Dalila plans an experiment to examine plant growth. She
made a table to record her results.
What addition to her table would most improve her
experimental investigation?
O a row in which no fertilizer is used
a row in which 12 grams of fertilizer are used
O a column that shows how the dependent variable
changes
a column that shows how the independent variable
changes
Answer:
Its A. On Edg
Explanation:
The addition to Dalila's table that would most improve her experimental investigation is a column that shows how the independent variable changes. Option C
What addition to her table would most improve her experimental investigation?Adding a column that displays how the independent variable is changing would give us helpful information about the specific thing we are changing in the experiment. In this situation, Dalila is testing different things like the amount or type of fertilizer.
Dalila can watch how the independent variable changes and see how it affects plant growth. She can then compare different conditions or treatments to understand what works best. This would help us better understand and explain the data, which would make our conclusions about how the independent variable affects plant growth more reliable.
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At which two points will the kinetic energy of the block be the same? A and B A and C B and D B and C
Answer:
B and D
Explanation:
I included the picture associated with the problem below:
Seeing as B and D are at the same level here, they posses the same amounts of kinetic energy. Another pair that would be correct, although it is not a choice, is A and E. This is because they too have the same kinetic energy (0J because they are stationary). Hope this helps! :)
A 0.25-g paint chip comes off a satellite
orbiting Earth. The velocity of the paint
chip is 7000 m/s. Which is the kinetic
energy of the paint chip?
Answer:
6125 J
Explanation:
Kinetic energy, [tex]KE=0.5mv^{2}[/tex] where m is the mass of the paint chip while v is the velocity of the paint chip. Substituting m with 0.25g= 0.00025 Kg while v is 7000 m/s then
[tex]KE=0.5\times 0.00025\times 7000^{2}=6125 J[/tex]
Therefore, the kinetic energy is equivalent to 6125 J
1.)Describe an experience where you encountered a buoyant force and tell what it felt like.
answer ASAP please. (Not to be rude)
Swimming: Knowing I would not sink made feel safe.
Taking off in an aircraft: I felt heavier.
Explanation:
The buoyant force originates from the weight applied to the item by the liquid. Since the weight increments as the profundity press, the base of an article are constantly bigger than the power on the top - consequently the net upward power.
It follows up on an article inverse to gravity by liquid which is being submerged mostly or totally in the liquid. It contradicts the heaviness of the item. The buoyant force is given by volume dislodged by an item into the thickness of liquid into gravitational quickening.
Which type of force is used by your legs to pedal a bicycle?
Gravity
Friction
Strong push
Weak pull
Answer:
Strong Push
Explanation:
tbh it's self explanatory! but, i just took this test and this was the correct answer, i hope this helps you! <3
6. The electric field caused by an electron is weakest near the electron.
7. An electric field becomes weaker as distance from the electron increase
6. "The electric field caused by an electron is weakest near the electron" is FALSE.
7. "An electric field becomes weaker as distance from the electron increase" is TRUE.
Explanation:
The "electrical field" covers the electrical charge and exerts, attracts or repels other charges in the field.The electric field caused by an electron is strongest near the electron while it become weak as distance from the electron increase.
The reason behind is, at a point the direction of the field line is at that point the direction of the field. The relative magnitude of the electric field will be proportional to the field line density. The field is strongest where the field lines are near together and when the field lines are at increasing distance the field is weakest.
Resistance and length of a conductor are:
A.directly proportional
B.inversely proportional
C.seldom proportional
D.not proportional
Answer:
Directly Propotional
Explanation:
Doubling the length will double its resistance while halving its length would halve its resistance. Also the resistance of a conductor is inversely proportional to its cross-sectional area(A)
The iron nail’s mass is 16 grams and its temperature drops 650 C when dropped into the water. How much heat energy did the iron nail transfer to the water?
