In a certain grocery store, strawberries cost $5.92 per pound ( 5.92 dollars/lb ). what is the cost per ounce?

Sample Response: There is no solution to the system in its original form. There are no points in common. If the signs are reversed, the system has an intersection with an infinite number of solutions.

Solution:

The table which is about kind of jeans and it's color is

Style       Color  

regular      light blue  

loose fit    indigo  

boot cut     washed  

slim fit       black

 slim fit     blue

(a) A regular can be chosen out of five  colors, A loose fit can also be chosen in five colors,Similarly a boot cut as well as slim fit can also  be chosen out of five colors.

If you consider this as a relation , total number of relation that is total jeans =  1×5 + 1×5 +1×5+1×5= 20 Jeans = 10 Pairs of jeans(Possible)

(b)  Total number of jeans , if i have one pair of jeans of each possible style and color = As there are 5 colors and 4 styles , the jeans are in pair = 5×4×2=40

Number of Black color jeans = 2× black color in  4 styles= 2×4=8

Probability of an event = [tex]\frac{\text{Total possible outcome}}{\text{Total favorable outcome}}[/tex]

Probability of choosing a pair of black jeans at random=[tex]\frac{8}{40}=\frac{1}{5}[/tex]

28 x 4 = 112

30 x 4 = 120

32 x 4 = 128

34 x 4 = 136

36 x 4 = 144

domain = {112,120,128,136,144}

The total amount that Isaiah spent at the store will be equal to $27.44.

Mathematical expressions with two algebraic symbols on either side of the equal (=) sign are called equations.

This relationship is illustrated by the left and right expressions being equal to one another. The left-hand side equals the right-hand side is a basic, straightforward equation.

As per the given information in the question,

Amount spent by Isaiah on gift = $19.60

Let the total amount spent at the store be x.

The amount that he spent on the gift was 5/7 of the total amount that he spent at the store.

So, the equation according to the statement will be,

5/7 of x = $19.60

x = (19.60 × 7)/5

x = 137.2/5

x = $27.44

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Isaiah spent 5/7 of the total amount at the store on a gift. To find the total amount spent, represented by x, we use the equation (5/7) * x = $19.60 and solve for x by multiplying $19.60 by 7/5, which yields $27.44.

The question involves finding the total amount spent by Isaiah at the store. Since it is given that $19.60 is 5/7 of the total amount, we can set up the following equation to represent this information: (5/7) * x = $19.60. To find x, we need to perform the inverse operation, which is to divide $19.60 by 5/7, or equivalently to multiply $19.60 by the reciprocal of 5/7, which is 7/5.

Here is the step-by-step solution:

Answer:

The most common salary is $605. The salary that half the employees salaries surpass is $630. The percent of employees salary that serve because $700 is 75%. Percent of employees salaries that were less than $480 is 25%. The 9% percent of employees salaries this surpass $891 years. The total weekly salary of 104 employees is 57200.

Step-by-step explanation:

It is given that mean is $550, first quartile is $480,  median is $630, third quartile is $700,  mode is $605 and 91st percentile is $891.

First quartile is at 25% of the data, median is at 50% of the data, third quartile is at 75% of the data.

The mode of a set of data values is the value that occurs most often.

The most common salary is mode, therefore the most common salary is $605.

The salary that half the employees salaries surpass is $630. Because median is the half of the data.

The percent of employees salary that serve because $700 is 75%. Because $700 is third quartile.

Percent of employees salaries that were less than $480 is 25%. Because $480 is first quartile.

The percent of employees salaries this surpass $891 years is 9%. Because $891 is 91 percentile. Therefore 9% employees get more than $891.

If the company has 104 employees than the total salary of employees is

[tex]104\times 550=57200[/tex]

because means is $550, therefore the total weekly salary of 104 employees is 57200.

The most common salary is [tex]605USD[/tex].

The salary that half the employees' salaries surpass is [tex]630USD[/tex].

The percent of employees salary that serves because [tex]700USD[/tex] is [tex]75[/tex]%.

The percent of employees' salaries that were less than [tex]480USD[/tex] is [tex]25[/tex]%.

The [tex]9[/tex]% percent of employees' salaries surpass [tex]891USD[/tex] years.

The total weekly salary of [tex]104[/tex] employees is [tex]57200[/tex].

Given Mean is [tex]550USD[/tex], the first quartile is [tex]480USD[/tex].

