Answer:
The distance traveled by the car during this time is 1.18 km.
Explanation:
Initial speed of the car, u = 0 (at rest)
Final sped of the car, [tex]v=350\ km/h = 97.23\ m/s[/tex]
Acceleration of the car, [tex]a=4\ m/s^2[/tex]
We need to find the distance would the car travel during this time. It can be calculated using third equation of motion. It is given by :
[tex]v^2-u^2=2ad[/tex]
[tex]v^2=2ad[/tex]
[tex]d=\dfrac{v^2}{2a}[/tex]
[tex]d=\dfrac{(97.22\ m/s)^2}{2\times 4\ m/s^2}[/tex]
d = 1181.46 m
or
d = 1.18 km
So, the distance traveled by the car during this time is 1.18 km. Hence, this is the required solution.
A car changes velocity at a constant acceleration of 2.5m/s to reach 43.7m/s in 2.7 s how fast was the car moving when it began to accelerate?
The formula we can use in this case is:
v = v0 + a t
where v is final velocity, v0 is initial velocity, a is acceleration and t is time
So finding for v0:
v0 = v – a t
v0 = 43.7 – (2.5) 2.7
v0 = 36.95 m/s
The car was moving at a speed of 36.95 m/s when it began to accelerate.
Explanation:To find the initial velocity of the car when it began to accelerate, we can use the equation for average velocity:
V = (U + V)/2
Where:
V is the final velocity (43.7 m/s)U is the initial velocity (unknown)Given that the car changes velocity at a constant acceleration, we can use the kinematic equation:
V = U + at
Where:
a is the acceleration (2.5 m/s²)t is the time (2.7 seconds)Substituting the known values, we have:
43.7 m/s = U + (2.5 m/s²)(2.7 s)
Simplifying the equation, we find:
U = 43.7 m/s - (2.5 m/s²)(2.7 s)
U = 43.7 m/s - 6.75 m/s
U = 36.95 m/s
Therefore, the car was moving at a speed of 36.95 m/s when it began to accelerate.
The tension t at each end of the chain has magnitude 25 n. what is the mass of the chain? (use g = 9.8 m/s2 for the acceleration due to gravity. give your answer correct to at least two decimal places.)
The mass of the chain in two decimal places is 2.55 kg.
What is the mass of the chain?
The tension at the end of the chain is due to the weight of the weight supported by the chain.
The mass of the chain is calculated by applying Newton's second law of motion as follows;
W = mg
where;
m is the mass of the chaing is acceleration due to gravitym = W / g
The mass of the chain is calculated as;
m = ( 25 N ) / ( 9.8 m/s² )
m = 2.55 kg
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The mass of the chain can be calculated using the formula Mass = tension / gravity. Given the values for tension and gravity, the mass of the chain is approximately 2.55 kg.
Explanation:This is a problem related to the physics concept of force, mass, and acceleration due to gravity. Since we know that the tension in the chain isn't affected by the chain's length, we can assume that the tension is evenly distributed along the chain, with 25 N at each end.
The tension in the chain is equal to the weight of the chain. Therefore, we can use the formula for calculating the weight, which is Weight = mass x gravity. Since we know that the weight is equal to the tension, we can solve the formula for mass, which gives us Mass = tension / gravity. Substituting the given values, we have: Mass = 25 N / 9.8 m/s² = 2.55 kg.
Therefore, the mass of the chain is approximately 2.55 kg.
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The flight from kampala to singapore takes 7.0 hours. what is the plane's angular velocity relative to the earth's surface? give your answer in ∘/h.
Final answer:
The Earth rotates at an angular velocity of 15 degrees per hour. Without specific flight path distances, we refer to Earth's rotation speed as a base reference for understanding angular velocity in a general sense.