The heat energy transferred by the iron nail is 4680 J
Explanation:
The thermal energy transferred by a substance to another substance is given by the equation
[tex]Q=mC\Delta T[/tex]
where
m is the mass of the substance
C is its specific heat capacity
[tex]\Delta T[/tex] is its change in temperature
For the iron nail in this problem, we have:
m = 16 g
[tex]C=0.450 J/g^{\circ}C[/tex]
[tex]\Delta T = -650^{\circ}C[/tex]
So, the amount of heat energy given off by the nail is
[tex]Q=(16)(0.450)(-650)=-4680 J[/tex]
where the negative sign indicates that the heat is given off.
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(2) 16 year old Kasey sends her 48 year old dad, Steve, on a trip to to explore the universe. When Steve returns,
he has aged 10 years, and is shocked to discover that Kasey is now the same age he is! How fast was Steve's
spaceship traveling while he was away? (Give your answer in terms of a fraction of the speed of light.)
The speed of the spaceship is 0.971c
Explanation:
Since Steve is moving at a speed close to the speed of light, the time observed by Kasey will be dilated, according to the equation
[tex]T' = \frac{T}{\sqrt{1-(\frac{v}{c})^2}}[/tex]
where
T' is the time measured by Kasey
T is the time measured by Steve
v is Steve's speed
c is the speed of light
Here we have:
T = 10 years (time measured by Steve)
When Steve is back, his age is 48 + 10 = 58 years. Kasey has now the same age, so the amount of time passed according to Kasey is
[tex]T' = 58 -16=42 y[/tex]
Substituting into the equation, we can fidn the speed of Steve's spaceship:
[tex]\sqrt{1-(\frac{v}{c})^2}=\frac{T'}{T}\\1-(\frac{v}{c})^2=(\frac{T'}{T})^2\\v=c\sqrt{1-(\frac{T'}{T})^2}=c\sqrt{1-(\frac{10}{42})^2}=0.971 c[/tex]
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a block of wood is found to have dimensions of 6.21 cm x 4.63 cm x 5.34 cm. Calculate the volume of the block
Answer:
153.54 cm³
Explanation:
The formula for the volume of a cube is v = lwh, where l is the length, w is the width, and h is the height of the block. Multiply, 6.21*4.63*5.34 = 153.54
what is the kinetic energy of a 1.00g hailstone falling at 8.50m/s
Answer:
36.125 J
Explanation:
The formula for kinetic energy is KE = .5(m)(v²).
Using the given information, mass = 1 g and v = 8.50. Plug that information into the equation. KE = .5(1)(8.50²) = 36.125 J.
The kinetic energy of a 1.00 g hailstone falling at 8.50 m/s is calculated using the formula KE = 1/2*mv^2. Hence the kinetic energy is 0.036125 Joules.
The question asks for the kinetic energy of a hailstone. The formula to find kinetic energy (KE) is KE = 1/2*mv^2, where 'm' is the mass in kilograms and 'v' is the velocity in meters per second. For the given hailstone with a mass of 1.00 gram (which is 0.001 kg) falling at a speed of 8.50 m/s, the kinetic energy can be calculated as follows:
Convert the mass from grams to kilograms: 1.00 g = 0.001 kg.
Substituting the values in the formula:
KE = 1/2 * 0.001 kg * (8.50 m/s)^2
KE = (1/2) * 0.001 kg * 72.25 m^2/s^2
KE = 0.00036125 kg·m^2/s^2
KE = 0.36125 J
Therefore, the kinetic energy of the hailstone is 0.3612 Joules.
Which of the following correctly describe magnetic field lines?
Check all that apply.
A. They begin on north poles and end on south poles.
B. They always cross.
C. Field lines that are close together indicate a weaker magnetic
field.
D. They form complete loops.
The magnetic field lines start at a magnet's north pole and end at the south pole.
A. They begin on north poles and end on south poles.
Explanation:
Magnetic field lines are a visual instrument used to speak to attractive fields. They portray the bearing of the attractive power on a north monopole at some random position. The north post of one magnet draws in the south shaft however repulses the north shaft of another magnet dissimilar to shafts pull in and like shafts repulse.
