how does gravity affect the velocity of falling objects?

please help asap I need this question answered by tommorow​

In polar covalent bonding, electrons are shared unequally between atoms, due to the unequal distribution of electrons between atoms of different elements, slightly positive and slightly negative charges appear in different parts of the molecule.

In this context, water molecule is an exellent example of this type of bonding:

Water ([tex]H_{2}O[/tex]) can stick to itself through hydrogen bonds, because a water molecule consists of 2 hydrogen atoms attached to 1 oxygen atom.  

The oxygen atom tends to monopolize more electrons and keeps them away from hydrogen. Then, it can be said that a water molecule will have a negative side (oxygen) and a positive side (hydrogen).  

Thanks to this polarity, water molecules can stick together with the formation of hydrogen bonds to attract a partial positive charge of hydrogen and a more electronegative atom, such as oxygen.

Answer

4.8 N

If the box is moving with a constant velocity, then we can say that the system is in equilibrium. This is because if the external force (F->) was greater than other forces the box would be accelerating. This tells us that this force (F->) is just enough to overcome friction and so it must be equal to 4.8 N.

The normal force has no effect to the horizontal velocities or forces. It is equal to -Weight. That is -74 N. The negative sign shows that the force is in opposite direction.

Here is your answer

[tex]<b>5 watts</b>[/tex]

REASON :

Given,

t= 20 secs

F= 20 N

s (displacement)= 5m

Now,

Power= \frac{Work done}{time}

P= W/t ...... (i)

W= F×s×cos(theta)

W= 20×5 × 1 (theta is 0 degree; so cos0= 1)

W= 100 J

Hence,

P= 100/20 (from eq. i)

P= 5 watts

HOPE IT IS USEFUL

Answer:

The coefficient of static friction between the hockey puck and the surface.

Explanation:

Static friction is the force that keeps an object from moving. A force must be applied enough to overcome the static friction to move the object. If a smaller force is applied on the object, there is an equal opposite force by static friction against it.

Force of static friction can be calculated if the coefficient of static friction is known.

Salt + water because salt dissolved in water

To protect a material from the influence of an external magnetic field, the material should be kept in soft iron ring.

So the correct answer is A.

Hope this helps,

Davinia.

its d: mass increase

Answer:

The answer is formation of a solid and release of heat (APEX)

Explanation:

An electrically charged element is called an "ion". A neutral element is an atom.

The changing magnetic field caused by the material's motion induces a current in the coil of wire proportional to the change in field. If a 0 is represented, the magnetic field does not change between the two domains of a bit, so no current is induced as the magnetic material passes the coil.

Answer:

Change in the direction of current in a wire will change the magnetic field caused by that wire

Explanation:

As we know by Biot Savart law that magnetic field due to a current carrying element is given by

[tex]dB = \frac{\mu_o i (\vec {dL} \times \hat r)}{4\pi r^2}[/tex]

so here if the direction of current in the wire reversed then it will change the direction of length vector

This will reverse the direction of magnetic field at a given space

So magnetic field produced by a current carrying element only depends on the direction of the current so on reversing the direction of current we can change the magnetic field direction

Answer:

0.25 m

Explanation:

The period of a pendulum is given by

[tex]T=2 \pi \sqrt{\frac{L}{g}}[/tex]

where  in this case

T = 1.0 s is the period of the pendulum

g = 9.81 m/s^2 is the acceleration due to gravity

L is the length of the pendulum

Re-arranging the equation and solivng for L, we find the length of the pendulum:

[tex]L=g (\frac{T}{2 \pi})^2=(9.81 m/s^2)(\frac{1.0 s}{2\pi})^2=0.25 m[/tex]

Answer:

.248490m

Explanation:

Using the equation:

T=Time

L=Length

g=Gravitational Force≈9.81

T= [tex]2\pi \sqrt{L/g}[/tex] or easier written to find the length using time: [tex]L=\frac{T^{2} *g}{4\pi^{2} }[/tex]

so simply plugging in 1 for T we get [tex]\frac{9.81}{4\pi^{2} } \\[/tex]≈.25m

Final answer:

Ground-based radio telescopes can collect data during both day and night and in all weather conditions (B). They are not affected by daylight or clouds as their observations are based on radio waves which can penetrate atmospheric barriers.

Explanation:

The correct answer to the student's question about when ground-based radio telescopes can collect data from distant objects in space is B. during the day or night and in any weather conditions. Unlike optical telescopes, radio telescopes are not limited by the presence of sunlight or the visibility conditions provided by the Earth's atmosphere. Radio waves can penetrate clouds, and because the Sun is not particularly bright at many radio wavelengths, radio telescopes can operate effectively during both daytime and nighttime. This capability greatly enhances the flexibility of radio astronomy compared to traditional optical astronomy, which can be susceptible to factors such as light pollution and weather conditions.

