Ch = sh = why and find the stuff
What are the concentrations of hydroxide and hydronium ions in a solution with a pH of 4.6?
1.3 × 10–4 M H3O+ and 7.7 × 10–11 M OH–
2.5 × 10–5 M H3O+ and 4.0 × 10–10 M OH–
7.9 × 10–6 M H3O+ and 1.3 × 10–9 M OH–
8.7 × 10–7 M H3O+ and 1.1 × 10–8 M OH–
Answer:
2.5 × 10–5 M H3O+ and 4.0 × 10–10 M OH–
Explanation:
pH = - log[H3O+]
Therefore;
pH = - log[H3O+] = 4.6
Hence;
[H3O+] = 10^-4.6
= 2.51 ×10^-5 M
= 2.5 ×10^-5 M
Additionally;
pH + pOH = 14
Thus; pOH = 14 -pH
= 14 -4.6
= 9.4
but; pOH = - log [OH-]
Therefore;
[OH-] = 10^-9.4
= 3.98 × 10^-10 M
= 4 × 10^-10 M
Answer:
2.5 × 10–5 M H3O+ and 4.0 × 10–10 M OH–
Imagine you are on a roller coaster. Imagine that you are riding a skateboard or running across a ball field. What are some clues that you are moving?
✯Hello✯
↪ You can see the setting changing around you
↪ You can feel a higher pressure/wind on your face
↪ There is adrenaline going through you
↪ (if this isnt the context you are looking for just comment)
❤Gianna❤
A 10.0 ml solution of 0.300 m nh3 is titrated with a 0.100 m hcl solution. calculate the ph after the addition of 10.0 ml hcl.
To calculate the pH after the addition of 10.0 mL of HCl to a 10.0 mL solution of NH3, we need to understand the reaction that occurs between the two. NH3 is a weak base, while HCl is a strong acid. The reaction between NH3 and HCl results in the formation of NH4+ ions and Cl- ions, which will affect the pH of the solution.
Explanation:To calculate the pH after the addition of 10.0 mL of HCl to a 10.0 mL solution of NH3, we need to understand the reaction that occurs between the two. NH3 is a weak base, while HCl is a strong acid. The reaction between NH3 and HCl is:
NH3 + HCl -> NH4+ + Cl-
This reaction results in the formation of NH4+ ions and Cl- ions. Since HCl is a strong acid, it will completely dissociate in water, while NH3 is a weak base, it will only partially ionize. Therefore, after the addition of HCl, the solution will contain NH4+ ions and Cl- ions, which will affect the pH of the solution.
To calculate the pH, we need to determine the concentration of NH4+ ions in the solution. Since the initial solution of NH3 is 0.300 M, the concentration of NH4+ ions will be equal to the concentration of NH3 that has been converted to NH4+. To find this, we can use the stoichiometry of the reaction:
1 mol NH3 = 1 mol NH4+ ions
Therefore, the concentration of NH4+
...
Final answer:
To calculate the pH after the addition of 10.0 mL of 0.100 M HCl to a 10.0 mL solution of 0.300 M NH3, we need to consider the reaction between NH3 and HCl. NH3 is a weak base and HCl is a strong acid. The balanced chemical equation for the reaction is NH3 + HCl → NH4Cl.
Explanation:
To calculate the pH after the addition of 10.0 mL of 0.100 M HCl to a 10.0 mL solution of 0.300 M NH3, we need to consider the reaction between NH3 and HCl. NH3 is a weak base and HCl is a strong acid.
The balanced chemical equation for the reaction is NH3 + HCl → NH4Cl. Here, NH3 reacts with HCl to form NH4Cl.
Since NH3 is a weak base, it will not completely dissociate in water. However, HCl is a strong acid and will dissociate completely. Therefore, the concentration of HCl will be equal to 0.100 M after the addition.
Using the equation, we can determine the number of moles of HCl added and the resulting concentration of HCl in the final solution. Then, the pH can be calculated using the formula pH = -log[H+], where [H+] is the concentration of H+ ions in the solution.
Which of the following is the best lewis symbol for oxygen?
The best Lewis symbol for oxygen in O2 is :O=O:, showing a double bond and octets for each oxygen atom. This structure, however, does not explain the paramagnetic properties of oxygen, which are due to unpaired electrons not depicted in the Lewis symbol.
