What’s the square root of 108 a to the 7th power b to the 5th power

Answer:   [tex]\bold{x^{\frac{1}{3}}}[/tex]

Step-by-step explanation:

[tex]\sqrt[6]{x^2} =x^{\frac{2}{6}}=x^{\frac{1}{3}}[/tex]

Answer:

2x + 3y = -10

Step-by-step explanation:

First convert the line into slope intercept form to find the slope of the line.

2x + 3y = 4

3y = 4 - 2x

y = -2/3x + 4/3

The slope of the line is -2/3. Parallel lines have the same slope so the slope for a line through the point (1,-4) will be -2/3. Substitute m = -2/3 and (1,-4) into the point slope of a line.

[tex]y --4 = -\frac{2}{3}(x-1)\\y + 4 = -\frac{2}{3}(x -1)[/tex]

Now convert the line into standard form by using the distributive property.

[tex]y + 4 = -\frac{2}{3}(x -1)\\y + 4 = -\frac{2}{3}x + \frac{2}{3}\\3y + 12 = -2x + 2\\2x + 3y + 12 = 2\\2x + 3y = -10[/tex]

Answer:

20

Step-by-step explanation:

Answer:

i got 15.5

Step-by-step explanation:

Answer: 3 classes

If we removed 5 students from each of the classrooms, we would be able to keep the 18 classes and give them exactly 30 students. However, we would also have the leftover students to put into classrooms.

If there are 18 classrooms with 5 extra students from each, we can use 18*5 to find how many total students we have.

18 * 5 = 90.

If each class size is 30, we need to divide 90 by 30 to find how many classes we need.

90 / 30 = 3 classes

Therefore, to reduce the class size to 30 students per class, 3 new classes must be formed.

To reduce the class size from 35 students to 30 students in a school with 18 classes, we need to calculate the total number of students and then determine how many new classes are needed.

1. **Total number of students:**

  [tex]\[ \text{Total students} = 18 \text{ classes} \times 35 \text{ students/class} = 630 \text{ students} \][/tex]

2. **Number of classes required with 30 students per class:**

 [tex]\[ \text{Required classes} = \frac{630 \text{ students}}{30 \text{ students/class}} = 21 \text{ classes} \][/tex]

3. **New classes to be formed:**

  [tex]\[ \text{New classes} = \text{Required classes} - \text{Current classes} = 21 - 18 = 3 \text{ classes} \][/tex]

Answer:

d). f(x)=-1/2x +6 (see attachment)

Step-by-step explanation:

Answer:

4.5 * 10^-11

Step-by-step explanation:

the reason why is there is 11 zeros in front of the 45

hope this helps :)

Answer:

Step-by-step explanation:

House?

Number of hours left to work(x) = 15 hours - (3 hours/day)x

Note how this Number of hours decreases steadily from its initial value (15 hours) at the rate of 3 hours/day.  The domain of x is [0,5].

By slope intercept form, the number of days that the Rebecca should volunteer exists 5 days.

The "equation of the straight line exists y = mx + c this form exists named slope intercept form".

Rebecca must complete 15 hours of volunteer work. She does 3 hours each day.

The linear equation exists in slope intercept form exists y = mx + c, where 'm' exists the slope straight line and 'c' exists y-intercept.

y = 15 hours - 3 hours/day x days

y = 15 - 3x ............(1)

To find y-intercept put x=0 in (1) we get,  

y = 15 - 3(0)

 = 15

y = 15

which exists the amount of volunteer hours.

Rebecca must complete at day 0.

0 = 15 - 3x

3x = 15

x = 5 [Number of days Rebecca would have to volunteer]

Therefore, utilizing slope intercept form, the number of days that the Rebecca should volunteer exists 5 days.

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Answer:

Not entirely positive of about the answers, but all of the values would equal 15

First Y = 5

First X = 15

Second X = -3

Answer:

x / y

0/5

15/0

-3/6

Step-by-step explanation:

Answer:

The line y = 5x - 13, looks slanted right upwards

Step-by-step explanation:

To easily solve this question, we use a graphing tool, or a calculator to plot the graph.

Please see image below.

From looking at the graph, we know that the function is slanted right upwards.

Answer:

A

Step-by-step explanation:

This is an even polynomial because both ends end up. This means the degree of the polynomial is even. This means b and c are not solutions since their degrees are odd.