Explanation:
The flight from Kampala to Singapore takes 7.0 hours. To calculate the plane's angular velocity relative to the Earth's surface, we need to understand that completing a flight between two points on Earth's surface involves moving over a certain segment of Earth's rotation. Since the Earth completes one full rotation (360 degrees) in 24 hours, we can calculate the angular velocity (in degrees per hour) by simply dividing the total degrees by the total hours.
Angular velocity = Total rotation / Time = 360 degrees / 24 hours = 15 degrees per hour.
However, this is the angular velocity of the Earth itself. A plane's angular velocity relative to Earth would depend on the distance traveled. But without specific details on the distance covered, we can only refer to the Earth's own rotation speed as a base reference, which is 15 degrees per hour. For a specific flight, beyond this basic understanding, actual calculation would require details about the exact flight path length over the Earth's surface.
The blade on a typical table saw rotates at 3300 revolutions per minute. calculate the linear velocity in miles per hour of one of the teeth at the edge of the 14 inch diameter blade.
Final answer:
The linear velocity of a tooth at the edge of the 14 inch diameter blade on a typical table saw can be calculated by converting the blade's rotational speed from revolutions per minute to radians per second and using the formula for linear velocity. The calculated value will give the speed of the tooth in miles per hour.
Explanation:
To calculate the linear velocity of a tooth at the edge of the blade, we need to first convert the blade's rotational speed from revolutions per minute to radians per second. We can do this by multiplying the revolutions per minute (rpm) by 2π (since there are 2π radians in one revolution) and dividing by 60 (to convert minutes to seconds). So, the angular velocity of the blade is:
ω = (3300 rpm) x (2π rad/rev) / (60 s/min)
Next, we can use the formula for linear velocity to find the speed of a point on the edge of the blade. The formula is:
v = ω x r
where v is the linear velocity, ω is the angular velocity, and r is the radius. In this case, the blade has a diameter of 14 inches, so the radius is half of that, which is 7 inches or 0.5833 feet. Converting this to miles, we get:
r = 0.5833 ft x (1 mile/5280 ft)
Finally, we can substitute the values into the formula:
v = (3300 rpm) x (2π rad/rev) / (60 s/min) x 0.5833 ft x (1 mile/5280 ft)
Calculating this equation gives the linear velocity of a tooth at the edge of the blade.
Which action occurs during a nuclear change?
A.No energy is involved in the reaction.
B.The nucleus disappears.
C.Matter changes from one state to another.
D.Elements are created that differ from the reactants.
1. Some wooden rulers do not start with 0 at the edge, but have it set on a few millimeters. How could this improve the accuracy of the ruler?
2. You find a micrometer that has been badly bent. How would it compare to a new, high-quality meter stick in terms of precision? Its accuracy?
3. Does parallax affect the precision of a measurement that you make? Explain.
4. A box has a length of 18.1 cm and a width of 19.2 cm and it is 20.3 cm tall.
a. what is the volume?
b. how precise is the measure of length? Of volume?
c. How tall is a stack of 12 of these boxes?
d. how precise is the measure of the height of one box? Of 12 boxes?
1. Some wooden rulers do not start with 0 at the edge, but have it set on a few millimeters because the cut of the woof alters the length of the first measures. Moreover, some objects are difficult to be aligned on the ruler, thus, in order to remove this difficulty, some wooden rulers do not start with 0 at the edge.
2. The micrometer has been badly bent which means that it will not measure properly and will not be perfectly parallel with the surface to be measured. This distortion will change its precision. The device should be parallel with the surface to be measured in order to maintain its accuracy.
3. No, the parallax will not affect the precision of a measurement that we take as precision is the closeness of the readings and the readings are already precise, thus taking the reading with the same parallax won't impair the precision but decreases the accuracy.