Explanation:The best Lewis symbol for oxygen, when considering the molecule O₂, is :O=O:. This Lewis structure indicates that there is an O=O double bond and each oxygen atom has eight electrons around it, satisfying the octet rule. However, this structure does not account for the paramagnetic properties of oxygen, which experimental studies have shown is due to the presence of two unpaired electrons in each oxygen molecule.
Because the Lewis structure of O₂ is expected to show all electrons as paired, there is a discrepancy with the observed magnetic behavior. Paramagnetism arises in molecules that have unpaired electrons, which is why liquid oxygen is attracted to magnetic fields despite the Lewis structure suggesting otherwise.
In which solution is AgCl most soluble?A. in a solution that is 0.20 M in CaCl2B. in a solution that is 0.20 M in AgNO3C. in a solution that is 0.20 M in KNO3
Answer: option C. in a solution that is 0.20 M in KNO₃.
Explanation:
This question deals with the common ion effect.
Any presence in a solution of a common ion with the solute will decrease its solubility and here you can find why.
AgCl (silver chloride) is highly insoluble in water.
Its solubility equation is given by this equilibrium equation:
AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)
The constant for this equilibrim is called constant of solubility product and is indicated as Ksp:
Ksp = [Ag⁺][Cl⁻]Then, any increase of the product ions (on the right side of the equilibrium equation), will result, according to Le Chatelier's principle in a shift of the equilibrium toward the left side, this is in an increase of the AgCl(s), meaning that less AgCl will be soluble.
Let's see in which of the given solutions is AgCl most soluble
A. Solution 0.20 M in CaCl₂
CaCl₂ is a ionic compound which also ionizes in solution, given Ca²⁺ and Cl⁻ ions. So, you can see that it will increase the concentration of Cl⁻, which means that the equlibrium AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq), will be shifting to the left, decreasing the solubility of silver chloride.
B. Solution 0.20 M in AgNO₃
AgNO₃ is also a ionic salt which dissociates in water giving Ag⁺ and NO₃ ions. So, it will increase Ag⁺ ions, also shifting the equilibrium AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq) to the left, decreasing the solubility of silver chloride.
C. Solution 0.20 M in KNO₃
Since KNO₃ has no common ions with AgCl, it will not affect the equilibrium equation in the same manner and you can expect that AgCl is most soluble in KNO₃.
AgCl is most soluble in the 0.20 M KNO3 solution because it does not provide common ions to AgCl, thus avoiding the reduction of AgCl's solubility due to the common ion effect.
Explanation:The solubility of AgCl (silver chloride) in various solutions can be affected by the common ion effect. However, due to the formation of a two-coordinate complex with chloride ions, AgCl₂⁻, AgCl's solubility in solutions can differ from what the common ion effect alone would predict. The given information states that AgCl is approximately 10 times more soluble in 1.0 M KCl than in pure water, despite the common ion effect suggesting it should be much less soluble.
Given the choices of:
A 0.20 M CaCl₂ solutionA 0.20 M AgNO₃ solutionA 0.20 M KNO₃ solutionAgCl would be most soluble in the solution that does not contain a common ion with AgCl. Because CaCl₂ and KNO₃ are both salts with different ions than Ag+ and Cl−, they would not directly provide a common ion that would decrease the solubility of AgCl through the common ion effect. Whereas the AgNO₃ solution contains Ag+ ions which would vastly decrease the solubility of AgCl due to the common ion effect. Therefore, the AgCl is most soluble in the 0.20 M KNO₃ solution (Choice C), because it does not supply any common ions that could reduce its solubility.
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Liquids that dissolve freely in one another in any proportion are
dgdfasfdsafdsagdfggxcvxcvxczgdfsgsdfhgfghfjghfgfhjgfd
please need help on this please
Answer:1.b
2.c
3.a
4.d
5.c
6.b
7.d
8.d
9.c
10.a
Explanation:
What type of molecule is formed when a halogen combines with hydrogen
When a halogen combines with hydrogen, a covalent molecule is formed.
When a halogen, such as chlorine (Cl), fluorine (F), bromine (Br), or iodine (I), combines with hydrogen (H), they typically form covalent molecules. In covalent bonding, atoms share electrons to achieve a stable electron configuration. Halogens have one electron missing in their outermost electron shell, while hydrogen needs one more electron to complete its shell. To satisfy these electron needs, they share electrons through a covalent bond.
