to reaction 1 mole of silicon dioxide react with 3 moles of carbon to give 1 mole of silicon carbide and 2 moles of carbon monoxide.

Then 2.8 moles of silicon dioxide will react with :

[tex]\frac{3}{1}\times 2.8 mol=8.4 mol[/tex] of carbon

Then 2.8 moles of silicon dioxide will give :

[tex]\frac{1}{1}\times 2.8 mol= 2.8 mol[/tex] of silicon carbide

Then 2.8 moles of silicon dioxide will give :

[tex]\frac{2}{1}\times 2.8 mol= 5.6 mol[/tex] of carbon monoxide

[tex]2.8SiO_2(s)+8.4C(s)\rightarrow 2.8SiC(s)+5.6CO(g)[/tex]

E) When 2.45 moles of carbon are present.

According to reaction 3 moles of carbon reacts with 1 mole of silicon dioxide react with to give 1 mole of silicon carbide and 2 moles of carbon monoxide.

Then 2.45 moles of carbon will react with :

[tex]\frac{1}{3}\times 2.45 mol=0.8166 mol[/tex] of silicon dioxde

Then 3 moles of carbon  will give :

[tex]\frac{1}{3}\times 2.45 mol= 0.8166 mol[/tex] of silicon carbide

Then 6 moles of carbon will give :

[tex]\frac{2}{3}\times 2.45 mol= 1.6333 mol[/tex] of carbon monoxide

[tex]0.816SiO_2(s)+2.45C(s)\rightarrow 0.816SiC(s)+1.63CO(g)[/tex]

When a soft drink starts to warm to room temperature, the air at the top of the can or bottle starts to sink into the water creating more bubbles and/or fizz. The space at the top of the can or bottle starts to shrink up.

Answer:

As the refrigerant begins to warm up to room temperature, the air inside the bottle that is between the refrigerant and the bottle cap begins to slowly come down. As you might already imagine, air in contact with the liquid can generate bubbles, and this is what happens when the air in the bottle starts to drop as the soda heats up.

Explanation:

You have seen that at room temperature it is common for soda to overflow bubbles. This is because the air inside the soda bottle begins to come down and when it comes in contact with the liquid causes a lot of bubbles and can even make the soda overflow.

The answer is D!

Here is a website to prove my answer:

https://chemstuff.co.uk/unit-2/functional-groups/

Using stoichiometry and the balanced chemical equation provided, the first row of the table is completed with 3 moles of SiO₂, 9 moles of C, 3 moles of SiC, and 6 moles of CO.

The student's question involves completing a table for a chemical reaction with known mole ratios. The balanced equation is SiO₂(s) + 3C(s) ightarrow SiC(s) + 2CO(g). To complete the table for the first row where 9 moles of carbon (C) are provided, we apply stoichiometry based on the balanced equation:

For every 3 moles of C used, 1 mole of SiO₂ is required, so 9 moles of C would need 9/3 = 3 moles of SiO₂.

For every 3 moles of C, 1 mole of SiC is produced, so 9 moles of C will yield 9/3 = 3 moles of SiC.

Each mole of SiO₂ reacts to form 2 moles of CO, so for 3 moles of SiO₂, we will get 3 × 2 = 6 moles of CO.

Therefore, the completed first row is: 3 moles of SiO₂, 9 moles of C, 3 moles of SiC, and 6 moles of CO.

Using the ratio of the given balanced equation, the completed tabel is:

molSiO2             molC             molSiC               molCO

   3                       9                     3                          6    

     1                       3                     1                          2    

   13                    39                   13                          26    

   2.5                  7.5                 2.5                     5.0    

    1.4                    4.2                  1.4                        2.8    

From the question, we are to complete the given table:

molSiO2             molC             molSiC               molCO

_____                   9                    _____              _____

1                         _____               _____              _____

_____                _____              _____                26

_____                  7.5                   _____             _____

1.4                       _____               _____             _____

The given balanced chemical equation is:

SiO₂(s) + 3C(s) → SiC(s) + 2CO(g)

This means

1 mole of SiO₂ is required to react with 3 moles of C to produce 1 mole of SiC and 2 moles of CO

The ratio of equation is:

1 : 3 : 1 : 2

Using this ratio, we can complete the given table

Thus,

Using the ratio of the balanced equation, the completed tabel is

molSiO2             molC             molSiC               molCO

   3                       9                     3                          6    

     1                       3                     1                          2    

   13                    39                   13                          26    

   2.5                  7.5                 2.5                     5.0    

    1.4                    4.2                  1.4                        2.8    

the answer is c- thunderstorms                                                        

dgdfasfdsafdsagdfggxcvxcvxczgdfsgsdfhgfghfjghfgfhjgfd

Answer:

color key

creating a color key

Have known pH values

Explanation:

To determine the pH of a solution using a pH indicator paper, you need a Colour key.

Colour key is need determine the pH of a solution.

To learn more about pH value and colour key refer:https://brainly.com/question/13576450

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