Mrs. Mary Moolah invested $20,000 in
two different types of bonds. The first
type paid a 5% interest rate, and the
second paid an 8% rate. Lif Mrs. Moolah's
combined profit from both investments
was $1,150, how much did she invest at
the 5% rate?

Answer:

Part 12) [tex]Center\ (2,-3),r=2\ units, (x-2)^2+(y+3)^2=4[/tex]

Part 13) [tex]m\angle ABC=47^o[/tex]

Step-by-step explanation:

Part 12) we know that

The equation of a circle in center-radius form is equal to

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem

Looking at the graph

The center is the [tex]point\ (2,-3)[/tex]

The radius is [tex]r=2\ units[/tex]

substitute in the expression above

[tex](x-2)^2+(y+3)^2=2^2[/tex]

[tex](x-2)^2+(y+3)^2=4[/tex]

Part 13) we know that

The measure of the external angle is the semi-difference of the arcs it covers.

so

[tex]m\angle ABC=\frac{1}{2}[arc\ DE-arc\ AC][/tex]

we have

[tex]arc\ DE=142^o[/tex]

[tex]arc\ AC=48^o[/tex]

[tex]m\angle ABC=\frac{1}{2}[142^o-48^o][/tex]

[tex]m\angle ABC=47^o[/tex]

Answer:

Goal amount of $10,000

Deadline of next year

Step-by-step explanation:

Tyrone can make his financial goal ‘specific’ by deciding on a target amount for his emergency fund. He can make it 'timely' by assigning a deadline by which to save that amount.

To make Tyrone's financial goal specific, he could give himself a target amount to save for the emergency fund. This could be a fixed sum, like $1000, or a figure based on monthly expenses, like saving for 6 months' worth of living expenses. This clarity can help him to plan and track his progress.

To make his goal timely, he could give himself a deadline by which he wants to achieve this goal. For example, he might aim to save his specified amount within a year or two. The timetable can provide added motivation to adhere to a budget and save consistently.

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Answer:

Currency= $291 and check= $581.25.

Step-by-step explanation:

Given: Cash received= $75

          Total deposit= $872.25

Lets assume currency deposited be dollar "x"

∴  As given check deposited will be "2x"  

Now, calculating amount of currency deposited.

We know that, [tex]currency\ deposit + check\ deposit= \$872.25[/tex]

∴ [tex]x+2x= \$872.25[/tex]

⇒[tex]3x=\$872.25[/tex]

Cross multiplying

∴[tex]x= \$290.75 \approx \$291 \textrm{ as Kenneth John have not deposited any coins}[/tex]

∴  Amount of currency deposited is $291.

Next, computing to get amount deposited through check.

As we know check deposited is double of currency.

Check deposited= [tex]2\times \$291= \$ 582[/tex]

∵ No coins were deposited and there is total deposit is $872.25.

∴ We will consider amount deposited through check is $581.25.

Kenneth John deposited $290.75 in currency and $581.50 in checks.

To determine the amounts of currency and checks deposited by Kenneth John, we will define the variables for clarity. Let C represent the amount in currency deposited and CH represent the amount in checks deposited.

Given:

The total deposit after adding checks and currency is $872.25.

The checks deposited totaled twice the currency deposited (CH = 2C).

We can set up the following equation based on the given information:

[tex]C + CH = 872.25[/tex]

Since CH = 2C, we substitute CH:

[tex]C + 2C = 872.25[/tex]

This simplifies to:

[tex]3C = 872.25[/tex]

Solving for C, we divide both sides of the equation by 3:

[tex]C = \[\frac{872.25}{3} = 290.75[/tex]

Kenneth deposited $290.75 in currency.

Then, we calculate the amount in checks:

[tex]CH = 2 \times 290.75 = 581.50[/tex]

Answer:

The number of child tickets sold was 36

Step-by-step explanation:

The complete question is

At the city museum, child admission is $5.80 and adult admission is $9.30. On Monday, four times as many adult tickets as child tickets were sold, for a total sales of $1548.00. How many child tickets were sold that day?