In hydrogen chloride (HCl), hydrogen shares its electron with chlorine, forming a covalent bond. This sharing allows both atoms to achieve a stable electron configuration. Covalent molecules, in contrast to ionic compounds, involve the sharing of electrons rather than the transfer of electrons, resulting in the formation of discrete molecules with relatively low melting and boiling points.
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Oxidation/reduction (redox) reactions like this: 2H2(g) + O2(g) ⇒ 2H2O(l) will occur spontaneously. To make the reaction proceed in the reverse direction, you must put energy (electricity) into reaction. This is called
The process is called electrolysis.
The equilibrium constant, k, for a redox reaction at 25° c is 7.3 × 107. what is the value of e° if the overall reaction transfers 2 electrons? the equilibrium constant, k, for a redox reaction at 25° c is 7.3 × 107. what is the value of e° if the overall reaction transfers 2 electrons? 0.23 v 0.47 v 0.16 v 0.86 v
Answer:
0.23 V.
Explanation:
∵ ΔG° = -RT lnK.
∴ ΔG° = -RTlnK = -(8.314 J/mol)(298 K) ln(7.3 × 10⁷) = - 44.86 x 10³ J/mol.
∵ ΔG° = - nFE°
∴ E° = - ΔG°/nF = - (- 44.86 x 10³ J/mol)/(2 x 96500 s.A/mol) = 0.2324 V ≅ 0.23 V.
To calculate the value for the standard cell potential (E°) in a redox reaction given the equilibrium constant (K) and the number of electrons transferred, you can use the Nernst equation in a simplified form. The Nernst equation shows the relationship between the cell potential (E), the standard cell potential (E°), the number of electrons transferred (n), and the reaction quotient (Q). Assuming Q=K at equilibrium, solving the equation will provide you the value for E°.
Explanation:The equilibrium constant, K, for a redox reaction is logarithmically related to the reaction's cell potential. The Nernst equation, an essential concept in electrochemistry, can help calculate the standard cell potential, E°, with the provided K and number of electrons transferred.
The Nernst equation in a simplified form, including values for fundamental constants (R and F) and standard temperature (298 K), along with a factor converting from natural to base-10 logarithms, is:
E = E° - (0.0592/n)logQ Where E° is the standard cell potential, n is the number of electrons transferred, and Q is the reaction quotient, essentially a measure of the value of product and reactants concentrations at any point.
From the equilibrium constant K, we can calculate Q. For a redox reaction at equilibrium, Q is equal to K. Given that the overall redox reaction transfers 2 electrons (n=2), the equilibrium constant, K, is 7.3 x 10^7, and assuming that Q=K, the equation simplifies into: E = E° - (0.0592/2)log(7.3 x 10^7). Solving this equation will give you the value for E°.
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Consider the same cycle with non-isentropic turbine and pump. (e) Plot the variation of net power output, rate of heat transfer through the boiler, and cycle thermal efficiency for equal values of isentropic efficiency for turbine and pump ranging from 70% to 100%. Suppose the cooling water circulating through the condenser enters at 22C (State 5) and exits at 35C (State 6) for the ideal cycle. The cooling water leaving the condenser enters a wet cooling tower and is cooled back to 22C by using ambient air entering the cooling tower at total pressure of 1 atm, dry bulb temperature of 20C, and relative humidity of 60% (State 7). The air exiting at the top of the cooling tower is saturated at 30C (State 8). There is make-up water supply at 22C (State 9). (f) Calculate the mass flow rate (kg/s) of cooling water. (g) Find the mass flow rate (kg/s) of air entering the cooling tower. (h) Determine the mass flow rate (kg/s) required of the make-up water in the cooling tower.
The 60% is the total of the humid y
In an electromagnet, you can increase the strength of the magnetic field by Question 6 options: decreasing the thickness of the wires increasing the number of coils in the wires
The electromagnetic strength can be increased by increasing the number of coils in the wires but not by decreasing the thickness of the wires - there is no mathematical relationship between wire thickness and field strength.
Hope this helps!