A metal is a magnet on the off chance that it repulses a known magnet. Be that as it may, the Magnetic field lines don't simply end at the tip of the magnet. They go directly through it so that inside the magnet the attractive field focuses from the south shaft toward the north post.
Answer:
A
Explanation:
Which does not provide a significant voltage difference in a circuit?
A) wet cells
B) wires
C) electrical outlet
D) dry cells
Answer:
b - wires
Explanation:
cells , dry cells , electrical outlets are all responsible for the varying electron pressure/ potential difference hence wires is our answer because wires are just conductors which can only influence resistance.
The western shoreline of a continent in the Northern Hemisphere runs directly in a north-south direction. Prevailing winds blowing from the __________ will produce coastal upwelling. Which word best completes the sentence? north east west south
Answer:
Your answer is "West".
Explanation:
Final answer:
Prevailing winds from the north create coastal upwelling along western shorelines in the Northern Hemisphere due to the Ekman Transport moving water offshore and pulling up colder, nutrient-rich deep water.
Explanation:
Prevailing winds blowing from the north will produce coastal upwelling along a continent's western shoreline in the Northern Hemisphere. This occurs because the Ekman Transport moves surface water 90° to the right of the wind direction due to the Coriolis effect, causing surface water to move offshore. As a consequence, the water displaced near the coast is replaced by cold, nutrient-rich deeper water that is brought to the surface through upwelling, leading to a high level of productivity in these coastal waters.
An airplane has a mass of 2×10^6 kg and air flows past the power surface of the wings at 100ms¯¹. If the wings have a surface area of 1200m², how fast must the air flow over the upper surface of the wing if the plane is to stay in the air? Consider only the Bernoulli's effect.
Answer:
190 m/s
Explanation:
For the plane to stay in the air, the lift force must equal the weight.
The lift force is also equal to the pressure difference across the wings (pressure at the bottom minus pressure at the top) times the area of the wings.
Therefore:
mg = (P₂ − P₁) A
P₂ − P₁ = mg / A
Using Bernoulli equation:
P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂
P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²
½ ρ (v₁² − v₂²) = P₂ − P₁
½ ρ (v₁² − v₂²) = mg / A
v₁² − v₂² = 2mg / (Aρ)
v₁² = v₂² + 2mg / (Aρ)
Substituting values (assuming air density of 1.225 kg/m³):
v₁² = (100 m/s)² + 2 (2×10⁶ kg) (9.8 m/s²) / (1200 m² × 1.225 kg/m³)
v₁² = 36,666.67 m²/s²
v₁ = 191 m/s
Rounding to two significant figures, the air must move at 190 m/s over the top of the wing.
To keep the plane in the air, the air flowing over the upper surface of the wings must be faster than the air flowing past the lower surface. This is due to Bernoulli's principle, which states that as the speed of a fluid increases, its pressure decreases. We can use the equation v₂ = sqrt(v₁² + 2(P₁ - P₂)/ρ) to calculate the speed of the air over the upper surface of the wing.
Explanation:To keep the plane in the air, the air flowing over the upper surface of the wings must be faster than the air flowing past the lower surface. This is due to Bernoulli's principle, which states that as the speed of a fluid increases, its pressure decreases. The difference in pressure between the upper and lower surfaces of the wing creates lift.
To calculate the speed of the air over the upper surface of the wing, we can use the equation:
P₁ + ½ρv₁² = P₂ + ½ρv₂²
P₁ is the pressure below the wing, P₂ is the pressure above the wing, ρ is the density of the air, v₁ is the speed of the air below the wing, and v₂ is the speed of the air above the wing.
We can rearrange the equation to solve for v₂:
v₂ = sqrt(v₁² + 2(P₁ - P₂)/ρ)
Plugging in the given values, we get:
v₂ = sqrt(100² + 2(0 - P₂)/(1.2))
Since we don't have the specific values for P₁ and P₂, we cannot calculate the exact speed of the air over the upper surface of the wing. However, we can determine that it must be greater than 100 m/s in order for the plane to stay in the air.
Learn more about Bernoulli's principleAn object of mass 12kg is held at a weight of 5m above the ground for 30s. Calculate the workdone during this period.
Answer:
0 J
Explanation:
Work = force × distance
Since the object isn't moved, the distance is 0. So the work is 0.
The work done while holding an object at a certain height with no movement is zero because work requires movement. The work done pulling a cart at an angle involves the horizontal component of force and distance, while pulling horizontally simply requires multiplying force by distance.
Explanation:When an object of mass 12kg is held at a height of 5m above the ground without any vertical or horizontal movement, the work done during the time it is held is zero. This is because work is defined as the force applied to an object times the distance over which the force is applied (Work = Force × Distance). If there is no movement, the distance is zero, hence no work is done, regardless of the time the object is held in place.
For part (a) of the student's example question, the work done on the cart by the boy pulling it with a 20-N force at an angle of 30° for a distance of 12 m can be found using the formula for work done when a force is applied at an angle to the displacement. The work is calculated as the product of the horizontal component of the force and the distance: Work = F × d × cos(θ), where F is the applied force, d is the distance, and θ is the angle of force. Therefore, Work = 20 N × 12 m × cos(30°) = 240 Nm × √3/2 ≈ 207.85 J.
For part (b), if the boy pulls with the same force horizontally, the work done would simply be the force times the distance, since the angle θ would be 0° and cos(0°) is 1. So, Work = 20 N × 12 m = 240 J.
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A cupcake recipe designed to produce 28 cupcakes calls for 360 grams of flour Determine the quantity of flour that would be
required to make 32 cupcakes. (Round the final answer to four decimal place.)
The quantity of flour required is
grams
411.4272 grams of flour is required to make 32 cupcakes.
What are Measurements?Measurement is defined as the quantification of characteristics of an object or phenomenon that can be used to compare them with other objects or phenomena. Measurement is described as the process of determining how large or small a physical quantity is compared to a basic reference quantity of the same type.
Above given example is measured as:
Since 360 grams of flour is used to make 28 cupcakes, so, the amount (mass) of flour is distributed evenly over all 28 cupcakes
Each cupcake requires 360/28 grams of flour = 12.8571 grams.
So, for making 32 cupcakes= 32* 12.8571= 411.4272 grams of flour is required
Thus, 411.4272 grams of flour is required to make 32 cupcakes.
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6. Mr. Leppold jumps out of a plane with a parachute...before the chute opens,
does he have potential or kinetic energy, or both? Explain, and how does the
potential & kinetic energy change as he falls?
1) He has both potential and kinetic energy
2) Before the parachute opens, the potential energy decreases and the kinetic energy increases
Explanation:
1)
The gravitational potential energy of a body is the energy possessed by the object due to its position in a gravitational field, and it is given by:
[tex]PE=mgh[/tex]
where
m is the mass of the body
g is the acceleration of gravity
h is the height of the body above the ground
On the other hand, the kinetic energy of a body is the energy possessed by the body due to its motion; it is given by
[tex]KE=\frac{1}{2}mv^2[/tex]
where
v is the speed of the object
Here Mr. Leppold has both potential and kinetic energy before opening the parachute, because:
- It is moving at a certain speed, so [tex]v\neq 0[/tex], therefore he has kinetic energy
- He is at a certain height above the ground, [tex]h\neq 0[/tex], therefore he has potential energy
2)
The total mechanical energy of Mr.Leppold is the sum of the potential and the kinetic energy:
[tex]E=PE+KE[/tex]
According to the law of conservation of energy, in absence of air resistance, this quantity remains constant.
During the fall, the height of Leppold decreases: this means that as [tex]h[/tex] decreases, the potential energy decreases too.
However, the total energy E must remain constant: therefore, this means that the kinetic energy KE must increase, and this occurs because the speed of Mr. Leppold increases as he falls.