Let

x ----> the number of child tickets sold

y ----> the number of adult tickets sold

we know that

[tex]5.80x+9.30y=1,548.00[/tex] ---> equation A

[tex]y=4x[/tex] ----> equation B

Solve by substitution

Substitute equation B in equation A    

[tex]5.80x+9.30(4x)=1,548.00[/tex]

solve for x

[tex]5.80x+37.2x=1,548.00[/tex]

[tex]43x=1,548.00[/tex]

[tex]x=36[/tex]

therefore

The number of child tickets sold was 36

I think 68 or56

It can't be 34 that would be less, 146 would be over quarter

Good evening ,

Answer:

Step-by-step explanation:

measure arc AB = 2×(m∠AXB) = 2×(34) = 68°.

:)

The equation of parabola is expressed as: y² = -20x

What is the equation of the parabola?

A parabola refers to an equation of a curve, such that a point on the curve is equidistant from a fixed point, and a fixed line.

The fixed point is called the focus of the parabola, and the fixed line is called the directrix of the parabola.

Given, vertex = (0, 0)

Focus = (-5, 0)

We have to find the equation of the parabola.

The equation is of the form y = -ax²

Directrix x = 5.

As every point on parabola is equidistant from focus and directrix, the equation will be

y² + (x + 5)² = (x - 5)²

y² + x² + 10x + 25 = x² - 10x + 25

y² = - 10x - 10x

y² = -20x

Therefore, the equation of parabola is y² = -20x

Answer:

[tex]\frac{y}{x+y}[/tex]

Step-by-step explanation:

The required answer is the rate at  which Machine A  works when the two machines are combined.

Note: the rate of doing work is express as

[tex]rate=\frac{1}{time taken} \\[/tex]

Hence we can conclude that Machine A working rate is

[tex]machine A=\frac{1}{x} \\[/tex] and machine B working rate is

[tex]machine B=\frac{1}{y} \\[/tex]

When the two machine works together, the effective working rate is

[tex]\frac{1}{x}+\frac{1}{y}\\\frac{xy}{x+y}\\[/tex]

The fraction of the work that Machine B will not have complete because of Machine A help is the total work done by machine A

Hence the fraction of work done by A is expressed as

[tex]\frac{1}{x}*combine working rate[/tex]

[tex]\frac{1}{x}*\frac{xy}{x+y}\\\frac{y}{x+y} \\[/tex]

Hence the fraction of the work that Machine B will not have complete because of Machine A help is the total work done by machine A is [tex]\frac{y}{x+y} \\[/tex]

Answer:

24 times

Step-by-step explanation:

Given:

Number of cups required = 6 cups

Measuring cup capacity = [tex]\frac{1}{4}=0.25[/tex] of a cup.

Now, each time the measuring cup fills 0.25 of a cup.

So, we use unitary method to find the number of times the measuring cup has to be used to get a total of 6 cups.

∵ 0.25 cups = 1 time the measuring cup being used.

∴ 1 cup = [tex]\frac{1}{0.25}=4[/tex] times the measuring cup being used.

So, 6 cups = [tex]4\times 6=24[/tex] times the measuring cup being used.

Hence, the number of times the measuring cup has to be used to get 6 cups of flour is 24 times.

Answer:

  36 square feet

Step-by-step explanation:

The area of one barrier is the product of the given dimensions:

  (9 ft)(2 ft) = 18 ft²

Two such barriers will have twice the area: 36 ft².

The combined area of the two barriers is calculated by multiplying the length by the height for each barrier to get an area for each one, and then those two areas are added together. Each barrier has an area of 18 square feet, so the total combined area is 36 square feet.

The question is asking for the combined area of two barriers, each being 9 feet long and 2 feet high. In order to find this, we must multiply the length by the height for each barrier, and then add these two areas together. The calculation would look like this:

Area of each barrier = Length x Height = 9 ft x 2 ft = 18 square feet

Now, since there are two barriers:

Combined Area = 2 x Area of each barrier = 2 x 18 square feet = 36 square feet

Therefore, the combined area of the two barriers is 36 square feet.