To determine between A and D look at the x-intercepts. The x-intercepts of a polynomial graph have a special relationship with its equation. The x-intercepts are the solutions or roots of the factors. This means that when each factor is set equal to 0 and solved, its solution is an x-intercept. Here the x-intercepts are x = -1, 0,3. This means the factors are x(x+1)(x-3).

Notice at x = -1, the function touches but does not cross? This means the factor has an even exponent on it.

So the expression is likely x(x+1)^2 (x-3).

Since only one factor has an exponent, the answer is A.

I'm pretty sure the answer is D

Answer:

The answer is D

Step-by-step explanation:

To find the slope you do y2-y1/x2-x1. This will leave you with 3/1 which is equivalent to 3.

Final answer:

Explanation of values of t for which the given expression can be factored into binomials.t = 0; pairs of binomials: (x) and (3x + 8)

t = 1; pairs of binomials: (x + 1) and (3x + 8)

t = 2; pairs of binomials: (x + 2) and (3x + 4)

Explanation:

Values of t for which 3(x²) + tx + 8 can be factored into binomials: To factor this expression, we need to identify values of t that allow the expression to be split into two binomials that, when multiplied, give the original expression.

t = 0; pairs of binomials: (x) and (3x + 8)

t = 1; pairs of binomials: (x + 1) and (3x + 8)

t = 2; pairs of binomials: (x + 2) and (3x + 4)

Answer:

If it is a cube, the answer would be 76.7 .

Step-by-step explanation:

Answer:

Step-by-step explanation:

Two negatives make a positive, so -(-4) = +4. On a number line, -(-4) would be located 4 units to the right of 0.

The statement "It is 4 units to the right of 0" best describes the location of −(−4) on a number line.

When you have a double negative like −(−4), it becomes positive, so −(−4) is equal to 4, and it is 4 units to the right of 0 on the number line.

The statement "It is 4 units to the right of 0" accurately describes the location of −(−4) on a number line. When dealing with a double negative like −(−4),

it effectively becomes a positive value. In this case, −(−4) simplifies to 4. Therefore, the point −(−4) is located at the position corresponding to the number 4 units to the right of the origin, which is represented by 0 on the number line.

Moving to the right on the number line means increasing the numerical value, so, as a result, −(−4) is found 4 units to the right of 0.

This concept highlights the fundamental principle that negating a negative value results in a positive value, and the position of that positive value is to the right of the origin on the number line.

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Hello, this is a bet tough so follow the steps!

First we need to set up long division.

     __

33|35

    If we calculate 33 divided by 35 we get 1 with a remainder of 2.

Our work:

  1

   __

33|35

   -33

_____

      2

So therefore we get 1 with a remainder of 2.

Enjoy your day!

Answer:  The correct option is (B) 9.

Step-by-step explanation:  We are given to simplify the following expression :

[tex]E=3^5\div 3^3.[/tex]

We will be using the following property of exponents :

[tex]\dfrac{x^a}{x^b}=x^{a-b}.[/tex]

Therefore, the simplification of the given expression is as follows :

[tex]E\\\\=3^5\div 3^3\\\\\\=\dfrac{3^5}{3^3}\\\\\\=3^{5-3}\\\\=3^2\\\\\=9.[/tex]

Thus, the required simplified answer is 9.

Option (B) is CORRECT.

Answer:

(A) [tex]x=60^{\circ}[/tex]

Step-by-step explanation:

Given: It is given that the circle P is circumscribed about quadrilateral ABCD and ∠BCD=120°.

To find: The value of x

Solution: It is given that the circle P is circumscribed about quadrilateral ABCD and ∠BCD=120°.

Now, we know that the sum of opposite angles in a cyclic quadrilateral is 180°, therefore

[tex]{\angle}BAD+{\angle}BCD=180^{\circ}[/tex]

substituting the given values, we get

[tex]x+120^{\circ}=180^{\circ}[/tex]

[tex]x=60^{\circ}[/tex]

Thus, the value of x is 60°.

Hence, option A is correct.

Answer: 60

Step-by-step explanation:

Answer:

The correct options are 1 and 2.

Step-by-step explanation:

The vertices of triangle are S(-4,4), T(-1,4), R(-1,1).

