To find the total number of candies, square 108 and then multiply by 100. The steps result in a total of 1,166,400 candies in the store.
Calculating the Total Number of Candies
The expression provided is (108) 2 × 100. To calculate this, first square 108, which means you multiply 108 by itself, and then multiply the result by 100. So the calculation will look like this: 108 × 108 × 100.
To carry out this multiplication, the steps are:
Square 108: 108 × 108 = 11,664.
Multiply the result by 100: 11,664 × 100 = 1,166,400.
Therefore, the total number of candies in the store is 1,166,400.
To find the total number of candies in the store given the expression [tex](108)^2[/tex] times 100, you first square 108 to get 11,664 and then multiply that by 100, resulting in 1,166,400 candies.
The student's question asks for the total number of candies in a store given the expression [tex](108)^2[/tex] times 100.
To find the total, we need to calculate the square of 108 and then multiply the result by 100.
First, 1082 equals 11,664 (108 multiplied by itself).
Next, we multiply 11,664 by 100 to find the total number of candies, which gives us 1,166,400 candies.
Hence, there are 1,166,400 candies in the store.
Step-by-Step Solution:
Calculate the square of 108: 108 x 108 = 11,664.Multiply the result by 100: 11,664 x 100 = 1,166,400.Therefore, the store has 1,166,400 candies in total.
Name 3 decimals with a product about 40.
What is the value of P?
10p + 5 = 18p–6/2
It's 18p - 6 over 2.
What is 80% as a fraction in reduced form ?
80% as a fraction in reduced form is 4/5.
To express 80% as a fraction in reduced form, you need to convert the percentage to a fraction. The term reduced form means simplifying the fraction to its lowest terms.
Here's a step-by-step explanation:
Step 1: Understand what a percentage represents
A percentage is a way to express a fraction or ratio out of 100. So, when you see 80%, it means 80 out of 100.
Step 2: Write the percentage as a fraction
To convert a percentage to a fraction, you can write it as a fraction with the percentage as the numerator and 100 as the denominator. Therefore, 80% can be written as 80/100.
Step 3: Simplify the fraction
To reduce the fraction to its lowest terms, you need to find the greatest common divisor (GCD) between the numerator and denominator. In this case, both 80 and 100 can be divided by 20. Dividing both the numerator and denominator by 20, we get:
80/100 = (80 ÷ 20) / (100 ÷ 20) = 4/5.
Step 4: Interpret the reduced fraction
The fraction 4/5 is the reduced form of 80%. It means that 80% is equivalent to four-fifths (4 parts out of 5).
Therefore, 80% as a fraction in reduced form is 4/5.
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Slope for (6,-10) (-15,15)
Just need the equation please help I'm dum
it is 1,831 feet from Igor's house to his school how many feet does Igor Walk to school in. 5days
How do you write $2.161616 as a fraction and mixed number
Translate 1 hundreds 4 ones 2 tens and 1 tenths
what's the answer for X?
plzzzzzzzzzzzzzz answer
Emily spent a total of 38.04 on four CDs if each CD cost the same amount what is a reasonable amount for each CD explain why your answer is reasonable
A zookeeper weighed an African elephant to be 9 × 103 to the power of 3 pounds and an African lion to be 4 × 102 to the power of 2 pounds. How many times greater is the weight of the elephant than the weight of the lion?
A) 2.25 times 10 to the power of 1
B) 5
C) 13 times 10 to the power of 5
B) 3.6 times 10 to the power of 6
Answer:
[tex]2.25\times 10^1[/tex] times greater is the weight of the elephant than the weight of the lion.
Step-by-step explanation:
Given : A zookeeper weighed an African elephant to be [tex]9\times 10^3[/tex] pounds and an African lion to be [tex]4\times 10^2[/tex] pounds.
To find : How many times greater is the weight of the elephant than the weight of the lion?
Solution :
A zookeeper weighed an African elephant to be [tex]9\times 10^3[/tex] pounds.
A zookeeper weighed an African lion to be [tex]4\times 10^2[/tex] pounds
Now, Divide the weighed an African elephant with weighed an African lion to determine times greater is the weight of the elephant than the weight of the lion,
[tex]n=\frac{9\times 10^3}{4\times 10^2}[/tex]
[tex]n=2.25\times 10^1[/tex]
Therefore, Option A is correct.
[tex]2.25\times 10^1[/tex] times greater is the weight of the elephant than the weight of the lion.
Solve for p.
3p − 4 = 11
p = 7
p = -5
p = −3
p = 5
Find two consecutive odd integers such that the sum of the smaller and 3 times the larger is 330
To solve this problem, the two consecutive odd integers are defined as x and x+2. A mathematical equation is created according to the problem conditions and solved. The consecutive odd integers are found to be 81 and 83.
Explanation:Let's define the two consecutive odd integers as x (the smaller) and x+2 (the larger). Given the condition from the question that the sum of the smaller integer and three times the larger integer is 330, we can form the equation x + 3*(x+2) = 330.
We'll simplify that equation, which gives us: x + 3x + 6 = 330, and combining like terms, we get 4x + 6 = 330. We can solve for x by subtracting 6 from both sides and then dividing both sides by 4, which results in x = 81. Given that x represents the smaller odd integer, the larger integer would be x + 2 or 83.
So, the two consecutive odd integers fulfilling the conditions given are 81 and 83.
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The two consecutive odd integers such that the sum of the smaller and 3 times the larger is 330 are 81 and 83.
Denote the smaller odd integer as x and the larger consecutive odd integer as x + 2.
