Answer:
The mass of the object on the Moon (and anywhere else) is about 30.61kg. Please see more detail below.
Explanation:
Weight is the gravitational force exerted on the object and is a function of mass and gravitational acceleration:
(weight) = (mass) x (gravitational acceleration)
We are to find the mass, knowing the weight on Earth to be 300N:
(mass) = (weight on Earth) / (gravitational acceleration on Earth) = 300N / 9.8 m/s^2 = 30.61 kg
The mass of the object is 30.61kg.
The mass of the object is independent of gravity. Therefore the answer to the question "What is its mass on the Moon" is 30.61kg.
If the question were what is its weight on the Moon, the answer would be
(weight on Moon) = (mass) x (grav.accel. on Moon) = 30.61kg x 1.62 m/s^2 = 49.59N
which is about 1/6 of the object's weight on the Earth.
A bullet is fired at 660m/s and strikes a target 200.0 meters away. What is the time of the bullet’s flight?
Given data
Velocity of bullet (v) = 660 m/s,
target distance (d) = 200 m ,
time of bullet's flight (t) = (distance traveled) ÷ (velocity of bullet)
= 200 ÷ 660
= 0.30 sec.
Time of bullet's flight is 0.30 seconds.
Landon's new toy arrived in the mail covered in foam packing peanuts. The foam packing peanuts have a mass of 30 g and a volume of 60 cm3. What is the density? 2 g/cm3
180 g/cm
3 0.5 g/cm
3 2
The formula for calculating density is P=M/V where P is the density, M is the mass, and V is the volume.
The problem gives you the mass, 30g, and the volume, 60cm^3;you can plug those into the equation, which should give you P=30/60.
Your answer should end up being P=0.5 g/cm^3.
WORK:
P=M/V
P=30g/60cm^3
P=0.5g/cm^3
Answer:
p=0.5 g/cm3 C is the answer
what are the units for the spring constant,k?
Answer:
[tex]\frac{kg}{s^2}[/tex] or [tex]\frac{N}{m}[/tex]
Explanation:
The force in a spring is described as (F) = (k) x (d) with (d) being the displacement, measured in meters. (F) is to come out in Newtons. So (k) is assigned the appropriate unit for that to happen. The two possibilities listed above achieve that.
Answer:
The units for the spring constant k is [tex]\frac{kg}{s^2}\ \text{or}\ \frac{N}{m}[/tex].
Explanation:
According to hooks law:
[tex]F=-kx[/tex]
Where F is a force, k is spring constant and x is distance.
Here, the negative sign of the force of the spring, which implies the force of the spring, is opposed to the displacement of the spring.
Now in order to find the units for spring constant k, ignore the negative sign as we are looking only at the magnitude.
[tex]F=kx[/tex]
[tex]\frac{F}{x}=k[/tex]
Therefore,
[tex]\frac{kg}{s^2}\ \text{or}\ \frac{N}{m}[/tex]
Hence, the units for the spring constant k is [tex]\frac{kg}{s^2}\ \text{or}\ \frac{N}{m}[/tex].
the force needed to lift a 3000 N truck using a jack with a MA of 15
As we know that mechanical advantage is defined as
[tex]MA = \frac{F_o}{F_{in}}[/tex]
now here we have
[tex]MA = 15[/tex]
also we have
[tex]F_O = 3000 N[/tex]
now we will have
[tex]15 = \frac{3000}{F_{in}}[/tex]
now we will have
[tex]F_{in} = \frac{3000}{15}[/tex]
[tex]F_{in} = 200 N[/tex]
so our applied force will be 200 N
CAN SOMEONE PLEASE HELP ME WITH MY PHYSICS QUESTIONS? I NEED CORRECT ANSWERS ONLY
Consider a situation where you are playing air hockey with a friend. The table shoots small streams of air upward to keep the puck afloat and to minimize friction. When you barely tap the puck forward, it
A. slows and stops.
B. moves with a constant speed until hitting the other end.
C. moves backward with an equal and opposite velocity.
D. continues to accelerate.
Which of the following situations demonstrates balanced forces? A. a child on a moving seesaw B. a car driving on a straight freeway at 60 miles per hour C. a clock's pendulum in motion D. a rock thrown upward, being acted on by gravity
Answer: option B. a car driving on a straight freeway at 60 miles.
