Which of the following is a possible disadvantage of recursion? Question 10 options: Recursive solutions can be less efficient than their iterative counterparts Recursive solutions tend to be longer than their iterative counterparts Recursive solutions are more likely to go into infinite loops than their iterative counterparts Recursive solutions tend to have more local variables than their iterative counterparts

Answers

Answer 1

Answer:

Recursive solutions can be less efficient than their iterative counterparts

Explanation:

Recursion can be defined or described as a method of solving a problem where the solution depends on solutions to smaller instances of the same problem.

It entails using iteration to ensure that smaller parts of a solution are satisfied towards solving thw overall problem.

Ita major disadvantage seems to be that it seem to be less efficient than their iterative counterparts. This is as a result of concentrating on trying to solve a smaller instances.


Related Questions

Create a public non-final class named Larger parameterized by a type T that implements Comparable. (Please use T or the test suite will fail.) You should provide a single instance method named larger that accepts an array of the parameterized type as the first argument and a single value of the parameterized type as the second argument. larger should return true if the second argument is larger than or equal to every value of the array and false otherwise. If either the array or the value are null you should throw an IllegalArgumentException. As an ungraded bonus challenge, see if you can make the compiler warning about unchecked operations go away…​ (Note that normally we would write this as a class method. Java does support type parameters for static methods, but we aren’t going to cover that in class. So we’ll use an instance method here instead.) Note also that this homework is not due until Friday but was accidentally released Thursday. It does rely on material we will cover Friday. Feel free to wait to complete it then.

Answers

Answer:

see explaination

Explanation:

class Larger<T extends Comparable<T>> {

public boolean larger(T[] arr, T item) {

if (arr == null || item == null)

throw new IllegalArgumentException();

for (int i = 0; i < arr.length; i++) {

if (item.compareTo(arr[i]) < 0) {

return false;

}

}

return true;

}

}

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