24-7=17
17
pennies
7 nickles
total value is
5(7)+1(17)=35+17=52
cents
An electrician earns $110 after his first hour of working for a client. His total pay based on the number of hours worked can be represented using the sequence shown.
110, 130, 150, 170, ...
Which recursive formula can be used to determine the total amount of money earned for each successive hour worked based on the amount of money currently earned?
The recursive formula that could be used for measuring the total amount of money is f(n+1)=f(n)+20.
Given that,
The electrician earns $110.And, the sequence should be 110, 130, 150, 170, and so on. Here we assume that f(x) represent pay. And, x be the number of hours worked.Based on the above information, we can see that there are 20 increments in every next number.
So, the equation should be f(n+1)=f(n)+20
Learn more: brainly.com/question/11679190
NEED ANSWERS ASAP 80 POINT QUESTIONS
a) The value of homes in one area went up by an average of 2.3% in the past year. Estimate the value today of a home that was valued at $265,000 last year.
b) This year, the annual sales through one Century 21 office with 12 sales agents were $42 million. Estimate the revenue for the office if it received an average of 20% of the 6% commission on sales.
c) a) From the revenue in part (b) above, the office manager must pay all costs of operating the sales office, including advertising, utilities, phones, insurance, and salaries for all noncommission employees. For the current year, these costs amount to $468,000. Find the profit as a percent of total revenue to the real estate office and round to the nearest tenth of a percent.
A) 265,000* 1.023 = $271,095
B) 42,000,000*0.06 = 2,520,000*0.20 = $504,000
C) 504000 - 468000 = 36000/504000 = 0.0714 = 7.1%
Use inductive reasoning to describe each pattern and find the next two terms of each sequence.
1, 4, 9, 16, 25, …
Answer:
B. Multiply by 2; 64, 128.
solve the literal equation for y a=9y-3yx
Final answer:
To solve the literal equation for y in the given equation a=9y-3yx, we can rearrange the terms and isolate y on one side. The solution for y is (a - 9y) / (-3x).
Explanation:
To solve the literal equation for y, we need to isolate y on one side of the equation.
Given the equation a = 9y - 3yx, we can start by rearranging the terms.
Subtract 9y from both sides:
a - 9y = -3yx
Divide both sides by -3x:
(a - 9y) / (-3x) = y
So, the solution for y is (a - 9y) / (-3x).
Final answer:
To solve the given literal equation for y, factor out y and then divide by (9 - 3x) to obtain the equation y = a / (9 - 3x), which allows y to be expressed in terms of a and x.
Explanation:
To solve the literal equation for y given as a = 9y - 3yx, we want to isolate y on one side of the equation. To do this, we first factor out y from the terms on the right side of the equation:
a = y(9 - 3x)
Next, we divide both sides of the equation by (9 - 3x) to get y by itself:
y = a / (9 - 3x)
This equation represents the value of y in terms of a and x. In the context of a linear equation, such as y = 9 + 3x, the number 9 is the y-intercept (denoted as the b term), and the number 3 is the slope (denoted as the m term).
Write each statement in if-then form.
3. “Those who do not remember the past are condemned to repeat it” (George Santayana)
4. Adjacent angles share a common vertex and a common side
which is larger 42mm or 10cm, 15mm or 0.15, 10mm or 2 cm
1. 10 cm
2. 15 mm
3. 2 cm
Hope this helps even though it's pretty late!
If a, b, and c are nxn invertible matrices, does the equation c^-1(a+x)b^-1 have a solution c
There is a solution. Starting from C−1(A+X)B−1=In C−1(A+X)B−1=In, multiply both of the sides of the equation, by C and multiply both sides of the equation by B.
In other terms, this is the solution:
Given: C^(-1)(A + X)B^(-1) = In
= CC^(-1)(A + X)B^(-1)B = CInB
= In(A + X)In = CB
= AInIn + XInIn = CB
= A + X = CB
X = CB – A
The final answer Is X = CB – A
Write the equation of the linear function for which f(0)=3 and f^-1(0)=-2
Find the markup $111.00 percent of markup 50%
Answer:
$166.50
Step-by-step explanation:
1. Congruent triangles are ______ similar
A. Never
B. Always
C. Sometimes
2. Similar triangles are ____ similar
A. Sometimes
B. Always
C. Never
What is 3/10 divided by 4/5
Simplify the expression.
12 x [(9 + 6) / 3}
A.
38
B.
54
C.
60
D.
110
Seorang penjual beras mencampur 3 jenis beras. campuran pertama terdiri atas 1 kg jenis a , 2 kg jenis b , dan 4 kg jenis c dijual dengan harga Rp.19.500 . campuran beras kedua terdiri dari 2 kg jenis a dan 3 kg jenis b dijual harga Rp.19.000 . campuran beras ketiga terdiri atas 1 kg jenis b dan 1 kg jenis c dijual dengan harg Rp.6.250 . harga beras jenis manakah yang paling mahal
The type of rice which is most expensive is [tex]\boxed{\text{\bf type B}}[/tex].