If I have 12 moles of gas with a temperature of 16°C, what is the volume of the gas if the pressure is 14atm
Answer:
20.3 L
Explanation:
Assuming that the gas behaves similar to an ideal gas we can use the ideal gas law equation
PV = nRT
Where
P - pressure - 14 atm
V - volume
n - number of moles - 12 mol
R - universal gas constant - 0.0821 L.atm /mol.K
T - absolute temperature - 16 degrees + 273 = 289 K
Substituting the values in the equation
14 atm x V = 12 mol x 0.0821 L.atm/mol.K x 289 K
V = 20.3 L
When a mercury-202 nucleus is bombarded with a neutron, a proton is ejected. What element is formed?
That will make a gold-202 nucleus.
ExplanationRefer to a periodic table. The atomic number of mercury Hg is 80.
Step One: Bombard the [tex]\displaystyle ^{202}_{\phantom{2}80}\text{Hg}[/tex] with a neutron [tex]^{1}_{0}n[/tex]. The neutron will add 1 to the mass number 202 of [tex]^{202}_{\phantom{2}80}\text{Hg}[/tex]. However, the atomic number will stay the same.
New mass number: 202 + 1 = 203.Atomic number is still 80.[tex]^{202}_{\phantom{2}80}\text{Hg} + ^{1}_{0}n \to ^{203}_{\phantom{2}80}\text{Hg}[/tex].
Double check the equation:
Sum of mass number on the left-hand side = 202 + 1 = 203 = Sum of mass number on the right-hand side.Sum of atomic number on the left-hand side = 80 = Sum of atomic number on the right-hand side.Step Two: The [tex]^{203}_{\phantom{2}80}\text{Hg}[/tex] nucleus loses a proton [tex]^{1}_{1}p[/tex]. Both the mass number 203 and the atomic number will decrease by 1.
New mass number: 203 - 1 = 202.New atomic number: 80 - 1 = 79.Refer to a periodic table. What's the element with atomic number 79? Gold Au.
[tex]^{203}_{\phantom{2}80}\text{Hg} \to ^{202}_{\phantom{2}79}\text{Au} + ^{1}_{1}p[/tex].
Double check the equation:
Sum of mass number on the left-hand side = 203 = 202 + 1 = Sum of mass number on the right-hand side.Sum of atomic number on the left-hand side = 80 = 79 + 1 = Sum of atomic number on the right-hand side.A gold-202 nucleus is formed.
Why would two poles of different magnets attract each other?
When two magnets are brought near each other, like poles repel; opposite poles attract. When a magnet is brought near a piece of iron, the iron also gets attracted to the magnet, and it acquires the same ability to attract other pieces of iron.
Answer:
The poles closest to each other are opposite poles.
Explanation:
Which factors would decrease the rate of a reaction? I. Lowering the temperature II. Increasing the concentration of reactants III. Adding a catalyst
Answer:
(for those of us with 4 answer choices)
Explanation:
a p e x
A factor that will decrease the rate of chemical reaction is lowering the temperature.
The rate of a chemical reaction is the speed at which a chemical reaction takes place. The rate of chemical reaction is directly proportional to the concentration of the reactant and the temperature of the reactant.
That is, as the temperature of the reactant increases, the rate of the reaction increases, while a decrease in temperature will decrease the rate of reaction.
Thus, a factor that will decrease the rate of chemical reaction is lowering the temperature.
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Which of the following functions occurs in the part of the digestive system indicated by the arrow?Secretion of buffers and digestive enzymesAcid breakdown of swallowed foodsSecretion of bile and buffersAbsorption of water and ions
A system at equilibrium contains i2(g) at a pressure of 0.21 atm and i(g) at a pressure of 0.23 atm . the system is then compressed to half its volume. find the pressure of i when the system returns to equilibrium.
The pressure would be 6000 Newton’s
The pressure of I when the system returns to equilibrium is 0.589 atm.
What is equilibrium?Equilibrium is defined as a state of a reversible chemical process in which there is no net change in the quantity of reactants and products.
To calculate the pressure we considered the equation
I2 -> 2Ig
Kp = I² / I2
= (0.23)² / 0.21 = 0.25
I2 at initial = 2 x 0.21 = 0.42
I2 at equilibrium = 0.42 - x
Ig at initial = 2 x 0.23 = 0.46
Ig at equilibrium = 0.46 - 2x
Solving x using equilibrium constant
0.25 = (I)² / I2 = (0.46 + 2x)² / 0.42-x
0.25 (0.42 - x) = (0.46 + 2x)²
0.105 - 0.25x = 0.1764 + 4x²
-0.25 - 4x² = 0.1764 - 0.105
4.25 x² = 0.0714
x² = 0.714 / 4.25
x² = 0.0168
x = 0.129 atm
PI2 = 0.42 + 2x0.129
PI2 = 0.678 atm
PI = 0.46 + 0.129
PI = 0.589 atm
Thus, the pressure of I when the system returns to equilibrium is 0.589 atm.