4. Length of box=18.1 cm, width= 19.2 cm and height=20.3 cm, then the a.volume=length×width×height
=[tex]18.1{\times}19.2{\times}20.3[/tex]
=[tex]7050cm^{3}[/tex]
b. The reading of the length is precise to 0.1 centimeters, while the volume's reading is precise to 10 cm³.
c. The stack of 12 of the boxes has height=[tex]12{\times}19.3[/tex]
=[tex]232cm[/tex]
d.The measure of one box is precise to 0.1 cm, while the measurement of the combined boxes is precise to 1 cm.
Ismarelda has enough money to purchase 27 bottles of root beer for her party at her home she is expecting 4 guests.
What is the largest numbers of bottles of root beer she needs to purchase if she want every one ( including herself ) to have equal number of root beers
If a glass is knocked off of a table that is 1.4m tall, how long does it take for the glass to hit the ground?
The main reason for positioning many radio telescopes across a large area and combining the signals is
Choose the 200 kg refrigerator. Set the applied force to 400 N (to the right). Be sure friction is turned off.What is the net force acting on the refrigerator?
The net force acting on the refrigerator is 400 N to the right
[tex]\texttt{ }[/tex]
Further explanationNewton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.
[tex]\boxed {F = ma }[/tex]
F = Force ( Newton )
m = Object's Mass ( kg )
a = Acceleration ( m )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
mass of refrigerator = m = 200 kg
magnitude of applied force = F = 400 N
magnitude of frictional force = f = 0 N
Asked:
net force = ΣF = ?
Solution:
We will use Newton's Law of Motion to solve this problem as follows:
[tex]\Sigma F = F - f[/tex]
[tex]\Sigma F = 400 - 0[/tex]
[tex]\boxed{\Sigma F = 400 \texttt{ N} }[/tex]
[tex]\texttt{ }[/tex]
We could also calculate the acceleration of the refrigerator as follows:
[tex]\Sigma F = ma[/tex]
[tex]a = \Sigma F \div m[/tex]
[tex]a = 400 \div 200[/tex]
[tex]\boxed{a = 2 \texttt{ m/s}^2 }[/tex]
[tex]\texttt{ }[/tex]
Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441Newton's Law of Motion: https://brainly.com/question/10431582Example of Newton's Law: https://brainly.com/question/498822[tex]\texttt{ }[/tex]
Answer detailsGrade: High School
Subject: Physics
Chapter: Dynamics
A 3-kg block is observed to accelerate at a rate twice that of a 6-kg block. is the net force acting on the 3-kg block twice as large as that acting on the 6-kg block? explain.
The force acting on a body is directly proportional to both mass and acceleration. Hence, the an increase in acceleration with a smaller mass does not make an increase in force than that act on a larger mass with less acceleration. Hence, the net force will be the same for both masses.
What is force?Force is an external agent acting on a body to deform it or to change its state of motion or rest. Force is a vector quantity thus, it is characterized by a magnitude and direction.
The force according to second law of motion is the product of mass and acceleration of the body. Hence, an increase in mass or acceleration or both results in an increase in force.
Here, the force F1 is acting on the mass 3 Kg with an acceleration of 2a
and force F2 is acting on 6 Kg with an acceleration a.
Then F1 = 3 × 2 a = 6a
F2 = 6 × a = 6a.
Thus, net force of both are equal.
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This map shows the Mid-Atlantic Ridge, which spreads approximately 2.5 cm/year. What is the rate of the spread in m/month?
A) .002
B) .3
C) 216
D) 777600
The answer is A 00.2
Explain the difference between si base units and derived units. give an example of each
Final answer:
SI base units are the seven fundamental units in the SI system, such as kilograms for mass; derived units, such as grams per milliliter for density, are constructed by combining base units. Derived units are essential for expressing a wide range of physical quantities, demonstrating the SI system's adaptability.
Explanation:
The difference between SI base units and derived units lies in their definitions and applications. SI base units are the seven fundamental units of measurement in the International System of Units (SI) that are defined by specific physical phenomena and are independent of each other. These include the kilogram (kg) for mass and the meter (m) for length, among others. On the other hand, derived units are units that are constructed by combining the base units according to algebraic relationships. Examples of derived units include grams per milliliter (g/mL) for density and joules (J) for energy, which are obtained by combining base units in multiplicative ways.