According to the problem, the sum of the smaller integer and 3 times the larger integer is 330. So, we have the equation:
x + 3(x + 2) = 330
Now, solve for x :
1. Distribute the 3 on the left side:
x + 3x + 6 = 330
2. Combine like terms:
4x + 6 = 330
3. Subtract 6 from both sides to isolate terms with x:
4x = 324
4. Divide both sides by 4 to solve for x:
[tex]\[ x = \frac{324}{4} \]\[ x = 81 \][/tex]
So, the smaller odd integer x is 81. Now find the larger consecutive odd integer:
x + 2 = 81 + 2 = 83
Therefore, the two consecutive odd integers are 81 and 83.
To verify:
- The sum of the smaller integer and 3 times the larger integer:
[tex]\[ 81 + 3 \cdot 83 = 81 + 249 = 330 \][/tex]
The verification confirms that the solution is correct.
So, the two consecutive odd integers such that the sum of the smaller and 3 times the larger is 330 are 81 and 83.
ellen and tasha took a long bicycle trip last weekend.they rode the first 10 miles at a rate of 12 miles per hour. They realized they had to go faster to get to their destination before dark. So they sped up for the last 12 miles of the trip. The entire trip took 1 hour and 20 minutes. At what rate did they travel the last 12 miles? As mile per hours.
Simplify
7/3+3(2/3−1/3)^2
The required answer of the given expression is 8/3.
What is simplification?Simplification generally means finding an answer for the complex calculation that may involve numbers on division, multiplication, square roots, cube roots, plus and minus.
The given expression is,
7/3 + 3(2/3 − 1/3)²
Solving the bracket,
= 7/3 + 3{(2− 1)/3}²
solving the fraction,
= 7/3 + 3(1/3)²
solving the square,
= 7/3 + 3(1/9)
= 7/3 + 1/3
adding them we get,
= 8/3
which is the required answer of the given expression.
Thus, the required answer of the given expression is 8/3.
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During low tide in Wrightsville, North Carolina, the beachfront in some places is about 350 feet from the ocean to the homes. High tide can chance the width of a beach at a rate or -17 feet an hour. It takes 6 hours for the ocean to move from low to high tide.
a. What is the change in the width of the beachfront from low to high tide?
b. What is the distance from the ocean to the homes at high tide?
The change in the width of the beachfront from low to high tide is 102 feet, and the distance from the ocean to the homes at high tide is 248 feet.
a. To find the change in width from low to high tide, we multiply the rate of change (-17 feet/hour) by the time it takes for the ocean to move from low to high tide (6 hours).
So, -17 feet/hour * 6 hours = -102 feet. Therefore, the width of the beachfront decreases by 102 feet from low to high tide.
b. At high tide, the distance from the ocean to the homes is the sum of the original distance (350 feet) and the change in width during the tide change (-102 feet), resulting in 350 feet + (-102 feet) = 248 feet.
What is the correct classification of the system of equations below?
12x − 3y = 9
y − 4x = -3
parallel
coincident
intersecting
James has 195.84 square yards of land he can use to grow vegetables. He wants to divide this into patches of 16.32 square yards. He will be able to create garden patches on his land. If he wants to create garden patches with an area of 32.64 square yards, he will be able to create patches on the land.
Answer:
With 16.32 square yards, James gets 12 patches.
With 32.64 square yards, he gets 6 patches.
Step-by-step explanation:
James has 195.84 square yards of land he can use to grow vegetables.
He wants to divide this into patches of 16.32 square yards.
So, he will get [tex]\frac{195.84}{16.32}=12[/tex] equal patches.
If he wants to create garden patches with an area of 32.64 square yards, then he gets [tex]\frac{195.84}{32.64}=6[/tex] patches.
When making a full batch of tuna you will mix one pouch of tuna with 26 ounces 737 g of mayonnaise how much Tony mayonnaise would you need when making a double batch
Determine the intervals on which the function is increasing, decreasing, and constant. (5 points)
The function is increasing in:
x< -1
and it is decreasing in:
x > -1
and nowhere constant.
Step-by-step explanation:We know that the graph of a function is increasing if we get a line in a graph with a positive slope i.e. with the increasing values of x the y-value is also increasing.The function is decreasing if the graph of a function is a line with a negative slope i.e. with the increasing values of x the y-value is decreasing.The function is constant over a interval if the graph of the function over that interval is a straight line with zero slope ; i.e. a line which is parallel to the x-axis over the interval.April can run at a rate that is 2 miles per hour faster then Donna's rate. one day, april gave donna a 25 minute head start on a run. if April passes Donna five miles from the starting point, how fast is each Runner running?
Let us say that:
s = speed of Donna
s + 2 = speed of April
Then we are also given that:
t + (25/60) = time of Donna
t = time of April
The distance taken by the two should be equal. We know that distance is the product of speed and time, so:
s * (t + 25/60) = (s + 2) t
We also know that:
(s + 2) * t = 5
s = 5/t – 2
So that:
(5/t – 2) * (t + 25/60) = 5
5 + 125/60t – 2t – 50/60 = 5
25/12t – 2t – 5/6 = 0
Multiply everything by t:
- 2t^2 – 5/6 t + 25/12 = 0
t^2 + 5/12 t = 25/24
Completing the square:
(t + 5/24)^2 = 25/24 + (5/24)^2
t + 5/24 = ± 1.04
t = -1.25 h, 0.83 h
Since time cannot be negative, therefore t = 0.83 h
So,
(s + 2) * t = 5
s + 2 = 5/0.83 = 6 miles per hour
s = 4 miles per hour
Answers:
speed of Donna = 4 miles / hr
speed of April = 6 miles / hr
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