Further details:
It is given that the rice seller mixes three types of rice and the total number of mixture is three.
The first mixture consists [tex]1\text{ kg}[/tex] rice of type [tex]\text{A}[/tex], [tex]2\text{ kg}[/tex] rice of type [tex]\text{B}[/tex] and [tex]4\text{ kg}[/tex] rice of type [tex]\text{C}[/tex].
The selling price of the first mixture is [tex]19500[/tex].
In equation form it can be written as follows:
[tex]\boxed{\text{A}+2\text{B}+4\text{C}=19500}[/tex] .......(1)
The second mixture consists [tex]2\text{ kg}[/tex] rice of type [tex]\text{A}[/tex] and [tex]3\text{ kg}[/tex] rice of type [tex]\text{B}[/tex].
The selling price of the second mixture is [tex]19000[/tex].
In equation form it can be written as follows:
[tex]\boxed{2\text{A}+3\text{B}=19000}[/tex] ......(2)
The third mixture consists [tex]1\text{ kg}[/tex] rice of type [tex]\text{B}[/tex] and [tex]1\text{ kg}[/tex] rice of type [tex]\text{C}[/tex].
The selling price of the third mixture is [tex]6250[/tex].
In equation form it can be written as follows:
[tex]\boxed{\text{B}+\text{C}=6250}[/tex] ........(3)
Rearrange the equation (3) to obtain the value of [tex]\text{B}[/tex] as follows:
[tex]\text{B}=6250-\text{C}[/tex] ...........(4)
Substitute this value of [tex]\text{B}[/tex] in equation (2).
[tex]\begin{aligned}2\text{A}+3(6250-\text{C})&=19000\\2A+(3\cdot 6250)-3\text{C}&=19000\\2\text{A}-3\text{C}+18750&=19000\\2\text{A}-3\text{C}&=19000-18750\\2\text{A}-3\text{C}&=250\end{aligned}[/tex]
Further solve the above equation,
[tex]\text{A}-1.5\text{C}=125[/tex] ......(5)
Now substitute the value of [tex]\text{B}[/tex] from equation (4) in equation (1) to obtain an equation in the form of [tex]\text{A}[/tex] and [tex]\text{C}[/tex] as follows,
[tex]\begin{aligned}\text{A}+2(6250-\text{C})+4\text{C}&=19500\\ \text{A}+(2\cdot 6250)-2\text{C}+4\text{C}&=19500\\ \text{A}+12500+2\text{C}&=19500\\ \tex{A}+2\text{C}&=19500-12500\end{aligned}[/tex]
Further the above equation can be simplifies as follows,
[tex]\text{A}+2\text{C}=7000[/tex] .......(6)
Subtract the equation (4) from (5) to obtain the value of [tex]\text{A}[/tex] and [tex]\text{C}[/tex].
[tex]\begin{aligned}\text{A}+2\text{C}-\text{A}+1.5\text{C}&=7000-125\\3.5\text{C}&=6875\\ \text{C}&=1964.3\end{aligned}[/tex]
Substitute this value of [tex]\text{C}[/tex] in equation (5) to obtain the value of [tex]\text{A}[/tex] as follows,
[tex]\begin{aligned}\text{A}+(2\cdot 1964.3)&=7000\\ \text{A}&=7000-3928.6\\ \text{A}&=3071.4\end{aligned}[/tex]
Again substitute [tex]\text{C}=1964.3[/tex] in equation (4) to obtain the value of [tex]\text{B}[/tex].
[tex]\begin{aligned}\text{B}&=6250-1964.3\\&=4285.7\end{aligned}[/tex]
Therefore, the most expensive type of rice is [tex]\boxed{\text{\bf type B}}[/tex].
Learn more:
1. Problem on percentage in a survey: https://brainly.com/question/3724002
2. Problem on unit conversion factor: https://brainly.com/question/5009365
3. Problem on to find the value in pounds: https://brainly.com/question/4837736
Answer details:
Grade: Middle School
Subject: Mathematics
Chapter: Mixtures
Keywords: Rice seller, mixture, sold, expensive, type A, type B, type C, simplification, consist, 19500, 1 kg,addition, substitution, multiplication.
Joey has 5.75 made up of all dimes and quarters. If joey has 38 coins. How many of each each coin does he have?
3. Start with the following statement: Vertical angles are congruent. a. State the conditional and three other forms of the statement. b. Write all 4 forms of the statement using symbols. c. If you know that a statement is true, what do you know about the truth of its converse, inverse, and contrapositive? BONUS: Use at least one truth table AND at least one property to support your reasoning.
Now suppose that the 5 (identical) prizes will be distributed among the 8 people. a winner can receive more than one prize. in how many ways could the 5 prizes be distributed?
what is 1/8(−8c+16)−1/3(6+3c)?
Thank you!!
Answer: The required simplified expression is -2c.
