Answer:
3.98 x 10⁻⁴ M.
Explanation:
∵ pH = - log[H₃O⁺]
∴ 3.4 = - log[H₃O⁺].
∴ log[H₃O⁺] = - 3.4.
∴ [H₃O⁺] = 3.98 x 10⁻⁴ M.
Answer: The hydronium ion concentration for the solution is [tex]3.98\times 10^{-4}M[/tex]
Explanation:
pH is defined as the negative logarithm of hydrogen ion concentration or hydronium ion concentration present in a solution.
To calculate the pH of the reaction, we use the equation:
[tex]pH=-\log[H_3O^+][/tex]
We are given:
pH of the solution = 3.40
Putting values in above equation, we get:
[tex]3.40=-\log[H_3O^+][/tex]
[tex][H_3O^+]=3.98\times 10^{-4}M[/tex]
Hence, the hydronium ion concentration for the solution is [tex]3.98\times 10^{-4}M[/tex]
Dan used the following method to convert 27.7778 cm/s to km/h. An equation is shown. The expression on the left has three terms separated by the multiplication sign. The first term is 27.7778 cm by 1 h. The second term is 1 km by 100,000 cm. The third term is 1 s by 0.000277778 h. The number on the right of the equal to sign is 1 km per hour. (1 km = 100,000 cm and 1 s = 0.000277778 h) What is the error in Dan's conversion method?
A. 1 h should be written as 1 s.
B. 1 km should be written as 1 cm.
C. 27.7778 cm should be written as 27.7778 km.
D. 0.000277778 h should be written as 0.000277778 s.
A is correct (1 h should be written as 1 s)
I just took this exam. :)
Answer:
Your correct answer is A. 1 h should be written as 1 s.
Explanation:
What are the concentrations of hso4−, so42-, and h+ in a 0.35 m khso4 solution? (hint: h2so4 is a strong acid; ka for hso4− = 1.3 ✕ 10−2.)?
[H+] = 0.051 M
[SO4=] = 0.051M
[HSO4-] = 0.16M
Explanation;HSO4- <==> H+ + SO4= ..... Ka = 1.3x10^-2
Ka = [H+] [SO4=] / [HSO4-]
1.3x10^-2 = x^2 / (0.21-x)
Using algebra and solving the quadratic equation to solve for x.
x = 0.051
Therefore;
[H+] = [SO4=] = 0.051M
[HSO4-] = 0.16M
Answer : The concentration of [tex]HSO_4^-[/tex], [tex]SO_4^{2-}[/tex] and [tex]H^+[/tex] are 0.29 M, 0.061 M and 0.061 M respectively.
Explanation :
First we have to calculate the concentration of [tex]HSO_4^-[/tex]
The dissociation of [tex]KHSO_4[/tex] is:
[tex]KHSO_4\rightarrow K^++HSO_4^-[/tex]
As, 1 mole of [tex]KHSO_4[/tex] gives 1 mole of [tex]HSO_4^-[/tex]
So, 0.35 M of [tex]KHSO_4[/tex] gives 0.35 M of [tex]HSO_4^-[/tex]
Now we have to determine the concentration of [tex]SO_4^{2-}[/tex] and [tex]H^+[/tex].
The dissociation of [tex]HSO_4^-[/tex] is:
[tex]HSO_4^-\rightleftharpoons H^++SO_4^{2-}[/tex]
Initial conc. 0.35 0 0
At eqm. (0.35-x) x x
The expression of acid dissociation constant will be:
[tex]K_a=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}[/tex]
Now put all the given values in this expression, we get:
[tex]1.3\times 10^{-2}=\frac{(x)\times (x)}{(0.35-x)}[/tex]
[tex]x=0.061M[/tex]
Thus, the concentration of [tex]SO_4^{2-}[/tex] = x = 0.061 M
The concentration of [tex]H^+[/tex] = x = 0.061 M
The concentration of [tex]HSO_4^-[/tex] = 0.35 - x = 0.35 - 0.061 = 0.29 M
A volume of 10.0L of gas at a temperature of 5c is cooled to a temperature of 85C at constant pressure what is the new volume of gas
I don't know how 5°C cooled to 85°C but the answer would be 12.878L
Answer:
At constant pressure the new volume of gas is 12.878 L.