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Which term describes the object that revolves around a central body?
A. Central body
B. Period
C. Orbit
D. Satellite
Answer:
d satellite i think
Explanation:
i eliminated all the other answers, when i notice that Orbit, Period, and Rotation are not Bodies.
Answer:
satallite
Explanation:
Metallic bonds share electrons __________.
A
Unequally in all directions
B
Unequally in two directions
C
Equally in two directions
D
Equally in all directions
Final answer:
In a metallic bond, electrons are shared equally in all directions.
Explanation:
In a metallic bond, electrons are shared equally in all directions.
Metallic bonds form between metal atoms and are characterized by a sea of delocalized electrons that can move freely throughout the metal lattice. The shared electrons are not localized between any specific pairs of atoms, but rather are delocalized and shared among all the metal atoms.
For example, in a piece of solid copper, the copper atoms are held together by metallic bonds. The outer electrons of each copper atom are delocalized and can move freely throughout the entire structure, giving copper its high electrical and thermal conductivity.
A 75 kg baseball player runs at a velocity of 6 m/s before sliding to a stop at second base. a. What is the kinetic energy of the runner before he begins his slide? b. What is the kinetic energy of the runner once he reaches the base? c. What is the change in the kinetic energy of the runner? d. How much work is done by friction in stopping the runner? e. If the runner slides for 2 m, what is the force of friction that acts upon him?
Answer:
a. [tex]\displaystyle k_o=1350\ J[/tex]
b. [tex]\displaystyle k_1=0\ J[/tex]
c. [tex]\Delta k=-1350\ J[/tex]
d. [tex]W=-1350\ J[/tex]
e. [tex]F=-675\ N[/tex]
Explanation:
Work and Kinetic Energy
When an object moves at a certain velocity v0 and changes it to v1, a change in its kinetic energy is achieved:
[tex]\Delta k=k_1-k_0[/tex]
Knowing that
[tex]\displaystyle k=\frac{mv^2}{2}[/tex]
We have
[tex]\displaystyle \Delta k=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}[/tex]
The work done by the force who caused the change of velocity (acceleration) is
[tex]\displaystyle W=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}[/tex]
If we know the distance x traveled by the object, the work can also be calculated by
[tex]W=F.x[/tex]
Being F the force responsible for the change of velocity
The 75 kg baseball player has an initial velocity of 6 m/s, then he slides and stops
a. Before the slide, his initial kinetic energy is
[tex]\displaystyle k_o=\frac{mv_0^2}{2}[/tex]
[tex]\displaystyle k_o=\frac{(75)6^2}{2}[/tex]
[tex]\boxed{\displaystyle k_o=1350\ J}[/tex]
b. Once he reaches the base, the player is at rest, thus his final kinetic energy is
[tex]\displaystyle k_1=\frac{(75)0^2}{2}[/tex]
[tex]\boxed{\displaystyle k_1=0\ J}[/tex]
c. The change of kinetic energy is
[tex]\Delta k=k_1-k_0=0\ J-1350\ J[/tex]
[tex]\boxed{\Delta k=-1350\ J}[/tex]
d. The work done by friction to stop the player is
[tex]W=\Delta k=k_1-k_0[/tex]
[tex]\boxed{W=-1350\ J}[/tex]
e. We compute the force of friction by using
[tex]W=F.x[/tex]
and solving for x
[tex]\displaystyle F=\frac{W}{x}[/tex]
[tex]\displaystyle F=\frac{-1350\ J}{2\ m}[/tex]
[tex]\boxed{F=-675\ N}[/tex]
The negative sign indicates the force is against movement
Which of the following statements about motion are true? Select all that apply.
A. If an object is changing direction, a force must be acting on it.
B. If an object is changing speed, a force may or may not be acting on it.
C. An object can move to the right only if a force is pushing or pulling it to the right.
D. An object that is moving through outer space far from any other objects will keep moving in a straight line indefinitely.