Derived units can express a wide variety of physical quantities such as area, volume, density, and energy, showcasing the versatility of the SI system. Combining prefixes with base units can also create new units of larger or smaller sizes, enhancing the adaptability of the system to cover a broad range of measurements from the microscopic to the astronomical scale.
hich of these statements explains the relationship among elements, compounds, and mixtures?
Elements are made of compounds and mixtures.
Both compounds and mixtures are made up of elements.
Mixtures are made of elements, and elements are made of compounds.
Compounds are made of mixtures, and mixtures are made of elements.
A cylinder has a length of 3.23 cm, a diameter of 1.75 cm, and a mass of 65.3 grams. What is the density of the cylinder? Based on its density, of what kind of material might it be made? Material is likely to be: ______________________________ (Show your work.)
To find the density of a cylinder, its volume is first determined using the formula V = πr²h. After correcting the radius and height according to the question, the density is calculated as mass divided by volume, approximately 6.65 g/cm³. Compared to standard material densities, the cylinder may be made of a type of stainless steel or a similar metal alloy.
Explanation:To calculate the density of the cylinder, we first need to find its volume using the formula V = πr²h. Given that the length (height) is 3.23 cm and the diameter is 1.75 cm, the radius (r) would be half of the diameter, which is 0.875 cm. However, there seems to be a typo or mistake in the provided sample work as it uses a radius of 0.750 cm and a height of 5.25 cm, which do not match the question's parameters. Assuming the correct measurements, we would use:
V = π × (0.875 cm)² × 3.23 cm = 9.818 cm³
Now, to find the density, we divide the mass by the volume:
Density = Mass / Volume = 65.3 g / 9.818 cm³ = 6.65 g/cm³
Based on common material densities, this cylinder could potentially be made of stainless steel which typically has a density around 8 g/cm³; however, since our calculated density is slightly less, it could be a stainless steel alloy or a similar metal with a slightly lower density.
A bird can fly 25 km/h. How long does it take to fly 3.5km?
The equation of motion that we can use in this case is:
t = d / v
where t is time, d is distance, v is velocity
Therefore calculating for t:
t = 3.5 km / (25 km / h)
t = 0.14 h = 8.4 minutes
It takes approximately 8.4 minutes for a bird flying at 25 km/h to cover a distance of 3.5 km.
Explanation:To determine how long it takes for a bird to fly 3.5 km at a speed of 25 km/h, we can use the formula for time, which is distance divided by speed. The calculation is as follows:
Time = Distance / Speed
Time = 3.5 km / 25 km/h = 0.14 h
To convert hours to minutes, multiply by 60:
Time = 0.14 h × 60 minutes/h = 8.4 minutes
Thus, it will take the bird approximately 8.4 minutes to fly 3.5km.
On your first attempt you leave the surface of the earth at v = 5534 m/s. how far from the center of the earth will you get?
Final answer:
The speed mentioned is approximately half the escape velocity from Earth and is not sufficient to escape Earth's gravitational field. The object will ascend to a maximum altitude before falling back down. A specific calculation would require further application of physics principles.
Explanation:
The question is related to the concept of escape velocity in physics, which is the speed needed to break free from a planet's gravitational pull without further propulsion. The escape velocity from the surface of the Earth is approximately 11 km/s. At a speed of 5534 m/s, which is approximately 5.5 km/s (half the escape velocity), the object will not have enough kinetic energy to completely escape Earth's gravity and hence will reach a maximum altitude before falling back to Earth. To calculate precisely how far from the center of the Earth you would get with the initial speed of 5534 m/s, you would need to use the equations for gravitational potential energy and kinetic energy, considering how much kinetic energy converts into potential energy as the object ascends against Earth's gravity.