Explanation:
Charles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly. So the ratio between volume and temperature will always have the same value:
[tex]\frac{V}{T} =k[/tex]
where the temperature is expressed in degrees kelvin (° K)
Then, when considering the two situations 1 and 2, keeping the amount of gas and the temperature constant, the relationship must be met:
[tex]\frac{V1}{T1} =\frac{V2}{T2}[/tex]
In this case, you know:
V1= 10 LT1= 5 +273 = 278°K (where 0°C=273°K)V2= ?T2= 85 + 273 = 358°KReplacing:
[tex]\frac{10}{278} =\frac{V2}{358}[/tex]
Solving:
[tex]V2=\frac{10}{278} *358[/tex]
V2=12.878 L
At constant pressure the new volume of gas is 12.878 L.
"what is the ph of a 0.160 m ammonia solution"? express your answer numerically to two decimal places.
Final answer:
The pH of a 0.160 M ammonia solution can be calculated using the pOH method. The concentration of hydroxide ions in the solution is approximately 1.125 x 10^-4 M, resulting in a pOH of approximately 3.95. The pH of the solution is approximately 10.05.
Explanation:
The pH of a 0.160 M ammonia solution can be calculated using the pOH method. Ammonia is a weak base, so we can use the equation:
pOH = -log[OH-]
pH + pOH = 14
First, we need to find the concentration of hydroxide ions ([OH-]) in the solution. The Kb value for ammonia (NH3) is 1.8 x 10-5.
Given that [NH3] = 0.160 M, we can calculate [OH-] using the Kb expression:
Kb = [NH3][OH-] / [NH4+]
Since [NH4+] can be ignored in this dilute ammonia solution, the equation simplifies to:
Kb = [NH3][OH-].
Now, rearranging the equation to solve for [OH-], we get:
[OH-] = Kb / [NH3]
Substituting the given values into the equation:
[OH-] = (1.8 x 10-5) / (0.160)
[OH-] = 1.125 x 10-4 M
Next, we can calculate the pOH of the solution using the equation:
pOH = -log[OH-]
pOH = -log(1.125 x 10-4)
pOH ≈ 3.95
Finally, we can find the pH using the equation:
pH = 14 - pOH
pH = 14 - 3.95
pH ≈ 10.05
How many moles in 36.50 g of Fe2O3? (Molar Mass Fe2O3 = 159.7 g.mol)
Answer:
0.2286 mol
Explanation:
Mass = 36.5g
Molar Mass = 159.7 g/mol
Number of moles = ?
The formular relating these parameters is given as;
Number of moles = Mass / Molar mass
Number of moles = 36.5 / 159.7 = 0.2286 mol
What type of chemical equation is cellular respiration
Cellular Respiration is an Exothermic reaction as the product is ATP (energy)
please mark me as the brainliest
Answer:
Exothermic reaction because the product produced is ATP (energy)
Explanation:
When a small volume of NaOH solution is added to a acetate/acetic acid buffer system, which of the following occur? a. The pH will increase. b. The concentration of acetic acid will decrease. c. The pH will decrease. d. The concentration of acetate will increase. e. The pH will stay the same. f. The final volume of the solution will increase.
When NaOH is added to an acetate/acetic acid buffer system, the pH increases, the concentration of acetic acid decreases, and the concentration of acetate increases.
Explanation:When a small volume of NaOH solution is added to an acetate/acetic acid buffer system, the following occur:
The pH of the solution increases.The concentration of acetic acid decreases.The concentration of acetate increases.This is because when NaOH is added, it reacts with acetic acid to form sodium acetate and water. The increase in concentration of sodium acetate leads to an increase in the concentration of acetate ions, causing the pH to increase. At the same time, the reaction consumes acetic acid, resulting in a decrease in its concentration.