The true statements about motion are A, B, and D. While changing direction or speed often involves a force, speed can also change due to factors like gravity. An object in a vacuum will continue to move indefinitely in a straight line, if no other forces act on it.
Explanation:The statements about motion that are true are A, B, and D. Statement A is true because according to Newton's first law of motion, an object will continue to move in a straight line unless acted upon by an external force. Therefore, changing direction implies a force.
B is true because both acceleration and deceleration (changing speed) can be caused by forces; however, an object can also change its speed due to factors like gravity or friction, particularly in fluid mechanics. Statement D is true in the context of an ideal vacuum, where an object would indeed continue to move indefinitely if no other forces were present. However, C is not necessarily true because an object can also move due to inertia or if it was already in motion.
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Final answer:
The true statements about motion, based on Newton's Laws, are that an object changing direction requires a force, and an object in outer space will maintain its motion in a straight line indefinitely in the absence of external forces. Statements asserting the necessity of a force to maintain motion or to move to the right are false due to Newton's first law of inertia.
Explanation:
The discussion of motion and force is grounded in the principles of Newton's Laws of Motion, specifically the first law which is also known as the law of inertia. Here's an assessment of the provided statements:
A. True, according to Newton's first law, an object will not change its state of motion unless a net force is acting on it. Changing direction is a form of acceleration, and hence a force must be present.
B. False. If an object is changing speed, a force must be acting on it. This is based on Newton's second law, which states that the acceleration (change in speed) of an object is due to a net force acting on it.
C. False. An object can continue to move to the right without any forces pushing or pulling it, provided that it was already moving to the right and no forces are acting to stop it or change its direction. This is also an implication of Newton's first law.
D. True. This statement is a direct consequence of Newton's first law. An object in motion will continue to move in a straight line at constant velocity if no external force acts on it.
Runaway truck ramps are common on mountainous highways in case the brakes fail on large trucks. If a
runaway 60,000 kg truck is moving at 27 m/s, how much work must be done to stop the truck?
Answer:
[tex]W=-21,870,000\ J[/tex]
Explanation:
Work and Kinetic Energy
The work an object does due to its motion is equal to the change of its kinetic energy. Being ko and k1 the initial and final kinetic energy respectively and m the mass of the object, then
[tex]W=\Delta k=k_1-k_0[/tex]
Since
[tex]\displaystyle k=\frac{mv^2}{2}[/tex]
We have
[tex]\displaystyle W=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}[/tex]
The truck has a mass of 60,000 kg and is moving at 27 m/s. The runaway truck ramp must stop the truck, so the final speed is 0. Thus
[tex]\displaystyle W=\frac{(60,000)0^2}{2}-\frac{(60,000)(27)^2}{2}[/tex]
[tex]W=0-21870000\ J[/tex]
[tex]\boxed{W=-21,870,000\ J}[/tex]
The work done to stop a 60,000-kg truck moving at 27 m/s is -2.2 × 10⁷ J.
What does the work-energy principle state?The principle of work and kinetic energy (also known as the work-energy theorem) states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle.
We can calculate the work done to stop the truck using the work-energy principle.
W = ΔK
W = 1/2 × m × v² - 1/2 × m × u²
W = 1/2 × 60,000 kg × (0 m/s)² - 1/2 × 60,000 kg × (27 m/s)²
W = -2.2 × 10⁷ J
where
W is the work.K is the kinetic energy.m is the mass.v is the final speed.u is the initial speed.The work done to stop a 60,000-kg truck moving at 27 m/s is -2.2 × 10⁷ J.
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An electric field from a charge has a magnitude of 4.5 × 104 N/C at a certain location that points inward. If another charge with a magnitude of −2.0 × 10−6 C is brought near it, what is the strength of the electrostatic force that acts on this charge and how do the two charges behave?
0.09 N; repel each other
−0.09 N; attract each other
−2.3 N; repel each other
2.3 N; attract each other
The two charges repel each other and the electrostatic force on the second charge is 0.09N
Electrostatic force:Let us consider the charge [tex]Q_1[/tex] has an electric field [tex]E_1=4.5\times10^4 N/C[/tex]
and the charge [tex]Q_2=-2.0\times10^{-6} C[/tex].