Two planes leave wichita at noon. one plane flies east 30 mi/h faster than the other plane, which is flying west. at what time will they be 1200 mi apart?
The time they will be 1200 mi apart is [tex]\(12:00 PM + \frac{1200}{2S + 30}\)[/tex] hours.
Let's denote the speed of the slower plane as [tex]\(S\) (in mi/h)[/tex]. The faster plane, which is flying east, will have a speed of [tex]\(S + 30\) mi/h[/tex].
The relative speed between the two planes is the sum of their individual speeds:
[tex]\[ \text{Relative speed} = S + (S + 30) = 2S + 30 \, \text{mi/h} \][/tex]
Now, we know that the planes leave at noon, and we want to find the time it takes for them to be 1200 mi apart. Let t be the time in hours.
The distance traveled by the slower plane in t hours is [tex]\(S \cdot t\)[/tex], and the distance traveled by the faster plane is [tex]\((S + 30) \cdot t\)[/tex]. The sum of these distances is the total distance between the planes:
[tex]\[ S \cdot t + (S + 30) \cdot t = 1200 \][/tex]
Combine like terms:
[tex]\[ 2S \cdot t + 30 \cdot t = 1200 \][/tex]
Factor out t:
[tex]\[ t(2S + 30) = 1200 \][/tex]
Now, solve for t:
[tex]\[ t = \frac{1200}{2S + 30} \][/tex]
We know that when t is the time, it should be in hours, and we want to find at what time they will be 1200 mi apart. If they leave at noon, the time will be [tex]\(12:00 PM\) + \(t\) hours[/tex].
So, the time they will be 1200 mi apart is [tex]\(12:00 PM + \frac{1200}{2S + 30}\)[/tex] hours.
A hockey player is standing on his skates on a frozen pond when an opposing player, moving with a uniform speed of 13 m/s, skates by with the puck. After 1.5 s, the first player makes up his mind to chase his opponent. (a) If he accelerates uniformly at 4.0 m/s2, how long does it take him to catch his opponent? (Assume the player with the puck remains in motion at constant speed.) (b) How far as he traveled
Let us say that:
1 = 1st player notation
2 = 2nd player notation (the opponent)
a. First let us establish the distance travelled by the 2nd player:
d2 = 13 m/s * (t + 1.5)
d2 = 13 t + 19.5
Then the distance of the 1st player:
d1 = v0 t + 0.5 a t^2 (v0 initial velocity = 0 since he started from rest)
d1 = 0.5 * 4 m/s^2 * t^2
d1 = 2 t^2
The two distances must be equal, d1 = d2:
2 t^2 = 13 t + 19.5
t^2 – 6.5 t = 9.75
Completing the square:
(t – 3.25)^2 = 9.75 + (- 3.25)^2
t – 3.25 = ±4.5
t = -1.25, 7.75
Since time cannot be negative, therefore:
t = 7.75 seconds
So he catches his opponent after 7.75 seconds.
b. Using the equation:
d1 = 2 t^2
d1 = 2 * (7.75)^2
d1 = 120.125 m
So he travelled about 120.125 meters when he catches up to his opponent.
It takes 3.25 seconds for the first player to catch the opponent. The first player has traveled 21.125 meters when they catch the opponent.
Given:
Opponent's speed (v₁) = 13 m/s
Acceleration of the first player (a) = 4.0 m/s²
Time (t) = 1.5 s
(a) We can use the following equation:
v = u + at
13 = 0 + 4.0 × t
t = 13 / 4.0
t = 3.25 s
Therefore, it takes 3.25 seconds for the first player to catch the opponent.
(b) we can use the equation:
s = ut + (1/2)at²
s = 0 × 3.25 + (1/2) × 4.0 × (3.25 )²
s = 0 + (1/2) × 4.0 × 10.5625
s = (1/2) × 4.0 × 10.5625
s = 21.125 m
Therefore, the first player has traveled 21.125 meters when they catch the opponent.