If triangle translated 2 units left,

[tex](x,y)\rightarrow (x-2,y)[/tex]

and then reflected over the y-axis,

[tex](x-2,y)\rightarrow (-x+2,y)[/tex]

The relation between image and preimage is

[tex](x,y)\rightarrow (-x+2,y)[/tex]                          ..... (1)

The vertices of image are

[tex]S(-4,4)\rightarrow S'(6,4)[/tex]

[tex]T(-1,4)\rightarrow T'(3,4)[/tex]

[tex]R(-1,1)\rightarrow R'(3,1)[/tex]

Therefore the vertices of image are S'(6,4),T'(3,4), R'(3,1).

1. A reflection over the y-axis and then a translation 2 units right is defined as

[tex](x,y)\rightarrow (-x+2,y)[/tex]

It is equivalent to relation 1, therefore option 1 is correct.

2. A 180 rotation about the origin, then a translation 2 units right, and then a reflection over the x-axis is defined as

[tex](x,y)\rightarrow (-x+2,y)[/tex]

It is equivalent to relation 1, therefore option 2 is correct.

3. A reflection over the y-axis and then a translation 2 units left is defined as

[tex](x,y)\rightarrow (-x-2,y)[/tex]

It is not equivalent to relation 1, therefore option 3 is incorrect.

4. A 180 rotation about the origin, then a translation 2 units left, and then a reflection over the x-axis is defined as

[tex](x,y)\rightarrow (-x-2,y)[/tex]

It is not equivalent to relation 1, therefore option 4 is incorrect.

5. A reflection over the x-axis and then a translation 2 units right is defined as

[tex](x,y)\rightarrow (x+2,-y)[/tex]

It is not equivalent to relation 1, therefore option 5 is incorrect.

6. A reflection over the x-axis and then a translation 2 units left is defined as

[tex](x,y)\rightarrow (x+2,-y)[/tex]

It is not equivalent to relation 1, therefore option 6 is incorrect.

Therefore the correct options are 1 and 2.

Answer:

1 and 2 are the correct answers.

Step-by-step explanation:

3^2 = 9

3^4= 81

9 x 81 = 729

Your answer is 729 . Good luck (:

Answer:

The answer is [tex]\frac{4y}{y+3}[/tex] ⇒ the 4th answer

Step-by-step explanation:

* Lets talk about the product of two fraction

- If we have two fraction a/b and c/d, the product of them

  will be ac/bd

- The there is any simplify can do between numerator and

  denominator we must to make it

Ex: 2a²/5b × 15b/4a, we can simplify 2a² with 4a at first and

      simplify 15b with 5b and then put the answer

∵ 2a²/4a = a/2 ⇒ 2 ÷ 4 = 1/2 and a² ÷ a = a

∵ 15b/5b = 3 ⇒ 15 ÷ 5 = 3 and b ÷ b = 1

∴ 2a²/5b × 15b/4a = a/1 × 3/2 = 3a/2

* Now lets solve the problem

∵ [tex]\frac{2y}{y-3}*\frac{4y-12}{2y+6}[/tex]

- We can simplify the second fraction at first

∵ [tex]\frac{4y-12}{2y+6}=\frac{4(y-3)}{2(y+3}=\frac{2(y-3)}{y+3}[/tex]

- At first we took 4 as a common factor from 4y - 12 ⇒ 4(y - 3)

 and then simplify 4 with 2 in the denominator

- we can cancel the term x - 3 in the numerator of the second

 fraction with the same term in the denominator of the first fraction

∴ [tex]\frac{2y}{1}*\frac{2(1)}{y+3}=\frac{4y}{y+3}[/tex]

* The answer is [tex]\frac{4y}{y+3}[/tex]

Answer:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

[tex]a = 15\ ft\\\\k = 40\ ft[/tex]

[tex]y = 15sin(\frac{\pi}{10}t) + 40[/tex]

Step-by-step explanation:

In this problem the amplitude of the sinusoidal function is given by the length of the blades.

[tex]a = 15\ ft[/tex]

The mill is 40 feet above the ground, therefore the function must be displaced 40 units up on the y axis. So:

[tex]k = 40\ ft[/tex]

We know that the blades have an angular velocity w = 3 rotations per minute.

One rotation = [tex]2\pi[/tex]

1 minute = 60 sec.