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Bases on Graham's law of diffusion, how does the speed of diffusion of neon (M=20.2) compare to the Krpton (M=83.8)
Answer:
2.037.
Explanation:
Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.∨ ∝ 1/√M.
Where, ∨ is the rate of diffusion.
M is the molar mass of the gas.
For Ne and Kr:(∨)Ne/(∨)Kr = √(M of Kr/M of Ne) = √(83.8 / 20.2) = 2.037.
Lewis structure for 2O2
I'm okay with making lewis structures where there will be one 'thing' in the middle but in 2O2 I'm unsure because there are 2 oxygen's in the middle but is there an oxygen on either side or on top of the middle oxygen's? I'm unsure about the the difference between the 'big number' and the subscript number.
the big number describes the number ratio in a chemical equation
so for example,
2H2 + O2 --> 2H2O means
2 moles of hydrogen reacts with one mole of oxygen to form 2 moles of water
and as you know, the small (subscript) number determines the number of atoms of that element in one molecule of a compound
so I believe that drawing a normal lewis structure ( O=O ) should be correct
Explanation:
For what I understand in the question, the "big number" is called a stoichiometric coefficient and represents the ammount of molecules of the substance that follows it ( in this case O2) involved in a reaction.
In this case there is no reaction but it asks you for the lewis structure of two molecules of oxygen (O2).
The lewis structure of oxygen is: O=O
Two molecules of it can bond by london forces or dative unions forming what is known as a dimer (two molecules of the same substance bonded).
2. When a molecule of NAD+ (nicotinamide adenine dinucleotide) gains a hydrogen atom (not a proton), the molecule becomes _____. A) dehydrogenated B) oxidized C) reduced D) redoxed
Answer:
C) reduced
Explanation:
NAD+ is an oxidizing agent which accepts electrons from other molecules and becomes reduced. When NAD+ is reduced, NADH is formed, which can then be used as a reducing agent to donate electrons. The electron transfer reactions are the main function of NAD.NAD+ accepts a hydrogen ion (H+) and two electrons (2e−), as it becomes reduced to NADH + H+.NAD+ becomes reduced when it gains a hydrogen atom, transforming into NADH, which plays a significant role in cellular energy metabolism.
Explanation:When a molecule of NAD+ (nicotinamide adenine dinucleotide) gains a hydrogen atom, the molecule becomes reduced. This process of gaining an electron (or hydrogen atom) is known as reduction in metabolism. Essentially, NAD+ serves as an important electron carrier within cells and as it accepts electrons, it becomes reduced to its alternate form called NADH. It's important to note that oxidation and reduction reactions often go hand in hand in biological systems, which is why they are typically referred to as redox reactions. In this context, NAD+ is reduced (gains an electron) to form NADH, which then plays a crucial role in energy metabolism within the cell.
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What is the name of this compound?
A. ethanal
B. ethylamine
C. ethanoic acid
D. methyl ethanoate
Answer:
B. ethylamine.
Explanation:
Since the compound contains NH₂, it is an amine compound.The alkyl group C₂H₅- contains 2 C atoms (ethyl group).So, the compound is ethylamine.
Which of these processes most likely helps in the constant formation of Earth's crust?
A)the liquid core rising to Earth's crust during earthquakes
B)the solid core melting and rising on Earth's crust during earthquakes
C)the outer crust dissolving in the liquid mantle during volcanic eruptions
D)the liquid mantle flowing through the cracks in Earth's crust during volcanic eruptions
The liquid mantle flowing through the cracks in Earth's crust during volcanic eruptions.
Explanation;The Earth’s crust is the outermost layer of our planet and is less than 1% of the entire Earth's size. There is the crust and then the mantle and they both contain different kinds of rocks which make them different to each other.The crust of the Earth is composed of a great variety of igneous, metamorphic, and sedimentary rocks. The crust is underlain by the mantleFinal answer:
The formation of Earth's crust is most likely due to the D. liquid mantle flowing through cracks during volcanic eruptions, as at divergent boundaries, molten material from the mantle rises and cools to form new crust.
Explanation:
The processes that help in the constant formation of Earth's crust are primarily associated with tectonic activities and the movement of magma. According to the options provided, the liquid mantle flowing through the cracks in Earth's crust during volcanic eruptions (D) is the most likely process responsible for the formation of new crust. This is because at divergent boundaries, such as the Mid-Ocean Ridge, molten material from the mantle rises through the gaps created by tectonic plates moving apart.
As the molten material cools, it solidifies and forms new crust. Convection currents in the mantle (B) are thought to drive the movement of tectonic plates, contributing to processes such as sea floor spreading and the creation of new crust along the Mid-Ocean Ridge. Additionally, subduction zones where oceanic crust collides with continental crust (B) can lead to volcanic activity and the formation of new crust.
How many distinct monochlorinated products including stereoisomers can result when the alkane below is heated in the presence of cl2?
When an alkane is heated in the presence of chlorine gas, monochlorinated products can be formed.
Explanation:These products can include stereoisomers. In the case of methane, there are four possible monochlorinated products including stereoisomers. The alkane is not specified in the question, but let's assume it is methane (CH4) as an example. When methane is heated in the presence of chlorine gas (Cl2), a substitution reaction occurs. One of the hydrogen atoms in methane can be replaced by a chlorine atom, resulting in a monochlorinated product. In this case, there are four possible monochlorinated products (CH3Cl, CH2Cl2, CHCl3, CCl4) including different stereoisomers.
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How do intermolecular forces affect the boiling point of a liquid
The Intermolecular forces increase with increasing polarization of bonds. The strength of Intermolecular forces (and therefore impact on boiling points) is ionic > hydrogen bonding > dipole dipole > dispersion. Boiling point increases with molecular weight, and with surface area.
Which value is most likely to be the pH of salt that is formed by the reaction of a week acid and a strong base ?
Answer:
When an acid and strong reacts with each other the formation of salt occurs, and this reaction is named as neutralization reaction. The pH of salt depends upon the nature of acid and bases reacting in the reaction. When a week acid and a strong base reacts with each other, the base dominates the nature of salt because base involved is strong. The pH of the salt will be greater than 7.
When silver tarnishes, ag atoms are oxidized to form ag+ ions. ag atoms are reduced to form ag+ i?
Ag atoms are oxidized to form Ag+ ions
Explanation;Silver tarnish is the result of the oxide on the silver surface reacting with hydrogen sulfide (H2S) in air. This leaves a black film of silver sulfide (Ag2S). Silver atoms are oxidized to form Ag+ ions. When a thin coating of silver sulfide forms on the surface of silver, it darkens the silver.The offending silver tarnish can be removed by either striping it from the surface or reversing the chemical reaction and turn silver sulfide back into silver.Silver tarnishes when it is oxidized to form Ag+ ions. The process involves the loss of electrons. Silver ions can be reduced back to silver atoms in certain chemical reactions by the use of reducing agents like iron (II) ions or zinc, but not during the tarnishing process which is an oxidation process.
Explanation:When silver tarnishes, the silver atoms (Ag) are indeed oxidized to form Ag+ ions. This is a chemical reaction where silver loses electrons and hence, is oxidized. This process is represented in the reaction depicted: Ag+ (aq) + e¯ → Ag(s). However, it should be noted that in an oxidation reaction, while one species (here - silver) is oxidized, another species must be reduced concurrently. In the context of your question, Ag atoms are not reduced back to Ag+ ions, as that would counteract the oxidation process.
In cases where silver is recovered from solutions, such as a cyanide solution, reducing agents such as iron (II) ions or zinc might be added, leading to a reaction: 2[Ag(CN)₂](aq) + Zn(s) → 2Ag(s) + [Zn(CN)4] ²¯ (aq). This is a chemical reduction as silver ions are reduced back to silver atoms.
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[Standard Enthalpy of Formation]
Remember to show work and explain.
5. Calculate the change in enthalpy for:
6. Calculate the ∆H_rxn given the following
Answer:
5. ΔH = 238.7 kJ; 6 ΔH, = -1504.6 kJ
Step-by-step explanation:
Question 5:
We have three equations:
(I) CH₃OH + ³/₂O₂ ⟶ CO₂ + 2H₂O; ΔH = -726.4 kJ
(II) C + O₂ ⟶ CO₂; ΔH = -393.5 kJ
(III) H₂ + ½O₂ ⟶ H₂O; ΔH = -285.8 kJ
From these, we must devise the target equation:
(IV) C + 2H₂ + ½ O₂ → CH₃OH; ΔH = ?
The target equation has 1C on the left, so you rewrite Equation (II)..
(V) C + O₂ ⟶ CO₂; ΔH = -393.5 kJ
Equation (V) has 1CO₂ on the right, and that is not in the target equation.
You need an equation with ½O₂ on the left, so you reverse Equation (I).
When you reverse an equation, you reverse the sign of its ΔH.
(VI) CO₂ + 2H₂O ⟶ CH₃OH + ³/₂O₂; ΔH = 726.4 kJ
Equation (VI) has 2H₂O on the left, and that is not in the target equation.
You need an equation with 2H₂O on the right. Double Equation (III).
When you double an equation, you double its ΔH.
(VII) 2H₂ + O₂ ⟶ 2H₂O; ΔH = -571.6 kJ
Now, you add equations (V), (VI), and (VII), cancelling species that appear on opposite sides of the reaction arrows.
When you add equations, you add their ΔH values.
We get the target equation (IV)
(V) C + O₂ ⟶ CO₂; ΔH = -393.5 kJ
(VI) CO₂ + 2H₂O ⟶ CH₃OH + ³/₂O₂ ; ΔH = 726.4 kJ
(VII) 2H₂ + O₂ ⟶ 2H₂O; ΔH = -571.6 kJ
(IV) C + 2H₂ + ½ O₂ → CH₃OH; ΔH = -238.7 kJ
Question 6
We have three equations:
(I) Mg + ½O₂ → MgO; ΔH = -601.7 kJ
(II) Mg + S ⟶ MgS; ΔH = -598.0 kJ
(III) S + O₂ ⟶ SO₂; ΔH = -296.8 kJ
From these, we must devise the target equation:
(IV) 3Mg + SO₂ → MgS + 2MgO; ΔH = ?
The target equation has 1SO₂ on the left, so you reverse Equation(III).
(V) SO₂ ⟶ S + O₂; ΔH = 296.8 kJ
Equation (V) has 1S on the right, and that is not in the target equation.
You need an equation with 1S on the left, so you rewrite Equation (II).
(VI) Mg + S ⟶ MgS; ΔH = -598.0 kJ
Equation (V) has 1O₂ on the right, and that is not in the target equation.
You need an equation with 1O₂ on the left. Double Equation (I).
(VII) 2Mg + O₂⟶ 2MgO ; ΔH = -1203.4 kJ
Now, you add equations (V), (VI), and (VII), cancelling species that appear on opposite sides of the reaction arrows.
We get the target equation (IV)
(V) SO₂ ⟶ S + O₂; ΔH = 296.8 kJ
(VI) Mg + S ⟶ MgS; ΔH = - 598.0 kJ
(VII) 2Mg + O₂ ⟶ 2MgO; ΔH = -1203.4 kJ
(IV) 3Mg + SO₂ → MgS + 2MgO; ΔH = -1504.6 kJ
oxygen travels at a velocity of 29.0 m/s. at what velocity would sulpur tetrafluoride travel under the same conditions?
2.54m/s. See the attached image for work. X represents the velocity of SF4.
To calculate the velocity of sulfur tetrafluoride under the same conditions as oxygen, we need to consider their molar masses and use the formula for calculating the velocities of gases.
Explanation:In order to determine the velocity at which sulfur tetrafluoride would travel under the same conditions as oxygen, we need to consider their molar masses. The molar mass of sulfur tetrafluoride (SF4) is 108.07 g/mol, while the molar mass of oxygen (O₂) is 32.00 g/mol. Since the velocities of gases are inversely proportional to the square root of their molar masses, we can use the formula:
The velocity of sulfur tetrafluoride = Velocity of oxygen × √(molar mass of oxygen / molar mass of sulfur tetrafluoride)
Using the given velocity of oxygen as 29.0 m/s, we can substitute the molar masses and calculate the velocity of sulfur tetrafluoride.
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If the equation CO(g) + 2H2(g) →← → ← CH3OH(g) + energy is for a system at equilibrium, increasing the temperature will cause _____. [
CH3OH] to increase and [CO] to decrease [
CH3OH] to decrease and [CO] to increase
both [CH3OH] and [CO] to increase
both [CH3OH] and [H2] to decrease
Answer:
[CH₃OH] to decrease and [CO] to increase.
Explanation:
Since the energy appears as a product. So, the system is exothermic that releases heat. Increasing the temperature of the system will cause the system to be shifted to the left side to attain the equilibrium again. So, the right answer is:[CH₃OH] to decrease and [CO] to increase.
A compound that changes color when it is in contact with an acid or base is called
If a dozen apples has a mass of 2.0 kg and 0.20 bushel is 1 dozen apples, How many bushels of apples are in 1.0 Kg of apples
If 1 dozen apples has a mass of 2.0 kg and 0.20 bushel is 1 dozen apples, how many bushels of apples are in 1.0 kg of apples?
0.1 bushels
There are 0.1 bushels in 1 kg of apple.
What is a dozen ?A dozen is a set of 12 things. A dozen of apples mean 12 piece of apples , a dozen of people mean 12 people.
It is given that
a dozen apples has a mass of 2.0 kg
and 0.20 bushel is 1 dozen apples,
bushels of apples are in 1.0 Kg of apples = ?
If 2 kg apples mean 1 dozen = 12 apples
then 1 kg apples will mean 6 apples
1 dozen or 12 apples = 0.20 bushels
6 apples will be 0.20 /2 = 0.1 bushels
Therefore there are 0.1 bushels in 1 kg of apple.
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which compounds are reactants in the process of cellular respiration
A. C6H12O6 and O2
B. C6H12O6 and CO2
C.H2O and CO2
D. H2O and O2
The reactants of cellular respiration are glucose and oxygen, or A. They react to form carbon dioxide, water, and energy as products.
The reaction shown below is used in the production of steel. It is an exothermic reaction. An engineer thinks that by finding the correct catalyst, he can reduce the amount of energy released by the reaction. Will his plan have the desired effect? Explain your answer.
Fe3O4(s) + 4C(s) → 3Fe(s) + 4CO(g)
No. Catalyst only reduce the activation energy, but don't change the energy released by the reaction.
A catalyst will alter the enthalpy of a reaction (the amount of heat that is released/absorbed) so it's not going to have the desired effect.
What are catalysts?A catalyst is a substance that speeds up a chemical reaction, or lowers the temperature or pressure needed to start one, without itself being consumed during the reaction.
A catalyst increases the rate of a reaction, but does not get consumed in the reaction and does not alter the equilibrium constant.
In other words, a catalyst affects the kinetics of a reaction, but not the thermodynamics.
They work by increasing the rate of reaction through lowering the activation energy.
Hence, a catalyst will alter the enthalpy of a reaction (the amount of heat that is released/absorbed) so it's not going to have the desired effect.
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If the Earth did not have internal energy, which of the following carbon cycle process would not be possible?
a. respiration
b. consumption
c. rock formation
d. burning fossil fuels
Answer:
c. rock formation
Explanation:
The Earth’s internal energy provides the means for the parts of the carbon cycle that involve plate tectonics, such as rock formation and subduction.
If the Earth did not have internal energy, the carbon cycle process which would not be possible is: C. rock formation.
Carbon cycle can be defined as the series of biogeochemical processes through which atoms of carbon or carbon compounds are interconverted and used within an environment, by transporting carbon from the atmosphere to the Earth and then back to the atmosphere.
Basically, the four (4) main processes associated with carbon cycle include the following:
Respiration.Consumption.Combustion such as burning of fossil fuels.Rock formation.Of all the aforementioned processes, only rock formation requires that the Earth has sufficient internal energy for the movement of materials around the core and the mantle, thereby, leading to gradual but significant changes within the Earth's crust.
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A piece of metal weighing 57.3 g is heated to a temperature of 88.0°C and is then immersed in 155 g of water at a temperature of 21.53°C. After equilibration the temperature is 24.72°C. If CH2O = 4.184 J/g°C, what is Cmetal?
A) .370 J/g°C
B) .164 J/g°C
C) 1.00 J/g°C
D) 2.11 J/g°C
E) .571 J/g°C
The answer is E. You must use the formula q=mCDeltaT to solve this equation. You must also use the formula that q(reaction)=q(solution) to solve this problem
Answer:
The specific heat capacity of the metal piece is [tex]0.571J/g^oC[/tex].
Explanation:
The heat given by the hot body(metal pace) is equal to the heat taken by the cold body(water).
[tex]q_1=-q_2[/tex]
[tex]m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)[/tex]
where,
[tex]c_1[/tex] = specific heat of metal = ?
[tex]c_2[/tex] = specific heat of water = [tex]4.184 J/g^oC[/tex]
[tex]m_1[/tex] = mass of metal = 57.3 g
[tex]m_2[/tex] = mass of water = 155 g
[tex]T_f[/tex] = final temperature of water = [tex]24.72^oC[/tex]
[tex]T_1[/tex] = initial temperature of metal = [tex]88^oC[/tex]
[tex]T_2[/tex] = initial temperature of water = [tex]21.53^oC[/tex]
Now put all the given values in the above formula, we get
[tex]57.3g\times c_1\times (24.5-88.0)^oC=-155g\times 4.184J/g^oC\times (24.72-21.53)^oC[/tex]
[tex]c_1=0.571 J/g^oC[/tex]
The specific heat capacity of the metal piece is [tex]0.571J/g^oC[/tex].
In the equilibrium and concentration gizmo, you learned that you can predict the direction of a reaction by comparing the reaction quotient (qc) with the known equilibrium constant kc. you can do the same thing using partial pressures:
The direction of a chemical reaction depends on the comparison between the reaction quotient and the equilibrium constant. If the reaction quotient is greater than the equilibrium constant, the reaction goes in the reverse direction, and vice versa. This can be determined using concentrations (Qc, Kc) or partial pressures (Qp, Kp).
Explanation:In the context of chemistry, a reaction's direction can indeed be predicted by comparing the reaction quotient (Qc) with the equilibrium constant (Kc). If Qc > Kc, the reaction will tend to move in the reverse direction to reach equilibrium, as it indicates that there are too many products and not enough reactants. Conversely, if Qc < Kc, the reaction will proceed in the forward direction, as it means that there are too many reactants and not enough products. Similarly, partial pressures can be used using the reaction quotient (Qp) and equilibrium constant (Kp). These concepts are central in the study of chemical equilibria, and understanding them will help comprehend how concentrations and pressures influence the direction of reactions.
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Equilibrium constants for gas-phase reactions can be expressed in terms of partial pressures. The relationship between partial pressures (Kp) and molar concentrations (Kc) can be derived from the ideal gas equation.
In chemistry, for gas-phase solutions, the equilibrium constant can be expressed either in terms of molar concentrations (Kc) or partial pressures (Kp) of the reactants and products. These two equilibrium constants are interrelated and can be derived using the ideal gas equation: PV = nRT where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature.
The equilibrium constant Kp for a reaction involving gases is defined in terms of the partial pressures of the gases. For example, consider the reaction:
[tex]C_2H_6(g)[/tex]⇌ [tex]C_2H_4(g) + H_2(g)[/tex]
The equilibrium constant expression based on partial pressures would be:
[tex]Kp = (PC_2H_4)(PH_2) / PC_2H_6[/tex]
The reaction quotient (Qc or Qp) is calculated using initial or current pressures and can predict the direction of the reaction:
If Q < K, the reaction will proceed forward to produce more products.If Q = K, the system is already at equilibrium.If Q > K, the reaction will proceed in reverse to form more reactants.Using partial pressures allows for a precise understanding of how the system behaves under different conditions, including changes in initial amounts of reactants/products, temperature, and volume.
A 0.133 mol sample of gas in a 525 ml container has a pressure of 312 torr. The temperature of the gas is ________ °c.
Answer:
[tex]-253.2 ^{\circ}C[/tex]
Explanation:
First of all, we need to convert the pressure of the gas from torr to Pa. We know that:
1 torr = 133.3 Pa
So, the pressure in Pascals is
[tex]p=(312 torr)(133.3 Pa/torr)=4.16\cdot 10^4 Pa[/tex]
Then we also have:
n = 0.133 number of moles of the gas
[tex]V=525 mL=0.525 L=5.25\cdot 10^{-4} m^3[/tex] volume of the gas
The ideal gas equation states that
[tex]pV=nRT[/tex]
where R is the gas constant and T the absolute temperature. Solving the equation for T, we find
[tex]T=\frac{pV}{nR}=\frac{(4.16\cdot 10^4 Pa)(5.25\cdot 10^{-4} m^3)}{(0.133 mol)(8.314 J/mol K)}=19.8 K[/tex]
In Celsius, it becomes
[tex]T=19.8 K-273=-253.2 ^{\circ}C[/tex]
How do we determine the number of electrons an element has
Answer:
Explanation:
The number of protons in the nucleus of the atom is equal to the atomic number (Z). The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus.
The pressure of a sample of helium is 2.0 atm in a 200-mL container. If the container is compressed to 10 mL without changing the temperature, what is the new pressure?
Answer:
40 atm
Explanation:
Boyle’s law states that for a fixed amount of gas the pressure is inversely proportional to the volume of the gas at constant temperature.
P1V1 = P2V2
Where P1 is pressure and V1 is volume at the first instance
And P2 is pressure and V2 is volume at the second instance
Substituting the values in the equation
2.0 atm x 200 mL = P2 x 10 mL
P2 = 40 atm
The new pressure is 40 atm
The new pressure of the helium gas is 40 atm.
To calculate the new pressure of the helium, we use the formula below.
Formula:
PV = P'V'.................. Equation 1Where:
P = Original pressureV = Original volumeP' = New pressureV' = New volume.Make P' the subject of the equation
P' = PV/V'................ Equation 2From the question,
Given:
P = 2.0 atmV = 200 mLV' = 10 mLSubstitute these values into equation 2
P' = (2×200)/10P' = 40 atm.Hence, The new pressure of the helium gas is 40 atm.
Learn more about pressure here: https://brainly.com/question/25736513
How do the number and kind of atoms in the reactants compare to the number and kind of atoms in the products
the number and kind of each atom on the reactants side must be equal to number and kind of each atom on products side.
Final answer:
In a chemical reaction, the number and type of atoms remain constant from reactants to products, following the law of conservation of matter. Chemical equations are balanced by adjusting the molecular coefficients to ensure this atomic consistency. Conservation of mass is also observed, with mass being equivalent in the reactants and products.
Explanation:
In accordance with the law of conservation of matter, the number and kind of atoms must remain constant throughout a chemical reaction. This means the number of each type of atom in the reactants is equal to the number of each type of atom in the products.
To ensure this is the case, chemists balance chemical equations by adjusting coefficients in front of the chemical formulas, which represent the amount (in moles) of substances involved in the reaction. Balancing an equation may require a methodical back-and-forth process until the same numbers of atoms for each element are present on both sides of the equation.
Furthermore, while the number of atoms is conserved during the reaction, the number of molecules may change because molecules can break apart, and atoms rearrange to form different molecules. The mass of the reactants and products is also conserved, exemplified by Avogadro's number relating atoms to moles, and moles to molar mass. This conservation of mass is a fundamental concept in chemical reactions.