In contrast to optical observations that often require dry, dark skies and suffer from issues such as light scattering and 'bad seeing' due to atmospheric turbulence, radio telescopes can obtain high-resolution data with technologies like interferometers and very long baseline interferometry. For instance, the Very Long Array (VLA) and the Atacama Large Millimeter/submillimeter Array (ALMA) show the potential of these instruments in capturing precise cosmic phenomena. Moreover, radio astronomy has pushed the boundaries for ground-based observations, with advancements such as radar astronomy that involves both transmitting and receiving signals, enabling studies of celestial bodies within our solar system.

Final answer:

Ground-based radio telescopes can collect data during both the day and night and are not significantly affected by weather conditions. The correct answer is option (B).

Explanation:

Ground-based radio telescopes can collect data from distant objects in space during the day or night and in any weather conditions. Unlike optical telescopes that are impacted by weather and light conditions, radio telescopes are less affected because they collect and focus radio waves.

Weather conditions, such as clouds, or the presence of sunlight do not significantly hinder the operation of radio telescopes, making option B the correct answer: during the day or night and in any weather conditions.

Wave interference is the phenomenon that occurs when two waves meet while traveling along the same medium. The interference of waves causes the medium to take on a shape that results from the net effect of the two individualwaves upon the particles of the medium.Hope this help!

wave interference is the phenomenon that occers when two waves meet while traveling along the same medium. The interference of waves causes the medium to take shape that results that the net effect of the two individual waves upon the particals of the medium.

Kinetic energy = (1/2) (mass) (speed)²

KE = (1/2) (1 kg) (30 m/s)²

KE = (1/2) (1 kg) (900 m²/s²)

KE = 450 kg-m²/s²

KE = 450 Joules

That's at the instant it leaves the thrower's hand.  After that, gravity immediately begins to rob its kinetic energy, so the KE starts decreasing right away.

The kinetic energy of a 1-kilogram ball thrown into the air with an initial velocity of 30 m/sec is 450 J.

The kinetic energy of an object is given by the formula KE = 1/2 mv[tex]^[/tex], where m is the mass of the object and v is its velocity.

In this case, the mass of the ball is 1 kilogram and the initial velocity is 30 m/sec.

Plugging these values into the formula, we get KE = 1/2 * 1 kg * (30 m/sec)[tex]^[/tex] = 450 J.

Period is the time taken for one complete oscillation in a harmonic motion.

Five oscillations take 13.5s

Period= total time for the n vibrations÷ the n vibrations.

Then one oscillation will take 13.5s÷5=2.7s

Therefore the period of the this motion is 2.7s

As speed changes, wavelength changes and frequency stays constant. (1)

Answer:

As speed changes, wavelength changes and frequency stays constant.  

Explanation:

The answer is: The acceleration of the object B is half of the object A.

We can solve this problem applying the Newton's Second Law, which states that the product of the mass and the acceleration of a body is equal to the force applied to that body.

[tex]F=ma[/tex]

So,

For the object A, we have:

[tex]F=15N\\m=25Kg[/tex]

Calculating the acceleration we have:

[tex]a=\frac{F}{m}=\frac{15\frac{kg.m}{s^{2}}}{25Kg}=0.6\frac{m}{s^{2} }[/tex][/tex]

For the object B, we have:

[tex]F=15N\\m=50Kg[/tex]

Calculating the acceleration we have:

[tex]a=\frac{F}{m}=\frac{15\frac{kg.m}{s^{2}}}{50Kg}=0.3\frac{m}{s^{2} }[/tex][/tex]

Hence,

[tex]ObjectA=0.6\frac{m}{s^{2}}\\\\ObjectB=0.3\frac{m}{s^{2}}[/tex]

So, what is true about the acceleration of object A and object B?

The answer is that the acceleration of the object B is half of the object A acceleration since the mass of the object B is two times the mass of the object A.

Have a nice day!

The acceleration of Object A will be greater than the acceleration of Object B, as Object A has half the mass of Object B but both are subjected to the same force.

The question pertains to the basic principles of Newton's Second Law of Motion, which states that the force acting on an object is equal to the mass of that object multiplied by its acceleration (F = ma). For Object A with a mass of 25 kilograms and Object B with a mass of 50 kilograms, both subjected to the same force of 15 newtons, we can determine that Object A will have a greater acceleration than Object B.