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Answer: Our required probability is 0.7241.

Step-by-step explanation:

Since we have given that

Probability that new product have been successes P(S) = 60%

Probability that new product have not been successes P(F) = 40%

Probability that their successful products were predicted to be successes = P(A|S)=70%

Probability that their failed products were predicted to be successes =P(A|F) = 40%

So, Probability that this new camera phone will be successful if its success has been predicted is given by

[tex]P(S|A)=\dfrac{P(S).P(A|S)}{P(S).P(A|S)+P(F).P(A|F)}\\\\P(S|A)=\dfrac{0.7\times 0.6}{0.7\times 0.6+0.4\times 0.4}\\\\P(S|A)=0.7241[/tex]

Hence, our required probability is 0.7241.

Answer: her interest in 3 years is $45

Step-by-step explanation:

For simple interest, the principal is not compounded. The interest is only on the original capital. The formula for simple interest is expressed as

I = PRT/100

Where

I represents the interest on the principal

P represents the initial amount

R represents the interest rate.

T represents the time in years.

From the information given

P = $300

R = 5%

T = 3 years

I = 300×5×3)/100

I = 4500/100 = 45

Answer:

Answer C: Becky is 27; John is 31

Step-by-step explanation:

1. John is 4 years older than Becky--27(Becky's age)+ 4=31(John's age)

2. Sum of their ages is 58--27(Becky's age)+31(John's age)=58

So, the correct answer is Answer C.

Answer:

C. Becky is 27; John is 31

Using the values in the table you can easily use the provided x-values to plug into any equation to get a corresponding f(x) value. When applying this to the 4 functions, we see that only the second answer choice will give the exact same outputs when the inputs are plugged in from the table.

[tex]4x^2+3x-6[/tex]

[tex]x=-2\\f(-2)=4(-2)^2+3(-2)-6\\f(-2)=4[/tex]

[tex]x=0\\f(0)=4(0)^2+3(0)-6\\f(0)=-6[/tex]

[tex]x=4\\f(4)=4(4)^2+3(4)-6\\f(4)=70[/tex]

Answer: 0.036756909

Step-by-step explanation:

Formula for Binomial probability distribution.

[tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex]

, where x= number of success

n= total trials

p=probability of getting success in each trial.

According to the given information , we have

n= 10 , p= 0.30  and x= 6

Then, the required probability will be :

[tex]P(x=6)=^{10}C_6(0.3)^6(1-0.3)^{10-6}\\\\= \dfrac{10!}{6!(10-6)!}\times(0.3)^6(0.7)^4\\\\=\dfrac{10\times9\times8\times7\times6!}{6!4!}(0.3)^6(0.7)^4\\\\=(210)(0.000729)(0.2401)=0.036756909[/tex]

Hence, the required provability = 0.036756909

The probability of 6 successes given that a single success has a probability of 0.30 is given by the binomial distribution and P ( A ) = 0.03675 or 3.675 %

Given data ,

To find the probability of exactly 6 successes in 10 trials, with a probability of success (p) equal to 0.30, we can use the binomial probability formula:

P ( x ) = [ n! / ( n - x )! x! ] pˣqⁿ⁻ˣ

P(X = k) is the probability of getting exactly k successes,

n is the total number of trials,

k is the number of desired successes,

p is the probability of success for a single trial,

In this case, n = 10, k = 6, and p = 0.30. The binomial coefficient C(n, k) is calculated as:

P(n, k) = n! / (k! * (n - k)!)

Substituting the values into the formula, we have:

P(X = 6) = C(10, 6) x (0.30)⁶ * (1 - 0.30)⁽¹⁰⁻⁶⁾

Calculating the binomial coefficient:

C(10, 6) = 10! / (6! x (10 - 6)!)

= 10! / (6! x 4!)