Explanation:
A balance forces are said to act on an object when net force on an object is zero and the object is either at rest or moves with constant speed without changing direction.
In option A, C, and D the objects are changing direction during their motion. In option B, a car moves on a straight freeway in a single direction at constant speed of 60 miles per hour. Hence, the correct demonstration of balanced forces is by option B.
the answer is the car on the highway of your doing study island
Suppose you are pushing a car with a certain net force. If you then push it twice the net force, the car's acceleration
A. becomes four times as much.
B. becomes two times as much.
C. stays the same.
D. becomes half as much.
From my calculations The answer is B
A horizontal force of 90.0 N is required to push a 75.0 kg along a horizontal surface at a constant speed. What is the magnitude of the force of friction (90.0N)
== You're pushing the load straight along the horizontal surface at a constant speed.
== The speed and direction of the load are not changing, so there is no acceleration.
== From Newton's 2nd law of motion, we know that F = m A . Since A=0, F must also be zero. That means NO NET FORCE is acting on the load.
== But how can that be ? You're pushing it with 90 N !
== The NET force is zero. So something else must be pushing the box, also with 90 N of force, exactly opposite to YOUR force, and they add up to zero.
== THERE's your force of friction !
In this case, the force of friction is 90.0 N. This is inferred from the fact that the object is moving at a constant speed, implying that the force applied is countered by an equal force of friction. This is an application of Newton's first law of motion.
Explanation:The force of friction can be determined by using the basic principles of physics. In the scenario presented, the box is being moved at a constant speed, which implies that the force of friction is equal to the force applied, 90.0 N. This is because when an object moves at a constant speed, it suggests there is a balance of forces meaning the force you're applying (90.0 N in this case) is battling against an equal force in the opposite direction, this opposing force being the force of friction.
This applies the principles of Newton's first law - an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force. This equilibrium of forces is what's keeping the box moving at a constant speed.
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In a cricket match, the 0.16kg ball is bowled with a straight arm. During one particular delivery, the ball leaves the bowler's hand horizontally, with a speed relative to the ground of 80.8 mph. The bowler's arm is 0.64 m long and the bowler is running at 10.0 mph when the ball is released.
Calculate the centripetal force exerted on the ball in the bowler's hand, in N.
Note: 1 mph = 0.447 ms^-1.
Answer:
412.1 N
Explanation:
First of all let's calculate the total speed of the ball as it is released, which is equal to the speed of the ball + the speed of the bowler:
[tex]v=80.8 mph +10.0 mph=90.8 mph[/tex]
Now let's convert it into m/s. We know that
[tex]1 mph = 0.447 m/s[/tex]
So
[tex]1 mph:0.447 m/s = 90.8 mph:v\\v=\frac{(0.447 m/s)(90.8 mph)}{1 mph}=40.6 m/s[/tex]
And now we can calculate the centripetal force, which is given by:
[tex]F=m\frac{v^2}{r}[/tex]
where
m = 0.16 kg is the mass of the ball
v = 40.6 m/s is the speed of the ball
r = 0.64 m is the radius of the circular path (equal to the length of the bowler's arm)
Substituting:
[tex]F=(0.16 kg)\frac{(40.6 m/s)^2}{0.64 m}=412.1 N[/tex]
what the hell does "Give an example of a situation in your life in which you depend on testing and evaluation in a product design to keep you safe." even mean?
A force of 200N acts on a surface of area 10cm2 normally calculate the pressure exerted on the surface
The SI unit of pressure is the pascal (Pa). It is a derived unit equal to 1 newton per square meter (1 N/m²).