Step-by-step explanation: We are given to simplify the following expression :
[tex]E=\dfrac{1}{8}(-8c+16)-\dfrac{1}{3}(6+3c)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
We will be using the following distributive property :
[tex]a(b+c)=ab+ac.[/tex]
From expression (i), we get
[tex]E\\\\\\=\dfrac{1}{8}(-8c+16)-\dfrac{1}{3}(6+3c)\\\\\\=\dfrac{1}{8}\times(-8c)+\dfrac{1}{8}\times16-\dfrac{1}{3}\times6-\dfrac{1}{3}\times3c\\\\=-c+2-2-c\\\\=-2c.[/tex]
Thus, the required simplified expression is -2c.
Graph y=3x and make a table of values too
The difference of three times a number and 4 is -19?
what makes this graph misleading?
Find two consecutive even numbers such that the sum of the number and twice the greater number is 100
f(x) = 2x + 6, g(x) = 4x2 Find (f + g)(x).
Answers are: 8x^3 + 24x
2x+6/4x^2
4x^2 + 2x + 6
-4x^2 + 2x + 6
Answer: The correct option is
(C) [tex]4x^2+2x+6.[/tex]
Step-by-step explanation: We are given the functions f(x) and g(x) as follows :
[tex]f(x)=2x+6,\\\\g(x)=4x^2.[/tex]
We are to find the value of (f+g)(x).
We know that
for any two functions p(x) and q(x), we have
[tex](p+q)(x)=p(x)+q(x).[/tex]
So, we get
[tex](f+g)(x)\\\\=f(x)+g(x)\\\\=2x+6+4x^2\\\\=4x^2+2x+6.[/tex]
Thus, the required value is [tex](4x^2+2x+6).[/tex]
Option (C) is CORRECT.
A bit-map terminal has a 1024x768 display. the display is redrawn 75 times a second. how long is the pulse corresponding to one pixel
The pulse corresponding to one pixel is approximately 1.27 microseconds.
Explanation:In this case, we can calculate the duration of the pulse corresponding to one pixel by dividing the time required to redraw the display by the total number of pixels.
Given that the display is redrawn 75 times a second, and the display has a resolution of 1024x768 pixels, the total number of pixels is 1024 * 768 = 786,432 pixels.
To find the duration of the pulse corresponding to one pixel, we can divide the time required to redraw the display (1/75 seconds) by the total number of pixels (786,432 pixels).
Therefore, the pulse corresponding to one pixel is approximately 1.27 microseconds.
The sides of a triangle are in the ratio 3:4:5. What is the length of each side if the perimeter of the triangle is 30 cm?
A. 2.5 cm, 5. cm, 7.5 cm
B. 9 cm, 10 cm, 11 cm
C. 7.5 cm, 10 cm, 12.5 cm
D. 2.5 cm, 7.5 cm, 12.5 cm
ram wants to work to preserve marine habitats. Which field of study would be most useful to him
A) Meteorology
B)Zoology
C)Oceanography
D)Botany
A triangle has a perimeter of 10x+2. Two sides have lengths of 5x and 2x+9. What is the length of the 3rd side
The table shows a function. Is the function linear or nonlinear? x y 8 14 9 8 10 0
a bunch of has 10 3/4 lb of ground beef that will be priced at 3:40 per pound he divides the me into 8 equal packages to the nearest cent what will be the price of each package
The penny size d is given by the literal equation d = 4n - 2, solve for n
Answer:
The value of the equation for n is [tex]n=\frac{d +2}{4}[/tex].
Step-by-step explanation:
Consider the provided equation.
[tex]d = 4n - 2[/tex]
We need to solve the equation for n.
Add 2 from both the sides.
[tex]d +2= 4n - 2+2[/tex]
[tex]d +2= 4n [/tex]
Divide both side of the equation with 4.
[tex]\frac{d +2}{4}= \frac{4n}{4} [/tex]
[tex]\frac{d +2}{4}= n [/tex]
Hence, the value of the equation for n is [tex]n=\frac{d +2}{4}[/tex].
Solve: $|2x - 1| = |3x + 5|$. write your answers as a list of numbers, separated by commas,
e.g. "23, 19" (but without the quotes).
Solution 1:
If |a| = |b|, then either a = b or a = -b. Hence, if |2x - 1| = |3x + 5|, then either 2x - 1 = 3x + 5 or 2x - 1 = -(3x + 5).
If 2x - 1 = 3x + 5, then x = -6. If 2x - 1 = -(3x + 5), then x = -4/5. Therefore, the solutions are x = \boxed{-6, -4/5}.
Solution 2:
Another approach is to square both sides. Squaring both sides, we get 4x^2 - 4x + 1 = 9x^2 + 30x + 25 (because |a|^2 = a^2 for all a). This simplifies to 5x^2 + 34x + 24 = 0, which factors as (x + 6)(5x + 4) = 0, so the solutions are x = -6 and x = -4/5, as before. You must be careful when using this approach because squaring both sides of an equation can introduce false solutions. Thus, we need to check that both of these "solutions" work in the original expression before declaring them correct.