= (10 x 9 x 8 x 7) / (4 x 3 x 2 x 1)

= 210

Substituting the values into the formula:

P(X = 6) = 210 x (0.30)⁶ (0.70)⁴

P ( X = 6 ) = P ( A ) = 210 ( 0.000729 ) ( 0.2401 )

P ( A ) = 0.036756909

Therefore, the probability of getting exactly 6 successes in 10 trials, with a probability of success of 0.30, is approximately 0.03675 or 3.675 %

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Answer:

The Amount draw from the account after 10 years is $109,555 .

Step-by-step explanation:

Given as :

The principal deposited in account = p = $50,000

The rate of interest = 8% semiannually

The time period for the amount will be in account = t = 10 years

Let The Amount draw from the account after 10 years = $A

Now, From Compound Interest method

Amount = principal × [tex](1+\dfrac{\texrm rate}{2\times 100})^{\textrm 2\times time}[/tex]

A = p × [tex](1+\dfrac{\texrm r}{2\times 100})^{\textrm 2\times t}[/tex]

Or, A = $50,000 × [tex](1+\dfrac{\texrm 8}{2\times 100})^{\textrm 2\times 10}[/tex]

Or, A = $50,000 × [tex](1.04)^{20}[/tex]

Or, A = $50,000 × 2.1911

Or, A = $109,555

So, The Amount draw from the account after 10 years = A = $109,555

Hence,The Amount draw from the account after 10 years is $109,555 . Answer

Answer:

cos(3x) --> cos³(x) - 3sin²(x)cos(x)

Step-by-step explanation:

The text in pink are the trig identities I used to convert cos(2x) and sin(2x) into their other equivalent forms.

This question is pretty much asking if you know how to use your trig identities if i understand it correctly.

Final answer:

To rewrite cos 3x using only sin x and cos x, we can use the trigonometric identity: cos 3x = 4(cos x)^3 - 3(cos x). This identity allows us to express cos 3x in terms of cos x. However, if we want to rewrite it using only sin x and cos x, we can use the Pythagorean identity: (cos x)^2 = 1 - (sin x)^2.

Explanation:

To rewrite cos 3x using only sin x and cos x, we can use the trigonometric identity: cos 3x = 4(cos x)^3 - 3(cos x). This identity allows us to express cos 3x in terms of cos x. However, if we want to rewrite it using only sin x and cos x, we can use the Pythagorean identity: (cos x)^2 = 1 - (sin x)^2. So, we can substitute this identity into the previous equation to get: cos 3x = 4(1 - (sin x)^2)^3 - 3(1 - (sin x)^2).

Answer:

0.64

Step-by-step explanation:

Given: Craig has a box of chocolate with 5 rows in it.

           Each row has 20 chocolate.

           Craig and his friends eat 64 chocolate.

As given, we understand that there is box of chocolate with 5 rows and each row have 20 chocolate, therefore we can find total number of chocolate.

Total number of chocolate=[tex]5\ rows \times 20\ chocolates = 100\ chocolates[/tex]

∴ Total number of chocolates in box= 100.

Now, we know craig and his friends eat 64 chocolate.

∴ To find decimal of number chocolate eaten out of 100 chocolate, we need to  put numbers in fraction first then convert it in decimal.

Number of chocolate ate by craig and his friends is [tex]\frac{64}{100} = 0.64[/tex]

∴ Craig and his friends eat 0.64 chocolates.

Answer: Our required probability is [tex]\dfrac{1}{36}[/tex]

Step-by-step explanation:

Since we have given that

Total number of outcomes in single die = 6

So, total number of outcomes if three different die = [tex]6^3=216[/tex]

Number of favourable outcome i.e. exactly roll the same number = (1,1,1), (2,2,2) (3,3,3) (4,4,4) (5,5,5), (6,6,6) = 6

So, Probability of getting exactly roll the same number is given by

[tex]\dfrac{\text{number of favourable outcome}}{\text{Number of total outcomes}}\\\\=\dfrac{6}{216}\\\\=\dfrac{1}{36}[/tex]