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which factor is most likely to determine which plants can survive in an area??(APEX)
A. types of animals
B. atmosphere pressure
C. amount of rainfall
D. human presence
The answer is c because some plants can die from too much water
Answer: C. amount of rainfall
Explanation:
The amount of rainfall is an abiotic factor (non-living) which is necessary for the growth of plants. The water from the rainfall is necessary for the large scale natural irrigation of an agricultural land, forest, meadow or grassland. The water enters into the soil and through the roots the water is absorbed by the plants.
If a region receives very low annual rainfall then the region may experience desertification. The soil will become compact and dry which cannot support the growth of plants.
If a region receives adequate rainfall then the soil will hold water it will remain fertile to support the diversity of plants.
In a concentrated solution there is _____.
A. no solvent
B. a small amount of solute
C. a large amount of solute
D. no solute
Answer:
C. a large amount of solute
Explanation:
To make a solution we need both solute and solvent. Therefore both options A and D are incorrect. In a dilute solution there is a lower concentration of solute dissolved in the solvent. Therefore option B is incorrect. In a concentrated solution there is a higher concentration of solute dissolved in the solvent. Therefore option C is correct.
In the concentrated solution there is "large amount of the solute". The correct option is C.
The concentrated solution is the solution in which the solution contains a large amount of the solute as compared to the amount that could be dissolve. When the amount of the solute added to the solvent is in the large amount that could be dissolve then the solution is referred as the concentrated solution.
The concentration of the solution is the measurement of the amount of the solute which is dissolved in the amount of solution or the solvent. The concentrated solution becomes more solute when we added the more solute. Therefore, the option C is correct.
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Consider the following balanced equation: SiO2(s)+3C(s)→SiC(s)+2CO(g) Complete the following table showing the appropriate number of moles of reactants and products. If the number of moles of a reactant is provided, fill in the required amount of the other reactant, as well as the moles of each product formed. If the number of moles of a product is provided, fill in the required amount of each reactant to make that amount of product, as well as the amount of the other product that is made.
Mol SiO2 Mol C Mol SiC Mol CO
Row 1: 3 _____ _____ _____
Row 2: _____ 6 _____ _____
Row 3: _____ _____ _____ 16
Row 4: 2.8 _____ _____ _____
Row 5: _____ 2.45 _____ _____
A. complete the first row. Express your answers using one significant figure separated by commas. Mol C, Mol SiC, Mol CO =
B. Complete the second row. Express your answers using one significant figure separated by commas. Mol SiO2, Mol SiC, Mol CO =
C. Complete the third row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =
D. Complete the fourth row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =
E. Complite the fifth row. Express your answers using three significant figures separated by commas. Mol SiO2, Mol SiC, Mol CO =
Answer:
mol(SiO₂) mol(C) mol(SiC) mol(CO)
Row 1: 0.8 x 10 0.9 x 10 0.3 x 10 0.6 x 10
Row 2: 0.2 x 10 0.6 x 10 0.2 x 10 0.4 x 10
Row 3: 8.0 2.4 x 10 8.0 1.6 x 10
Row 4: 2.8 8.4 2.8 5.6
Row 5: 0.816 2.45 0.816 1.63
Explanation:
From the balanced equation:SiO₂(s) + 3C(s) → SiC(s) + 2CO(g),
It is clear that 1.0 mole of SiO₂ reacts with 3.0 moles of C to produce 1.0 mole of SiC and 2.0 moles of CO.
We can complete the table of no. of moles of each component:A. complete the first row. Express your answers using one significant figure separated by commas. Mol C, Mol SiC, Mol CO =
3.0 moles of SiO₂:
We use the triple amount of SiO₂, so we multiply the others by 3.0.
So, it will be 3.0 moles of SiO₂ with 9.0 moles of C that produce 3.0 moles of SiC and 6.0 moles of CO.
B. Complete the second row. Express your answers using one significant figure separated by commas. Mol SiO2, Mol SiC, Mol CO =
6.0 mole of C:
We use the double amount of C, so we multiply the others by 2.0.
So, it will be 2.0 moles of SiO₂ with 6.0 moles of C that produce 2.0 moles of SiC and 4.0 moles of CO.
C. Complete the third row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =
16.0 moles of CO:
We use the amount of CO higher by 8 times than that in the balanced equation, so we multiply the others by 8.0.
So, it will be 8.0 moles of SiO₂ with 24.0 moles of C that produce 8.0 moles of SiC and 16.0 moles of CO.
D. Complete the fourth row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =
2.8 moles of SiO₂:
We use the amount of SiO₂ higher by 2.8 times than that in the balanced equation, so we multiply the others by 2.8.
So, it will be 2.8 moles of SiO₂ with 8.4 moles of C that produce 2.8 moles of SiC and 5.6 moles of CO.
E. Complite the fifth row. Express your answers using three significant figures separated by commas. Mol SiO2, Mol SiC, Mol CO =
2.45 moles of C:
We use the amount of C lower by 0.8167 times than that in the balanced equation, so we multiply the others by 0.8167.
So, it will be 0.8167 moles of SiO₂ with 2.45 moles of C that produce 0.8167 moles of SiC and 1.633 moles of CO.
The answers are expressed in the required significant figures in the answer part (table above).
Answer:
A) [tex]3SiO_2(s)+9C(s)\rightarrow 3SiC(s)+6CO(g)[/tex]
B) [tex]2SiO_2(s)+6C(s)\rightarrow 2SiC(s)+4CO(g)[/tex]
C)[tex]8.0SiO_2(s)+24C(s)\rightarrow 8.0SiC(s)+16CO(g)[/tex]
D)[tex]2.8SiO_2(s)+8.4C(s)\rightarrow 2.8SiC(s)+5.6CO(g)[/tex]
E)[tex]0.816SiO_2(s)+2.45C(s)\rightarrow 0.816SiC(s)+1.63CO(g)[/tex]
Explanation:
[tex]SiO_2(s)+3C(s)\rightarrow SiC(s)+2CO(g)[/tex]
A) When 3 moles of silicon dioxide are present.
According to reaction 1 mole of silicon dioxide react with 3 moles of carbon to give 1 mole of silicon carbide and 2 moles of carbon monoxide.
Then 3 moles of silicon dioxide will react with :
[tex]\frac{3}{1}\times 3mol=9 mol[/tex] of carbon
Then 3 moles of silicon dioxide will give :
[tex]\frac{1}{1}\times 3 mol= 3 mol[/tex] of silicon carbide
Then 3 moles of silicon dioxide will give :
[tex]\frac{2}{1}\times 3 mol= 6 mol[/tex] of carbon monoxide
[tex]3SiO_2(s)+9C(s)\rightarrow 3SiC(s)+6CO(g)[/tex]
B) When 6 moles of carbon are present.
According to reaction 3 moles of carbon reacts with 1 mole of silicon dioxide react with to give 1 mole of silicon carbide and 2 moles of carbon monoxide.
Then 6 moles of carbon will react with :
[tex]\frac{1}{3}\times 6 mol=2 mol[/tex] of silicon dioxde
Then 3 moles of carbon will give :
[tex]\frac{1}{3}\times 6 mol= 2 mol[/tex] of silicon carbide
Then 6 moles of carbon will give :
[tex]\frac{2}{3}\times 6 mol= 4 mol[/tex] of carbon monoxide
[tex]2SiO_2(s)+6C(s)\rightarrow 2SiC(s)+4CO(g)[/tex]
C)When 6 moles of carbon are present.
According to reaction ,1 mole of silicon carbide and 2 moles of carbon monoxide is produced when, 3 moles of carbon reacts with 1 mole of silicon dioxide reacts.
Then 16 moles of carbon monoxide will be produced from :
[tex]\frac{1}{2}\times 16 mol=8 mol[/tex] of silicon dioxide
Then 16 moles of carbon monoxide will give :
[tex]\frac{3}{2}\times 16 mol= 24 mol[/tex] of carbon
Along with 16 moles of carbon monoxide will give :
[tex]\frac{1}{2}\times 16 mol= 8 mol[/tex] of silicon carbide
[tex]8SiO_2(s)+24C(s)\rightarrow 8SiC(s)+16CO(g)[/tex]
D) When 2.8 moles of silicon dioxide are present.