Your pressure is ...
... (200 N)/(10 cm²) × (100 cm/m)² = 200,000 Pa
how would you present weight change if earth had twice the mass that it does now
It would double. g = GM/r^2 where G is the gravitational constant, M is the mass of the Earth, and r is the radius of the Earth. So, if the Earth's mass doubled, g would double, therefore, so would your weight
2350m = is how many kilameters
Answer:
2.35 killometers
Explanation:
an airplane travels at a speed of 90 m/s for 30 minutes. how far does it travel?
a geostationary satellite has a orbital radius of 4.23*10.7m.
a).calculate it’s speed in orbit
Answer ;
Note : Satellite completes one orbit in the same time the earth rotates one about its axis
circumference of the orbit = 2 ×π × 4.23×10⁷ (similar to the earth orbital speed
The time of earth/orbit traveled = 23.93 hrs ,
Speed of the orbit = (distance) ÷ (time)
= circumference ÷ time
= (2 ×π × 4.23×10⁷) ÷ 23.93 (1 hr = 3600 sec.)
= 3085.14 m/s
The orbital velocity is 3085.14 m/s
a car travels at a speed of 20 km/hr for 3 hours. how far does it travel in kilometers
Formula
d = r * t
Givens
r = 20 km/hourt = 3 hoursd = ??Solution
d = 20 km/hour * 3 hrd = 60 km the hours cancel outi did this in class a while ago so you multiply 20 * 3. And you answer is 60.
if you need any more help feel free to message me :)
A 70 kg man is walking at a speed of 2 m/s. What is his Kinetic Energy?
Kinetic energy = 1/2 (mass) (speed squared)
KE = 1/2 (70kg) (2m/s)^2
KE = (35 kg) (4 m^2/s^2)
KE = (140) kg-m^2/s^2
That's 140 Newton-meter
or
140 Joules
The kinetic energy is 140 joules
The parameters given in the question are
mass= 70 kg
velocity= 2m/s
Kinetic energy= 1/2mv²
= 1/2 × 70 × 2²
= 0.5 × 70 × 4
= 140 joules
Hence the kinetic energy is 140 joules
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A 50 Kg box sits at rest on a 30 degree ramp where the coef of static friction is 0.5773. How hard would you have to push horizontally to get the box to start to move up the ramp?
Given data
m = 50 Kg
Weight(W) = 50×9.81 = 490.5 N
Coefficient of friction (μs) = 0.5773
Angle of ramp = 30 degrees
Determine the horizontal push (P) = ?
P cos Θ = W sin Θ + μs P sin Θ + μs W cos Θ
P (cos Θ -μs sin Θ ) = W ( sin Θ + μs cos Θ)
P = W ( sin Θ + μs cos Θ)/ (cos Θ -μs sin Θ )
P= 841.58 N
Harizontal push is required = 841.58
Complete the steps for converting 3.6 gallons per minute to milliliters per second. (1 gallon = 3.79 liters and 1 liter = 1,000 milliliters)
Given that,
Capacity = 3.6 gallons per minutes
Convert it into milliliters per seconds
Since, 1 gallon = 3.79 liters
1 liters = 1000 milliliters
Capacity= (3.6*3.79*1000)/(60)
Capacity = 227.4 milliliters per second.
3.6 gallons per minute is equivalent to a flow rate of 227.4 milliliters per second.
Here are the steps to convert 3.6 gallons per minute to milliliters per second:
Convert gallons to liters: 3.6 gallons * 3.79 liters/gallon = 13.644 liters per minute.
Convert minutes to seconds: Since there are 60 seconds in a minute, divide 13.644 liters by 60 to get the flow rate in liters per second: 13.644 liters / 60 seconds = 0.2274 liters per second.