Hence, our required probability is [tex]\dfrac{1}{36}[/tex]

a) The recurrence relation for the number of ternary strings of length n that do not contain two consecutive 0s is [tex]\(a_n = 2a_{n-1} + a_{n-2}\).[/tex]

b) The initial conditions for the recurrence relation are [tex]\(a_1 = 3\) and \(a_2 = 9\).[/tex]

c) There are 21 ternary strings of length six that do not contain two consecutive 0s.

a) To derive the recurrence relation, consider the possibilities for the last digit in the string. If the last digit is 1 or 2, it doesn't affect the constraint of avoiding consecutive 0s. Hence, for strings of length n that end in 1 or 2, there are[tex]\(a_{n-1}\)[/tex]possibilities. However, if the last digit is 0, the previous digit cannot be 0 to satisfy the constraint. Therefore, for strings of length n that end in 0, there are \(a_{n-2}\) possibilities. This results in the recurrence relation[tex]\(a_n = 2a_{n-1} + a_{n-2}\).[/tex]

b) The initial conditions are established by considering strings of length 1 and 2. For strings of length 1, there are three possibilities (0, 1, or 2). For strings of length 2, there are nine possibilities (00, 01, 02, 10, 11, 12, 20, 21, 22), but among these, 00 is excluded to avoid consecutive 0s, leaving a total of nine valid strings. Therefore, the initial conditions are[tex]\(a_1 = 3\) and \(a_2 = 9\).[/tex]

c) To find the number of ternary strings of length six that do not contain two consecutive 0s, utilize the recurrence relation. Starting from the initial conditions, compute[tex]\(a_6 = 2a_5 + a_4\)[/tex] using the relation, which results in [tex]\(a_6 = 21\).[/tex]

Thus, there are 21 ternary strings of length six that satisfy the condition of not having two consecutive 0s.

"In summary, the recurrence relation [tex]\(a_n = 2a_{n-1} + a_{n-2}\)[/tex]governs the number of ternary strings of length n without consecutive 0s, with initial conditions[tex]\(a_1 = 3\) and \(a_2 = 9\)[/tex]. Computing[tex]\(a_6\)[/tex]using the relation yields 21 valid ternary strings of length six that do not contain two consecutive 0s."

The recurrence relation for the number of ternary strings of length n that do not contain two consecutive 0s is a_n = 2a_n-1 + 2a_n-2. The initial conditions are a_1 = 3 and a_2 = 8. Using these, we calculate that there are 448 such ternary strings of length six.

Ternary Strings without Consecutive 0s

Let's define a ternary string as a string composed of the digits 0, 1, and 2. We need to find a recurrence relation for the number of such strings of length n that do not contain two consecutive 0s.

Part (a)

Let a_n represent the number of ternary strings of length n that do not contain consecutive 0s. Consider the possibilities for the first digit of the string:

Thus, we have the recurrence relation: a_n = 2a_{n-1} + 2a_{n-2}

Part (b)

The initial conditions can be determined as follows:

Part (c)

Using the recurrence relation and initial conditions:

Therefore, the number of ternary strings of length six that do not contain two consecutive 0s is 448.

Answer:

the answer is 1:12

Step-by-step explanation:

hope it helps!

Answer:

The length of each side is 17 in, 24 in, 24 in.

Step-by-step explanation:

Given,

Perimeter of the triangle = [tex]25\ in[/tex]

Length of 1st side = [tex]2w+1[/tex]

Length of 2nd side = [tex]3w[/tex]

Length of 3rd side = [tex]3w[/tex]

The perimeter of a triangle is equal to the sum of the length of all the three sides of the triangle.

Perimeter of the triangle = Length of 1st side + Length of 2nd side + Length of 3rd side

Now substituting the given values, we get;

[tex]2w+1+3w+3w=25\\\\8w+1=25\\\\8w=25-1\\\\8w=24\\\\w=\frac{24}{8}=3[/tex]

Now we have the value of w so we can calculate the length of each side.

Length of 1st side = [tex]2w+1=2\times8+1=16+1=17\ in[/tex]

Length of 2nd side = [tex]3w=3\times8=24\ in[/tex]

Length of 3rd side = [tex]3w=3\times8=24\ in[/tex]

Thus the length of each side is 17 in, 24 in, 24 in.