It is given that the electric field E₁ is pointed inwards the charge Q₁, so charge Q₁ must be negative.
So, if a charge [tex]Q_2=-2.0\times10^{-6} C[/tex] which is also negative is brought near the charge Q₁, then both the charges will repel each other.
The electrostatic force acting on the second charge is given by:
[tex]F=E_1Q_2\\\\F=4.5\times10^4\times(2.0)\times10^{-6} \\\\F=0.09N[/tex]
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The electrostatic force on a charge of −2.0 × 10−6 C in an electric field of 4.5 × 10⁴ N/C is −0.09 N, meaning the charges attract each other.
Explanation:If an electric field has a magnitude of 4.5 × 104 N/C and is directed inward, and a charge of −2.0 × 10−6 C (negative charge) is brought into this field, we can calculate the electrostatic force acting on this charge. The formula for the force (F) due to an electric field (E) on a charge (q) is F = qE. Applying the given values:
F = (−2.0 × 10−6 C)(4.5 × 104 N/C) = −9.0 × 10−2 N, which simplifies to −0.09 N. Since the force is negative and the electric field is directed inward, this means that the force on the negative charge is directed outward, which corresponds to an attraction between the two charges. Therefore, the correct answer from the options provided would be −0.09 N; attract each other.
What controls the traits an organism has?
The Traits an organism displays are ultimately determined by the genes it inherited from its parents, in other words by its genotype. Variant copies of a gene are called alleles, and an individuals genotype is the sum of all the alleles inherited from the parents.
if you wanted to control sound reflection
in an office would you install metal wood or cork partitions
To control sound reflection in an office, cork partitions would be installed.
What is meant by reflection of sounds ?It is referred to as the reflection of sound when sound is travelling through one medium and then collides with the surface of another medium and travels in a different direction. The incidental and reflected sound waves are the ones that are being analysed.
An echo is a sound that is heard after a surface has reflected it.
In the same way that heat or light are partially reflected and partially absorbed when they strike a surface, sound does the same.
Hard surfaces reflect sound more effectively than soft surfaces do, and vice versa.
One of the most popular materials for reducing sound reflection is cork, due to its capacity for both sound absorption and sound proofing.
Hence,
To control sound reflection in an office, cork partitions would be installed.
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Two baddies of equal masses move with uniform velocities V and 2V respectively.The ratio of their kinetic energies
The ratio (2nd to 1st) of their kinetic energies is 4
Explanation:
The kinetic energy of an object is the energy possessed by the object due to its motion, and it is calculated as
[tex]K=\frac{1}{2}mv^2[/tex]
where
m is the mass of the object
v is its speed
In this problem, we have:
- A first object with mass m and speed V, so its kinetic energy is
[tex]K_1 = \frac{1}{2}mV^2[/tex]
- A second object with mass m (same as first object) and speed 2V, so its kinetic energy is
[tex]K_2 = \frac{1}{2}m(2V)^2=4(\frac{1}{2}mV^2)[/tex]
So, the ratio of theri kinetic energies is
[tex]\frac{K_2}{K_1}=\frac{4(\frac{1}{2}mV^2)}{\frac{1}{2}mV^2}=4[/tex]
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An object of known mass M with speed v0 travels toward a wall. The object collides with it and bounces away from the wall in the opposite direction in which the object was initially traveling. The wall exerts an average force F0 on the object during the collision. A student must use the equation Δp⃗ =F⃗ Δt to determine the change in momentum of the object from immediately before the collision to immediately after the collision. Which side of the equation could the student use to determine the change of the object's momentum?
Δp⃗ , because the mass of the object and the initial speed of the object are known.
A
F⃗ Δt, because the average force exerted on the object during the collision is known.
B
Either side of the equation may be used because the mass of the object, the initial speed of the object, and the average force exerted on the object during the collision are known.