The Median is [tex]630USD[/tex], the third quartile is [tex]700USD[/tex], the Mode is [tex]605 USD[/tex] and the [tex]91st[/tex] percentile is [tex]891USD[/tex].

The first quartile is at [tex]25[/tex]% of the data, the median is at [tex]50[/tex]% of the data, the third quartile is at [tex]75[/tex]% of the data.

The mode of a set of data values is the value that occurs most often, So the most common salary is a mode, therefore the most common salary is [tex]605USD[/tex].

As the median is half of the data, the salary that half of the employees' salaries surpass is [tex]630USD[/tex].

Given that [tex]700USD[/tex]  is the third quartile, so the percent of employees ' salary that serves

The Percent of employees' salaries that were less than is % as  first quartile.

The percent of employees salaries this surpass $891 years is [tex]9[/tex] %. Because [tex]891USD[/tex] is [tex]91[/tex] percentile. Therefore more than [tex]891USD[/tex].

If the company has [tex]104[/tex] employees then the total salary of employees is

[tex]104\times550=57200[/tex] because means is [tex]550USD[/tex], therefore the total weekly salary of [tex]104[/tex] employees is [tex]57200 USD[/tex].

Therefore, the most common salary is [tex]605USD[/tex]. The salary that half the employees' salaries surpass is [tex]630USD[/tex]. The percent of employees salary that serves because [tex]700USD[/tex] is [tex]75[/tex]%. The percent of employees' salaries that were less than [tex]480USD[/tex] is [tex]25[/tex]%.The [tex]9[/tex]% percent of employees' salaries surpass [tex]891USD[/tex] years and the total weekly salary of [tex]104[/tex] employees is [tex]57200[/tex][tex]USD[/tex].

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The problem calculates the probability of forming a legitimate basketball starting lineup from a given roster, using combinatorial methods to determine the ratio of favorable outcomes to total outcomes.

The question asks for the probability of selecting a legitimate starting lineup for a basketball team, given a roster with specific numbers of guards, forwards, centers, and swing players. A standard basketball starting lineup consists of 2 guards, 2 forwards, and 1 center. Given the roster has 3 guards, 5 forwards, 3 centers, and 2 swing players (who can play either guard or forward), we calculate the probability of forming a legitimate lineup through combinatorial methods.

To calculate the total number of ways to form a starting lineup, we consider the swing players as forwards when calculating combinations since they can play either role. The total number of ways to choose 2 guards out of 5 possible options (3 guards + 2 swing players), 2 forwards out of 7 possible options (5 forwards + 2 swing players treated as forwards), and 1 center out of 3 options is given by the product of combinations: C(5,2) * C(7,2) * C(3,1).

The total number of ways to select any 5 players out of the 13 (without regard for position) is C(13,5). Therefore, the probability is the ratio of these two numbers, rounded to three decimal places.

1 gallon = 16 cups

 2 gallons = 16 x 2 = 32

32-10=22

 there will be 22 cups left over

Answer:

Step-by-step explanation:

1 gallon = 16 cups

2 gallons = 16 x 2 = 32

32-10=22

there will be 22 cups left over

Answer: B: x-3 >_ 0

Step-by-step explanation:

Took test

The required percentages are:

(a) 86.64%

(b) 0.62%

(c) 0.04%

With the use of standard normal table, we can find the required percentage, such as:

(a)

→ [tex]P( -1.5<z<1.5)= P( z <1.5)- p( z < -1.5)[/tex]

                                 [tex]= 0.9332-0.0668[/tex]

                                 [tex]= 0.8664[/tex]

                                 [tex]= 86.64[/tex] (%)

(b)

→ [tex]P( z >2.5)=0.0062[/tex]

                    [tex]= 0.62[/tex] (%)

(c)

→ [tex]P( z < -3.5) + p( z > 3.5) = 0.0002+0.0002[/tex]

                                           [tex]= 0.0004[/tex]

                                           [tex]=0.04[/tex] (%)  

Thus the above approach is right.

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Answer:

The answer is 3/4

Step-by-step explanation:

Answer:

3rd Option is correct.

Step-by-step explanation:

Given: Equation is y = 3x - 1

We need to find another equation such that system of equation has infinitely solutions.