To find the acceleration for each object, divide the force by the mass of each object. For Object A: acceleration = 15 N / 25 kg = 0.6 m/s². For Object B: acceleration = 15 N / 50 kg = 0.3 m/s².

Hence, the acceleration of Object A is twice that of Object B, because Object B has twice the mass of Object A and since they are both subjected to the same force.

The specific heat capacities of different metals determine the amount of heat required to raise their temperature by 1K. The metals provided have the following heat capacities.

Aluminium-921

Brass-401

copper-376

Platinum-125

The higher the heat capacity, the more the energy required to raise the temperature. Therefore, aluminium has the least temperature increase.

Answer: A) Aluminum

Explanation:

If you are in USA TEST PREP!!!

Shiny surface are poor radiators of heat

A shiny , silver and smooth surface reduce the heat loss of a hot object to its cooler surroundings​ because good radiators and good absorbed of heat have dull, black and rough surfaces while on the other hand poor radiators have smooth and shiny surfaces therefore they reduce the heat loss of a hot object.

The gravitational force depends on the mass of objects and the distance between them, doubling in force with double the mass and reducing to one-fourth with double the distance due to the inverse-square law.

The relationship between gravitational force, mass, and distance is governed by the universal law of gravitation. According to this law, the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. This can be expressed by the formula F = G (m1*m2) / d2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the objects, and d is the distance between the centers of the two masses.

Doubling the mass of an object would result in a doubling of the gravitational force since force is linearly proportional to mass. Conversely, doubling the distance between two objects would result in the gravitational force being reduced to a quarter of its original value, as the force is inversely proportional to the square of the distance. Therefore, doubling the distance has a more significant effect in decreasing the gravitational force than doubling the mass has in increasing it.

During phase changes, energy changes are usually involved. For example, when solid dry ice vaporizes (physical change), carbon dioxide molecules absorb energy. Meanwhile, when liquid water becomes ice energy is released.

hope this helps :)

Energy can be converted from one form to another according to the law of conservation of energy. In physical changes, energy changes the state of a substance without altering its structure, whereas in chemical changes, it involves in forming and breaking bonds, releasing stored energy. These conversions are commonplace in everyday activities, including energy production from food and fuel.

Energy plays a vital role in both physical and chemical changes according to the law of conservation of energy, which states that energy can be neither created nor destroyed, only changed in form. In physical changes, energy is involved in changing the state of a substance without altering its chemical structure, such as melting ice into water. On the other hand, chemical changes involve the breaking and forming of chemical bonds with energy investment, releasing potential energy stored in molecules.

In everyday situations, energy involved in chemical changes significantly impacts our lives. For example, the macronutrients in food (proteins, fats, and carbohydrates) undergo metabolic reactions providing us with the energy we need. Similarly, fuels like gasoline, natural gas, and coal undergo combustion reactions to produce energy for different activities like transportation and heating.

The conversion of chemical energy into other forms of energy can be seen in many familiar instances, such as batteries in a cell phone or a car where chemical reactions produce electrical energy.

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that isn't a question, and it makes no sense

Answer:

1.quanti

2. quanti

3.quali

4.quanti

5.quanti

6.quali

7.Quali

8?Quanti

9.Quali

10.Quanti

The chemical equation needs to be balanced so that it follows the law of conservation of mass. A balanced chemical equation occurs when the number of the different atoms of elements in the reactants side is equal to that of the products side. Balancing chemical equations is a process of trial and error.

In a closed all mass is conserved.  tThe Conservation of mass explains the balanced chemical equation.

This law states that in a closed system the mass of the total mass of all reactants is equal to the total mass of products in a reaction.

For example -

[tex]\bold {CH_4 + 2O_2 \rightarrow2 H_2O +CO_2}[/tex]

1 mole of methane reacts with 2 moles of oxygen to produce 2 moles of water and 1 mole of Carbon dioxide.

Means 3 moles or reactant 3 moles of products.

Therefore, the Conservation of mass explains the balanced chemical equation.

Learn more about Conservation of mass:

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Answer:

0.25 kg

Explanation:

Newton's second law states that:

[tex]F=ma[/tex]

where

F is the net force acting on an object

m is the object's mass

a is its acceleration

In this problem, we have:

[tex]F=0.5 N[/tex] is the force exerted on the object

m is the ball's mass

[tex]a=2.0 m/s^2[/tex] is its acceleration

Solving the formula for m, we can find the ball's mass:

[tex]m=\frac{F}{a}=\frac{0.5 N}{2.0 m/s^2}=0.25 kg[/tex]

Work = 6N x 12 meters = 72 J

The work done in lifting a 6-newton object by 12 meters is 72 joules.

When a 6-newton object is raised 12 meters, the work done can be calculated using the formula Work (W) = [tex]force (F) imes[/tex] distance (d). In this case, the force is equivalent to the weight of the object since it is being lifted against gravity. Thus, the work done is calculated as W = (6 N)(12 m) = 72 joules (J). Remember, work is the product of the force applied to an object and the distance the object moves in the direction of the force.

Answer:

B. A virtual image that is larger than the object

Explanation:

The magnification of a lens is given by

[tex]m=\frac{h_i}{h_o}=-\frac{d_i}{d_o}[/tex] (1)

where

[tex]h_i[/tex] is the size of the image

[tex]h_o[/tex] is the size of the object

[tex]d_i[/tex] is the distance of the image from the lens

[tex]d_o[/tex] is the distance of the object from the lens

Some considerations:

[tex]h_o, d_o[/tex] are always taken as positive

if [tex]h_i > h_o[/tex], the image is larger than the object, otherwise it is smaller

if [tex]d_i > 0[/tex], the image is real, otherwise it is virtual

In this situation, we have M = 3.0 (positive number and larger than 1). Looking at eq.(1), this implies:

1) [tex]h_i > h_o[/tex] --> image is larger than the object

2) [tex]d_i < 0[/tex] --> the image is virtual

So, the correct choice is

B. A virtual image that is larger than the object

Answer:

B. A virtual image that is larger than the object

Explanation:

Quiz verified

If your mass is 140kg , then your mass is 140kg.  

It doesn't make a bit of difference what time it is, whether you're happy or sad, sleeping or lifting weights or running, whether it's raining or shining, hot or cold, climbing a mountain or falling out of an airplane, on the surface of a planet, asteroid, comet or star, or floating or falling through empty lonely outer space.  Your mass is your mass.  The only way it can change is if YOU make changes in yourSELF, like eating a big steak, sweating through a long tough workout, or skipping dinner, or growing to maturity.

(I guess you're already pretty mature.  If your mass is 140kg, then you weigh about 308 pounds when you're on Earth.)

140 kg. since earth and space have different gravity, you will weigh differently. you dont grow or shrink in size. Weight is just how much your pulling on the earth and how much the earth is pushing back. Its in Newtons 3 laws.

[tex]\bf slope = m = \cfrac{rise}{run} \implies \cfrac{ \stackrel{out put}{f(x_2) - f(x_1)}}{ \stackrel{in put}{x_2 - x_1}}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}[/tex]

'Dispersion of Light' can be defined as the splitting of white light when it passes through a glass prism into its constituent spectrum of colors (i.e. violet, indigo, blue, green, yellow, orange and red).

Light can be split into seven wavelengths when the light is passed through a prism or scatterd by air molecules in the atmosphere.

The term diffraction has to do with the splittiing of light into several wavelengths. This is often achieved by passing the light through a prism which splits it into seven wavelengths.

Hence, light can be split into seven wavelengths when the light is passed through a prism or scatterd by air molecules in the atmosphere.

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Hello! The function of the Pinna is to be a kind of funnel that assists in directing sound further into the ear. Without this funnel the sound waves would take more direct routes to the auditory canal. This would be difficult and wasteful as much of the sound would be lost making it harder to understand the sounds.  Hope this helps!

The pinna plays a crucial role in the auditory system by aiding in sound collection, localization, amplification, and protection of the more sensitive parts of the ear.

The function of the pinna, which is the external part of the ear, is to collect sound waves and funnel them into the ear canal towards the eardrum. Additionally, the pinna helps in localizing the source of a sound by providing directional cues, which are particularly important for vertical localization (determining if a sound is coming from above or below). The unique shape of the pinna also aids in amplifying certain frequencies, which can enhance the perception of sound.

To understand the role of the pinna in sound localization, consider the following:

 1. Sound Collection: The cupped shape of the pinna collects sound waves and directs them into the ear canal. This increases the sound pressure at the eardrum, which is beneficial for hearing faint sounds.

 2. Directional Cues: The pinna's shape causes different frequencies to be reflected or absorbed in a way that depends on the angle of incidence of the sound wave. This creates a unique frequency signature for sounds coming from different directions, especially in the vertical plane.

 3. Amplification: The pinna can amplify certain frequencies, particularly those in the range of human speech, making it easier to hear and understand conversations in noisy environments.

 4. Protection: The pinna also serves to protect the more delicate structures of the middle and inner ear from mechanical damage and foreign objects.