According to reaction 1 mole of silicon dioxide react with 3 moles of carbon to give 1 mole of silicon carbide and 2 moles of carbon monoxide.
Then 2.8 moles of silicon dioxide will react with :
[tex]\frac{3}{1}\times 2.8 mol=8.4 mol[/tex] of carbon
Then 2.8 moles of silicon dioxide will give :
[tex]\frac{1}{1}\times 2.8 mol= 2.8 mol[/tex] of silicon carbide
Then 2.8 moles of silicon dioxide will give :
[tex]\frac{2}{1}\times 2.8 mol= 5.6 mol[/tex] of carbon monoxide
[tex]2.8SiO_2(s)+8.4C(s)\rightarrow 2.8SiC(s)+5.6CO(g)[/tex]
E) When 2.45 moles of carbon are present.
According to reaction 3 moles of carbon reacts with 1 mole of silicon dioxide react with to give 1 mole of silicon carbide and 2 moles of carbon monoxide.
Then 2.45 moles of carbon will react with :
[tex]\frac{1}{3}\times 2.45 mol=0.8166 mol[/tex] of silicon dioxde
Then 3 moles of carbon will give :
[tex]\frac{1}{3}\times 2.45 mol= 0.8166 mol[/tex] of silicon carbide
Then 6 moles of carbon will give :
[tex]\frac{2}{3}\times 2.45 mol= 1.6333 mol[/tex] of carbon monoxide
[tex]0.816SiO_2(s)+2.45C(s)\rightarrow 0.816SiC(s)+1.63CO(g)[/tex]
How would you describe the sequence of reactions in a hydrogen bomb
A hydrogen bomb relies on a nuclear fission bomb to trigger a fusion reaction between deuterium and tritium using lithium deuteride as the fusion fuel. The explosion is enhanced by a U-238 shell which reflects neutrons back into the fuel and fissions to add to the energy output. This process results in a bomb significantly more powerful than atomic bombs.
Explanation:The construction and subsequent chain of reactions in a hydrogen bomb, or a thermonuclear bomb, typically begin with a nuclear fission bomb. The fission bomb, when exploded, produces extremely high temperatures necessary for fusion to occur. A common method is to use lithium deuteride as the fusion fuel, which is in close proximity to the fission bomb. Upon detonation, the fission bomb's gamma rays heat and compress the fusion fuel. Meanwhile, neutrons from the fission reaction cause the lithium to undergo a reaction to generate tritium: n + 6Li → ³ H + ª He. This newly generated tritium then fuses with deuterium in the reaction 2H+ ³H → He + n + 17.6 MeV, producing helium, another neutron, and a significant amount of energy.
Additional fusion and fission fuels are enclosed within a dense shell of U-238. This uranium shell serves two purposes: it reflects some neutrons back into the fuel to enhance fusion, and the fast-moving neutrons cause the uranium itself to fission, adding to the overall energy output of the bomb.
The first hydrogen bomb was detonated in 1952, but unlike the atomic bomb, a hydrogen bomb has never been used in warfare. Thermonuclear bombs are significantly more powerful than atomic ones - the power of a modern hydrogen bomb is approximately 1000 times that of the bombs dropped on Hiroshima and Nagasaki during World War II.
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To determine the pH of a solution using a pH indicator paper, you need a .
Answer:
color key
creating a color key
Have known pH values
Explanation:
To determine the pH of a solution using a pH indicator paper, you need a Colour key.
What is pH value and colour key?pH is a measure of how acidic/basic water is. The range goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base. pH is really a measure of the relative amount of free hydrogen and hydroxyl ions in the water.pH indicators are weak acids that exist as natural dyes and indicate the concentration of H+ (H3O+) ions in a solution via color change. A pH value is determined from the negative logarithm of this concentration and is used to indicate the acidic, basic, or neutral character of the substance you are testing.Colour key is need determine the pH of a solution.
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Which of the following types of reactions would decrease the entropy within a cell? A. Dehydration reaction, B. Hydrolysis, C. Respiration, D. Digestion, E. Catabolism
A. Dehydration reactions.
Explanation;Dehydration reactions refer to chemical events where a water molecule is lost because of the presence of another reacting molecule.Dehydration reaction is said to cause a decrease in entropy in various cells. Entropy within a cell refers to a state of inner instability secondary to different energies provided by the different molecular components.When the water component is removed, there will be less molecular energy and therefore decreased entropy.During a hot and humid day, large and dense clouds known as cumulonimbus clouds form. In many cases these clouds will result in ______________. A) hurricanes B) snowstorms C) thunderstorms D) pleasant weather
the answer is c- thunderstorms
If a piece of space debris is too large to be a meteoroid and too small to be a planet, it could be _______.