Convert liters to milliliters: Since there are 1,000 milliliters in a liter, multiply 0.2274 liters by 1,000 to get the flow rate in milliliters per second: 0.2274 liters * 1,000 milliliters/liter = 227.4 milliliters per second.
Therefore, 3.6 gallons per minute is equivalent to 227.4 milliliters per second.
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What is noetic science?
Noetic science is an interdisciplinary field that aims to understand consciousness and the human mind. It stems from the Greek word 'noesis' which means inner wisdom, direct knowing, or subjective understanding. It shares some principles with physics, particularly quantum physics, but also extends beyond traditional physics to explore consciousness and subjective experiences.
Explanation:Noetic science, which also aligns with concepts in cognitive science, is an interdisciplinary field that seeks to understand the nature of consciousness and the human mind. It looks into the capabilities of the mind beyond the physical realm and tries to understand phenomena like cognition and intuition.
The terms noetic science comes from the Greek word "noesis" which means inner wisdom, direct knowing, or subjective understanding. In essence, it is about investigating the nature of consciousness, going a step beyond the traditional physical sciences.
It explores the idea that consciousness isn't solely a product of the brain and attempts to bridge the gap between the objective sciences and the inner subjective experience. This would indeed fall under the wider umbrella of physics as it deals with aspects of energy and matter.
It shares some principles with physics, specifically quantum physics, in the sense that it investigates the fundamental nature of the universe and the interactions of energy and matter. However, it extends these investigations to encompass consciousness and subjective experiences which are more difficult to quantify and measure.
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if an object is moving at a constant speed, the forces acting on it must be ___. Another way to say this is that the net force = __.
Answer : Equal, Zero
If the object is moving at constant speed, it is under "equilibrium". So, forces acting on object are equal and the net force is zero.
A truck travelled at a constant speed for 6 hours. Then , it decreased itd speed by 13 mph for the remaining 228 miles. If the total distance was 876 miles, how long did it take to travel the remaining 228 miles
Answer:
Time taken to travel remaining 228 miles = 2.4 hours.
Explanation:
Total distance = 876 miles.
Distance traveled after speed reduction = 228 miles
So, distance traveled before = 876 - 228 =648 miles.
Time taken for this = 6 hours.
Speed before speed reduction = 648/6 = 108 mph.
Speed after speed reduction = 108 - 13 = 95 mph
Time taken to travel remaining 228 miles = 228/95 = 2.4 hours.
Answer:
2.4
Explanation:
I just had this question
A 0.14-kg pinecone is 16m above the ground. What is it’s gravitational potential energy
Given that:
mas (m) = 0.14 Kg ,
height (h) = 16 m,
Determine gravitational potential energy ?
Gravitational potential energy = m × g × h
= 0.14 × 9.81 × 16
= 21.97 Joules
Newton’s first law of motion is sometimes described as _____. the net force law the law of inertia the law of gravity F = ma
Newton's First Law expresses that a question will stay very still or in uniform movement in a straight line except if followed up on by an outer power. It might be viewed as an announcement about latency, that articles will stay in their condition of movement except if a power demonstrations to change the movement.
Hope this helps. ^_^
Answer:
The correct answer option is: the law of inertia.
Explanation:
Newton’s first law of motion is sometimes described as the law of inertia.
According to the first law of Newton, an object will remain at rest or in uniform motion in a straight line until and unless an external force is applied on it.
This law is also referred to as the law of inertia since the object tries to remain in its present or existing state of motion, showing resistance to bring change in its state.
a box with a mass of 12.5kg sits on the floor how high would you need to lift it has a GPE of 568j
A little help please?
Dora rolled a marble down a ramp and recorded the potential energy and kinetic energy of the marble at different positions on the ramp, as shown in the table.
(Look at Picture)
Which is the constant variable in this experiment?
A. Mass of marble
B. Kinetic energy of marble
C. Potential energy of marble
D. Height of marble from ground
Mass of marble is the constant variable in this experiment. Hence, option (C) is correct.