So:

[tex]w = \frac{3(2\pi)}{60}\ rad/s[/tex]

[tex]w = \frac{\pi}{10}\ rad/s[/tex]

Finally:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

[tex]a = 15\ ft\\\\k = 40\ ft[/tex]

[tex]y = 15sin(\frac{\pi}{10}t) + 40[/tex]

Answer:

a is the length of the blade

the vertical shift , k, is the height of the windmill

a= 15 k= 40

the period is 20 seconds

b = pi/10

y=15sin(π/10t)+40

Step-by-step explanation:

Answer:

[tex]\large\boxed{\ln e^4=4}[/tex]

Step-by-step explanation:

[tex]Use\\\\\log_ab^n=n\log_ab\\\\\log_aa=1\\\\\ln a=\log_e a\to\ln e=1\\====================================\\\\\ln e^4=4\ln e=4(1)=4[/tex]

4 is the value of the given logarithmic function.

The natural logarithm (ln) and the exponential function [tex](e^x)[/tex] are inverse operations of each other. Therefore, [tex]ln(e^x)[/tex] will cancel out and leave us with just x.

In this case,[tex]ln(e^4)[/tex] simplifies to just 4:

[tex]ln(e^4) = 4[/tex]

So,  the value of [tex]ln(e^4)[/tex] is 4.

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Answer:

x=37

Step-by-step explanation:

Since this is a right triangle, we can use Pythagorean theorem

a^2 +b^2 =c^2

12^2 +35^2 = x^2

144+1225= x^2

1369 = x^2

Take the square root

sqrt(1369) = sqrt(x^2)

37 = x

Answer:

x = 37

Step-by-step explanation:

Two leg lengths (35 and 12) are given, and the hypotenuse length is to be found.  The Pythagorean Theorem links, these three quantities and enables us to find x quickly and easily:

35² + 12² = x²  →  1225 + 144 = 1369  →  x² = 1369

Find x by taking the square root of both sides:

√(x²) = ±√1369  →  x = ± 37.

Because length is always +, omit x = -37 and keep x = +37.

Answer:

it’s d

Step-by-step explanation:

just took the test

The graph represents the equation g(x) = -∛(x - 1).

Option  D is the correct answer.

It is the movement of the shape in the left, right, up, and down directions.

The translated shape will have the same shape and shape.

There is a positive value when translated to the right and up.

There is a negative value when translated to the left and down.

We have,

f(x) = ∛x

Reflection over the x-axis.

f(x) = -∛x

And,

Translated one unit to the left.

g(x) = -∛(x - 1)

The graph of g(x) = -∛(x - 1) is shown on the given graph.

Thus,

The graph represents the equation g(x) = -∛(x - 1).

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Answer:

the answer is 3/4

Step-by-step explanation:

Answer:

The correct answer is 3/4

Step-by-step explanation:

1/2+1/4=3/4

The area of the copy would be 36 in x16in

The area of the copy of the photograph, with doubled dimensions of 12 inches by 8 inches, is 96 square inches, which is four times the area of the original photograph.

To find the area of a copy of a photograph with dimensions that are double the original, you first find the new dimensions. Since the original photograph is 6 inches by 4 inches, doubling both the length and the width gives us dimensions of 12 inches by 8 inches for the copy.

The area of a rectangle is found by multiplying the length by the width. Therefore, the area of the copied photograph is 12 inches x 8 inches, which equals 96 square inches. This is four times the area of the original photograph since the scale factor for both the length and the width is 2, and the area scales with the square of the scale factor (22).

In conclusion, the area of the copied photograph is 96 square inches. This calculation demonstrates that when you change the linear dimensions of a figure by a scale factor, the area changes by the square of that scale factor.

perpendicular means negative reciprocal so it would be -1/3

Answer:

slope = 0

Step-by-step explanation:

x = 3 is a vertical line parallel to the y- axis with undefined slope.

A line perpendicular to x = 3 is a horizontal line parallel to the x- axis with a slope of zero.

➷ It would be [tex]-2\sqrt{6}[/tex]

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Answer:

the answer is a b and e

Step-by-step explanation:

i jus took the assignment

Answer:

A,B,E

Step-by-step explanation:

passed the assignment

you would move the decimal to the right four times giving you 782000

Answer:

between 90° and 180°

Step-by-step explanation: