Show the output waveform of an AND gate with the inputs A, B,
and C indicated in the figure below.

Explanation:

See attached images

The transition from single-entity and multi-enterprise MPIs to an eMPI focuses on incorporating IPEC's core competencies for interprofessional collaborative practice, necessitating changes in data management, privacy, and interoperability at existing facilities.

The question pertains to researching the recommended core elements of a single-entity Master Patient Index (MPI) and a multi-enterprise MPI, and then discussing the emerging core elements of a new electronic MPI (eMPI). The core elements of an MPI often include the patient's name, date of birth, gender, and a unique identifier. In contrast, an eMPI for interprofessional collaborative practice, as described in the Interprofessional Education Collaborative (IPEC)'s 2017 update, emphasizes core competencies for effective interprofessional collaborative practice. These competencies include values/ethics for interprofessional practice, roles/responsibilities, interprofessional communication, and teams and teamwork. Transitioning to an eMPI implies adjustments in existing facilities to incorporate these competencies, focusing on enhanced interprofessional communication and teamwork for patient-centered care.

Moreover, the transition to an eMPI from traditional MPI systems necessitates changes in data management, privacy protocols, and interoperability standards. Facilities must ensure their systems can securely share and access patient information across different healthcare settings, maintaining data integrity and confidentiality.

To analyze the stack with all activation record instances when execution reaches position 1 (inside function `d`) in the provided program, we need to trace through the sequence of function calls and their respective activation records. Let's break down the steps leading up to this point:

1. Initial Setup:

  - `bigsub()` is the main function being executed.

  - `bigsub()` calls `a(true, bigl1)`.

2. Execution Flow:

  - `bigsub()` calls `a(true, bigl1)`.

  - Inside `a(flag, ap1)`:

    - `flag` is `true`.

    - `a()` then calls `b()`.

  - Inside `b()`:

    - `b()` defines local variables `bl1` and `bl2`.

    - `b()` calls `a(false, bl2)`.

  - Back inside `a(flag, ap1)` (after returning from `b()`):

    - Since `flag` is `true`, the `else` block in `a()` is not executed.

    - Therefore, `a()` does not call `c()`.

  - `a(true, bigl1)` completes execution.

3. Execution Flow after `a(true, bigl1)`:

  - `bigsub()` resumes execution after `a(true, bigl1)`.

  - No further significant function calls are made before the stack reaches `c(cp1, cp2)`.

4. Execution Reaches `c(cp1, cp2)`:

  - Inside `c(cp1, cp2)`:

    - `c()` defines the function `d(dp1, dp2)`.

    - `c()` then calls `d(cp1, cp2)`.

5. Execution Inside `d(dp1, dp2)` (Position 1):

  - Execution reaches the start of function `d(dp1, dp2)`.

Now, let's summarize the stack and activation records at this point:

- Stack Layout:

 1. `d(dp1, dp2)` activation record (current execution point)

    - Fields: `dp1`, `dp2`, `dl1` (local to `d()`)

 2. `c(cp1, cp2)` activation record

    - Fields: `cp1`, `cp2`

    - Contains function `d(dp1, dp2)` within its scope

 3. `a(flag, ap1)` activation record

    - Fields: `flag`, `ap1`, `al1`

    - Contains the call to `c(cp1, cp2)` within its scope

 4. `bigsub()` activation record

    - No specific fields needed for this context; serves as the outermost scope

- Additional Notes:

 - Each activation record (or stack frame) corresponds to a particular function call instance and contains its local variables and parameters.

 - The scope of each function determines which inner functions and variables are accessible within that context.

 - `d(dp1, dp2)`'s activation record is the current active frame when execution reaches position 1 inside `d()`, and it contains the local variables (`dp1`, `dp2`, `dl1`) defined within `d()`.

Answer:

The three major problem, which arise there are as follows:

Internet issues, server issues, and server down.

Explanation:

All the issues can be described as follows:

Final answer:

DNS issues could range from typos, an outdated or corrupted DNS cache, problems with the local DNS server, or issues with the host itself, each with varying likelihoods.

Explanation:

When your computer sends a DNS request and receives a response that the host name does not exist despite it being a commonly used host, several problems could be at play. One potential issue is a typo in the host name entered which is highly unlikely if the host is frequently visited and the URL was autofilled. Another issue could be that the DNS cache is outdated or corrupted; this is more common and clearing the cache could resolve this problem. Additionally, the local DNS server might be experiencing problems, such as being overwhelmed with requests or having a configuration issue which could be a moderate likelihood. Finally, the host itself may be experiencing issues, such as having moved to a new server or the domain name having expired, though this is less likely if no prior indication of such a change was given.

Answer:

The given python code mainly add values.

Explanation:

In the given python code, a r_in variable is defined, that reads a file in the next line, a while loop is declared, inside the loop "r_in" variable is used that provides slicing in the code.

Answer:

Check the explanation

Explanation:

When there is a need to initialize a lot of element of same data types,tht time we use arrays.

We have to use array  whenever it involves simple programs and cases,

dx:saving age of 100 childrans of sametype

When all the ele,ents are of different data type,we hould not use arrays,even when we initialize at runtime,we dont need arrays.i.e when size is not fixed

Linked list can be used instead of arrays

ArrayList:It provides methods for creating, searching, manipulating, and sorting arrays, thereby serving as the base class for all arrays in the common language runtime.

Advantages:

Readymade properties availaible ,so lot of writing and remembering the code can be avoided.

Provide the reference for other arrays

Helps in faster execution

To calculate the product sales and respective sales taxes for a retail company, divide the total collected amount by 1.06 to find the net sales, and then calculate individual taxes by applying the county and state tax rates.

The student has asked to write a program for calculating the sales tax for a retail company. When computing the amount of sales tax, you need to know the rate of the sales tax and apply it to the original price. However, in the context of the problem given, the total amount collected at the cash register already includes the sales tax. As such, the calculation to find the product sales (S) before tax should be done using the formula S = T / 1.06, where T is the total income including tax and 6% is the combined state and county sales tax rate.

Once you have the amount of product sales, you can calculate the individual sales taxes by applying the respective rates. For the county sales tax (2%), you would use the formula: County Sales Tax = S x 0.02. Similarly, for the state sales tax (4%), the formula is: State Sales Tax = S x 0.04. The total sales tax is simply the sum of these two.

Answer:

See explaination

Explanation:

import java.util.*;

public class qs {

public static void rearrange(Queue<Integer> q)

{

int n = q.size();

Stack<Integer> st = new Stack<Integer>();

Integer f;

for(int i = 0; i < n ; i++)

{

f = q.poll();

// Even elements are added back to the list

if(f%2==0)

q.add(f);

else

st.push(f);

}

// Odd elements are added to the list in reverse order

while(st.size()>0)

{

q.add(st.pop());

}

// Repeats the above process to correct the order of odd elements

for(int i = 0; i < n ; i++)

{

f = q.poll();

// Even elements are added back to the list

if(f%2==0)

q.add(f);

else

st.push(f);

}

//Order of Odd elements are reversed so as to match the actual order

while(st.size()>0)

{

q.add(st.pop());

}

}

public static void main(String[] args) {

int arr[] = {3, 5, 4, 17, 6, 83, 1, 84, 16, 37};

int n = arr.length;

Queue<Integer> q = new LinkedList<Integer>();

for(int i = 0;i<n;i++)

q.add(arr[i]);

System.out.print("\nOriginal Queue\n");

System.out.println(q.toString());

rearrange(q);

System.out.print("\nReordered Queue\n");

System.out.println(q.toString());

}

}

Answer:

If request granted then T₁ and T₂ are in deadlock.

Explanation:

See attached image

Answer:

All the methods in HashSet are inherited from the Collection interface.

All the methods in LinkedHashSet are inherited from the Collection interface.

All the methods in Set are inherited from the Collection interface.

Explanation:

These listed statements are true;

1. All the methods in HashSet are inherited from the Collection interface. True

2. All the methods in LinkedHashSet are inherited from the Collection interface. This is also true

3. All the methods in Set are inherited from the Collection interface. Also this statement is true.

The methods in HashSet, Set, LinkedHashSet, and TreeSet are all inherited from the Collection interface. Not all concrete classes of Collection have at least two constructors, not all of them. It's generally the interfaces that inherit from Collection.

The following are true regarding the described Java Collection Framework elements:

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The function so that the main() code below can be replaced by the simpler code is given below.

We are given that;

The functions

Now,

The main() code can then be simplified as:

int main() {

  double milesPerHour;

  double minutesTraveled;

  double milesTraveled;

  cin >> milesPerHour;

  cin >> minutesTraveled;

  milesTraveled = MphAndMinutesToMiles(milesPerHour, minutesTraveled);

  cout << "Miles: " << milesTraveled << endl;

  return 0;

}

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Final answer:

The student needs to write a function that converts speed from miles per hour and minutes traveled into miles, which involves programming and applying unit conversions. The MphAndMinutesToMiles() function calculates hours from minutes and then computes distance by multiplying with the provided speed.

Explanation:

The question involves creating a function to facilitate conversion of speed from miles per hour (mph) and travel time in minutes to the distance traveled in miles. This relates primarily to the field of Computers and Technology, particularly in the area of programming and software development, where such a function can be implemented in a variety of programming languages. The student is in college, as the task involves writing a function, which is a concept usually introduced at that level. The task requires understanding of unit conversions and how to apply them within a program.

Write the Function for MphAndMinutesToMiles:

To convert the main code to use the function MphAndMinutesToMiles(), begin by considering the basic formula for distance, which is speed multiplied by time. Since time is given in minutes, it needs to be converted to hours to match the units of miles per hour. This can be done by dividing the minutes by 60. Once the time is in hours, multiplying by the miles per hour speed will give the distance in miles.

The function might look something like:

  double MphAndMinutesToMiles(double mph, double minutes) {
      double hours = minutes / 60.0;
      return mph * hours;
  }

In the main program, you could then get the miles traveled by just calling:

  milesTraveled = MphAndMinutesToMiles(milesPerHour, minutesTraveled);

Answer:

Explanation:

tttttttttttt

Answer:

see explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem

Answer:

Due to Brainly's policy on answering questions, posting links as "credible source." is prohibited, but you can let me know in case you'll still want to know the "credible source."

Explanation:

The three improvements you think came about with the introduction of intrusion prevention technology are:

1.The prevention of intruders from attacking the database

2.The data is protected and is more secured as the intruders are removed from the network.

3.The  data is not changed and misused as hackers cannot access it

The best feature which is can be termed as the most beneficial is that data is not changed neither can it be misused as the company's data is secured and protected from the outside world and the data can be used effectively and efficiently without any major changes.This means the company does not suffer any losses due to hacking of data.

Answer:

see explaination

Explanation:

//Include required header file.

#include <stdio.h>

//Define the function isWordContainChar() having the

//required parameters.

int isWordContainChar(char* req_word, char search_char)

{

//Declare required variable.

int i;

//Start a for loop to traverse the string given in

//the function parameter.

for(i = 0; req_word[i] != '\0' ; i++)

{

//If the current character in the gievn word is

//matched with the character which needs to be

//found in the word, then return 1.

if(req_word[i] == search_char)

{

return 1;

}

}

//Otherwise, return 0.

return 0;

}

//Start the execution of the main() method.

int main(void)

{

//Declare the required variables.

int num_words, index, word_index;

char str_word[20][10];

char searchCharacter;

//Prompt the user to enter the number of words.

scanf("%d", &num_words);

//Prompt the user to enter the required words using a

//for loop and store them into an array.

for(index = 0; index < num_words; index++)

{

scanf("%s", str_word[index]);

}

//Prompt the user to enter a required character which

//needs to be found in a word.

scanf(" %c", &searchCharacter);

//Traverse the words stored in the array using a for

//loop.

for(index = 0; index < num_words; index++)

{

//Call the function isWordContainChar() with

//required arguments in rach iteration and if the

//value returned by this function is not 0, then

//display the current string in the array.

if(isWordContainChar(str_word[index],

searchCharacter) != 0)

{

printf("%s\n", str_word[index]);

}

}

return 0;

}

Answer:

Four

Explanation:

The domain name system is a naming database that maps the name people use to locate a website to the IP address that is then used by a computer to locate a website. It is connected to the Internet or a private network.

An IP address is a 32-bit binary number, but it's normally written out as 4 octets in decimal form as it is easier for humans to read.

Based on the information given, the number of octets for an Internet Protocol (IP) address is four.

It should be noted that a domain name system simply means the naming database that's useful in mapping the name that people use to locate a website to the IP address

Also, An IP address is a 32-bit binary number, but it's normally written out as 4 octets. Therefore, the number of Internet Protocol (IP) address that would have to be memorized is four.

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The statement regarding user intent is true; it indicates the user's motive behind a search query. User intent is a crucial element in fields such as SEO and helps provide accurate search results based on the user's objective when issuing a query.

The statement 'User intent refers to what the user was trying to accomplish by issuing the query' is true. The concept of user intent is critical in various fields such as search engine optimization (SEO), user experience design, and information retrieval. It is concerned with understanding the goals or objectives a user has in mind when they input a query into a search engine or another kind of system. User intent can be informational, navigational, or transactional, but fundamentally, it suggests that there is a purpose behind the words and phrases that users choose. Understanding user intent is essential for providing relevant and useful responses or results.

It is also related to the concept of truth-value, which refers to the validity of a sentence as being either true or false. For instance, the assertion itself is a sentence with a truth value. In the context of literature, the intent is often debated in terms of the author's intent versus the reader's interpretation, but in the technological realm, user intent usually refers to the direct objectives sought by the person posing the query.

Answer:

B

Explanation:

Answer: (a). safe    (b). not safe    (c). safe

Explanation:

quite a long way to go about this but it is straightforward nevertheless.

from the question we are given that the values;

(a).

Process             Max             Hold                    Need(Max-Hold)

P1                      70                  45                       25

P2                     60                  40                       20

P3                     60                   15                       45

P4                     60                   25                       35

#

we have the total units of memory to be 150

Our available becomes = 150 - (45+40+15+25) = 25

allocation for P1:

Process P2  has available resources to run = 70 - 60 -20 = 110 units

Process P1  has available resources to run = 70 units

Process P4 has available resources to run = 125 + 60 - 35 = 150 units

Process P3  has available resources to run = 110 + 60 - 45 = 125 units

from this regard we can conclude that it is Safe to grant the request.

(b). we are to add  a fourth process with max memory requirement of 60 and an initial need of 35 units.

Process             Max             Hold                    Need(Max-Hold)

P1                      70                  45                       25

P2                     60                  40                       20

P3                     60                   15                       45

P4                     60                   35                       25

Given our Total units = 150

We have our available units as 150 - (45 + 40 + 15 + 35) =  15

P2 is 20 but available in 15, Thus Minimum need for  a second process

This means that it is Not Safe to grant the request

(c). A fourth process arrives, with a maximum memory need of 50 and an initial need of 30 units

Process             Max             Hold                    Need(Max-Hold)

P1                      70                  45                       25

P2                     60                  40                       20

P3                     60                   15                       45

P4                     50                   30                       20

Given our Total units = 150

We have our available units as 150 - (45 + 40 + 15 + 30) =  20

We can see here that P4 requires 30 units, and thus it is allocated 30 units

From this we can simply state that'

It is Safe to grant request because 20 units will be left after the allocation for P4, so there is sufficient memory to guarantee the elimination of P2

Cheers i hope this helps!!!!

Following are the response to the given points:

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1. `Animal` is the superclass, and `Cat` is the subclass, signifying inheritance.

2. Private fields in `Animal` can't be directly accessed in `Cat`.

3. Created a `Cat` constructor and updated the test program.

4. Added a `toString` method for `Cat` and updated the test program.

5. Implemented an `isSleeping` method for `Cat` and updated the test program.

(Given in the attachment)

The question probable maybe:

PROGRAM

Consider the Animal and Cat classes in the following Java source code files. SAVE ALL 3.

/*

*Animal.java

*

*A simple class representing an animal.

*/

public class Animal {

private String name;

private int numLegs:

public Animal (String name, int numLegs) {

            this.name name;

             this.numlegs =  numLegs;

}

public String getName() {

             return this.name;

}

public int getNumLegs()   {

              return this.numLegs;

}

public boolean isSleeping(int hour, int minute) (

              if (hour> 24 || hour <0 || minute> 60 || minute < 0) {

                 throw new IllegalArgumentException("invalid time

specified");

}

              return (hour > 22 || hour <= 5)

}

public String toString() {

               return this.name;

}

public static void printAnimalName (Animal an) (

           // Output the name of the animal
               System.out.println( an );

      }

}

/*

*Cat.java

*

*A simple class represting a cat.

*/

public class Cat extends Animal {

        private boolean isShortHaired;

        public Cat() {

                    super ("Mycatt", 3);

         }

        public boolean isShortHaired() {

                     return this.isShorthaired;

          }

         public boolean isExtroverted() {

                    return false;

          }

}

/*

*testDriver.java

*

* A simple test program for the Animal class

*

*/

public class testDriver {

           public static void main (String [] argv) {

            }

}

QUESTIONS / TASKS •
1. Which class is the superclass? Which is the subclass? What does it mean that the Cat class extends the Animal class?

2. The Cat class cannot directly access the fields it inherits from Animal. Why not?

3. The subclass constructor typically calls the superclass constructor to initialize the inherited fields. Write a constructor for the Cat class above. It should take as parameters the cat’s name and a boolean indicating whether it is short-haired, and it should call the superclass constructor to initialize the inherited fields.

Update the test program to create an instance of class Cat.

Cat c = new Cat("Kitty", false);

4. To manipulate the inherited fields, the subclass can use the inherited accessor and mutator methods. Write a toString method for the Cat class above. It should return a string consisting of the cat’s name followed by either " (short-haired)" or " (long-haired)".

Update the test program to test your method.

System.out.println( c );

5. The subclass can override an inherited method, replacing it with a version that is more appropriate. Write an isSleeping method for the Cat class. It should reflect the fact that cats seem to sleep all of the time!

Update the test program to test your method.    

Permission marketing is the practice of providing incentives for customers to learn more about a service, which involves the consent of the consumer before sending information, distinguishing it from advertising, SEO, and branding.

Providing incentives for customers to learn more about your service is known as C) permission marketing. This approach involves getting the consent of the consumer before sending them more information about your products or services. While some may confuse this with branding, advertising, or search engine optimization, each of these has distinct functions within the realm of marketing strategies.

Advertising is a tool used to increase the chance that a firm's product or service is considered by consumers and involves creating awareness and desire amongst consumers for new and existing products. Marketing also involves fostering organic word-of-mouth from consumers themselves as opposed to formal advertising alone. Search engine optimization (SEO), on the other hand, focuses on enhancing the visibility of a website in search engine results.

Answer:

see explaination

Explanation:

Given that we have;

Defects before testing = Defects planted = 5

Defects after testing = 20

Seeded defects found = 2

Real, non seeded defects = 18

Hence, Total number of defects = (defects planted / seeded defects found) * real, non seeded defects = (5/2)*18 = 45

Therefore, Estimated number of real defects still present = estimated total number of defects - number of real, non seeded defects found = 45-18 = 27

Answer:

1 and 3

Explanation:

Answer:

Check the explanation

Explanation:

Program:

from modules import binSearch

from modules import insertionSort

unsort_list=['Paul', 'Aaron', 'Jacob', 'James', 'Bill', 'Sara', 'Cathy', 'Barbara', 'Amy', 'Jill']

print("The list of unsorted items are given below")

for i in unsort_list:

print(i)

insertionSort(unsort_list)

print("The list of sorted items are given below")

for i in unsort_list:

print(i)

while True:

userInput=raw_input("Enter the search string or quit to exit.. ")

if userInput == "quit":

print("quitting...")

break

else:

if binSearch(unsort_list, 0, len(unsort_list), userInput) != False:

print("%s was found." %userInput)

else:

print("%s was not found" %userInput)

USER> cat modules.py

def insertionSort(listarray):

"""This api in this module sorts the list in insertion sort algorithm"""

length=len(listarray)

currentIndex =1

while currentIndex < length:

index=currentIndex

placeFoundFlag=False

while index > 0 and placeFoundFlag == False:

if listarray[index] < listarray[index-1]:

temp=listarray[index-1]

listarray[index-1]=listarray[index]

listarray[index]=temp

index=index-1

else:

placeFoundFlag=True

currentIndex=currentIndex+1

def binSearch (listarray, init, lisLen, searchString):

"""This api in thie module search the given string from a given list"""

#check the starting position for the list array

if lisLen >= init:

#find the center point to start the search

mid = init + int((lisLen - init)/2)

#check if the string matches with the mid point index

if listarray[mid] == searchString:

return listarray[mid]

#now we will search recursively the left half of the array

elif listarray[mid] > searchString :

return binSearch(listarray, init, mid-1, searchString)

#now we will search recursively the right half of the array

else:

return binSearch(listarray, mid+1, lisLen, searchString)

else:

#string now found, return False

return False

Output:

The list of unsorted items are given below

Paul

Aaron

Jacob

James

Bill

Sara

Cathy

Barbara

Amy

Jill

The list of sorted items are given below

Aaron

Amy

Barbara

Bill

Cathy

Jacob

James

Jill

Paul

Sara

Enter the search string or quit to exit.. Amy

Amy was found.

Enter the search string or quit to exit.. AAron

AAron was not found

Enter the search string or quit to exit.. James

James was found.

Enter the search string or quit to exit.. Irvinf

Irvinf was not found

Enter the search string or quit to exit.. quit

quitting...

Kindly check the code output below.

Answer:

See explaination for program code

Explanation:

Code below:

def insertion_sort(names_list):

"""

function to sort name list using insertion sort

"""

for i in range(1, len(names_list)):

val = names_list[i]

temp = i

while temp > 0 and names_list[temp-1] > val:

names_list[temp] = names_list[temp-1]

temp = temp-1

names_list[temp] = val

def recursive_binary_search(names_list, left, right, search):

"""

function to search name in given list

"""

if right >= left:

# getting mid value

mid_index = int(left + (right - left)/2)

# comparing case insensitive name

if names_list[mid_index].lower() == search.lower():

# returning true if name found

return True

# shifting right left value as per comparing

elif names_list[mid_index].lower() > search.lower():

# calling function resursively

return recursive_binary_search(names_list, left, mid_index-1, search)

else:

return recursive_binary_search(names_list, mid_index+1, right, search)

else:

return False

def main():

# TODO: please feel free to add more name in below list

names = [

"Rakesh",

"Rahul",

"Amit",

"Gunjan",

"Alisha",

"Roy",

"Amrita"

]

print("sorting names....")

insertion_sort(names)

print("names sorted..")

while 1:

name = input("Enter name to search or quit to exit: ")

if name.lower() == 'quit':

break

# searhing name and based on result printing output

result = recursive_binary_search(names, 0, len(names)-1, name)

if result:

print("Name %s found in list" % name)

else:

print("Name %s not found in list" % name)

Answer:

Check the explanation

Explanation:

// include the necessary packages

import java.io.*;

import java.util.*;

// Declare a class

public class DataReader

{

// Start the main method.

public static void main(String[] args)

{

// create the object of scanner class.

Scanner scan = new Scanner(System.in);

// Declare variables.

boolean done = false;

boolean done1 = false;

float sum = 0;

double v;

int count = 0;

// start the while loop

while (!done1)

{

// start the do while loop

do

{

// prompt the user to enter the value.

System.out.println("Value:");

// start the try block

try

{

// input number

v = scan.nextDouble();

// calculate the sum

sum = (float) (sum + v);

}

// start the catch block

catch (Exception nfe)

{

// input a character variable(\n)

String ch = scan.nextLine();

// display the statement.

System.out.println(

"Input Error. Try again.");

// count the value.

count++;

break;

}

}

// end do while loop

while (!done);

// Check whether the value of count

// greater than 2 or not.

if (count >= 2)

{

// display the statement on console.

System.out.println("Sum: " + sum);

done1 = true;

}

}

}

}

Sample Output:

Value:

12

Value:

12

Value:

ten

Input Error. Try again.

Value:

5

Value:

nine

Input Error. Try again.

Sum: 29.0

Answer:

See Explaination for program code

Explanation:

Code below

import java.io.*;

import java.util.*;

// Declare a class

public class DataReader

{

// Start the main method.

public static void main(String[] args)

{

// create the object of scanner class.

Scanner scan = new Scanner(System.in);

// Declare variables.

boolean done = false;

boolean done1 = false;

float sum = 0;

double v;

int count = 0;

// start the while loop

while (!done1)

{

// start the do while loop

do

{

// prompt the user to enter the value.

System.out.println("Value:");

// start the try block

try

{

// input number

v = scan.nextDouble();

// calculate the sum

sum = (float) (sum + v);

}

// start the catch block

catch (Exception nfe)

{

// input a character variable(\n)

String ch = scan.nextLine();

// display the statement.

System.out.println(

"Input Error. Try again.");

// count the value.

count++;

break;

}

}

// end do while loop

while (!done);

// Check whether the value of count

// greater than 2 or not.

if (count >= 2)

{

// display the statement on console.

System.out.println("Sum: " + sum);

done1 = true;

}

}

}

}

Answer:

Check Explanation.

Explanation:

A programming language is used by engineers, technologists, scientists or someone that learnt about programming languages and they use these programming languages to give instructions to a system. There are many types for instance, c++, python, Java and many more.

So, the solution to the question above is given below;

#define the lists

boyNames=[]

girlNames=[]

#open the text file BoyNames.txt

with open('BoyNames.txt','r') as rd_b_fl:

boyNames=rd_b_fl.readlines()

boyNames=[name.strip().lower() for name in boyNames]

#open the text file GirlNames.txt

with open('GirlNames.txt','r') as rd_b_fl:

girlNames=rd_b_fl.readlines()

girlNames=[name.strip().lower() for name in girlNames]

#print the message to prompt for name

print('Enter a name to see if it is a popular girls or boys name.')

while True:

#prompt and read the name

name=input('\nEnter a name to check, or \"stop\" to stop: ').lower()

# if the input is stop, then exit from the program

if name=='stop':

break

# If the girl name exits in the file,then return 1

g_count=girlNames.count(name)

# if return value greater than 0, then print message

if g_count>0:

print(name.title()+" is a popular girls name and is ranked "

+str(girlNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular girls name")

## If the boy name exits in the file,then return 1

b_count=boyNames.count(name)

if b_count>0:

print(name.title()+" is a popular boys name and is ranked "

+str(boyNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular boys name")

Answer:

See explaination

Explanation:

Monopoly is a competition where there is a single seller and a single product in the market and hence no competition.

Monopolistic Competition is a competition where there are a large number of small firms competing with each other.

Oligopoly is a market that has a limited number of buyers and Sellers.

Perfect Competition is a market with large number of buyers and Sellers.

The pairing can be seen below:

1. Monitors is under monopolistic competition as there are a large number of firms competing.

2. USB drives this comes under perfect competition as there a large number of buyersand Sellers.

3. Central processing units (CPUs) this is under oligopoly as there a limited number of buyers and Sellers.

4. Microsoft's Windows this fall under monopoly market structure. They have no competition at all.

Answer:

See explaination

Explanation:

#include <iostream>

#include <iomanip>

using namespace std;

int main() {

int dem,i,j;

cout<<"Enter denominator value"<<endl;

cin>>dem;

int** arr=new int*[dem];

for(i=0;i<dem;i++)

{

if(i!=0)

cout<<setw(5)<<i<<"/"<<dem;

cout<<"\t";

}

cout<<endl;

for(i=1;i<dem;i++)

{ cout<<setw(5)<<i<<"/"<<dem<<"\t";

arr[i] = new int[dem];

for(j=1;j<dem;j++)

{

cout<<setw(5)<<i*j<<"/"<<dem<<"\t";

}

cout<<endl;

}

return 0;

}

Answer:

Explanation:

The solution code is written in Java.

Firstly, create a method buildArray that takes two parameters, an array and an array size (Line 10).

In the method, use the input size to build an array with size-length (Line 11). Next, create a Random object and use a for loop to repeatedly generate a random integer using the Random object nextInt method. The expression rand.nextInt(90) + 10 will return an integer between 10 - 99. Each generated random integer is assigned as the value for one array item (Line 16).

At last, print out the array to terminal (Line 19).

In the main program, we can test the method by passing an empty array and a value 12 as array size (Line 7). We will get a sample array as follow:

[81, 36, 15, 20, 32, 84, 10, 13, 98, 12, 45, 45]

Answer:

The loop in cpp language is as follows.

for(int n=10; n<=90; n++)

{

cout<<n<<" ";

count = count+1;

if(count==10)

{

cout<<""<<endl;

count=0;

}

}

Explanation:

1. The expected output is obtained using for loop.

2. The loop variable, n is initialized to the starting value of 10.

3. The variable n is incremented by 1 at a time, until n reaches the final value of 90.

4. Every value of n beginning from 10 is displayed folllowed by a space.

5. When 10 numbers are printed, a new line is inserted so that every line shows only 10 numbers.

6. This is achieved by using an integer variable, count.

7. The variable count is initialized to 0.

8. After every number is displayed, count is incremented by 1.

9. When the value of count reaches 10, a new line is inserted and the variable count is initialized to 0 again. This is done inside if statement.

10. The program using the above loop is shown below along with the output.

PROGRAM

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

   int count=0;

   for(int n=10; n<=90; n++)

   {

       cout<<n<<" ";

       count = count+1;

       if(count==10)

       {

           cout<<""<<endl;

           count=0;

       }

   }

   return 0;

}  

OUTPUT

10 11 12 13 14 15 16 17 18 19  

20 21 22 23 24 25 26 27 28 29  

30 31 32 33 34 35 36 37 38 39  

40 41 42 43 44 45 46 47 48 49  

50 51 52 53 54 55 56 57 58 59  

60 61 62 63 64 65 66 67 68 69  

70 71 72 73 74 75 76 77 78 79  

80 81 82 83 84 85 86 87 88 89  

90

1. In the above program, the variable count is initialized inside main() but outside for loop.

2. The program ends with a return statement since main() has return type of integer.

3. In cpp language, use of class is not mandatory.