Answer:

After 4 miles driven by cab the amount would be same in both cities.

Step-by-step explanation:

Let the number of miles be 'x'.

Given:

In NYC

Flat fee of cab = $4

Per mile charge = $1.25

Total cab charges is equal to sum of Flat fee of cab and per mile charge multiplied by number of miles.

Framing in equation form we get;

Total cab charges in NYC = [tex]4+1.25x[/tex]

In Chicago

Flat fee of cab = $6

Per mile charge = $0.75

Total cab charges is equal to sum of Flat fee of cab and per mile charge multiplied by number of miles.

Framing in equation form we get;

Total cab charges in Chicago = [tex]6+0.75x[/tex]

Now we need to find number of miles driven so that the amount could same in both cities.

Total cab charges in NYC = Total cab charges in Chicago

[tex]4+1.25x=6+0.75x[/tex]

Combining like terms we get;

[tex]1.25x-0.75x=6-4\\\\0.5x=2[/tex]

using Division Property we will divide both side by 0.5 we get;

[tex]\frac{0.5x}{0.5} =\frac{2}{0.5} \\\\x=4[/tex]

Hence After 4 miles driven by cab the amount would be same in both cities.

Answer:

Step-by-step explanation:

k = 6

To find the value of k, rationalize the denominator of 2/√3, and compare it with 2k/3 to find k = √3.

To rationalize the denominator of the fraction 2/√3, we need to make the denominator a rational number. We can do this by multiplying both the numerator and the denominator by √3.

So, after rationalizing, the fraction becomes 2√3/3. According to the problem statement, this is equivalent to 2k/3.

Therefore, we can equate 2k to 2√3:

2k = 2√3

k = √3

So, the value of k is √3.

The complete question is

When the denominator of 2/√3 is rationalized ,it becomes 2k/3​. Find k

Answer: the measure of angle A is 12 degrees

Step-by-step explanation:

Let x represent the measure of angle A.

Let y represent the measure of angle B.

Let z represent the measure of angle C.

In triangle ABC, the measure of angle B is 60 more than A. This means that

y = x + 60

The measure of angle C is eight times the measure of A. This means that

z = 8x

Also, the sum of the angles in a triangle is 180 degrees. Therefore

x + y + z = 180 - - - - - - - - - 1

Substituting y = x + 60 and z = 8x into equation 1, it becomes

x + x + 60 + 8x = 180

10x + 60 = 180

10x = 180 - 60 = 120

x = 120/10 = 12

Answer:

Step-by-step explanation:

measure of A=x

∠C=8x

∠B=x+60

in a triangle sum of angles=180°

x+8x+x+60=180

10x=120

x=12

m∠A=12°

Denzel took 1/40 of his earnings to the park but did not spend it on rides or popcorn.

Let's break down the information provided step by step to find the fraction of Denzel's earnings that he took to the park but did not spend on rides or popcorn.

Denzel put 1/2 of his earnings into savings. This means he kept 1/2 as his spending money for the amusement park.

Denzel spent 1/5 of the remaining amount on popcorn. This means he spent 1/5 * 1/2 = 1/10 of his earnings on popcorn.

Denzel also spent 3/4 of the remaining amount on rides. This means he spent 3/4 * 1/2 = 3/8 of his earnings on rides.

To find the fraction of his earnings that he took to the park but did not spend on rides or popcorn, we need to subtract the fractions spent on rides and popcorn from the fraction he took to the park.

Fraction taken to the park but not spent on rides or popcorn = 1/2 - (1/10 + 3/8)

To subtract fractions, we need a common denominator. The least common multiple of 10 and 8 is 40.

Converting the fractions to have a common denominator:

1/2 - (1/10 + 3/8) = 20/40 - (4/40 + 15/40) = 20/40 - 19/40 = 1/40

Therefore, Denzel took 1/40 of his earnings to the park but did not spend it on rides or popcorn.