C
Neither side of the equation may be used because there are too many unknown quantities before, during, and after the collision.
Neither side of the equation may be used because there are too many unknown quantities before, during, and after the collision
Explanation:
The impulse theorem states that the change in momentum of an object is equal to the impulse, which is the product between the average force applied and the duration of the collision:
[tex]\Delta p = F \Delta t[/tex]
where
[tex]\Delta p[/tex] is the change in momentum
F is the average force
[tex]\Delta t[/tex] is the duration of the collision
In this problem, neither side of the equation can be used to measure the change in momentum. In fact:
- The change in momentum (left side) is given by
[tex]\Delta p = m(v-u)[/tex]
where
m is the mass of the object
u is the initial velocity
v is the final velocity
Here the final velocity is not known, so it's not possible to use this side of the equation
- The impulse (right side) is given by
[tex]F\Delta t[/tex]
here the average force is known, however the duration of the collision is not known, so it's not possible to use this side of the equation.
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Neither side of the equation may be used because there are too many unknown quantities before, during, and after the collision. Therefore, option (C) is correct.
According to the impulse-momentum theorem, "The change in momentum of an object is equal to the impulse produced by the object. Where the impulse is expressed as the product of average force on the object and the duration of collision (reaction time)".
The expression is given as,
..............................................(1)
Here, [tex]\delta p[/tex] is the change in momentum, [tex]F_{av.}[/tex] is the average force and t is the reaction time.
In equation (1), [tex]\delta p[/tex] is the change in momentum which is given as,
[tex]\delta p = m(v-u)[/tex]
Here, m is the mass, v and u are the final and initial velocities of object respectively.
Since, object's mass (m) and velocities are not given. Therefore, left hand side of equation (1) cannot be used to determine the change of object's momentum.Also, right hand side of equation (1) requires the duration of collision (t), which is missing in the problem.Thus, we can conclude that there are various unknown variables present in the problem, for which neither side of the equation may be used to determine change in momentum of object. Hence, option (C) is correct.
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Which would you sprinkle around the electromagnet that you produced in the laboratory activity to see its magnet
field lines?
Which would you use to determine the direction of the field lines around a magnet?
Which would you use with a circuit to determine if a magnet was moving in close proximity to the
circuit?
The Answer are:
1. iron shavings
2. compass
3. galvanometer
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Iron shavings ,compass and galvanometer use to determine the direction of the magnetic field lines around a magnet.
What is electromagnet?An electromagnet is a magnet whose magnetic field is generated by an electric current. Wire coiled into a coil is used to make electromagnets.
A current flowing through the wire produces a magnetic field that is focused in the hole.
A tiny compass may be used to map out magnetic field lines. As illustrated, The compass is moved from point to point around a magnet, with a small line drawn in the direction of the needle at each point.
The course of the magnetic field line is then shown by joining the lines together.
Hence, iron shavings ,compass and galvanometer use to determine the direction of the iron magnetic field lines around a magnet.
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Write balanced nuclear equation for the decay of strontium 94 into yttrium
The nuclear decay equation is [tex]_{38}^{94}Sr \rightarrow _{39}^{94}Y + e^- + \overline{\nu}[/tex]
Explanation:
First of all, we look at the periodic table to see what is the atomic number of the two elements involved.
We notice that:
The atomic number of strontium is 38The atomic number of yttrium is 39This means that in the decay, a neutron from the nucleus of strontium transforms into a proton (because the atomic number, which is the number of protons, increases by 1 unit).
Therefore, this means that the decay involved is a beta-minus decay, in which a neutron converts into a proton emitting an electron (to conserve the charge) alongside an anti-neutrino.
Therefore, the balanced nuclear decay equation is:
[tex]_{38}^{94}Sr \rightarrow _{39}^{94}Y + e^- + \overline{\nu}[/tex]
where the mass number (94) does not change, since the number of nucleons (protons+neutrons) remains the same.
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