I think it could be "an asteroid" .
Which is a system of applied science used to provide people with things they need or desire
Technology
Explanation;Applied science entails the application of knowledge from one or more natural scientific fields to solving practical problems.Technology is a specific system of applied science. It is a means by which a society provides it's members with things they need/desire.The main aim of technology is to create products that solve problems and improve human life. It is a practical application of scienceEnergy and Specific Heat
1. Draw a graph of an exothermic reaction. Label reactants, products and ∆H.
2. Calculate the amount of energy required to raise the temperature of 3.00g of gold from 45.9 to 93.0°C.
3. 1.70g of a silvery metal requires 1000.J of energy to change its temp from 298K to 2749K. Is the metal pure silver?
Answer:
1. Kindly, see the attached image.
2. 18.369 J.
3. Yes, the metal is pure silver.
Explanation:
1. Draw a graph of an exothermic reaction. Label reactants, products and ∆H.
Kindly, see the attached image that shows the graph of an exothermic reaction.2. Calculate the amount of energy required to raise the temperature of 3.00 g of gold from 45.9 to 93.0°C.
To solve this problem, we can use the relation:Q = m.c.ΔT.
Where, Q is the amount of energy required to raise the temperature of gold (J).
m is the mass of the gold (m = 3.0 g).
c is the specific heat of gold (c = 0.13 J/g.°C).
ΔT is the temperature difference between the initial and final T (ΔT = 93.0 °C - 45.9 °C = 47.1 °C).
∴ Q = m.c.ΔT = (3.0 g)(0.13 J/g.°C)(47.1 °C) = 18.369 J.
3. 1.70 g of a silvery metal requires 1000.0 J of energy to change its temp from 298 K to 2749 K. Is the metal pure silver?
To determine wither the metal is pure or not, we should calculate the specific heat (c) of Ag and compare it with the reported value in the table.As mentioned in details in the second point, we can use the relation:
Q = m.c.ΔT
Q = 1000.0 J, m = 1.70 g, ΔT = 2749 - 298 = 2451 °C.
∴ c = Q/(m.ΔT) = (1000.0 J)/(1.70 g)(2451 °C) = 0.239 J/g.°C ≅ 0.24 J/g.°C.
The calculated value is the same as the value reported in the table, so the metal is pure silver.Consider the reaction between no and cl2 to form nocl. 2no(g) + cl2(g) ⇌ 2nocl(g) a reaction mixture at a certain temperature initially contains only [no] = 0.50 m and [cl2] = 0.50 m. after the reaction comes to equilibrium, the concentration of nocl is 0.30 m. what is the value of kc at this temperature?
The reaction given is 2NO(g) + Cl2(g) ⇌ 2NOCl(g). The initial concentrations of NO and Cl2 are 0.50 M. At equilibrium, concentration of NOCl is 0.30 M, while concentrations of NO and Cl2 are 0.20 M. The equilibrium constant Kc for this reaction at this temperature is thus calculated to be 9.0 M⁻².
Explanation:The value of Kc at a given temperature for a reaction can be calculated using the equilibrium concentrations of the reactants and products in the chemical equation. The reaction described here is 2NO(g) + Cl2(g) ⇌ 2NOCl(g).
At equilibrium, the concentration of NOCl is given as 0.30 M, while we are not provided with the equilibrium concentrations of NO and Cl2, but we know that initially they were both 0.50 M.
The expression for the equilibrium constant Kc in this case would be: Kc = [NOCl]² / ([NO]² [Cl2])
Therefore, calculating equilibrium concentrations of NO and Cl2 from the balanced chemical equation since each 2 moles of NO and Cl2 react to form 2 moles of NOCl, [NO] = [Cl2] = 0.50M - 0.30M = 0.20M.
Substituting these equilibrium concentrations, the value of the Kc becomes:
Kc = (0.30²) / (0.20² * 0.20) = 9.0 M⁻²
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The small intestine couldn't work without the _________ because fats couldn't be broken down