What is control variable?A control variable, also known as a scientific constant, is an experimental component that remains constant (controlled) and unaltered over the course of a research.
If control variables were not maintained constant throughout the experiment to examine the relative relationship between the dependent variable (DV) and independent variable(IV), the outcomes of the experiment could be significantly impacted . The experimenter is not very interested in the control variables themselves.
In this experiment, Mass of marble remains constant. So, Potential energy of marble is the constant variable in this experiment. Hence, option(C) is correct.
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Object A has of mass 7.20 kilograms, and object B has a mass of 5.75 kilograms. The two objects move along a straight line toward each other with velocities +2.00 meters/second and -1.30 meters/second respectively. What is the total kinetic energy of the objects after the collision, if the collision is perfectly elastic?
A.
19.3 joules
B.
21.9 joules
C.
38.5 joules
D.
43.0 joules
E.
50.8 joules
Answer:
A. 19.3 joules
Explanation:
The collisions is perfectly elastic: this means that both total momentum and total kinetic energy are conserved after the collision.
Therefore, we can just calculate the total initial kinetic energy before the collision, and then say that it is equal to the total kinetic energy after the collision.
The kinetic energy of object A is:
[tex]K_A = \frac{1}{2}m_A v_A^2=\frac{1}{2}(7.2 kg)(+2.0 m/s)^2=14.4 J[/tex]
The kinetic energy of object B is:
[tex]K_B = \frac{1}{2}m_B v_B^2=\frac{1}{2}(5.75 kg)(-1.3 m/s)^2=4.9 J[/tex]
So, the total kinetic energy before (and after) the collision is
[tex]K=K_A + K_B=14.4 J+4.9 J=19.3 J[/tex]
A force of 8480 is applied to a car to decelerate it at a rate of 32.0 m s squared. What is the mass of the car?
Given data
Force (F) = 8480 N,
acceleration (a) = -32 m/s² ,
mass of the car (m) = ?
We know that, from Newtons II law,
F = m.a
=> m = F ÷ a ,
= 8480 ÷ (-32)
= 265 Kg (Neglect negetive sign)
Mass of the car is 265 Kg
The magnitude of the centripetal force acting on an object traveling in a horizontal circular path will decrease and if the
Answer:
The radius of the path is increased
Explanation:
The centripetal force is represented by the equation:
[tex]F=\frac{mv^2}{r}[/tex]
where [tex]F[/tex] is the centripetal force, [tex]m[/tex] is the mass of the object on the circular path, [tex]v[/tex] is its velocity and [tex]r[/tex] the radius of the circle
From the equation we can observe that the centripetal force and the radius of the circular path are inversely proportional: if the radius increases the force decreases, and if the radius decreases the force increases.
Thus, the complete sentence is:
The magnitude of the centripetal force acting on an object traveling in a horizontal circular path will decrease and if the radius of the path is increased
The magnitude of centripetal force will decrease if the radius of the circular path increases, as the force is inversely proportional to the radius of curvature while being directly proportional to the square of the velocity and the mass of the rotating body.
Explanation:The magnitude of the centripetal force acting on an object traveling in a horizontal circular path is influenced by several factors, including the mass of the object, its velocity, and the radius of the path. Newton's second law implies that the centripetal force, which is always directed towards the center of rotation, is essential in maintaining circular motion. If we use the formula Fc = mv2/r, where Fc is the centripetal force, m is the mass, v is the velocity, and r is the radius, it is clear that the centripetal force is directly proportional to both the mass and the square of the velocity, but inversely proportional to the radius.
Therefore, an increase in the radius of the circular path would result in a decrease in the centripetal acceleration and thus, a decrease in the centripetal force, as centripetal acceleration (ac = v2/r) is directly proportional to the square of the object's velocity and inversely proportional to the radius of curvature (r).
you add 8950 J of heat to 174 g of iron. What is the temperature of the iron (c=452 J/(kj * C degrees))?