We know that System of Equations having infinitely many solution has ratio as following,

[tex]\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}[/tex]

where a is coefficient of x and b is coefficient of y while c is constant term.

Clearly from Given Options Second equation is not a line with different coefficients. Its actually same with some changes.

Consider,

y = 3x - 1

transpose 3x to LHS

y - 3x = -1

Multiply both sides with -1

-y + 3x = 1

3x - y = 1

Therefore, 3rd Option is correct.

Answer:

The figure is a rectangle

Step-by-step explanation:

* Lets explain how to solve the problem

- To prove the following set of coordinates represents which figure

  lets find the distance between each two points and the slopes of

  the lines joining these points

- The rule of the distance between two point is

 [tex]d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]

- The rule of the slope is [tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

- Remember:

* Parallel lines have same slopes

* The product of the slopes of the perpendicular lines is -1

# points (7 , 10) and (4 , 7)

∵ [tex]d1=\sqrt{(4-7)^{2}+(7-10)^{2}}=\sqrt{18}[/tex]

∵ [tex]m1=\frac{7-10}{4-7}=\frac{-3}{-3}=1[/tex]

# points (4 , 7) and (6 , 5)

∵ [tex]d2=\sqrt{(6-4)^{2}+(5-7)^{2}}=\sqrt{8}[/tex]

∵ [tex]m2=\frac{5-7}{6-4}=\frac{-2}{2}=-1[/tex]

# points (6 , 5) and (9 , 8)

∵ [tex]d3=\sqrt{(9-6)^{2}+(8-5)^{2}}=\sqrt{18}[/tex]

∵ [tex]m3=\frac{8-5}{9-6}=\frac{3}{3}=1[/tex]

# points (9 , 8) and (7 , 10)

∵ [tex]d4=\sqrt{(7-9)^{2}+(10-8)^{2}}=\sqrt{8}[/tex]

∵ [tex]m4=\frac{10-8}{7-9}=\frac{2}{-2}=-1[/tex]

∵ d1 = d3 = √18 and d2 = d4 = √8

∴ Each two opposite sides are equal

∵ m1 = m3 = 1 and m2 = m4 = -1

∴ Each two opposite sides are parallel

∵ m1 × m2 = 1 × -1 = -1

∵ m2 × m3 = 1 × -1 = -1

∵ m3 × m4 = 1 × -1 = -1

∵ m4 × m1 = 1 × -1 = -1

∴ Each two adjacent sides are perpendicular

- The set of coordinates represents a figure has these properties:

1. Each two opposite sides are equal

2. Each two opposite sides are parallel

3. Each two adjacent sides are perpendicular

∴ The figure is a rectangle

Final answer:

To find the position vector given the acceleration, initial velocity, and initial position, we integrate the acceleration vector to find the velocity vector, and then integrate the velocity vector to find the position vector. The resulting position vector is r(t) = (⅔t³ + t)i - sin t j - ¼ cos 2t k.

Explanation:

Finding the Position Vector

The question asks us to find the position vector of a particle given its acceleration vector a(t) = 8t i + sin t j + cos 2t k, initial velocity v(0) = i, and initial position r(0) = j. To find the position vector, we first need to integrate the acceleration vector to find the velocity vector, and then integrate the velocity vector to find the position vector.

Step 1: Find the Velocity Vector

Integrate the acceleration vector for time to get the velocity vector. The indefinite integral of the acceleration vector gives:

Using the initial velocity v(0) = i, we find C1 = 1, C2 = 0, and C3 = 0. Therefore, the velocity vector is v(t) = (4t² + 1)i - cos t j + ½sin 2t k.

Step 2: Find the Position Vector

Integrate the velocity vector concerning time to get the position vector. The indefinite integral of the velocity vector gives:

Using the initial position r(0) = j, we find C4 = 0, C5 = 1, and C6 = 0. Thus, the position vector is r(t) = (⅔t³ + t)i - sin t j - ¼ cos 2t k.

The number of three person group that can be formed in a club of 8 people would be = 56.

To calculate the number of three person groups when 8 people are involved, the following steps needs to be taken as follows;

The combination formula should be used = n!/(n-r)!r!

Where:

n= 8

r= 3

Combination=8!/(8-3)!×3!

= 8×7×6×5!/5!×3!

= 8×7×6/3×2×1

= 336/6

= 56

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x *9 =35

x =35/9

 if you need it in decimal format it would be 3.888888889