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How do constellations differ from other groupings of stars such as galaxies?
A car starts from rest and after 5 seconds it is moving at 35 m/s. what is the car's average acceleration?
You throw a beanbag in the air and catch it 2.2s later at the same place you threw it. How high did it go? What was its initial velocity?
The beanbag was thrown in a motion with an initial velocity of 10.78 m/s and reached a peak height of 5.929m.
Explanation:The height and initial velocity of a thrown object can be calculated using kinematics, a branch of physics that describes motion of objects. Since the beanbag is thrown up and comes back to the same spot, the total time of its flight (2.2s) is split between the time going up and the time coming back down.
We can simplify calculations by assuming that the time for the journey upwards equals the time for the journey downwards, i.e., 1.1s each.
The highest point is reached when the velocity is zero. We can use the formula v= u + at to find the initial velocity (u), where v is the final velocity, a is acceleration due to gravity (-9.8m/s² due to the upward direction), and t is the time (1.1s). For the highest point, we can use the formula h = ut + 0.5at².
Calculating this, we find the initial velocity u = -9.8 × 1.1 = -10.78 m/s (it's negative because we took upward direction as negative). To calculate the highest point or maximum height, we find h = -10.78 × 1.1 + 0.5 × -9.8 × (1.1)² = -5.929 m (this is also negative due to upward direction). Hence, the beanbag was thrown up with an initial velocity of 10.78 m/s and reached a maximum height of 5.929 m.
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henry was given this cool toy for his birthday;he can use it to tell how fast someone is going at that moment in time. the toy must calculate the persons....
average velocity
average speed
acceleration
instantaneous speed
Answer:
Instantaneous speed
Explanation:
It is given that, Henry was given this cool toy for his birthday. He can use it to tell how fast someone is going at that moment in time. The toy must calculate the person's instantaneous speed.
Instantaneous speed of an object is defined as the speed at a particular instant. Mathematically, it is given by :
[tex]v= \lim_{\Delta t \to 0}(\dfrac{\Delta x}{\Delta t})[/tex]
Instantaneous speed is a scalar quantity. It does not involve any direction.
So, Henry must calculate the person's instantaneous speed. Hence, the correct option is (d).
in a historical movie, two knights on horseback start from rest at 88.0 m spartans ride directly toward each other to do battle. Sir George’s acceleration has a magnitude of 0.300 m/s^2, while Sir Alfred’s has a magnitude of 0.200 m/s^2. Relative to Sir George’s starting point, where do the knights collide?
A 590-kg rocket is at rest on the launch pad. what upward thrust force is needed to accelerate the rocket uniformly to an upward speed of 28 m/s in 3.3 s?
Final answer:
To find the upward thrust force needed to accelerate the rocket, we use Newton's second law of motion. The upward thrust force needed is approximately 4989.2 N.
Explanation:
To find the upward thrust force needed to accelerate the rocket, we can use Newton's second law of motion, which states that force is equal to mass times acceleration. In this case, the mass of the rocket is 590 kg and the acceleration is the change in velocity divided by the time taken.
Using the formula acceleration = (final velocity - initial velocity) / time, we can calculate the acceleration:
acceleration = (28 m/s - 0 m/s) / 3.3 s = 8.48 m/s²
Now that we have the acceleration, we can calculate the upward thrust force:
force = mass x acceleration = 590 kg x 8.48 m/s² = 4989.2 N
Therefore, the upward thrust force needed to accelerate the rocket uniformly to an upward speed of 28 m/s in 3.3 s is approximately 4989.2 N.
To accelerate the 590-kg rocket uniformly to an upward speed of 28 m/s in 3.3 s, a thrust force of approximately 5010.2 N is required, calculated using Newton's second law.
To determine the upward thrust force needed to accelerate the rocket uniformly, we can use Newton's second law, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).
First, calculate the acceleration (a) of the rocket using the kinematic equation:
v = u + at
where:
v is the final velocity (28 m/s),
u is the initial velocity (0 m/s, as the rocket is at rest),
a is the acceleration, and
t is the time (3.3 s).
Rearrange the equation to solve for acceleration:
a = (v - u) / t
Substitute the values:
a = (28 m/s - 0) / 3.3 s ≈ 8.48 m/s^2
Now, use Newton's second law to find the force (F):
F = ma
F = 590 kg × 8.48 m/s^2 ≈ 5010.2 N
The __________ houses the nucleus and other cell parts.
A.
neural receptor
B.
myelin sheath
C.
cell body
D.
axon terminal
The part of the neuron that houses the nucleus and other cell parts is the cell body that is in Option c, as the cell body, also known as the soma, is a central part of a eukaryotic cell.
What is the cell body?The cell body includes the nucleus and other organelles like the mitochondria, endoplasmic reticulum, Golgi apparatus, and cytoplasm. The cell body is the main site for the metabolic and biochemical processes of the cell, and it is responsible for maintaining the integrity of the cell and regulating its activities. In the case of neurons, the cell body also contains the genetic information of the neuron in the form of DNA, which is used to synthesize the proteins and other molecules needed for the growth, repair, and maintenance of the neuron.
Hence, the part of the neuron that houses the nucleus and other cell parts is the cell body that is in Option c.
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The greater the mass of an object, the greater its force due to gravity
True, the greater the mass of an object, the greater its force due to gravity.
What is force due to gravity?Force due to gravity is gravitational pull on object due to its position on earth's surface.The force due to gravity on object's is calculated by applying Newton's second law of motion as follows;
F = mg
where;
m is the mass of the objectg is acceleration due to gravityFrom the formula given above we can conclude that, the greater the mass of an object, the greater its force due to gravity.
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The statement addresses Isaac Newton's law of gravitation which suggests that the greater the mass of an object, the greater its force due to gravity. Gravitational attraction is a universal property of mass. Mass is constant while weight varies with the gravitational field strength.
Explanation:The statement in question - 'The greater the mass of an object, the greater its force due to gravity' - is a fundamental principle in Physics, specifically in the study of gravity. Gravity is essentially a 'built-in' property of mass, meaning all masses in the universe interact via the force of gravitational attraction. The British physicist Sir Isaac Newton concluded that the gravitational attraction between two bodies is proportional to their masses and inversely proportional to the square of the distance between them. This is illustrated in Newton's law of gravitation, formulated as Fgravity = G × (M1 × M2) / R².
It's important to note also that the weight of an object, which is the force of gravity acting on it, varies with the strength of the gravitational field. Mass, however, is a constant property of an object and does not change regardless of the gravity acting on it. Mass is a measure of the amount of matter in an object, whereas weight is the gravitational pull acting on that matter.
Understanding these principles allows us calculate the masses of astronomical objects and understand a range of natural phenomena, from the motion of a falling apple to the orbits of planets.
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The density of water is 1.00 g/cm3. What is its density in kg/m3?
The density of water is 1.00 g/cm3, then in kilograms per centimeter cube unit, its density would be 1000 kg/m³.
What is density?It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
As given in the problem we have to calculate the density of water in kilogram per centimeter cube,
1 cm³ = 1×10⁻⁶ m³
1 gram = 1×10⁻³ kg
The density of the water= mass of the water /volume of the water
=1.00 g/cm3
=1×10⁻³ kg /1×10⁻³ kg
=1000 kg/m³
Thus, if the density of water is 1.00 g/cm3, then in kilograms per centimeter cube unit its density would be 1000 kg/m³.
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What is the primary reason that we launch x-ray telescopes into space rather than building them on the ground?
Answer:
X-Rays from space do not reach the ground.
Explanation:
which of the following descriptions could apply to an accelerating car