Question: Denzel earned money after school. He put 1/2 of this month's earnings into savings. He took the rest to spend at the amusement park. He spent 1/5 of this amount on popcorn and 3/4 of it on rides. What fraction of his earnings did he take to the park but not spend on rides or popcorn?

Answer:

Correct answer: False

Step-by-step explanation:

coeff c= 3/2 = 1,5        coeff c₁ = 18/8 = 2,25

c ≠ c₁

God is with you!!!

Answer: False

Step-by-step explanation: When we are asked to determine whether two ratios form a proportion, what we are really being asked to do is to determine whether the ratios are equal because if the ratios are equal, then we know they form a proportion.

So in this problem, we need to determine whether 3/2 = 18/8. The easiest way to determine whether 3/2 = 18/8 is to use cross products. If the cross products are equal, then the ratios are equal.

The cross products for these two ratios are 3 x 8 and 2 x 18.

Since 3 x 8 is 24 and 2 x 18 is 36, we can easily see that 24 ≠ 36 so the cross products are not equal which means that the ratios are not equal and since the ratios are not equal, we know that they do not form a proportion.

So the answer is false. 3/2 and 18/8 do not form a proportion.

Answer: $116,000

Step-by-step explanation:

The net operating income will be the operation profit after deducting the expenses from the accrued revenue (reserve exclusive)

The revenue generated are $215,000 + $3,000

= $218,000

Expenses incurred;

$102,000

The net operating income = $218,000 - $102,000

= $116,000

Note that reserves is not used in business operation. Therefore it cannot be regarded either as revenue or expenses.

y coordinate of midpoint of line AB is 6

Solution:

Given that endpoints of line AB is (10, 14) and (4, -2)

To find:  y-coordinate of the midpoint of line AB

The midpoint of line AB is given as:

For a containing [tex]A(x_1, y_1)[/tex] and [tex]B(x_2, y_2)[/tex] the midpoint is given as:

[tex]M(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)[/tex]

Here in this question,

[tex]\left(x_{1}, y_{1}\right)=(10,14) \text { and }\left(x_{2}, y_{2}\right)=(4,-2)[/tex]

So midpoint is:

[tex]\begin{aligned}&M(x, y)=\left(\frac{10+4}{2}, \frac{14-2}{2}\right)\\\\&M(x, y)=\left(\frac{14}{2}, \frac{12}{2}\right)\\\\&M(x, y)=(7,6)\end{aligned}[/tex]

Therefore y coordinate of midpoint of line AB is 6

Answer:

There were 440 Standard version of songs downloaded in Web music store.

Step-by-step explanation:

Given,

Total number of songs downloaded = 1310

Total size of the downloaded songs = 4752 MB

Size of standard version of song = 2.1 MB

Size of high quality version of song = 4.4 MB

Solution,

Let the number of standard version  of song be 'x'.

And also let the number of high quality version of song be 'y'.

Now, total number of songs is the sum of total number of standard version  of song and total number of high quality version of song.

On framing the above sentence in equation form, we get;

[tex]x+y=1310\ \ \ \ \ equation\ 1[/tex]

Now, Total size of the downloaded songs is the sum of total number of standard version of song multiplied with size of standard version  of song and total number of high quality version of song multiplied with size of high quality version of song.

On framing the above sentence in equation form, we get;

[tex]2.1x+4.4y=4752[/tex]

Multiplying with 10 on both side, we get;

[tex]10(2.1x+4.4y)=4752\times10\\\\21x+44y=47520\ \ \ \ equation\ 2[/tex]

Now multiplying equation 1 by 21, we get;

[tex]21(x+y)=1310\times21`\\\\21x+21y=27510\ \ \ \ equation\ 3[/tex]

Now subtract equation 3 from equation 2, we get;

[tex](21x+44y)-(21x+21y)=47520-27510\\\\21x+44y-21x-21y=20010\\\\23y=20010\\\\y=\frac{20010}{23}\\\\y=870[/tex]

On substituting the value of y in equation 1, we get the value of x;

[tex]x+y=1310\\\\x+870=1310\\\\x=1310-870=440[/tex]

Hence There were 440 Standard version of songs downloaded in Web music store.